I am trying to achieve dynamic $row values from an array, and show them as output. It keeps showing nothing while the values are already there.
This is what I have so far, where:
$row["lg_".$val.""]; should return:
$lg_it
'it' is the $val from the array.
foreach($arrMapCookieToLang as $key => $val) {
$shrtKey = $row["lg_".$val.""];
<input type="text" name="lg_$val" value="$shrtKey">
}
Anyone an idea?
What you have should result in a syntax error. Try the following:
<?php
foreach($arrMapCookieToLang as $key => $val) {
$shrtKey = $row['lg_'.$val];
?>
<input type="text" name="lg_<?= $val ?>" value="<?= $shrtKey ?>">
<?php
}
You've missed to echo your input-field:
foreach($arrMapCookieToLang as $key => $val) {
$shrtKey = $row["lg_".$val.""];
echo '<input type="text" name="lg_' . $val .'" value="' . $shrtKey . '">';
}
Further, if you don't use the array key in the foreach-loop, you can omit the $key =>-part and just write
foreach($arrMapCookieToLang as $val) {
// ...
}
Instead, the
<input type="text" name="lg_$val" value="$shrtKey">
Maybe you should use the
echo "<input type=\"text\" name=\"lg_" . "$val\" value=\"$shrtKey\">";
Related
Trying to link two fields on a POST by getting the ID.
Each 'songfld' has a unique number as below.
The textarea is linked on that number.
The form fields:
<input type="text" name="songfld[901]" value="">
<textarea name="data[901][name]" id="txt-901" rows="2" cols="80"></textarea>
<input type="text" name="songfld[902]" value="">
<textarea name="data[902][name]" id="txt-902" rows="2" cols="80"></textarea>
And trying to get the 901 & 902 ID's here:
foreach($_POST['songfld'] as $val){
$val is the value from input
$id = $_POST['songfld'][0]; // the number in each name="songfld[X]"
$namefld = $_POST['data'][$id]['name']; // gives the value from textarea
echo "<P>$id $idfld $namefld";
}
Of course the value passes, but I'd like to have that unique number from each post as well.
hope someone knows this trick.
Inspect your data like this:
echo "<pre>";
print_r($_POST);
echo "</pre>";
exit;
Also try:
echo "<pre>";
print_r($_POST['songfld']);
echo "</pre>";
exit;
You'll see what is exactly in the arrays.
foreach($_POST['songfld'] as $name => $val){
...
}
Try this:
foreach($_POST['songfld'] as $key => $val){
// $key holds the value you are looking for
}
$sInputFields = '';
for( $i=901;$i<903;$i++ ){
$sInputFields .= '<input type="text" name="songfld[' . $i . ']" value="">';
$sInputFields .= '<textarea name="data[' . $i . '][name]" id="txt-' . $i . '" rows="2" cols="80"></textarea><br>';
}
echo $sInputFields;
You can try this
I'm building a very basic questionnaire (with response page) and it works but my form takes up too much space and looks clunky. How would i loop these question arrays so i can save space?
Here is a small bit of my code asking 2 questions:
<h3>Organisation?</h3>
<p><b>It was well organised</b><p>
<?php
$answers = array("Disagree","Agree");
for($i=0;$i<2;$i++) {
print '<input type="radio" name="org" value="'.$answers[$i].'">'.$answers[$i];
};
?>
</p>
<p><b>Adequate materials?</b><p>
<?php
$answers = array("Disagree","Agree");
for($i=0;$i<2;$i++) {
print '<input type="radio" name="lib" value="'.$answers[$i].'">'.$answers[$i];
};
?>
</p>
You should put the two rows in one php tag and use foreach instead, also you should let your php print the headers.
<?php
$answers= array("Disagree","Agree");
echo "<p><b>It was well organised</b></p><p>";
foreach ($answers as $value) {
print '<input type="radio" name="org" value="'.$value.'"> '.$value;
};
echo "</p>";
echo "<p><b>Adequate materials?</b></p><p>";
foreach ($answers as $value) {
print '<input type="radio" name="lib" value="'.$value.'"> '.$value;
};
echo "</p>";
?>
Sidenote: You have 4 opening p tags <p> and just 2 closing tags </p> in your own code. I added another two closing tags in my code where I expected them to be.
