I need you small help, I would like to update the existing record, If it already exists in table otherwise Insert the new record. I am not using the primary key column in the Where clause.
Every time Its insert the new record in the table with the same column 1 and column 2 values.
I have got the few response as well like use the REPLACE. But REPLACE will work for the case of Unique / Primary Key otherwise inserted the new record.
I have used the below query
Method 1:
IF EXISTS (select * from mytable3 WHERE field1 = 'A') THEN
BEGIN
UPDATE mytable3
SET (field1 ='A', field2 = 'DD')
WHERE field1 = 'A'
END
ELSE
BEGIN
INSERT INTO mytable3 (field1, field2) VALUES ('A', 'DD')
END
Method 2:
REPLACE mytable3 (field1, field2) VALUES ('A', 'DD');
Table structure:
CREATE TABLE mytable3
(
users int(11) NOT NULL AUTO_INCREMENT,
field1 varchar(10),
field2 varchar(10),
PRIMARY KEY(users)
);
insert into mytable3 (field1, field2) values('A', 'AA');
insert into mytable3 (field1, field2) values('B', 'BB');
insert into mytable3 (field1, field2) values('C', 'CC');
Note: every time Its insert the new record in the table with the same field 1 and field 2 values
------------------------- Original Question ------------------
I'm struggling to write MySql query to insert new records if not exists, otherwise Update the existing record. But I am facing the Syntax error as below:
Error Code: 1064. You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'IF EXISTS(SELECT * FROM wnduty.parcel-status-log
WHERE parcel-id = 1 AND `sh' at line 1
The SQl Query as below:
IF EXISTS(SELECT * FROM wnduty.`parcel-status-log` WHERE `parcel-id` = 1 AND `shipping-status-id` = 4)
THEN
BEGIN
UPDATE wnduty.`parcel-status-log` SET (`status-date` ='2016-06-10 10:41:58', `is-synced`= 3)
WHERE `parcel-id` = 1 AND `shipping-status-id` = 4
END
ELSE
BEGIN
INSERT INTO wnduty.`parcel-status-log` (`parcel-id`,`shipping-status-id`, `is-synced`,`status-date`)
values(1, 4, 1, '2016-06-10 10:41:58')
END
END IF
I have also try by below query but still syntax error..
INSERT INTO wnduty.`parcel-status-log` (`parcel-id`, `shipping-status-id`, `is-synced`, `status-date`) values(1, 4, 1, '2016-06-10 10:41:57')
ON DUPLICATE KEY UPDATE
`status-date` ='2016-06-13 11:41:58',`is-synced` = 3, `shipping-status-id` = 4 ;
I am using the MySql version as below:
innodb_version 5.7.12
protocol_version 10
version_compile_os Win64
You can use UPDATE INTO with the same syntax as INSERT INTO and if the record is a duplicate on any of the unique keys in the table then it will update the record, otherwise it will insert using the same SQL statement.
Just use REPLACE instead of INSERT, it does exactly what you are looking for ...
INSERT INTO wnduty.parcel-status-log ...
REPLACE wnduty.parcel-status-log ...
From mysql man :
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted. See Section 14.2.5, “INSERT Syntax”.
Full REPLACE example :
mysql> CREATE TABLE mytable ( users TINYINT(1), field varchar(10), PRIMARY KEY(users));
mysql> insert into mytable values(1, 'A');
mysql> insert into mytable values(2, 'B');
mysql> insert into mytable values(3, 'C');
Now Replace a row with a new value no matter if it exists or not :
mysql> REPLACE mytable (users, field) VALUES (2, "New Value");
mysql> REPLACE mytable (users, field) VALUES (4, "D");
Related
I want to add a row to a database table, but if a row exists with the same unique key I want to update the row.
For example:
INSERT INTO table_name (ID, NAME, AGE) VALUES(1, "A", 19);
Let’s say the unique key is ID, and in my Database, there is a row with ID = 1. In that case, I want to update that row with these values. Normally this gives an error.
If I use INSERT IGNORE it will ignore the error, but it still won’t update.
