mysql transaction - mixing insert & select to attain last_insert_id? - php

Question

I'm performing a transaction (using PDO), however I need to grab the insert id of the first element in the transaction, for example:
BEGIN
INSERT INTO user (field1,field2) values (value1,value2)
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
COMMIT;
Then do the pdo stuff:
[...]
$pdo->execute();
$foo = $pdo->lastInsertId(); // This needs to be the id from the FIRST insert
Is there a way to get the last insert id from the first element in a transaction? Perhaps using something like the following:
BEGIN
INSERT INTO user (field1,field2) values (value1,value2)
SELECT id AS user_id FROM user WHERE id=LAST_INSERT_ID()
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
COMMIT;
$pdo->execute();
$fooArray = $pdo->fetchAll();
$lastId = $fooArray[0]['user_id'];
Am I completely out to lunch with ^ ? Is there a better way to do this?
EDIT 1
Based on suggestion, i've updated the query to use variables... however, i don't know how to retrieve the variable values using PDO. Using $stmt->fetchAll() just returns an empty array;
BEGIN
DECLARE User_ID int
DECLARE Option_ID int
INSERT INTO user (field1,field2) values (value1,value2);
set User_ID = select LAST_INSERT_ID();
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
set Option_ID = select LAST_INSERT_ID();
select User_ID, Option_ID
COMMIT;

Answer 1

You can do it this way, put the value into variable then just select it
BEGIN
DECLARE User_ID int
DECLARE Option_ID int
INSERT INTO user (field1,field2) values (value1,value2);
set User_ID = select LAST_INSERT_ID();
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
set Option_ID = select LAST_INSERT_ID();
select User_ID, Option_ID
COMMIT;