I have 3 tables.
Table 1 : t_atc_list
id | a_name | s_title | r_name
------------------------------
80 | ss | 128 | 5
Where s_title & r_name is foreign key.
Table 2 : t_s_list
s_id | title
-------------
128 | Song Title
Table 3 : t_r_list
r_id | r_name
--------------
5 | Artist
I have used following query to have desired output in this format Song Title- Artist using album name that is a_name
$resultid=mysql_query("SELECT s_title, r_name FROM t_atc_list where a_name='$album' ");
$rowid=mysql_fetch_array($resultid);
$query=mysql_query("SELECT s.title, r.r_name FROM t_a_list as a, t_r_list as r, WHERE s.s_id=$rowid('s_title') and r.r_id= $rowid('r_name')");
$row=mysql_fetch_array($query);
I think the SQL query you want is:
SELECT
t.id,
t.a_name,
s.title as s_title,
r.r_name
FROM
t_atc_list t
INNER JOIN t_s_list s ON t.s_title = s.s_id
INNER JOIN t_r_list r ON t.r_name = r.r_id
WHERE
t.a_name = '$album'
FWIW, your table naming conventions and your schema in general are pretty wacky. At the very least, what's wrong with "tracks", "songs" and "artists", or whatever they are supposed to be (or for purists, "track", "song", "artist") for your table names?
$query=mysql_query("SELECT s.title, r.r_name
FROM t_a_list a, t_r_list r, WHERE s.s_id={$rowid['s_title']}
and r.r_id={$rowid['r_name']}");
you are misusing $rowid in the string. I don't know if it's THE problem but it certainly is one.
PS: you could rewrite the queries into one join-query. but before you delve into SQL, I suggest you get the PHP basics straight and read about arrays.
Related
I am working on a photography project and I am facing a bit issue with joining tables and retrieving data from mysql database.
I have created two tables for this project. One table named cm_team is for team members and another table named cm_events for photography events..Assume to shoot a event, we require 6 persons and the id of the person is stored in cm_events table.
As you can see from the above images.. I am storing the id's of members of cm_team in cm_events table.. I wish to obtain the name of the team member in the respective highlighted fields in the cm_events table..Any help is highly appreciated.
for example my desired output should be: instead of 5 under team_lead heading, I should get the name corresponding to 5 i.e Arjun
Something like this? (cleaner and faster than subqueries)
SELECT
`event`.client_name,
`event`.client_number,
# some more event cols ..
`team_lead`.`cm_name` AS `team_lead`,
`candid_photo`.`cm_name` AS `candid_photo`,
`candid_video`.`cm_name` AS `candid_video`,
`traditional_photo`.`cm_name` AS `traditional_photo`,
`traditional_video`.`cm_name` AS `traditional_video`,
`helper`.`cm_name` AS `helper`
FROM cm_events `event`
JOIN cm_team `team_lead` ON `team_lead`.`cm_code` = `event`.`team_lead`
JOIN cm_team `candid_photo` ON `candid_photo`.`cm_code` = `event`.`candid_photo`
JOIN cm_team `candid_video` ON `candid_video`.`cm_code` = `event`.`candid_video`
JOIN cm_team `traditional_photo` ON `traditional_photo`.`cm_code` = `event`.`traditional_photo`
JOIN cm_team `traditional_video` ON `traditional_video`.`cm_code` = `event`.`traditional_video`
JOIN cm_team `helper` ON `helper`.`cm_code` = `event`.`helper`
With Sub queries
DROP TABLE IF EXISTS T,t1;
CREATE TABLE T (
id int, name varchar(10));
insert into t values
(1 , 'aaa'),
(2 , 'bbb');
create table t1 (
id int, team_lead int,team_a int);
insert into t1 values
(1,1,2),
(2,2,2);
select t1.id, (select t.name from t where t.id = t1.team_lead) team_lead,
(select t.name from t where t.id = t1.team_a) team_a
from t1;
+------+-----------+--------+
| id | team_lead | team_a |
+------+-----------+--------+
| 1 | aaa | bbb |
| 2 | bbb | bbb |
+------+-----------+--------+
2 rows in set (0.001 sec)
I have following table 'persons' with same persons in different rows
id | firstname | surname | date_created
------------------------------------------------------
3 | Nelli | Schaller | 2017-08-22 20:57:19
------------------------------------------------------
4 | Carl | Schaller | 2019-06-21 08:29:45
------------------------------------------------------
48 | Nelli | Schaller | 2020-06-25 13:06:09
------------------------------------------------------
49 | Carl | Schaller | 2020-06-25 13:06:09
What I want to get are all unique Schallers with the biggest id / newest date_created value.