Use INSERT ... ON DUPLICATE KEY UPDATE
QUERY:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name="A", age=19
Check out REPLACE:
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
Example:
REPLACE INTO `tablename` (`id`, `name`, `age`) VALUES (1, "A", 19)
When using batch insert use the following syntax:
INSERT INTO TABLE (id, name, age) VALUES (1, "A", 19), (2, "B", 17), (3, "C", 22)
ON DUPLICATE KEY UPDATE
name = VALUES (name),
...
Any of these solution will work regarding your question:
INSERT IGNORE INTO table (id, name, age) VALUES (1, "A", 19);
or
INSERT INTO TABLE (id, name, age) VALUES(1, "A", 19)
ON DUPLICATE KEY UPDATE NAME = "A", AGE = 19;
or
REPLACE INTO table (id, name, age) VALUES(1, "A", 19);
Try this:
INSERT INTO table (id,name,age) VALUES('1','Mohammad','21') ON DUPLICATE KEY UPDATE name='Mohammad',age='21'
Note:
Here if id is the primary key then after first insertion with id='1' every time attempt to insert id='1' will update name and age and previous name age will change.
Try this out:
INSERT INTO table (id, name, age) VALUES (1, 'A', 19) ON DUPLICATE KEY UPDATE id = id + 1;
Hope this helps.
In case that you wanted to make a non-primary fields as criteria/condition for ON DUPLICATE, you can make a UNIQUE INDEX key on that table to trigger the DUPLICATE.
ALTER TABLE `table` ADD UNIQUE `unique_index`(`name`);
And in case you want to combine two fields to make it unique on the table, you can achieve this by adding more on the last parameter.
ALTER TABLE `table` ADD UNIQUE `unique_index`(`name`, `age`);
Note, just make sure to delete first all the data that has the same name and age value across the other rows.
DELETE table FROM table AS a, table AS b WHERE a.id < b.id
AND a.name <=> b.name AND a.age <=> b.age;
After that, it should trigger the ON DUPLICATE event.
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name = VALUES(name), age = VALUES(age)
Just because I was here looking for this solution but for updating from another identically-structured table (in my case website test DB to live DB):
INSERT live-db.table1
SELECT *
FROM test-db.table1 t
ON DUPLICATE KEY UPDATE
ColToUpdate1 = t.ColToUpdate1,
ColToUpdate2 = t.ColToUpdate2,
...
As mentioned elsewhere, only the columns you want to update need to be included after ON DUPLICATE KEY UPDATE.
No need to list the columns in the INSERT or SELECT, though I agree it's probably better practice.
When using SQLite:
REPLACE into table (id, name, age) values(1, "A", 19)
Provided that id is the primary key. Or else it just inserts another row. See INSERT (SQLite).
In case, you want to keep old field (For ex: name). The query will be:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name=name, age=19;
In my case i created below queries but in the first query if id 1 is already exists and age is already there, after that if you create first query without age than the value of age will be none
REPLACE into table SET `id` = 1, `name` = 'A', `age` = 19
for avoiding above issue create query like below
INSERT INTO table SET `id` = '1', `name` = 'A', `age` = 19 ON DUPLICATE KEY UPDATE `id` = "1", `name` = "A",`age` = 19
may it will help you ...
Following are some of the possible approaches:
Using INSERT INTO
The INSERT statement allows you to insert one or more rows into a table
First, specify the table name and a list of comma-separated columns inside parentheses after the INSERT INTO clause.
Secondly, put a comma-separated list of values of the corresponding columns inside the parentheses following the VALUES keyword.
INSERT INTO table_name(column_name1, column_name2, column_name3) VALUES("col_value_1", "col_value_2", "col_value_3");
Using INSERT INTO with WHERE NOT EXISTS clause
INSERT INTO table_name (column_name_1, column_name_2, column_name_3)
SELECT * FROM (SELECT "col_value_1", "col_value_2","col_value_3") AS tmp_name
WHERE NOT EXISTS (
SELECT column_name2 FROM table_name WHERE column_name = "sample_name"
) LIMIT 1;
Using REPLACE INTO
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
REPLACE INTO table_name(column_name1, column_name2, column_name3) VALUES("col_value_1", "col_value_2", "col_value_3");
I want to add a row to a database table, but if a row exists with the same unique key I want to update the row.
