This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
Extract JSONP Resultset in PHP
I get the response in the following format. Im facing trouble on how to get inside "Plugin" variable and access other variables inside it.I used json_decode(), but i cant access the variables.
Plugin
(
{
"plugin_a":"abc",
"plugin_b":"abc",
"plugin_c":"abc"
}
)
I tried
$a = json_decode($json,true);
echo $a['plugin_a'];
I dont get any output.
echo var_dump($json); gives me
string 'Plugin({
"plugin_a":"abc",
"plugin_b":"abc",
"plugin_ce":"abc" })'
try substr();
http://sandbox.phpcode.eu/g/40c20.php
<?php
$json = substr('Plugin
(
{
"plugin_a":"abc",
"plugin_b":"abc",
"plugin_c":"abc"
}
)', 9, -1);
print_r(json_decode($json));
Perhaps this will work for you:
$data=array('plugin_a'=>'abc','plugin_b'=>'bcd','plugin_c'=>'cde');
$json='{"Plugin":'.json_encode($data).'}';
$a=json_decode($json,true);
echo $a['Plugin']['plugin_a'];
It appears as though the actual json array may not have integrity. If this solution doesn't fit, can you post the code that actually builds the json array?
Related
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 3 years ago.
I want to echo a certain part of json in php. I don't know if the json data is valid or invalid.
I have tried the below code:
$get = get_content('domain');
$json = file_get_contents($get);
$decode = json_decode($json);
$final = $decode->count;
echo $final;
The json data which I get from an URL is:
{"15":{"xy":{"cost":6,"count":235}}}
I expect to see only the 235 part. This data keeps on changing. Sometimes the number 6 in the cost can vary as well.
EDIT: Fixed some code.
EDIT1: Actually the data was already a string so just used echo substr($get, 30, 3); to achieve the results.
Try this, it should work
echo $decode[15]['xy']['count'];
This question already has answers here:
How to display json values that are in 2nd level of a multi-dim array?
(3 answers)
How to extract and access data from JSON with PHP?
(1 answer)
Closed 3 years ago.
Need help. I am having trouble solving this json thingy. here's what is on my database
{"img":["images/logo2.png","images/logo.png"]}
I need to decode this images and show it like this
images/logo2.png
images/logo.png
A quick google search will give you this link: json_decode.
$someJson = '{"img":["images/logo2.png","images/logo.png"]}';
$encodeJson = json_decode($someJson, true);
echo $encodeJson['img'][0]; //images/logo2.png
echo $encodeJson['img'][1]; //images/logo.png
Hint: Having a look at the PHP-Manual is not prohibited. ;)
Maybe select your entry from database and put in a variable called $dataBaseEntry then copy paste this code?
$decoded = json_decode($dataBaseEntry, true); //true for associated array
$logos = $decoded['img'];
print_r($logos)
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 6 years ago.
Have tried every variation I can think of to access an object property in an array. I'm getting some data back form an API which i'm storing in a variable called $userTokenValid:
$userTokenValid = [{"authTokenValid":1}];
i'm then trying to access the authTokenValid property like so:
echo json_decode($userTokenValid[0]->authTokenValid);
I appreciate this might be quite basic but can't spot where I have gone wrong.
$userTokenValid isn't valid php. However [{"authTokenValid":1}] is a valid json string.
$userTokenValid = '[{"authTokenValid":1}]';
you can decode it with
$json = json_decode($userTokenValid);
finally
echo $json[0]->authTokenValid;
This question already has answers here:
Trying to parse JSON with PHP
(2 answers)
Accessing JSON array after json_decode/multidimensional array
(3 answers)
Closed 8 years ago.
I am receiving a multilevel json like this:
{"id":"3",
"field2":"ssss",
"field3":[
{"field31":"wwwww",
"field32":"qqqq"},
{"field31":"wwwww",
"field32":"qqqq"},
{"field31":"wwwww",
"field32":"qqqq"},
]}
I am reading json values (first level) like this in php:
$json = file_get_contents('php://input');
$json_post = json_decode(utf8_decode($json), true);
$id = $json_post['id'];
But I don't know how to get the json in the second level. What is the simplest way? I just need to get the json in other variable like $json_post, I will read it in a for bucle to get each row of the json file
It's going to give you a PHP object if you run json_decode(utf8_decode($json));
echo $json_post->field3->field31;
EDIT: I missed that you were using the conversion to array. This is what the array would look like
echo $json_post['field3']['field31'];
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
json decode in php
I want to get my id in php, actually without that php sdk files.
So i am using this.
$a = file_get_contents('https://graph.facebook.com/100004304380055...');
echo $a['id'];
The contents of the response are
{
"id": "100004304380055",
"name": "Ayush Mishra"
}
But it does not returns my id 100004304380055. I thing $a is not an array. I want to know how to make $a an array and then get my id by $a['id']. Please provide the code. Any help will be appreciated.
The endpoint is returning a JSON string; which is a format used to convey object information as a string. Convert the string back to an object, and grab the id property:
$data = json_decode($response);
echo $data->id;
Where $response is the result of your call to file_get_contents().