I have datestamps in the format YYYY-mm-dd HH:mm:ss
Is there an easy way to increase or decrease this by a set amount (say 1 hour or 1 day)?
$plus_day = date('Y-m-d H:i:s', strotime($your_time . " + 1 day"));
$plus_hour = date('Y-m-d H:i:s', strotime($your_time . " + 1 hour"));
Another option is to work with the DateTime class, which has a variety of ways of manipulating the date/time.
$incremented = date_create($date)->modify('+1 day')->format('Y-m-d H:i:s');
// Same as above
// $incremented = date_create($date . ' +1 day')->format('Y-m-d H:i:s');
// $incremented = date_create($date)->add(new DateInterval('P1D'))->format('Y-m-d H:i:s');
// $date = new DateTime($date); $date->modify('+1 day'); $incremented = $date->format('Y-m-d H:i:s');
See MySQL DATE_ADD function:
SELECT DATE_ADD(date, INTERVAL 1 HOUR) FROM tablename
Update
See #genesis' answer for the PHP way. Which you choose is up to whether you want to do the interval in mysql or php (I suspect PHP is the best option)
Related
I'd like to add 2 values from MySQL database in an php app. One is stored as a Datetime type, the other one as Time.
$datetime; // "2013-02-08 14:00:00"
$time; // "01:00:00"
I'd like to add 1 hour to $datetime, this doesn't give me the correct result:
$newdatetime = strtotime($datetime) + strtotime($time);
echo date('Y-m-d H:i:s', $newdatetime); // "1920-02-11 08:31:44"
How can I do this correctly?
$dt = new DateTime("2013-02-08 14:00:00");
$dt->modify('+1 hour');
echo $dt->format('Y-m-d H:i:s');
See it in action
$datetime = DateTime::createFromFormat('Y-m-d H:i:s', $datetime);
// extract H, M, S
$time = sscanf($time, '%d:%d:%d');
// build date interval string
$time = vsprintf('PT%dH%dM%dS', $time);
// add it to your date
$datetime->add(new DateInterval($time));
print $datetime->format('Y-m-d H:i:s');
But if $time is always one hour, John Conde's solution would be a better choice :P
Hmm I've dealt with it this way:
$datetime = "2013-02-08 14:00:00";
$time = "01:00:00"; //not always 1 hour, value from db
$t = explode(":",$time); // array(01,00,00)
$hour = mktime($t['0'],$t['1'],$t['2'],1,1,1970); // 3600
$newdatetime = strtotime($datetime) + $hour;
echo date("Y-m-d H:i:s",$added); // "2013-02-08 15:00:00"
Not the most elegant way, but works! As I'm looking now it's simmilar to One Trick Pony's solution, only not objective.
I use
$date = date("Y-m-d");
and in sql i use between max is = date("Y-m-d") min is = 6 days back
Is there a function that gives from date back $limit?
In PHP, it could be done like this:
$date_first = date("Y-m-d"); //today's date or use some other date
$date_second = date("Y-m-d", strtotime(date("Y-m-d", strtotime($date_first)) . " -6 day")); //date before 6 days
EDIT
Based on Dan Lee's suggestion(see the comment below):
$date_before = date("Y-m-d", strtotime("-6 day"));
You can use MySQL only for this task.
Take DATE_SUB() to subtract from the current time:
SELECT * FROM table WHERE date BETWEEN DATE_SUB(NOW(), INTERVAL 6 DAY) AND CURDATE()
You could also use the OO variation of #AkhileshBChandran's answer:
$dt = new DateTime('-6 days');
$sixDaysAgo = $dt->format('Y-m-d');
I'm really stuck with adding X minutes to a datetime, after doing lots of google'ing and PHP manual reading, I don't seem to be getting anywhere.
The date time format I have is:
2011-11-17 05:05: year-month-day hour:minute
Minutes to add will just be a number between 0 and 59
I would like the output to be the same as the input format with the minutes added.
Could someone give me a working code example, as my attempts don't seem to be getting me anywhere?
$minutes_to_add = 5;
$time = new DateTime('2011-11-17 05:05');
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$stamp = $time->format('Y-m-d H:i');
The ISO 8601 standard for duration is a string in the form of P{y}Y{m1}M{d}DT{h}H{m2}M{s}S where the {*} parts are replaced by a number value indicating how long the duration is.
