<?php
'<form method="post" action="postnotice.php");>
<p> <label for="idCode">ID Code (required): </label>
<input type="text" name="idCode" id="idCode"></p>
<p> <input type="submit" value="Post Notice"></p>
</form>'
?>
Alright, so that's part of my php form - very simple. For my second form (postnotice.php):
<?php
//Some other code containing the password..etc for the connection to the database.
$conn = #mysqli_connect($sql_host,$sql_user,$sql_pass,$sql_db);
if (!$conn) {
echo "<font color='red'>Database connection failure</font><br>";
}else{
//Code to verify my form data/add it to the database.
}
?>
I was wondering if you guys know of a simple way - I'm still quite new to php - that I could use to perhaps hide the form and replace it with a simple text "Attempting to connect to database" until the form hears back from the database and proceeds to the next page where I have other code to show the result of the query and verification of "idCode" validity. Or even database connection failure. I feel it wrong to leave a user sitting there unsure if his/her button click was successful while it tries to connect to the database, or waits for time out.
Thanks for any ideas in advance,
Luke.
Edit: To clarify what I'm after here was a php solution - without the use of ajax or javascript (I've seen methods using these already online, so I'm trying to look for additional routes)
what you need to do is give form a div and then simply submit the form through ajax and then hide the div and show the message after you get the data from server.
<div id = "form_div">
'<form method="post" id = "form" action="postnotice.php";>
<p> <label for="idCode">ID Code (required): </label>
<input type="text" name="idCode" id="idCode"></p>
<p> <input type="submit" value="Post Notice"></p>
</form>'
?>
</div>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').on('submit', function (e) {
$.ajax({
type: 'post',
url: 'postnotice.php',
data: $('form').serialize(),
success: function (data) {
if(data == 'success'){
echo "success message";
//hide the div
$('#form_div').hide(); //or $('#form').hide();
}
}
});
e.preventDefault();
});
});
</script>
postnotice.php
$idCode = $_POST['idCode'];
// then do whatever you want to do, for example if you want to insert it into db
if(saveSuccessfulIntoDb){
echo 'success';
}
try using AJAX. this will allow you to wait for a response from the server and you can choose what you want to do based on the reponse you got.
http://www.w3schools.com/ajax/default.ASP
AJAX with jQuery:
https://api.jquery.com/jQuery.ajax/
Related
I have a simple webstore and I'm trying to add multiple shipping options. There are two options and I want to store the option selected by the customer in a session (or alternatively a cookie).
The php script seems to work on its own but results in page reloading so I have been trying to implement ajax using jquery to send the data but either the code doesn't run or the page reloads.
I have tried to follow several answers, including substituting button for type="submit" but that results in the code not seeming to execute at all. Adding 'click' to .on triggers the code but also results in a reload. I've checked the console and can't see any issues. Thanks for any help.
jQuery
$(function(){
$('#shipping_form').on('submit', function(e){
e.preventDefault();
var ship = $('input[name="shipping_val"]').val();
$.ajax({
type: 'GET',
data: { discount: ship },
success: function(data) {
//go to next section
}
});
return false;
});
});
HTML/PHP
<?php
Session_start();
if(isset($_GET['shipping_submit'])){
$shipping_get = $_GET['shipping_val'];
}else{
$shipping_get = '3.99';
}
$_SESSION['shipping'] = $shipping_get ;
?>
<html>
<main class="container">
<form method="GET" name="shipping_form" id="shipping_form" action="">
<p>Please choose your prefered shipping method.</p>
<input type="radio" name="shipping_val" value="3.99" checked>
<label for="shipping_val">
Standard delivery
</label>
<input type="radio" name="shipping_val" value="6.99" >
<label for="shipping_val">
Express delivery
</label>
<button type="submit" id="shipping_submit" name="shipping_submit" >Update</button>
<?php
echo '<h1>' . $_SESSION['shipping'] . '</h1>';
?>
</form>```
Your problem is likely that you are using AJAX to submit data to the same file you are calling it from. Your ajax end point (PHP-side) needs to be a different PHP file.
See this other question:
values not updated after an ajax response
Updated: It still not work after I add "#".
I am new to ajax. I am practicing to send value to php script ,and get result back.
Right now, I met one issue which I can not show my result in my html page.
I tried serves answers online, but I still can not fix this issue.
My index.html take value from the form and send form information to getResult.php.
My getResult.php will do calculation and echo result.
How do I display result into index.html?