You could do:
<?php $questions = array(
'org' => 'It was well organized',
'lib' => 'Adequate materials?',
); ?>
<h3>Organisation?</h3>
<?php foreach ($questions as $f => $question): ?>
<p><b><?= $question; ?></b></p>
<?php foreach (array('Disagree', 'Agree') as $answer): ?>
<input type="radio" name="<?= $f ?>" value="<?= $answer ?>"> <?= $answer ?>
<?php endforeach; ?>
<?php endforeach; ?>
I think you are looking for something like this:
<h3>Organisation?</h3>
<?php
$answers = array("Disagree","Agree");
$first = ""; $second = "";
foreach($answers as $answer) {
$first .= '<input type="radio" name="org" value="' . $answer . '">' . $answer;
$second .= '<input type="radio" name="lib" value="' . $answer . '">' . $answer;
}
echo "<p><b>It was well organised</b></p><p>" . $first . "</p>";
echo "<p><b>Adequate materials?</b></p><p>" . $second . "</p>";
?>
Why not just make it a function?
function answers($name, $array)
{
$returnStr="";
for($i=0;$i<count($array);$i++)
{
$returnStr.='<p><input type="radio" name="'.$name.'" value="'.$array[$i].'"/> '.$array[$i].'</p>';
}
return $returnStr;
}
Then just call it
<h3>Organisation?</h3>
<p><b>It was well organised</b></p>
<?php echo answers("org",array("Agree","Disagree"));?>
I get two warnings Warning: Invalid argument supplied for foreach() but I still retrieve my expected post variables. Where am I going wrong? It says the warning is in regard to line 7, which in this case is the line that begins; foreach($value as $k => $v)
<!------------- quote.php ----------------->
<body>
What services are you interested in? <br/><br/>
<form name="input" action="quote2.php" method="post">
<?php
$services = array('Tree Felling', 'Height Reduction', 'Crown Thinning', 'Deadwooding/Ivy Removal', 'Stump Grinding', 'Other');
foreach ($services as $option) { ?>
<input id="<?= $option ?>" type="checkbox" name="services[]" value="<?= $option ?>" />
<label for="<?= $option ?>"><?= $option ?></label>
<br />
<? }
?>
<br/>
<input name="name" type="text" />NAME</br>
<input name="place" type="text"/>TOWN</br/>
<input type="submit" value="Submit">
</form>
</body>
<!------------ quote2.php -------------->
<?php
echo '<h3>SERVICES REQUIRED</h3>';
foreach ($_POST as $key => $value) {
foreach($value as $k => $v)
{
echo '<p>'.$v.'</p>';
}
}
echo "<hr /><h3>DETAILS</h3>";
echo $name = $_POST['name'];
echo "</br>";
echo $place = $_POST['place'];
echo "<hr/>"
?>
A number of the form controls do not have names that end in [] and so are not arrays.
You can't loop over a string.
You should pull out each value of the submitted data individually and only loop over services.
The problem is that there is a very real possibility that not all of the items in your $_POST array will have values of type array; which you are assuming according to the code in quote2.php
A simple is_array() check will ensure that only arrays get iterated over in the foreach, here is the edited file contents:
<!------------ quote2.php -------------->
<?php
echo '<h3>SERVICES REQUIRED</h3>';
foreach ($_POST as $key => $value) {
if (is_array($value)) {
foreach($value as $k => $v)
{
echo '<p>'.$v.'</p>';
}
}
}
echo "<hr /><h3>DETAILS</h3>";
echo $name = $_POST['name'];
echo "</br>";
echo $place = $_POST['place'];
echo "<hr/>"
?>
That should do the trick.
Try wrapping your foreach loop in an if statement to check the array is an array. For example:
if (is_array($services)) {
foreach ($services as $option) {
// Some code
}
}
Although I wouldn't worry too much. This is just a cleaner way of writing your code.
I have two array. What I want to do is compare the key ['user_id'] of two arrays, if they are the same, pass the ['user_id'] and ['ref'] in hidden form. I tried to put them into two foreach, but system seems into a dead lock.
<?php foreach($_SESSION['printing_set'] as $data) { ?>
<?php foreach(getProvenaMailableUserlist() as $userlist){ ?>
<input type="hidden" name="reference[<?php echo $data['user_id'] ?>]" value="<? if($userlist['user_id'] == $data['user_id']){echo $userlist['ref'];} ?>" />
<?php } ?>
<?php } ?>
What is the right way to do that?