For example, P1Y2DT5S means 1 year, 2 days, and 5 seconds.
In the example above, we are providing PT5M (or 5 minutes) to the DateInterval constructor.
PHP's DateTime class has a useful modify method which takes in easy-to-understand text.
$dateTime = new DateTime('2011-11-17 05:05');
$dateTime->modify('+5 minutes');
You could also use string interpolation or concatenation to parameterize it:
$dateTime = new DateTime('2011-11-17 05:05');
$minutesToAdd = 5;
$dateTime->modify("+{$minutesToAdd} minutes");
$newtimestamp = strtotime('2011-11-17 05:05 + 16 minute');
echo date('Y-m-d H:i:s', $newtimestamp);
result is
2011-11-17 05:21:00
Live demo is here
If you are no familiar with strtotime yet, you better head to php.net to discover it's great power :-)
You can do this with native functions easily:
strtotime('+59 minutes', strtotime('2011-11-17 05:05'));
I'd recommend the DateTime class method though, just posted by Tim.
I don't know why the approach set as solution didn't work for me.
So I'm posting here what worked for me in hope it can help anybody:
$startTime = date("Y-m-d H:i:s");
//display the starting time
echo '> '.$startTime . "<br>";
//adding 2 minutes
$convertedTime = date('Y-m-d H:i:s', strtotime('+2 minutes', strtotime($startTime)));
//display the converted time
echo '> '.$convertedTime;
I thought this would help some when dealing with time zones too. My modified solution is based off of #Tim Cooper's solution, the correct answer above.
$minutes_to_add = 10;
$time = new DateTime();
**$time->setTimezone(new DateTimeZone('America/Toronto'));**
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$timestamp = $time->format("Y/m/d G:i:s");
The bold line, line 3, is the addition. I hope this helps some folks as well.
A bit of a late answer, but the method I would use is:
// Create a new \DateTime instance
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00');
// Modify the date
$date->modify('+5 minutes');
// Output
echo $date->format('Y-m-d H:i:s');
Or in PHP >= 5.4
echo (DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00'))->modify('+5 minutes')->format('Y-m-d H:i:s')
If you want to give a variable that contains the minutes.
Then I think this is a great way to achieve this.
$minutes = 10;
$maxAge = new DateTime('2011-11-17 05:05');
$maxAge->modify("+{$minutes} minutes");
Use strtotime("+5 minute", $date);
Example:
$date = "2017-06-16 08:40:00";
$date = strtotime($date);
$date = strtotime("+5 minute", $date);
echo date('Y-m-d H:i:s', $date);
As noted by Brad and Nemoden in their answers above, strtotime() is a great function. Personally, I found the standard DateTime Object to be overly complicated for many use cases. I just wanted to add 5 minutes to the current time, for example.
I wrote a function that returns a date as a string with some optional parameters:
1.) time:String | ex: "+5 minutes" (default = current time)
2.) format:String | ex: "Y-m-d H:i:s" (default = "Y-m-d H:i:s O")
Obviously, this is not a fully featured method. Just a quick and simple function for modifying/formatting the current date.
function get_date($time=null, $format='Y-m-d H:i:s O')
{
if(empty($time))return date($format);
return date($format, strtotime($time));
}
// Example #1: Return current date in default format
$date = get_date();
// Example #2: Add 5 minutes to the current date
$date = get_date("+5 minutes");
// Example #3: Subtract 30 days from the current date & format as 'Y-m-d H:i:s'
$date = get_date("-30 days", "Y-m-d H:i:s");
one line mysql datetime format
$mysql_date_time = (new DateTime())->modify('+15 minutes')->format("Y-m-d H:i:s");
One more example of a function to do this: (changing the time and interval formats however you like them according to this for function.date, and this for DateInterval):
(I've also written an alternate form of the below function.)