Hers is html code
index.html
<html>
<body>
<form name="simIntCal" id="simIntCal" method="post"
>
<p id="Amount" >Amount(USD)</p>
<input id="amount_value" type="text" name="amount_value">
<p id="annual_rate" >Annual Rate of Interest
(%)</p>
<input id="rate_value" type="text" name="rate_value">
<p id="time_years" >Time (years)</p>
<input id="time_value" type="text" name="time">
<input id="calculate" type="submit" value="Calculate">
</form>
<p id="amount_inteCal" >The Amount (Acount
+ Interest) is</p>
<input id="result" type="text">
</body>
</html>
ajax script :
<script>
$('#simIntCal').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'getResult.php',
data: $('#simIntCal').serialize(),
success: function (result) {
$("#result").text(result);// display result from getResult.php
alert('success');
}
});
});
</script>
getResult.php
<?php
if ($_SERVER ["REQUEST_METHOD"] == "POST") {
//do some calculation
$result=10;//set result to 10 for testing
echo $result;
}
?>
You are missing the '#' in front of your css selector for result.
$("result").text(result);// display result from cal.php
Should be
$("#result").text(result);// display result from cal.php
index.php
----php start---------
if(isset($_POST['name'])){
echo 'Thank you, '.$_POST['name']; exit();
}
----php end ---------
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<script>
function test(){
var formDATA = {'name': $('#input_name').val()}
$.ajax({
type: 'POST',
url: 'index.php',
data: formDATA,
success: function(response){
$('#result').html();
}
});
}
</script>
<input id="input_name" type="text" value="">
<button onclick="test();">Test Ajax</button>
<div id="result"></div>
Try something simple, this is a very basic version of ajax and php all in one page. Since the button triggers the function you don't even need a form (doesn't mean you shouldn't use one). But i left it simple so you could follow everything.
Sorry when i added php open and closing tags it didn't show up as code.
Also don't forget to include your jquery resources.
In your html file where you want the result to display, you probably want to be using a div.
Currently your code is using an input field:
<input id="result" type="text">
And what you probably want is something like this:
<div id="result"></div>
Unless you were intending to have the result show up in an input field inside your form, and in that case, the input field isn't actually inside your form code.
I've been reading multiple threads about similar cases but even now I'm still unable to do it correctly.
What I want to do
Basically, i.e. I have form which allows user to change his login (simply query to database).
PHP script looks like that:
if(isset($_POST['login'])) {
$doEdit = $user->editData("login", $_POST['login']);
if($doEdit) {
$result = displayInfobox('success', 'Good!');
} else {
$result = displayInfobox('warning', 'Bad!');
}
} else {
$error = 'Bad!';
echo $error;
}
displayInfobox is just a div with class i.e. success and content - Good!.
Right now I would like to send this form by AJAX and display $result without reloading page.
HTML:
<form id="changeLogin" method="post" class="form-inline" action="usercp.php?action=editLogin">
<label for="login">Login:</label><br />
<div class="form-group ">
<input type="text" class="form-control" name="login" id="login" required>
<input type="submit" value="ZmieĆ" class="btn btn-primary">
</div>
</form>
And finnally - my jquery/ajax:
$("#changeLogin").submit(function(e) {
var postData = $(this).serializeArray();
var formURL = $(this).attr("action");
$.ajax({
url: formURL,
type: "POST",
data: postData,
success: function(result) {
alert(result);
},
error: function(response) {}
});
e.preventDefault();
});
$("#changeLogin").submit();
If I leave "success" blank, it works -> form is submitted by ajax, login changed, but I do not see the result message. Otherwise whole page get reloaded.
Also, when I hit F5 form is being submited once again (even in Ajax).
I cant add comments because i do not have enough reputation but...
You should delete the last line with $("#changeLogin").submit();
And then in your php script file you should echo the result so you can get this result in ajax request. After that in your success method you have to read the result and (for example) append it somewhere to show the success or error box
I think you can use a normal button instead of submit button,just onclick can be an ajax request, the form should not be submitted,good luck.
I'm having great issues making this contact form that can be seen on the below visual. What I want the contact form to do is display on submit a thank you message or a message of confirmation instead of redirecting to the contact.php file where there isn't any styles you can see this in action on the provided link.
I've found some information that I can do this with Jquery Ajax that I've also tried displayed below, but I still can't seem to get it to work on submit to show a message in the pop up.
Does anyone know an easier way to do this or maybe point me in the right direction as this is something that I've been trying to fix for god knows how long.
Thank you for any help
Visual:
http://madaxedesign.co.uk/dev/index.html
PHP & HTML:
<?php
$your_email = "maxlynn#madaxedesign.co.uk";
$subject = "Email From Madaxe";
$empty_fields_message = "<p>Please go back and complete all the fields in the form.</p>";
$thankyou_message = "<p>Thank you. Your message has been sent. We Will reply as soon as possible.</p>";
$name = stripslashes($_POST['txtName']);
$email = stripslashes($_POST['txtEmail']);
$message = stripslashes($_POST['txtMessage']);
if (!isset($_POST['txtName'])) {
?>
<form id="submit_message" class="hide_900" method="post" action="/contact.php" onsubmit="javascript: doSubmit();">
<div id="NameEmail">
<div>
<label for="txtName">Name*</label>
<input type="text" title="Enter your name" name="txtName" />
</div>
<div>
<label for="txtEmail">Email*</label>
<input type="text" title="Enter your email address" name="txtEmail" />
</div>
</div>
<div id="MessageSubmit">
<div>
<textarea maxlength="1200" title="Enter your message" name="txtMessage"></textarea>
<label for="txtMessage">Message</label>
</div>
<div class="submit">
<input type="submit" value="Submit" /></label>
</div>
</div>
</form>
Jquery:
function doSubmit(){
var postData = jQuery('#submit_message').serialize();
jQuery.ajax({
url: '/contact.php',
data: postData
}).done(function( html ) {
alert(html);
});
You can add return false; at the end of your doSubmit function or the following code to prevent the form to redirect the user to the action page.
