I've been looking at various PHP/AJAX file upload plugins online, but I'm having some trouble finding one feature I really need. For the purposes of this upload, each file that I upload must go into a directory with the same name as that file (minus the extension). Naturally, the nicest way would be to create that folder during the upload and then send the file to it. I know this involves mkdir() in some way, and I've found a number of scripts that even perform basic folder creation, but I'm not clear on how to do this dynamically using the filename. Any ideas?
Thanks!
When you upload a file in php it is stored in the $_FILES array, its name is stored in $_FILES['inputfield']['name'] where 'inputfield' is the name in the file input like:
<input type='file' name='inputfield' />
So then you would do:
$exp = explode(".",$_FILES['inputfield']['name']);
$filename = $exp[0];
$path = "/path/to/base/folder/" . $filename . "/" . $_FILES['inputfield']['name'];
move_uploaded_file($_FILES['inputfield']['tmp_name'], $path);
$fileName = $_FILES['fieldname']['name']
$foldername = substr($fileName, 0, strrpos($fileName, '.'));
Related
I am having a problem with move_uploaded_file().
I am trying to upload a image path to a database, which is working perfectly and everything is being uploaded and stored into the database correctly.
However, for some reason the move_uploaded_file is not working at all, it does not produce the file in the directory where I want it to, in fact it doesn't produce any file at all.
The file uploaded in the form has a name of leftfileToUpload and this is the current code I am using.
$filetemp = $_FILES['leftfileToUpload']['tmp_name'];
$filename = $_FILES['leftfileToUpload']['name'];
$filetype = $_FILES['leftfileToUpload']['type'];
$filepath = "business-ads/".$filename;
This is the code for moving the uploaded file.
move_uploaded_file($filetemp, $filepath);
Thanks in advance
Try this
$target_dir = "business-ads/";
$filepath = $target_dir . basename($_FILES["leftfileToUpload"]["name"]);
move_uploaded_file($_FILES["leftfileToUpload"]["tmp_name"], $filepath)
Reference - click here
Try using the real path to the directory you wish to upload to.
For instance "/var/www/html/website/business-ads/".$filename
Also make sure the web server has write access to the folder.
You need to check following details :
1) Check your directory "business-ads" exist or not.
2) Check your directory "business-ads" has permission to write files.
You need to give permission to write in that folder.
make sure that your given path is correct in respect to your current file path.
you may use.
if (is_dir("business-ads"))
{
move_uploaded_file($filetemp, $filepath);
} else {
die('directory not found.');
}
I have a form with a file to uplaod. All works find. But I don't want to move the file directly into a folder.
After submit I show a confirm page and there I show the uploaded file with
header('Content-Type: image/x-png');
$file = file_get_contents(\Illuminate\Support\Facades\Input::file('restImg'));
$imgType = \Illuminate\Support\Facades\Input::file('restImg')->guessClientExtension();
echo sprintf('<img src="data:image/png;base64,%s" style="max-height: 200px"/>', base64_encode($file));
This works fine. After the confirmation I like to move the file to a folder. How can I move the file after the confirmation? The Input::get('file') is not available anymore.
You will have to store the file in the initial upload somewhere temporarily other than the default tmp directory.
The documentation for PHP file uploads says:
The file will be deleted from the temporary directory at the end of the request if it has not been moved away or renamed
This means that moving onto the next request, the file will no longer be available.
Instead, move it to your own custom temp directory or rename it to something special, then keep the filename in the $_SESSION to persist it to the next request.
For Laravel, this should mean putting it in the /storage directory with something like this:
// Get the uploaded file
$file = app('request')->file('myfile');
// Build the new destination
$destination = storage_path() . DIRECTORY_SEPARATOR . 'myfolder';
// Make a semi-random file name to try to avoid conflicts (you can tweak this)
$extension = $file->getClientOriginalExtension();
$newFilename = md5($file->getClientOriginalName() . microtime()).'.'.$extension;
// Move the tmp file to new destination
app('request')->file('myfile')->move($destination, $newFilename);
// Remember the last uploaded file path at new destination
app('session')->put('uploaded_file', $destination.DIRECTORY_SEPARATOR.$newFilename);
Just remember to unlink() the file after the second request or do something else with it, or that folder will fill up fast.