What you are doing is printing again and again the part of '<input type="hidden" name="...'. here is what you should do
<?php
echo '<input type="hidden" name="reference[' . $data['user_id'] . ']" value="'; //olny one time.
foreach($_SESSION['printing_set'] as $data) {
foreach(getProvenaMailableUserlist() as $userlist){
if($userlist['user_id'] == $data['user_id']){
echo $userlist['ref']; //only if condition is true
}
}
}
echo '" />'; //only one time
?>
You've got some funky formatting going on, so it's hard to tell where the error might be. Try it like this:
<?php
foreach($_SESSION['printing_set'] as $data) {
foreach(getProvenaMailableUserlist() as $userlist){
$value = "";
if($userlist['user_id'] == $data['user_id'])
$value = $userlist['ref'];
echo "<input type='hidden' name='reference$user_id' value='$value' /> \n";
}
}
?>
I have following table.
<form method="post" action="test.php">
<input name="id[]" type="text" value="ID1" />
<input name="value[]" type="text" value="Value1" />
<hr />
<input name="id[]" type="text" value="ID2" />
<input name="value[]" type="text" value="Value2" />
<hr />
<input name="id[]" type="text" value="ID3" />
<input name="value[]" type="text" value="Value3" />
<hr />
<input name="id[]" type="text" value="ID4" />
<input name="value[]" type="text" value="Value4" />
<hr />
<input type="submit" />
</form>
And test.php file
<?php
$myarray = array( $_POST);
foreach ($myarray as $key => $value)
{
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
?>
But it is only returning this: <p>0</p><p>Array</p><hr />
What I'm doing wrong?
The foreach loops work just fine, but you can also simply
print_r($_POST);
Or for pretty printing in a browser:
echo "<pre>";
print_r($_POST);
echo "</pre>";
<?php
foreach ($_POST as $key => $value) {
echo '<p>'.$key.'</p>';
foreach($value as $k => $v)
{
echo '<p>'.$k.'</p>';
echo '<p>'.$v.'</p>';
echo '<hr />';
}
}
?>
this will work, your first solution is trying to print array, because your value is an array.
$_POST is already an array, so you don't need to wrap array() around it.
Try this instead:
<?php
for ($i=0;$i<count($_POST['id']);$i++) {
echo "<p>".$_POST['id'][$i]."</p>";
echo "<p>".$_POST['value'][$i]."</p>";
echo "<hr />";
}
?>
NOTE: This works because your id and value arrays are symmetrical. If they had different numbers of elements then you'd need to take a different approach.
You are adding the $_POST array as the first element to $myarray. If you wish to reference it, just do:
$myarray = $_POST;
However, this is probably not necessary, as you can just call it via $_POST in your script.
Why are you wrapping the $_POST array in an array?
You can access your "id" and "value" arrays using the following
// assuming the appropriate isset() checks for $_POST['id'] and $_POST['value']
$ids = $_POST['id'];
$values = $_POST['value'];
foreach ($ids as $idx => $id) {
// ...
}
foreach ($values as $idx => $value) {
// ...
}
Just:
foreach ( $_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
Because you have nested arrays, then I actually recommend a recursive approach:
function recurse_into_array( $in, $tabs = "" )
{
foreach( $in as $key => $item )
{
echo $tabs . $key . ' => ';
if( is_array( $item ) )
{
recurse_into_array( $item, $tabs . "\t" );
}
else
{
echo $tabs . "\t" . $key;
}
}
}
recurse_into_array( $_POST );
Came across this 'implode' recently.
May be useful to output arrays. http://in2.php.net/implode
echo 'Variables: ' . implode( ', ', $_POST);
$_POST is an array in itsself you don't need to make an array out of it. What you did is nest the $_POST array inside a new array. This is why you print Array.
Change it to:
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
$_POST is already an array. Try this:
foreach ($_POST as $key => $value) {
echo "<p>".$key."</p>";
echo "<p>".$value."</p>";
echo "<hr />";
}
As you need to see the result for testing purpose. The simple and elegant solution is the below code.
echo "<pre>";
print_r($_POST);
echo "</pre>";