I tried this
SELECT id, CONCAT(surname, ", ", firstname) AS person, date_created
FROM persons
WHERE
surname LIKE "schall%"
GROUP by firstname, surname
ORDER BY date_createdDESC, surname ASC LIMIT 0, 10
but get only as expected the first two entries (id 3 and 4) but I need 48 and 49.
As mentioned in some comment in this case the LIKE statement isn't necessary but in real live it will be the source for an autocomplete field so I need the LIKE
Any idea how to manage that?
Use NOT EXISTS:
SELECT p.id, CONCAT(p.surname, ', ', p.firstname) AS person, p.date_created
FROM persons p
WHERE p.surname LIKE '%schall%'
AND NOT EXISTS (SELECT 1 FROM persons WHERE firstname = p.firstname AND surname = p.surname AND id > p.id)
ORDER BY p.date_created DESC, person
If the condition to pick the latest of each group is the column date_created then change:
...AND id > p.id
with
...AND date_created > p.date_created
You could use subquery with group for max id
select t.max_id, t.person, m.date_created
from (
SELECT max(id) max_id, CONCAT(surname, ", ", firstname) AS person
FROM persons
WHERE surname LIKE "schall%"
ORDER BY date_createdDESC, surname ASC
GROUP BY CONCAT(surname, ", ", firstname)
) t
inner join persons m ON CONCAT(m.surname, ", ", m.firstname) = t.person
and m-id = t.max_id
SELECT p.*
FROM persons p
LEFT JOIN persons p2 ON p2.firstname = p.firstname
AND p2.lastname = p.lastname
AND p2.date_created > p.date_created
WHERE p2.id IS NULL
This is SQL Server syntax but MySQL is probably similar.
I'm assuming your id field doesn't need to be checked as well as the date_created since it's an identity column and would be larger anyway for the latter created records, but obviously adjust to your actual data.
The question has been resolved. But if you have a "better" or another way to do it then feel free to add a comment! Thanks all for reading! :)
I'm trying to make a dynamic query. Everything is working perfectly except for one thing. I've Google'd for days but I can't figure out how I can make the following work;
SELECT project.name, project.description, track.name, track.description
, SDG.position, SDG.title, SDG.description
, sprint_numbers.number, sprint_options.option
, resources.name, resources.description
, URLs.URL
FROM project INNER JOIN track ON project.track_id = track.id
INNER JOIN project_SDG ON project.id = project_SDG.project_id
INNER JOIN SDG ON project_SDG.SDG_id = SDG.id
INNER JOIN sprint ON sprint.project_id = project.id
INNER JOIN sprint_numbers ON sprint_numbers.id = sprint.sprint_number_id
INNER JOIN sprint_options ON sprint_options.id = sprint.sprint_option_id
INNER JOIN resources ON project.id = resources.project_id
INNER JOIN URLs ON URLs.id = resources.id
WHERE 1=1
AND MATCH (project.name) AGAINST (:name_project)
AND MATCH (project.description) AGAINST (:description_project)
AND SDG.id = :SDG_1
AND SDG.id = :SDG_2
The query executes but does not return anything. The problem is that the SDG.id can't be true to both :SDG_1 and :SDG_2.
Using the OR operator works, but that does not return it the way I want. It must "act" as an AND operator. (:SDG_1 & :SDG_2 are the names of the PHP variables that bind to the SQL statement parameters.)
The query should filter for both values. The values given to :SDG_1 and :SDG_2 must both exist in the SDG.id column of the project_SDG table. If the value of :SDG_1 exists, but :SDG_2 not, then the query should not return anything.
I found this on StackOverflow but it did not work for me: SELECTING with multiple WHERE conditions on same column
I hope someone can help me out.