var doSubmit = function (event) {
var postData = jQuery('#submit_message').serialize();
jQuery.ajax({
url: '/contact.php',
data: postData
}).done(function( html ) {
alert(html);
});
event.preventDefault();
}
$(function () {
$('#submit_message').submit(doSubmit);
});
Modified HTLM
<form id="submit_message">
...
</form>
What is this code doing ?
First, we are defining a function to submit the form data.
Notice the event argument in the function. The first variable in this function is all the form values serialized in a ajax-complient request string. The .ajax() function is sending all the datas to your server. Note that as you did not set the type argument in the .ajax() function, the data are going to be send using the GET HTTP method.
Finally, event.preventDefault() prevents the submit event to be triggered in the browser. When the browser detect a submit event, it will try to submit the form based on the action and the method parameters in the <form> html tag. Usually, this submission performs an user redirection to the action page. This event.preventDefault() will disable this redirection. Note that the event argument is going to be set automatically by jQuery.
Last part, the $(function() { ... }); part means "execute this part when the document is fully loaded." It ensures that the element with sumbit_message id exists before calling the .submit() method. This last method is an event binder. It means that when the submit event is fired on the submit_message form, the function doSubmit will be called.
I hope you have a better understanding of this script. This is a pretty basic one, but if you understand clearly the mechanics, it will help you do become a better jQuery programmer. :)
Fiddle Demo
1.<form onsubmit='confirm()'>
function confirm()
{
alert("Thank You");
}
2.in contact.php call the page that is displayed again
You need to prevent the default event of the form. To do this, add the e.preventDefault(); function to the top of your function in order to prevent this event from firing.
Also notice that we are passing the e parameter to your function. This represents the event that has been fired.
function doSubmit(e){
e.preventDefault();
var postData = jQuery('#submit_message').serialize();
jQuery.ajax({
url: '/contact.php',
data: postData
}).done(function( html ) {
alert(html);
});
}
Try this
change your form with
<form id="submit_message" class="hide_900" method="post">
and in script put it
$("#submit_message").submit(function(e){
e.preventDefault();
//call your ajax
});
Greetings from some noob trying to learn JQuery,
I am attempting to make it when you type something in a box below a div layer it reloads that layer upon submission of the form with a php get of the text box in the form. Expected behavior is it would reload that box, actual behavior is it don't do anything. Can someone help me out here.... Below is the code.
<div id="currentwxdiv">This is where the new stuff happens
</div>
<form name="changewx" action="/">
<input type="text" id="city">
<input type="submit" name="submit" class="button" id="submit_btn" value="New City" />
</form>
<script>
/* attach a submit handler to the form */
$('form[name="changewx"]').submit(function(event) {
/* get some values from elements on the page: */
var $form = $( this ),
city = $('#city').val()
/* Send the data using post and put the results in a div */
$('#currentwxdiv').load('http://api.mesodiscussion.com/?location=' + city);
return false;
});
</script>
Its giving the Javascript Console Error Error....
"XMLHttpRequest cannot load http://api.mesodiscussion.com/?location=goodjob. Origin http://weatherofoss.com is not allowed by Access-Control-Allow-Origin."
You are using POST method? is impossible to post to an external url because with ajax, the url fails the "Same Origin POlice".
If you use GET method, is possible to do that.
Another solution is to make a proxy. A little script that recive the params and then... using CURL or another thing you have to post to the external URL... finally, you jquery have to do the post thing to the proxy:
For example:
$.ajax({
url: '/proxy.php?location=' + city,
success: function(data) {
$('#currentwxdiv').html(data);
}
});
I do it so:
<div id="currentwxdiv">This is where the new stuff happens
</div>
<form name="changewx" action="/">
<input type="text" id="city">
</form>
<script>
$('#city').keyup(function() {
var city = $('#city').val()
$.ajax({
url: 'http://api.mesodiscussion.com/?location=' + city,
success: function(data) {
$('#currentwxdiv').html(data);
}
});
});
</script>
To help you out, i need to test this.
What's the url address of your html code working ?
http://api.mesodiscussion.com/?location= doesn't work... only list the directory content... maybe that's de problem?
Greatings.