How to print_r $_POST array? - php

Question

I have following table.
<form method="post" action="test.php">
<input name="id[]" type="text" value="ID1" />
<input name="value[]" type="text" value="Value1" />
<hr />
<input name="id[]" type="text" value="ID2" />
<input name="value[]" type="text" value="Value2" />
<hr />
<input name="id[]" type="text" value="ID3" />
<input name="value[]" type="text" value="Value3" />
<hr />
<input name="id[]" type="text" value="ID4" />
<input name="value[]" type="text" value="Value4" />
<hr />
<input type="submit" />
</form>
And test.php file
<?php
$myarray = array( $_POST);
foreach ($myarray as $key => $value)
{
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
?>
But it is only returning this: <p>0</p><p>Array</p><hr />
What I'm doing wrong?

Answer 1

The foreach loops work just fine, but you can also simply
print_r($_POST);
Or for pretty printing in a browser:
echo "<pre>";
print_r($_POST);
echo "</pre>";

Answer 2

<?php
foreach ($_POST as $key => $value) {
echo '<p>'.$key.'</p>';
foreach($value as $k => $v)
{
echo '<p>'.$k.'</p>';
echo '<p>'.$v.'</p>';
echo '<hr />';
}
}
?>
this will work, your first solution is trying to print array, because your value is an array.

Answer 3

$_POST is already an array, so you don't need to wrap array() around it.
Try this instead:
<?php
for ($i=0;$i<count($_POST['id']);$i++) {
echo "<p>".$_POST['id'][$i]."</p>";
echo "<p>".$_POST['value'][$i]."</p>";
echo "<hr />";
}
?>
NOTE: This works because your id and value arrays are symmetrical. If they had different numbers of elements then you'd need to take a different approach.

Answer 4

You are adding the $_POST array as the first element to $myarray. If you wish to reference it, just do:
$myarray = $_POST;
However, this is probably not necessary, as you can just call it via $_POST in your script.

Answer 5

Why are you wrapping the $_POST array in an array?
You can access your "id" and "value" arrays using the following
// assuming the appropriate isset() checks for $_POST['id'] and $_POST['value']
$ids = $_POST['id'];
$values = $_POST['value'];
foreach ($ids as $idx => $id) {
// ...
}
foreach ($values as $idx => $value) {
// ...
}

Answer 6

Just:
foreach ( $_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}

Answer 7

Because you have nested arrays, then I actually recommend a recursive approach:
function recurse_into_array( $in, $tabs = "" )
{
foreach( $in as $key => $item )
{
echo $tabs . $key . ' => ';
if( is_array( $item ) )
{
recurse_into_array( $item, $tabs . "\t" );
}
else
{
echo $tabs . "\t" . $key;
}
}
}
recurse_into_array( $_POST );

Answer 8

Came across this 'implode' recently.
May be useful to output arrays. http://in2.php.net/implode
echo 'Variables: ' . implode( ', ', $_POST);

Answer 9

$_POST is an array in itsself you don't need to make an array out of it. What you did is nest the $_POST array inside a new array. This is why you print Array.
Change it to:
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}

Answer 10

$_POST is already an array. Try this:
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}

Answer 11

As you need to see the result for testing purpose. The simple and elegant solution is the below code.
echo "<pre>";
print_r($_POST);
echo "</pre>";