EDIT: minimal reproducible example
QUERY:
SELECT * FROM project
INNER JOIN project_SDG ON project.id = project_SDG.project_id
INNER JOIN SDG ON project_SDG.SDG_id = SDG.id
WHERE SDG.id = 1 AND SDG.id = 7 AND SDG.id = 14 AND SDG.id = 17
Project table
+------------------+---------------------------+------------+
| id name | description | track_id |
+------------------+---------------------------+------------+
| 1 project name | This is a description 2 | |
+------------------+---------------------------+------------+
SDG table
+-----+-----------+-------------+---------------------------------------------+
| id | position | title | description |
+-----+-----------+-------------+---------------------------------------------+
| 1 | 1 | SDG 1 to 17 | There're multiple SDGs ranging from 1 to 17 |
| 17 | 17 | SDG 1 to 17 | There're multiple SDGs ranging from 1 to 17 |
+-----+-----------+-------------+---------------------------------------------+
project.SDG (bridge-table)
+------------+--------+
| project.id | SDG.id |
+------------+--------+
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
+------------+--------+
You want for each project.id both values :SDG_1 and :SDG_2 to exist for SDG.id, so use this in the WHERE clause:
WHERE 1=1
AND MATCH (project.name) AGAINST (:name_project)
AND MATCH (project.description) AGAINST (:description_project)
AND project.id IN (
SELECT project_id
FROM project_SDG
WHERE SDG_id IN (:SDG_1, :SDG_2)
GROUP BY project_id
HAVING COUNT(DISTINCT SDG_id) = 2
)
Could you provide a minimal reproducible example for your query?
Generally speaking, one field cannot be equal to two different values in the same time. So, you have either mixed up the logical operators or you need two different fields.
I can assume that in your case there may be several related records with different values. In this case, you need to join the same table twice with different aliases. Let's say as SDG1 and SDG2. After that you can compare
... `SDG1`.id = :SDG_1 AND `SDG2`.id = :SDG_2
Update:
The win trick is groupping. You can enumerate all required SDG IDs and count how many of them is in group. Just for example in case of two IDs:
SELECT project.id
FROM project
JOIN project_SDG ON project_SDG.project_id = project.id
JOIN SDG ON SDG.id = project_SDG.SDG_id
WHERE SDG.id IN(1,2)
GROUP BY project.id
HAVING COUNT(*) = 2
See my sandbox here: https://www.db-fiddle.com/f/pixe3Zcs75Mq2PyCYPk913/0
If you need all project's fields, you have to put this into sub-query as
... WHERE id IN ( subquery here )
Subquery example: https://www.db-fiddle.com/f/pixe3Zcs75Mq2PyCYPk913/1
I have already answered here, but I have another approch.
1. Find bunch of IDs assotiated with some project
To find project IDs we can test lonely pivot table without any join:
SELECT project_id FROM project_SDG
WHERE SDG_id IN(1,2,6)
GROUP BY project_id HAVING COUNT(*) = 3
it gives us list of Project IDs
2. Access all project fields and add extra conditions
SELECT project.*
FROM project
JOIN (
SELECT project_id FROM project_SDG
WHERE SDG_id IN(1,2,6)
GROUP BY project_id HAVING COUNT(*) = 3
) AS ids ON ids.project_id = project.id
WHERE
MATCH(project.name) AGAINST ('project') AND
MATCH(project.description) AGAINST ('sit')
you can play with it here: https://www.db-fiddle.com/f/pixe3Zcs75Mq2PyCYPk913/3
3. Prepare query on the PHP side
I will use known technique to prepare SQL statement.
$ids = [1, 2, 6]; // it can come from request parameters
$text1 = 'project';
$text2 = 'sit';
// build ?,?,?,... pattern
$qmarks = implode(',', array_fill(0, count($ids), '?'));
// Use SQL query above
$sth = $dbh->prepare("
SELECT project.*
FROM project
JOIN (
SELECT project_id FROM project_SDG
WHERE SDG_id IN({$qmarks})
GROUP BY project_id HAVING COUNT(*) = ?
) AS ids ON ids.project_id = project.id
WHERE
MATCH(project.name) AGAINST (?) AND
MATCH(project.description) AGAINST (?)
");
$sth->execute(array_merge($ids, [count($ids), $text1, $text2]));
$records = $sth->fetchAll();
maybe someone can help me.