For example:
INSERT INTO table_name (ID, NAME, AGE) VALUES(1, "A", 19);
Let’s say the unique key is ID, and in my Database, there is a row with ID = 1. In that case, I want to update that row with these values. Normally this gives an error.
If I use INSERT IGNORE it will ignore the error, but it still won’t update.
Use INSERT ... ON DUPLICATE KEY UPDATE
QUERY:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name="A", age=19
Check out REPLACE:
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
Example:
REPLACE INTO `tablename` (`id`, `name`, `age`) VALUES (1, "A", 19)
When using batch insert use the following syntax:
INSERT INTO TABLE (id, name, age) VALUES (1, "A", 19), (2, "B", 17), (3, "C", 22)
ON DUPLICATE KEY UPDATE
name = VALUES (name),
...
Any of these solution will work regarding your question:
INSERT IGNORE INTO table (id, name, age) VALUES (1, "A", 19);
or
INSERT INTO TABLE (id, name, age) VALUES(1, "A", 19)
ON DUPLICATE KEY UPDATE NAME = "A", AGE = 19;
or
REPLACE INTO table (id, name, age) VALUES(1, "A", 19);
Try this:
INSERT INTO table (id,name,age) VALUES('1','Mohammad','21') ON DUPLICATE KEY UPDATE name='Mohammad',age='21'
Note:
Here if id is the primary key then after first insertion with id='1' every time attempt to insert id='1' will update name and age and previous name age will change.
Try this out:
INSERT INTO table (id, name, age) VALUES (1, 'A', 19) ON DUPLICATE KEY UPDATE id = id + 1;
Hope this helps.
In case that you wanted to make a non-primary fields as criteria/condition for ON DUPLICATE, you can make a UNIQUE INDEX key on that table to trigger the DUPLICATE.
ALTER TABLE `table` ADD UNIQUE `unique_index`(`name`);
And in case you want to combine two fields to make it unique on the table, you can achieve this by adding more on the last parameter.
ALTER TABLE `table` ADD UNIQUE `unique_index`(`name`, `age`);
Note, just make sure to delete first all the data that has the same name and age value across the other rows.
DELETE table FROM table AS a, table AS b WHERE a.id < b.id
AND a.name <=> b.name AND a.age <=> b.age;
After that, it should trigger the ON DUPLICATE event.
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name = VALUES(name), age = VALUES(age)
Just because I was here looking for this solution but for updating from another identically-structured table (in my case website test DB to live DB):
INSERT live-db.table1
SELECT *
FROM test-db.table1 t
ON DUPLICATE KEY UPDATE
ColToUpdate1 = t.ColToUpdate1,
ColToUpdate2 = t.ColToUpdate2,
...
As mentioned elsewhere, only the columns you want to update need to be included after ON DUPLICATE KEY UPDATE.
No need to list the columns in the INSERT or SELECT, though I agree it's probably better practice.
When using SQLite:
REPLACE into table (id, name, age) values(1, "A", 19)
Provided that id is the primary key. Or else it just inserts another row. See INSERT (SQLite).
In case, you want to keep old field (For ex: name). The query will be:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name=name, age=19;
In my case i created below queries but in the first query if id 1 is already exists and age is already there, after that if you create first query without age than the value of age will be none
REPLACE into table SET `id` = 1, `name` = 'A', `age` = 19
for avoiding above issue create query like below
INSERT INTO table SET `id` = '1', `name` = 'A', `age` = 19 ON DUPLICATE KEY UPDATE `id` = "1", `name` = "A",`age` = 19
may it will help you ...
Following are some of the possible approaches:
Using INSERT INTO
The INSERT statement allows you to insert one or more rows into a table
First, specify the table name and a list of comma-separated columns inside parentheses after the INSERT INTO clause.
Secondly, put a comma-separated list of values of the corresponding columns inside the parentheses following the VALUES keyword.
