Can I get return via URL in php like below?
$var = http://www.example.com/give_data.php?id=4;
Your question is very confusing, but i think you want the contents of the file in your variable?
For that you can use file_get_contents
$var = file_get_contents('http://php.net/manual/en/function.file-get-contents.php');
You can use file_get_contents() as such:
$var = file_get_contents('http://www.xyz.com/give_data.php?id=4');
But that will just return whatever the give_data.php script outputs as a string. If you need more advanced data-types, I would recommend using json_encode() in give_data.php and $var = json_decode($var); after getting the data to get back your original data. Note that this won't work for complex PHP objects. If you really really need, you can use serialize() and unserialize(), but it's not as standard and will work in PHP-only.
Related
I have a curl function which outputs the following text from an api.
number=1&id=731&name=test&value=6311
How could I make a variable which will store one of these values in the text such as I want to make a variable called $name which will have the 'test' value from the output of the api. I saw different things such as in json you can use $variable['name'] but it doesn't seem to work like this.. help
Check this:
Parse query string into an array
Use parse_str function, it looks like:
$get_string = "number=1&id=731&name=test&value=6311";
parse_str($get_string, $get_array);
print_r($get_array);
I am making a web app. In one part of it, I have JS send a string(in json format) to PHP.
The value php receives is:
{"date":"24-03-2014","Cars":["Cheap","Expensive"]}
Now, this is saved in a variable $meta. The problem I am facing is, as to how do I convert this string into an object and reference each individual entry separately.
I have tried json_decode and json_encode
and then I have referenced each variable using $meta.["date"] and $meta.date but nothing seams to work. I am getting just { as the output.
What's the correct way to do this?
$str = '{"date":"24-03-2014","Cars":["Cheap","Expensive"]}';
$obj = json_decode($str);
echo $obj->date;
// 24-03-2014
Usually a $my_obj = json_decode($_POST['jsonstring'], 1); (true supply means it'll be returned as an assoviative array) should be the way to go. If I were you I'd probably try a var_dump($my_obj); to see what actually comes through. If it doesn't work you'll want to make sure that you correctly submit a valid json string, e.g. JSON.stringify();
You should check out the PHP doc page for json_decode here.
By default, unless you pass true as the second parameter for json_decode, the function call will return an object, which you can access the members of by using:
$meta->date
The arrow operator will allow you to access object values, not the square brackets or a dot.
How can i convert this string
$str = "array('3'=>'wwm','1'=>'wom')";
to real php associative array...
It's simple but REALLY INSECURE
$str = "array('3'=>'www.tension.com','1'=>'www.seomeuo.com','requestedBy'=>'1')";
eval("\$array = $str;");
You never should use this approach, there another ways to do it like: serialize() and unserialize()
You can use the eval() function for that:
$str = "array('3'=>'wwm','1'=>'wom')";
eval("\$a=$str;");
var_dump($a);
However using eval() in your code is considered to be risky and you should not use it. Try to use serialize(), unserialize() instead.
First of all. Do not use eval. It is Evil!
http://af-design.com/blog/2010/10/20/phps-eval-is-evil/
Secondly. The simple solution would not to be using this string but simply to use "serialize" when you put it in the DB and unserialize when you pull it out. You are storing a very unusual format.
$youtubes = array("lNT4H39G2rw","pF2_qvdm8DQ","_8ytwhhJwco","K16ZRFWR2Mc","9WuPxe7zc6Q","rXZIIclPnd0","J8ZwyN6E3_Q","OEWJbsh0z-4","o62-X0stdFM","aIIiww2Neq0","5TJc-VbNYg0","MYQa1Tgw_z8","alxzFm-bqug","UmI7oyllrlY","RGKFXDHFmn4");
function randomFromArray($data) {
global $$data;
echo $$data[rand(0,count($youtubes)-1)];
}
randomFromArray("youtubes");
I am trying to get this to work as a function, so I can enter the array name as a parameter. It is then supposed to echo a random entry from the array. The bit where it gets the random entry from array works on its own if I substitute it straight in, but I can't seem to get it working as a function.
Any help?
You're using the variable name $youtubes in your randomFromArray function in the call to count (but the variable is not available under that name there).
Btw., why don't you pass in (a reference to) the array instead of its name? Would be much tidier than using global $$data; The following code uses a reference to avoid copying the array (but remember that then, the outside array could be changed from inside the method):
$youtubes = // ...
function randomFromArray(&$data) {
echo $data[rand(0,count($data)-1)];
}
randomFromArray($youtubes);
dont call the function randomFromArray("youtubes"); in this way you call the function with youtubes parametar like a string. and inside the function itself you dont have a $youtubes variable. call the function like this randomFromArray($youtubes);
hope this would help
You are passing the string 'youtubes' into the function, not the array. You want to pass in the name of the array:
randomFromArray($youtubes);
$youtubes = array("lNT4H39G2rw","pF2_qvdm8DQ","_8ytwhhJwco","K16ZRFWR2Mc","9WuPxe7zc6Q","rXZIIclPnd0","J8ZwyN6E3_Q","OEWJbsh0z-4","o62-X0stdFM","aIIiww2Neq0","5TJc-VbNYg0","MYQa1Tgw_z8","alxzFm-bqug","UmI7oyllrlY","RGKFXDHFmn4");
function randomFromArray($data) {
echo $data[rand(0,count($data)-1)];
}
randomFromArray($youtubes);
There are some things fundamentally wrong here.
global $$data
Why is there a double $ sign? And where would this data be coming from?
echo $$data[rand(0,count($youtubes)-1)];
Your function doesn't know the variable $youtubes, since you have never defined it inside of the function. All your function knows is the $data variable that you are passing to it.
randomFromArray("youtubes"); You are passing a string to your function, rather then your array. You probably want this instead:
randomFromArray($youtubes); // Pointing to your actual array, rather then a string
Try reading up on PHP functions first before attempting to use them as you're lacking a lot of basic knowledge about them.
After you put a ; after global $$data, you can try this: $f = $$data; and then echo $f[rand(..)]; if you really want to use names instead variables as others suggested. And if you do that you can use the string (or $f) further in the function code.
Consider a php script visited with URL of foo?q=some&s=3&d=new. I wonder if there is a paractical method for parsing the url to create links with new variable (within php page). For example foo?q=**another-word**&s=3&d=new or foo?q=another-word&s=**11**&d=new
I am thinking of catching the requested URL by $_SERVER['REQUEST_URI'] then parsing with regex; but this is not a good idea in practice. There should be a handy way to parse variables attached to the php script. In fact, inverse action of GET method.
The $_GET variable contains an already parsed array of the current query string. The array union operator + makes it easy to merge new values into that. http_build_query puts them back together into a query string:
echo 'foo?' . http_build_query(array('q' => 'another-word') + $_GET);
If you need more parsing of the URL to get 'foo', use parse_url on the REQUEST_URI.
What about using http_build_query? http://php.net/manual/en/function.http-build-query.php
It will allow you to build a query string from an array.
I'd use parse_str:
$query = 'q=some&s=3&d=new';
parse_str($query, $query_parsed);
$query_parsed['q'] = 'foo-bar';
$new_query = implode('&', array_map(create_function('$k, $v',
'return $k."=".urlencode($v);'),
array_keys($query_parsed), $query_parsed));
echo $new_query;
Result is:
q=foo-bar&s=3&d=new
Although, this method might look like "the hard way" :)