I am trying to trim a string in PHP so that I can only get certain text from the String.
I have an email stored to a String for instance some_name#somedomain.com .
How can I remove the text after the '#' so that I would only 'some_name'?
In PHP you can do :
$string = 'some_name#somedomain.com';
$res = explode('#', $string);
echo $res[0];
Or you can use regexp, string functions in php ... etc
You should know both ways to do this:
substr
$mail = "some_name#somedomain.com";
echo substr($mail, 0, strpos($mail, '#') );
explode
list($name, $domain) = explode('#', $mail);
echo $name;
If you don't need the $domain you can skip it:
list($name) = explode('#', $mail);
More about list.
Demo: http://ideone.com/lbvQF
$str = 'some_name#somedomain.com';
$strpos = strpos($str, "#");
echo $email = substr($str, 0,$strpos);
you can try this to get string before #
Try This
$str1 = "Hello World";
echo trim($str1,"World");
You could try split using regex and the # symbol. This will return two Strings which you can then use just to acquire the 'some_name'.
http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/String.html
String s = "some_name#somedomain.com";
String name = s.substring(0,s.indexOf("#");
Related
How to remove 4th letter in string using PHP ?
I use this code.
<?php
$str = "1234567890";
$str2 = mb_substr($str, 4);
echo $str2;
?>
But it's will echo 567890
I want to echo 123567890 remove 4 from string.
How can i do ?
You can try substr_replace for this. Here we are replacing 4 which is at 3rd index.
Try this code snippet here
<?php
$str = "1234567890";
echo substr_replace($str, "", 3,1);
try setting the 3rd index to null
<?php
$str = "1234567890";
$str[3] = null;
echo $str;
try with below sulution:
$str = '1234567890';
$str_arr = str_split($str);
unset($str_arr[3]);
echo implode('', $str_arr);
output:
123567890
There are multiple ways of performing any operations on string variables in php
// can be used for printing purpose
$str = "1234567890";
echo substr($str,0,3).substr($str,4);
// actual replacement of string
$str = "1234567890";
echo substr_replace($str, "", 3,1);
This is my string:
monkey/rabbit/cat/donkey/duck
If my variable is cat...
$animal = cat
... I want to remove everything coming after cat.
My desired result is:
monkey/rabbit/cat
I tried to use str_replace:
$subject = 'monkey/rabbit/cat/donkey/duck';
$trimmed = str_replace($animal, '', $subject);
echo $trimmed;
But here I get the result:
monkey/rabbit//donkey/duck
So it is just cutting out cat.
You can combine strpos with substr:
$pos = strpos($subject, $animal);
if ($pos !== false) {
$result = substr($subject, 0, $pos + strlen($animal));
}
If you wold like to make sure it only the full segments are erased, in case of a partial match, you could use the offset argument of strpos:
$pos = strpos($subject, $animal);
if ($pos !== false) {
$result = substr($subject, 0, strpos($subject, '/', $pos));
}
You can use explode in your case:
$string = "monkey/rabbit/cat/donkey/duck";
$val = explode("donkey", $string );
echo $val[0];
Result: monkey/rabbit/cat
PS* Ofcourse there are better ways to do this
My approach would be to explode by your variable.
Take the first part and append the variable.
<?php
$string = 'monkey/rabbit/cat/donkey/duck';
$animal = 'cat';
$temp = explode($animal,$string);
print $temp[0] . $animal;
Will output nicely
monkey/rabbit/cat
There's no need to use any of strpos, strlen, substr or donkeys
<?php
$animal="cat";
$string1="monkey/rabbit/cat/donkey/duck";
$parts = explode($animal, $string1);
$res = $parts[0];
print("$res$animal")
?>
Here is a bit of explanation for what each step does:
$subject = 'monkey/rabbit/cat/donkey/duck';
$target = 'cat';
$target_length = strlen($target); // get the length of your target string
$target_index = strpos($subject, $target); // find the position of your target string
$new_length = $target_index + $target_length; // find the length of the new string
$new_subject = substr($subject, 0, $new_length); // trim to the new length using substr
echo $new_subject;
This can all be combined into one statement.
$new_subject = substr($subject, 0, strpos($subject, $target) + strlen($target));
This assumes your target is found. If the target is not found, the subject will be trimmed to the length of the target, which obviously is not what you want. For example, if your target string was "fish" the new subject would be "monk". This is why the other answer checks if ($pos !== false) {.
One of the comments on your question raises a valid point. If you search for a string that happens to be contained in one of the other strings, you may get unexpected results. There is really not a good way to avoid this problem when using the substr/strpos method. If you want to be sure to only match a complete word between your separators (/), you can explode by / and search for your target in the resulting array.
$subject = explode('/', $subject); // convert to array
$index = array_search($target, $subject); // find the target
if ($index !== false) { // if it is found,
$subject = array_slice($subject, 0, $index + 1); // remove the end of the array after it
}
$new_subject = implode('/', $subject); // convert back to string
I'm probably going to kop some flak for going down the RegExp route but...
