I am making a web app. In one part of it, I have JS send a string(in json format) to PHP.
The value php receives is:
{"date":"24-03-2014","Cars":["Cheap","Expensive"]}
Now, this is saved in a variable $meta. The problem I am facing is, as to how do I convert this string into an object and reference each individual entry separately.
I have tried json_decode and json_encode
and then I have referenced each variable using $meta.["date"] and $meta.date but nothing seams to work. I am getting just { as the output.
What's the correct way to do this?
$str = '{"date":"24-03-2014","Cars":["Cheap","Expensive"]}';
$obj = json_decode($str);
echo $obj->date;
// 24-03-2014
Usually a $my_obj = json_decode($_POST['jsonstring'], 1); (true supply means it'll be returned as an assoviative array) should be the way to go. If I were you I'd probably try a var_dump($my_obj); to see what actually comes through. If it doesn't work you'll want to make sure that you correctly submit a valid json string, e.g. JSON.stringify();
You should check out the PHP doc page for json_decode here.
By default, unless you pass true as the second parameter for json_decode, the function call will return an object, which you can access the members of by using:
$meta->date
The arrow operator will allow you to access object values, not the square brackets or a dot.
Related
When I print an object using print_r, is there any specific utility function in php to convert the output to an object?
There seems to be enough output to reconstruct the object, but I couldn't find the exact functions to accomplish this.
There is no automatic method to change print_r value back to an object. You are also missing important information like what type is stored at a key (string or number or ..)
You could use var_dump to get more detailed output that can be changed back to an object. But still this does not mean there is an automatic function for it.
Last you could use var_export ( http://php.net/manual/en/function.var-export.php ) to get valid PHP output you can use.
You could also use http://php.net/manual/en/function.serialize.php to pass objects around.
I have a string, more specifically, this one:
a:16:{s:9:"pseudonym";O:16:"SimpleXMLElement":0:{}s:14:"parallel_title";O:16:"SimpleXMLElement":0:{}s:9:"title_var";O:16:"SimpleXMLElement":0:{}s:6:"series";O:16:"SimpleXMLElement":0:{}s:9:"vol_title";O:16:"SimpleXMLElement":0:{}s:9:"reference";O:16:"SimpleXMLElement":0:{}s:10:"bound_with";O:16:"SimpleXMLElement":0:{}s:15:"general_remarks";O:16:"SimpleXMLElement":0:{}s:6:"copies";O:16:"SimpleXMLElement":1:{i:0;s:1:"1";}s:11:"remarks_BPH";O:16:"SimpleXMLElement":0:{}s:3:"ICN";O:16:"SimpleXMLElement":1:{i:0;s:4:"neen";}s:10:"provenance";O:16:"SimpleXMLElement":0:{}s:7:"binding";O:16:"SimpleXMLElement":0:{}s:10:"size_hxwxd";O:16:"SimpleXMLElement":0:{}s:6:"BookID";O:16:"SimpleXMLElement":1:{i:0;s:4:"6271";}s:5:"repro";O:16:"SimpleXMLElement":0:{}}
Is it possible to parse this string somehow? I need to display the keys and values in a list. I tried to use json_decode but it doesn't return anything, even with the second parameter set to true:
json_decode($string,true);
It's not JSON, it's serialized PHP. Use unserialize().
It's serialize object
Read more on PHP website
Disclaimer: I am fairly new to using json.
I am trying to use php to receive json data from an iPAd application. I know how to convert json to an array in php, but how do I actually receive it and store it into a variable so it can be decoded?
Here are a couple examples that I have tried based on google and stackoverflow searches.
$json_request = #file_get_contents('php://input');
$array = json_decode($json_request);
AND ALSO
$array = json_decode($_POST['data'], true);
Any suggestions?
You have the basic idea already.
you should test that the value is set and also strip extra slashes from the incoming string before trying to parse it as JSON.
if(isset($_POST['data'])){
$array = json_decode(stripslashes($_POST['data']),true);
//$array now holds an associative array
}//Data Exists
It also would not be a bad idea before you start working with the array to test that the call to json_decode() was successful by ensuring that $array isn't null before use.
If you do not fully trust the integrity of the information being sent you should do extended checking along the way instead of trusting that a given key exists.
if($array){ // Or (!is_null($array)) Or (is_array($array)) could be used
//Process individual information here
//Without trust
if(isset($array['Firstname'])){
$CustomerId = $array['Firstname'];
}//Firstname exists
}//$array is valid
I in-particular like to verify information when I am building queries dynamically for information that may not be required for a successful db insert.
In the above example $_POST['data'] indicates that what ever called the PHP script did so passing the JSON string using the post method in a variable identified as data.
You could check more generically to allow flexibility in the sending method by using the $_REQUEST variable, or if you know it is coming as via the get method you can check $_GET. $_REQUEST holds all incoming parameters from both get and post.
If you don't know what the name of the variable coming in is and want to play really fast and loose you could loop over the keys in $_REQUEST trying to decode each one and use the one that successfully decoded (if any). [Note: I'm not encouraging this]
I have a PHP multidimensional array witch i converted to JSON using JSON_encode().
I am using drupal so for those not familiar with it, drupal array often have keys that looks like that :
$some_array['und']['0']['value']
So my JSON object ends up looking like:
some_array.und.0.value
Now the problem is that when use the above syntaxe to retreive the value i the following JS error in the FB console : "missing name after . operator"
Also this data is meant to be used with a Jquery template, so i alos tried accessing this data directly in my template with:
${field_city.und.0.value}
Witch unfortunately didn't work either..
How would i go to fix that issue ? Can i access somehow this proprety with JS? Or is there a way that i have JSON_encode function replace all 0 by let's say "zero"? Or even replacing '0' when parsing the JSON string?
Suggestions much appreicated.
Try accessing it with some_array.und["0"].value. '0' is not a valid name for a javascript object, which is why accessing it via the . notation is not working.
However, if you access it via the square brackets, you can access keys with any name at all.
As well as using the dot notation, you can use regular array notation to access JSON nodes:
some_array.und['0'].value
I am trying to parse this json data from the url but i get NULL how do i fix this issue.
$source = file_get_contents('http://partners.socialvi.be/e414f702cf3db89a2fe58066bbab369d65b6a058/activities/available.json');
$json = json_decode($source);
var_dump($json);
That's because the API returns the data in JSONP format, not pure JSON. Notice the surrounding onSVJson([]). You'll either have to strip this out, or read the API documentation and try another request format. My guess would be that leaving out the final &callback=onSVJson should do the trick.
That's because if you call the url (go to http://partners.socialvi.be/e414f702cf3db89a2fe58066bbab369d65b6a058/activities/available.json?network_user_id=3459874&max_activities=9&callback=onSVJson with your browser) the json that is returned has no values
Remove the last part of the URL (&callback=onSVJson) and it'll work.
Many APIs offer a feature called JSONP, that allows the JSON to be passed to a callback function, in order to simplify access via cross domain JavaScript. But for PHP you don't need that.
The name of the callback function is typically specified using the callback GET parameter. If you leave that out, no callback function is used - just plain JSON.