INSERT INTO table_name(column_name1, column_name2, column_name3) VALUES("col_value_1", "col_value_2", "col_value_3");
Using INSERT INTO with WHERE NOT EXISTS clause
INSERT INTO table_name (column_name_1, column_name_2, column_name_3)
SELECT * FROM (SELECT "col_value_1", "col_value_2","col_value_3") AS tmp_name
WHERE NOT EXISTS (
SELECT column_name2 FROM table_name WHERE column_name = "sample_name"
) LIMIT 1;
Using REPLACE INTO
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
REPLACE INTO table_name(column_name1, column_name2, column_name3) VALUES("col_value_1", "col_value_2", "col_value_3");
I want to add a row to a database table, but if a row exists with the same unique key I want to update the row.
For example:
INSERT INTO table_name (ID, NAME, AGE) VALUES(1, "A", 19);
Let’s say the unique key is ID, and in my Database, there is a row with ID = 1. In that case, I want to update that row with these values. Normally this gives an error.
If I use INSERT IGNORE it will ignore the error, but it still won’t update.
Use INSERT ... ON DUPLICATE KEY UPDATE
QUERY:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name="A", age=19
Check out REPLACE:
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
Example:
REPLACE INTO `tablename` (`id`, `name`, `age`) VALUES (1, "A", 19)
When using batch insert use the following syntax:
INSERT INTO TABLE (id, name, age) VALUES (1, "A", 19), (2, "B", 17), (3, "C", 22)
ON DUPLICATE KEY UPDATE
name = VALUES (name),
...
Any of these solution will work regarding your question:
INSERT IGNORE INTO table (id, name, age) VALUES (1, "A", 19);
or
INSERT INTO TABLE (id, name, age) VALUES(1, "A", 19)
ON DUPLICATE KEY UPDATE NAME = "A", AGE = 19;
or
REPLACE INTO table (id, name, age) VALUES(1, "A", 19);
Try this:
INSERT INTO table (id,name,age) VALUES('1','Mohammad','21') ON DUPLICATE KEY UPDATE name='Mohammad',age='21'
Note:
Here if id is the primary key then after first insertion with id='1' every time attempt to insert id='1' will update name and age and previous name age will change.
Try this out:
INSERT INTO table (id, name, age) VALUES (1, 'A', 19) ON DUPLICATE KEY UPDATE id = id + 1;
Hope this helps.
In case that you wanted to make a non-primary fields as criteria/condition for ON DUPLICATE, you can make a UNIQUE INDEX key on that table to trigger the DUPLICATE.
ALTER TABLE `table` ADD UNIQUE `unique_index`(`name`);
And in case you want to combine two fields to make it unique on the table, you can achieve this by adding more on the last parameter.
ALTER TABLE `table` ADD UNIQUE `unique_index`(`name`, `age`);
Note, just make sure to delete first all the data that has the same name and age value across the other rows.
DELETE table FROM table AS a, table AS b WHERE a.id < b.id
AND a.name <=> b.name AND a.age <=> b.age;
After that, it should trigger the ON DUPLICATE event.
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name = VALUES(name), age = VALUES(age)
Just because I was here looking for this solution but for updating from another identically-structured table (in my case website test DB to live DB):
INSERT live-db.table1
SELECT *
FROM test-db.table1 t
ON DUPLICATE KEY UPDATE
ColToUpdate1 = t.ColToUpdate1,
ColToUpdate2 = t.ColToUpdate2,
...
As mentioned elsewhere, only the columns you want to update need to be included after ON DUPLICATE KEY UPDATE.
No need to list the columns in the INSERT or SELECT, though I agree it's probably better practice.
When using SQLite:
REPLACE into table (id, name, age) values(1, "A", 19)
Provided that id is the primary key. Or else it just inserts another row. See INSERT (SQLite).
In case, you want to keep old field (For ex: name). The query will be:
INSERT INTO table (id, name, age) VALUES(1, "A", 19) ON DUPLICATE KEY UPDATE
name=name, age=19;
In my case i created below queries but in the first query if id 1 is already exists and age is already there, after that if you create first query without age than the value of age will be none
REPLACE into table SET `id` = 1, `name` = 'A', `age` = 19
for avoiding above issue create query like below
INSERT INTO table SET `id` = '1', `name` = 'A', `age` = 19 ON DUPLICATE KEY UPDATE `id` = "1", `name` = "A",`age` = 19
may it will help you ...