$subject = 'monkey/rabbit/polecat/cat/catfish/duck';
$animal = "cat";
echo preg_replace('~(.*(?:/|^)' . preg_quote($animal) . ')(?:/|$).*~i', "$1", $subject);
This will ensure that your animal is wrapped immediately on either side with / characters, or that it's at the start or end of the string (i.e. monkey or duck).
So in this example it'll output:
monkey/rabbit/polecat/cat
Ending specifically with cat rather than stumbling at polecat or catfish
It might seem easy to do but I have trouble extracting this string. I have a string that has # tags in it and I'm trying to pull the tags maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa
And here is what I want to extract 33.536759,-7.613825,17z :
$var = preg_match_all("/#(\w*)/",$path,$query);
Any way I can do this? Much appreciated.
Change your regex to this one: /#([\w\d\.\,-]*)/.
This will return the string beginning with #.
$string = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
$string = explode('/',$string);
//$coordinates = substr($string[3], 1);
//print_r($coordinates);
foreach ($string as $substring) {
if (substr( $substring, 0, 1 ) === "#") {
$coordinates = $substring;
}
}
echo $coordinates;
This is working for me:
$path = "maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa";
$var = preg_match_all("/#([^\/]+)/",$path,$query);
print $query[1][0];
A regex would do.
/#(-*\d+\.\d+),(-*\d\.\d+,\d+z*)/
If there is only one # and the string ends with / you can use the following code:
//String
$string = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
//Save string after the first #
$coordinates = strstr($string, '#');
//Remove #
$coordinates = str_replace('#', '', $coordinates);
//Separate string on every /
$coordinates = explode('/', $coordinates );
//Save first part
$coordinates = $coordinates[0];
//Do what you want
echo $coordinates;
do like this
$re = '/#((.*?),-(.*?),)/mi';
$str = 'maps/place/Residences+Jardins+de+Majorelle/#33.536759,-7.613825,17z/data=!3m1!4b1!4m2!3m1!1s0xda62d6053931323:0x2f978f4d1aabb1aa';
preg_match_all($re, $str, $matches);
echo $matches[2][0].'<br>';
echo $matches[3][0];
output
33.536759
7.613825
How can I extract 4 from this string?
$string = "Rank_1:1:4";
I'm trying to get pagerank from Googles server, and the last value (4) is the actual pagerank.
Try
$string = "Rank_1:1:4";
$data = explode(':',$string);
echo end($data);
EDIT
as per #MichaelHampton, if they add more fields later, then use as below
$string = "Rank_1:1:4";
$data = explode(':',$string);
echo $data[2];
PHP has so many string function you can use ...
Variables
$find = ":";
$string = "Rank_1:1:4";
Using substr
echo substr($string, strrpos($string, $find) + 1);
Using strrchr
echo ltrim(strrchr($string, $find),$find);
$pattern = '/:\d+$/';
preg_match($pattern, $string, $matches);
$rank = substr($matches[0],1);
I have the following XML:
<id>tag:search.twitter.com,2005:22204349686</id>
How can i write everything after the second colon to a variable?
E.g. 22204349686
if(preg_match('#<id>.*?:.*?:(.*?)</id>#',$input,$m)) {
$num = $m[1];
}
When you already have just the tags content in a variable $str, you could use explode to get everything from the second : on:
list(,,$rest) = explode(':', $str, 3);
$var = preg_replace('/^([^:]+:){2}/', '', 'tag:search.twitter.com,2005:22204349686');
I am assuming you already have the string without the <id> bits.
Otherwise, for SimpleXML:
$var = preg_replace('/^([^:]+:){2}/', '', "{$yourXml->id}");
First, parse the XML with an XML parser. Find the text content of the node in question (tag:search.twitter.com,2005:22204349686). Then, write a relevant regex, e.g.
<?php
$str = 'tag:search.twitter.com,2005:22204349686';
preg_match('#^([^:]+):([^,]+),([0-9]+):([0-9]+)#', $str, $matches);
var_dump($matches);
I suppose you have in a variable ($str) the content of id tag.
// get last occurence of colon
$pos = strrpos($str, ":");
if ($pos !== false) {
// get substring of $str from position $pos to the end of $str
$result = substr($str, $pos);
} else {
$result = null;
}
Regex seems to me inappropriate for such a simple matching.
If you dont have the ID tags around the string, you can simply do
echo trim(strrchr($xml, ':'), ':');
If they are around, you can use
$xml = '<id>tag:search.twitter.com,2005:22204349686</id>';
echo filter_var(strrchr($xml, ':'), FILTER_SANITIZE_NUMBER_INT);
// 22204349686
The strrchr part returns :22204349686</id> and the filter_var part strips everything that's not a number.
Use explode and strip_tags:
list(,,$id) = explode( ':', strip_tags( $input ), 3 );
function between($t1,$t2,$page) {
$p1=stripos($page,$t1);
if($p1!==false) {
$p2=stripos($page,$t2,$p1+strlen($t1));
} else {
return false;
}
return substr($page,$p1+strlen($t1),$p2-$p1-strlen($t1));
}
$x='<id>tag:search.twitter.com,2005:22204349686</id>';
$text=between(',','<',$x);
if($text!==false) {
//got some text..
}