Additional Reference:
http://api.symfony.com/2.7/Symfony/Component/HttpFoundation/File/UploadedFile.html
So I have an upload service with many people uploading the same files to my Amazon S3 bucket. I changed my app design so the SHA1 of the file is calculated upon upload and checked against the list of uploaded files.
If it exists, I simply assign the file to the new uploader as well.
The problem with this is, the file being named as the first uploader named it. All subsequent uploaders will get the same first name.
I can use download="" attribute in HTML5 but it doesn't work in IE:
http://caniuse.com/#search=download
The files are stored remotely so I can't change the header unless I download it first to my local server which is illogical.
Please advice.
The only way I see this possible is to add a meta-data just before redirecting user to download.
You can add meta-data to your files in S3. With key as "Content-Disposition" and value as 'attachment; filename="~actual file name~"'. You can force the name and trigger download.
This way, you don't have to download any files to local file system.
The caveat to this is if someone else is also requesting the same file with in milli-seconds, first user might get the name as requested by second user.
use the rename() method
example:
$file = "boo.png";
$newName = "scary";
$ext = substr( $file, strpos( "." ), strlen( $file ) );
$path = "/images/downloaded/";
rename($path . $file, $path . $newName . $ext);
php documentation
I am uploading a file using PHP to a folder in my directory and am unable to rename it using the following code
$da = date("dmY");
$ja = $uid.$da;
$mukesh = $app.$ja;
// If no errors, upload the image, else, output the errors
if($err == '') {
if(move_uploaded_file($_FILES['userfile'][$mukesh], $uploadpath));
Here's PHP's official document about how to handle uploads: http://www.php.net/manual/en/features.file-upload.post-method.php
The method move_uploaded_file() requires two parameters, a filename of the temp file, and a new location.
$tmp = $_FILES['userfile']['tmp_name']; // temp path
move_uploaded_file($tmp, $uploadpath . '/' . $mukesh);
You will need to name your input element userfile.
<input type="file" name="userfile" />
Based on code snippet provided, you can do following
move_uploaded_file ($_FILES["userfile"]["tmp_name"], $uploadpath);
When you upload a file, files will be store in upload location specified in php.ini using a temporary name. This file location with name can be accessed by $_FILES["userfile"]["tmp_name"]
Lets say you upload an image.if no error then
$uploads_dir = 'as per you defined';
$tmp_name = $_FILES["userfile"]["tmp_name"];
$name = 'custom_file_name.png';//$_FILES["userfile"]["name"];
move_uploaded_file($tmp_name, $uploads_dir."/".$name);
You are renaming the temp name of file ...
When you want to rename the change the name with which you want to store the file
$filename = time().$_FILES['userfile']['name'];
$upload_path = 'path_to_ur_upload_folder'.$filename;
move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path );
first param in move_upload_file is temporary name that will be used by stream while copying an d uploading .. the second parameter is path where your file will be saved (along with file name).. it is the second parameter which will help you in renaming of file which is being uploaded
I already looked at this StackOverflow question and it didn't help (similarly titled).
I'm passing an image in from my Android application. If I type
$file = fopen('test.jpg', 'wb');
It works correctly and the image uploads; however, I want to allow for multiple uploads from android phones, so I want to randomize the name of the .jpg file so that I can save each new upload as a different name. I was trying this below:
$destination = time() + rand(1, 1000) . ".jpg";
$url_destination = "/project_images/" . $destination;
$file = fopen($url_destination, 'wb');
fwrite($file, $binary);
fclose($file);
It doesn't write the file to the server, however. I tried different variations of the URL there - with 'project_images/', '/project_images/', even trying the full URL (which the aforementioned StackOverflow post corrected me on), and I still can't get it to write.
The permissions of the project_images folder are set to allow files to be written to it. Any ideas?
Your problem is "/project_images" which is a wrong absolute path.
For it to work change it to "project_images/" or dirname(__FILE__).'/project_images/'.
For those who use XAMPP on Windows: use DIRECTORY_SEPARATOR instead /
dirname(__FILE__).DIRECTORY_SEPARATOR.'project_images'.DIRECTORY_SEPARATOR