I have 2 sql tables:
// groups
| id_group | namegroup |
+------------+-----------+
| 30 | s |
// contacts
| name | group |
+------+-------+
| juan | s |
I need to DELETE a group from ID, but no has contacts associated with it.
I test the following query but doesnt work.
DELETE
FROM group
WHERE id_group = 30
AND (
SELECT
count(*) AS id
FROM contacts co
INNER JOIN GROUP c ON co. GROUP = c.namegroup
WHERE c.id_group = 30
) = 0
Thanks
You can try the following query if you want to delete group having ID = 30 only if the group is not associated to any contact :
Query #1:
DELETE
`groups`
FROM `groups`
LEFT JOIN contacts
ON contacts.`group` = `groups`.namegroup
WHERE `groups`.id_group = 30
AND contacts.`group` IS NULL;
And if you want to delete all groups which don't have any associated contact then try the following query instead:
Query #2:
DELETE
`groups`
FROM `groups`
LEFT JOIN contacts
ON contacts.`group` = `groups`.namegroup
WHERE contacts.`group` IS NULL;
If you define firigen key mysql will handle this issue and you do not need to do anything
In these cases(without forigen key) i usually first run following query:
select count(*) as id from contacts co inner join group c on co.group=c.namegroup where c.id_group=30
And say to user which if they can delete or not and if he could delete that row:
delete from group where id_group=30
I tried to find a solution like query which you had but could not and suggest this solution for you.
i have 3 tables that looks like this:
game_table
+---------+------------+------------+----------------------+----------+
| game_id | game_title | sponser_id | game expiration date | prize_id |
+---------+------------+------------+----------------------+----------+
prize_table
+----------+---------------------------+------------+-------------+--------------------+--------------------------------------------+
| prize_id | prize_image_name | prize_cost | prize_title | remaining_quantity | prize_description |
+----------+---------------------------+------------+-------------+--------------------+--------------------------------------------+
sponser_table
+------------+--------------+
| sponser_id | sponser_name |
+------------+--------------+
how do i build query that select all data from the 3 tables that
meat the statement that go's something like pseudo code:
select all data from game_table and prize_table and sponser_table where game_table.sponser_id = 2 and game_table.prize_id = 2
i tried something like this :
SELECT game_list.*, prize_list.* ,sponser_list.* FROM game_list, prize_list,sponser_list
WHERE game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
but it gave me no good results .
You had a WHERE clause to limit to the correct ids, but you had no join conditions to relate your tables. Instead of the implicit join syntax you attempted (comma-separated table list), use a explicit JOINs with stated relating columns:
SELECT
game_list.*,
prize_list.* ,
sponser_list.*
FROM
game_list
JOIN prize_list ON game_list.prize_id = prize_list.prize_id
JOIN sponser_list ON game_list.sponser_id = sponser_list.sponser_id
WHERE game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
I would recommend against selecting all columns from each table though, since you are duplicating the id columns in at least two places. Instead, be explicit about the columns you want. This will also help you if you later add additional columns to these tables that should not be included in this query.
SELECT
game_id,
game_title,
game_list.sponser_id,
game_expiration_date,
game_list.prize_id,
prize_image_name,
prize_cost,
prize_title,
remaining_quantity,
prize_description,
sponser_name
FROM
game_list
JOIN prize_list ON game_list.prize_id = prize_list.prize_id
JOIN sponser_list ON game_list.sponser_id = sponser_list.sponser_id
WHERE game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
SELECT *
FROM game_table
JOIN prize_table USING (prize_id)
JOIN sponser_table USING (sponser_id)
WHERE sponser_id = 2
AND prize_id = 2
AND game_id = 2
SELECT
game_list.*, prize_list.* ,sponser_list.*
FROM game_list
JOIN prize_list ON game_list.prize_id = prize_list.prize_id
JOIN sponser_list ON game_list.sponser_id = sponser_list.sponser_id
WHERE
game_list.sponser_id=2 And game_list.prize_id = 2 And game_list.game_id=2 ;
From your description it appears that the tables may be related. If they are, you need to use a join, like this:
SELECT *
FROM game_table g
LEFT OUTER JOIN prize_table p ON p.prize_id=g.prize_id
LEFT OUTER JOIN sponser_table s ON s.sponser_id=g.sponser_id
WHERE g.game_id=2