PHP String Replacement - php

I wish to have one string that contains for instance (mystring):
file config.php
$mystring = "hello my name is $name and i got to $school";
file index.php
include('config.php');
$name = $_GET['name'];
$school = $_GET['school'];
echo $mystring;
Would this work ? or are there any better ways

$string = 'Hello, my name is %s and I go to %s';
printf($string, $_GET['name'], $_GET['school']);
or
$string = 'Hello, my name is :name and I go to :school';
echo str_replace(array(':name', ':school'), array($_GET['name'], $_GET['school']), $string);
You can automate that last one with something like:
function value_replace($values, $string) {
return str_replace(array_map(function ($v) { return ":$v"; }, array_keys($values)), $values, $string);
}
$string = 'Hello, my name is :name and I go to :school';
echo values_replace($_GET, $string);

No it won't work.
You have to define $name first before using it in another variable
config.php should look like
<?php
$name = htmlspecialchars($_GET['name']);
$school = htmlspecialchars($_GET['school']);
$mystring = "hello my name is $name and i got to $school";
and index.php like
<?php
include('config.php');
echo $mystring;
Why didn't you try it?
demo:
http://sandbox.phpcode.eu/g/2d9e0.php?name=martin&school=fr.kupky

Alternatively, you can use sprintf like this:
$mystring = "hello my name is %s and i got to %s";
// ...
printf($mystring, $name, $school);

This works because your $mystring literal is using double quotes, if you'd used single quotes then it would not work.
http://www.php.net/manual/en/language.types.string.php#language.types.string.parsing

Related

PHP preg_replace string within variables

I am using PHP 7.2.4, I want to make a template engine project,
I try to use preg_replace to change the variable in the string,
the code is here:
<?php
$lang = array(
'hello' => 'Hello {$username}',
'error_info' => 'Error Information : {$message}',
'admin_denied' => '{$current_user} are not Administrator',
);
$username = 'Guest';
$current_user = 'Empty';
$message = 'You are not member !';
$new_string = preg_replace_callback('/\{(\$[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*)\}/', 'test', $string);
function test($matches)
{
return '<?php echo '.$matches[1].'; ?>';
}
echo $new_string;
But it just show me
Hello , how are you?
It automatically remove the variable...
Update:
here is var_dump:
D:\Wamp\www\t.php:5:string 'Hello <?php echo $username; ?>, how are you?' (length=44)
You may use create an associative array with keys (your variables) and values (their values), and then capture the variable part after $ and use it to check in the preg_replace_callback callback function if there is a key named as the found capture. If yes, replace with the corresponding value, else, replace with the match to put it back where it was found.
Here is an example code in PHP:
$values = array('username'=>'AAAAAA', 'lastname'=>'Smith');
$string = 'Hello {$username}, how are you?';
$new_string = preg_replace_callback('/\{\$([a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*)}/', function($m) use ($values) {
return 'Hello <?php echo ' . (!empty($values[$m[1]]) ? $values[$m[1]] : $m[0]) . '; ?>';
}, $string);
var_dump($new_string);
Output:
string(47) "Hello Hello <?php echo AAAAAA; ?>, how are you?"
Note the pattern charnge, I moved the parentheses after $:
\{\$([a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*)}
^ ^
Actually, you may even shorten it to
\{\$([a-zA-Z_\x7f-\xff][\w\x7f-\xff]*)}
^^
Do you want something like this?
<?php
$string = 'Hello {$username}, how are you?';
$username = 'AAAAAA';
$new_string = preg_replace('/\{(\$[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*)\}/', $username, $string);
echo $new_string;
The result is:
Hello AAAAAA, how are you?
The more simple way would be to just write
<?php
$username = 'AAAAAA';
$string = 'Hello '.$username.', how are you?';
I'm a fan of keeping it simple so I would use str_replace since it will also change all instances which may come in handy as you go forward.
$string = 'Hello {$username}, how are you?';
$username = 'AAAAAA';
echo str_replace('{$username}',$username,$string);

Convert space seperated string to class in php

I have a string 'abc back'
Is there a simple way to convert this to like this "AbcBack" in PHP
Just try with ucwords:
$input = 'abc back';
$output = str_replace(' ', '', ucwords($input));
Use ucfirst() function in php.Use the code below
<?php
$string='abc back';
$p = explode($string," ");
$text="";
foreach($p as $m){
$text .= ucfirst($m);
}
echo str_replace(" ","",$text);// will print AbcBack
You can use ucwords() to. Use the code below
<?php
$string='abc back';
echo str_replace(" ","",ucwords($string));
Hope this helps you

Variable inside regular expression php

I a stuck with regular expression and i need help.
So basically i want to do somethning like this:
$data = "hi";
$number = 4;
$reg = '/^[a-z"]{1,4}$/';
if(preg_match($reg,$data)) {
echo 'Match';
}else {
echo 'No match';
}
But i want to use variable
$reg = '/^[a-z"]{1, variable here }$/';
I have tried:
$reg = '/^[a-z"]{1, '. $number .'}$/';
$reg = "/^[a-z\"]{1, $number}$/";
But not getting right result.
Tnx for help
In the first example you have space where you shouldn't have one,
you have:
$reg = '/^[a-z"]{1, '. $number .'}$/';
your should have:
$reg = '/^[a-z"]{1,'. $number .'}$/';
then it works just fine
Update: You have same error in second example - thanks to AbraCadaver
Another way to use variables in regex is through the use of sprintf.
For example:
$nonWhiteSpace = "^\s";
$pattern = sprintf("/[%s]{1,10}/",$nonWhiteSpace);
var_dump($pattern); //gives you /[^\s]{1,10}/

Removing Certain Text from String in PHP

I am trying to trim a string in PHP so that I can only get certain text from the String.
I have an email stored to a String for instance some_name#somedomain.com .
How can I remove the text after the '#' so that I would only 'some_name'?
In PHP you can do :
$string = 'some_name#somedomain.com';
$res = explode('#', $string);
echo $res[0];
Or you can use regexp, string functions in php ... etc
You should know both ways to do this:
substr
$mail = "some_name#somedomain.com";
echo substr($mail, 0, strpos($mail, '#') );
explode
list($name, $domain) = explode('#', $mail);
echo $name;
If you don't need the $domain you can skip it:
list($name) = explode('#', $mail);
More about list.
Demo: http://ideone.com/lbvQF
$str = 'some_name#somedomain.com';
$strpos = strpos($str, "#");
echo $email = substr($str, 0,$strpos);
you can try this to get string before #
Try This
$str1 = "Hello World";
echo trim($str1,"World");
You could try split using regex and the # symbol. This will return two Strings which you can then use just to acquire the 'some_name'.
http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/String.html
String s = "some_name#somedomain.com";
String name = s.substring(0,s.indexOf("#");

Grab variable from php URL string

What's the easiest way to grab a 6-character id from a string?
The id will always be after www.twitpic.com/ and will always be 6 characters.
e.g., $string = 'The url is http://www.twitpic.com/f1462i. Enjoy.';
$id = 'f1462i';
Thanks.
Here you go. Complete working code without regex :
<?php
$string = 'The url is http://www.twitpic.com/f1462i. Enjoy.';
$id = substr($string, strpos($string, 'http://www.twitpic.com/')+23, 6);
echo $id; //output: f1462i
?>
$string = "http://www.twitpic.com/f1462i" ;
$id = substr($string,strpos($string, 'twitpic.com')+strlen('twitpic.com')+1,6) ;
echo $id ;
preg_match("#twitpic\.com/(\w{6})#", "The url is http://www.twitpic.com/f1462i. Enjoy.", $m);
$id = $m[1];

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