Following are some of the possible approaches:
Using INSERT INTO
The INSERT statement allows you to insert one or more rows into a table
First, specify the table name and a list of comma-separated columns inside parentheses after the INSERT INTO clause.
Secondly, put a comma-separated list of values of the corresponding columns inside the parentheses following the VALUES keyword.
INSERT INTO table_name(column_name1, column_name2, column_name3) VALUES("col_value_1", "col_value_2", "col_value_3");
Using INSERT INTO with WHERE NOT EXISTS clause
INSERT INTO table_name (column_name_1, column_name_2, column_name_3)
SELECT * FROM (SELECT "col_value_1", "col_value_2","col_value_3") AS tmp_name
WHERE NOT EXISTS (
SELECT column_name2 FROM table_name WHERE column_name = "sample_name"
) LIMIT 1;
Using REPLACE INTO
REPLACE works exactly like INSERT, except that if an old row in the table has the same value as a new row for a PRIMARY KEY or a UNIQUE index, the old row is deleted before the new row is inserted.
REPLACE INTO table_name(column_name1, column_name2, column_name3) VALUES("col_value_1", "col_value_2", "col_value_3");
I am inserting multiple rows using one query and, obviously, the ID column auto increments each row. I want to create another ID column and have the ID remain the same for all rows inserted during the query. So if I insert 10 rows during one query, I want all 10 rows to have the id "1". How can this be done? Thanks for any help
If I understood your question correctly, you want to supply an ID for the specific group of INSERT statements.
Assumming you have this schema
CREATE TABLE TableName
(
RecordID INT AUTO_INCREMENT PRIMARY KEY,
OtherColumn VARCHAR(25) NOT NULL,
GroupID INT NOT NULL
)
You can have two statements for this:
1.) Getting the last GroupID and increment it by 1.
SELECT COALESCE(MAX(GroupID), 0) + 1 AS newGroupID FROM TableName
2.) once you have executed it, store the value in a variable. Use this variable for all the insert statement,
$groupID = row['newGroupID'];
$insert1 = "INSERT INTO TableName(OtherColumn, GroupID) VALUES ('a', $groupID)";
$insert2 = "INSERT INTO TableName(OtherColumn, GroupID) VALUES ('b', $groupID)";
$insert3 = "INSERT INTO TableName(OtherColumn, GroupID) VALUES ('c', $groupID)";
UPDATE 1
SQLFiddle Demo
I'm performing a transaction (using PDO), however I need to grab the insert id of the first element in the transaction, for example:
BEGIN
INSERT INTO user (field1,field2) values (value1,value2)
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
COMMIT;
Then do the pdo stuff:
[...]
$pdo->execute();
$foo = $pdo->lastInsertId(); // This needs to be the id from the FIRST insert
Is there a way to get the last insert id from the first element in a transaction? Perhaps using something like the following:
BEGIN
INSERT INTO user (field1,field2) values (value1,value2)
SELECT id AS user_id FROM user WHERE id=LAST_INSERT_ID()
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
COMMIT;
$pdo->execute();
$fooArray = $pdo->fetchAll();
$lastId = $fooArray[0]['user_id'];
Am I completely out to lunch with ^ ? Is there a better way to do this?
EDIT 1
Based on suggestion, i've updated the query to use variables... however, i don't know how to retrieve the variable values using PDO. Using $stmt->fetchAll() just returns an empty array;
BEGIN
DECLARE User_ID int
DECLARE Option_ID int
INSERT INTO user (field1,field2) values (value1,value2);
set User_ID = select LAST_INSERT_ID();
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
set Option_ID = select LAST_INSERT_ID();
select User_ID, Option_ID
COMMIT;
You can do it this way, put the value into variable then just select it
BEGIN
DECLARE User_ID int
DECLARE Option_ID int
INSERT INTO user (field1,field2) values (value1,value2);
set User_ID = select LAST_INSERT_ID();
INSERT INTO user_option (user_id,field2) values (LAST_INSERT_ID(),value2);
set Option_ID = select LAST_INSERT_ID();
select User_ID, Option_ID
COMMIT;