This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 6 years ago.
Have tried every variation I can think of to access an object property in an array. I'm getting some data back form an API which i'm storing in a variable called $userTokenValid:
$userTokenValid = [{"authTokenValid":1}];
i'm then trying to access the authTokenValid property like so:
echo json_decode($userTokenValid[0]->authTokenValid);
I appreciate this might be quite basic but can't spot where I have gone wrong.
$userTokenValid isn't valid php. However [{"authTokenValid":1}] is a valid json string.
$userTokenValid = '[{"authTokenValid":1}]';
you can decode it with
$json = json_decode($userTokenValid);
finally
echo $json[0]->authTokenValid;
Related
This question already has answers here:
How to display json values that are in 2nd level of a multi-dim array?
(3 answers)
How to extract and access data from JSON with PHP?
(1 answer)
Closed 3 years ago.
Need help. I am having trouble solving this json thingy. here's what is on my database
{"img":["images/logo2.png","images/logo.png"]}
I need to decode this images and show it like this
images/logo2.png
images/logo.png
A quick google search will give you this link: json_decode.
$someJson = '{"img":["images/logo2.png","images/logo.png"]}';
$encodeJson = json_decode($someJson, true);
echo $encodeJson['img'][0]; //images/logo2.png
echo $encodeJson['img'][1]; //images/logo.png
Hint: Having a look at the PHP-Manual is not prohibited. ;)
Maybe select your entry from database and put in a variable called $dataBaseEntry then copy paste this code?
$decoded = json_decode($dataBaseEntry, true); //true for associated array
$logos = $decoded['img'];
print_r($logos)
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 3 years ago.
I'm trying to acces to range but is tnot working
$json = '{"range":[[1,2,20],[3,4.5]]}';
var_dump(json_decode($json->'range'));//doesn't work
var_dump(json_decode($json['range']));//doesn't work
Whay is the way to acces to range?
You need to json_decode() your JSON string first to turn it into an object. After that you can access the object properties with the -> operator.
So the correct way is this
var_dump(json_decode($json)->range));
But it is more readable if you split it into multiple statements:
$decoded = json_decode($json);
var_dump($decoded->range);
you must use this one.
json_decode($json)->range;
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 4 years ago.
I have been scratching my head with this one and wonder if anybody would be kind enough to give me a pointer. I am extracting some data as a variable from JSON to PHP, and I can do this no problem when there are nested nodes - IF the node is a text but not if the node is a number. I am using json_decode
THIS IS NOT THE SAME AS How do I extract data from JSON with PHP?
This is ok
$get_temp = $jsonobj->main->temp;
This is not working
$get_weather = $jsonobj->main->0->weather;
So my question is how do I target the node when it is a number?
Thanks
Probabily you have an array into main node.. so you can get its value with an index like this:
$get_weather = $jsonobj->main[0]->weather;
Where 0 is the index that you want to get
$get_weather = $jsonobj->main[$x]->weather;
$x would be the index
This should work:
$get_weather = $jsonobj->main[0]->weather;
This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 5 years ago.
I have a JSON output that looks like this:
{"data":[{"QID":"Q1234","MgrQID":"5678","NTID":"blah"}]}
I am trying to access just the data within the square brackets, inside the data array?
I have tried $jsonVar['data'] and $jsonVar->data and neither of them are working.
Is there a way I can just get access to [{"QID":"Q1234","MgrQID":"5678","NTID":"blah"}]?
Try this example:
<?php
$data = '{"data":[{"QID":"Q1234","MgrQID":"5678","NTID":"blah"}]}';
$test = json_decode($data, true);
echo json_encode($test['data']);
?>
Output:
[{"QID":"Q1234","MgrQID":"5678","NTID":"blah"}]
This question already has answers here:
Trying to parse JSON with PHP
(2 answers)
Accessing JSON array after json_decode/multidimensional array
(3 answers)
Closed 8 years ago.
I am receiving a multilevel json like this:
{"id":"3",
"field2":"ssss",
"field3":[
{"field31":"wwwww",
"field32":"qqqq"},
{"field31":"wwwww",
"field32":"qqqq"},
{"field31":"wwwww",
"field32":"qqqq"},
]}
I am reading json values (first level) like this in php:
$json = file_get_contents('php://input');
$json_post = json_decode(utf8_decode($json), true);
$id = $json_post['id'];
But I don't know how to get the json in the second level. What is the simplest way? I just need to get the json in other variable like $json_post, I will read it in a for bucle to get each row of the json file
It's going to give you a PHP object if you run json_decode(utf8_decode($json));
echo $json_post->field3->field31;
EDIT: I missed that you were using the conversion to array. This is what the array would look like
echo $json_post['field3']['field31'];