// Return adjusted time.
function addMinutesToTime( $dateTime, $plusMinutes ) {
$dateTime = DateTime::createFromFormat( 'Y-m-d H:i', $dateTime );
$dateTime->add( new DateInterval( 'PT' . ( (integer) $plusMinutes ) . 'M' ) );
$newTime = $dateTime->format( 'Y-m-d H:i' );
return $newTime;
}
$adjustedTime = addMinutesToTime( '2011-11-17 05:05', 59 );
echo '<h1>Adjusted Time: ' . $adjustedTime . '</h1>' . PHP_EOL . PHP_EOL;
Without using a variable:
$yourDate->modify("15 minutes");
echo $yourDate->format( "Y-m-d H:i");
With using a variable:
$interval= 15;
$yourDate->modify("+{$interval } minutes");
echo $yourDate->format( "Y-m-d H:i");
In certain situations I want to add 1 day to the value of my DATETIME formatted variable:
$start_date = date('Y-m-d H:i:s', strtotime("{$_GET['start_hours']}:{$_GET['start_minutes']} {$_GET['start_ampm']}"));
What is the best way to do this?
There's more then one way to do this with DateTime which was introduced in PHP 5.2. Unlike using strtotime() this will account for daylight savings time and leap year.
$datetime = new DateTime('2013-01-29');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.3
$datetime = new DateTime('2013-01-29');
$datetime->add(new DateInterval('P1D'));
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.4
echo (new DateTime('2013-01-29'))->add(new DateInterval('P1D'))->format('Y-m-d H:i:s');
// Available in PHP 5.5
$start = new DateTimeImmutable('2013-01-29');
$datetime = $start->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
If you want to do this in PHP:
// replace time() with the time stamp you want to add one day to
$startDate = time();
date('Y-m-d H:i:s', strtotime('+1 day', $startDate));
If you want to add the date in MySQL:
-- replace CURRENT_DATE with the date you want to add one day to
SELECT DATE_ADD(CURRENT_DATE, INTERVAL 1 DAY);
The DateTime constructor takes a parameter string time. $time can be different things, it has to respect the datetime format.
There are some valid values as examples :
'now' (the default value)
2017-10-19
2017-10-19 11:59:59
2017-10-19 +1day
So, in your case you can use the following.
$dt = new \DateTime('now +1 day'); //Tomorrow
$dt = new \DateTime('2016-01-01 +1 day'); //2016-01-02
Use strtotime to convert the string to a time stamp
Add a day to it (eg: by adding 86400 seconds (24 * 60 * 60))
eg:
$time = strtotime($myInput);
$newTime = $time + 86400;
If it's only adding 1 day, then using strtotime again is probably overkill.
You can use
$now = new DateTime();
$date = $now->modify('+1 day')->format('Y-m-d H:i:s');
You can use as following.
$start_date = date('Y-m-d H:i:s');
$end_date = date("Y-m-d 23:59:59", strtotime('+3 days', strtotime($start_date)));
You can also set days as constant and use like below.
if (!defined('ADD_DAYS')) define('ADD_DAYS','+3 days');
$end_date = date("Y-m-d 23:59:59", strtotime(ADD_DAYS, strtotime($start_date)));
I suggest start using Zend_Date classes from Zend Framework. I know, its a bit offtopic, but I'll like this way :-)
$date = new Zend_Date();
$date->add('24:00:00', Zend_Date::TIMES);
print $date->get();
Using server request time to Add days. Working as expected.
25/08/19 => 27/09/19
$timestamp = $_SERVER['REQUEST_TIME'];
$dateNow = date('d/m/y', $timestamp);
$newDate = date('d/m/y', strtotime('+2 day', $timestamp));
Here '+2 days' to add any number of days.
One liner !
echo (new \DateTime('2016-01-01 +1 day'))->format('Y-m-d H:i:s');
I get the time:
$today = time();
$date = date('h:i:s A', strtotime($today));
if the current time is "1:00:00 am", how do i add 10 more hours to become 11:00:00 am??
strtotime() gives you a number back that represents a time in seconds. To increment it, add the corresponding number of seconds you want to add. 10 hours = 60*60*10 = 36000, so...
$date = date('h:i:s A', strtotime($today)+36000); // $today is today date
Edit: I had assumed you had a string time in $today - if you're just using the current time, even simpler:
$date = date('h:i:s A', time()+36000); // time() returns a time in seconds already
$tz = new DateTimeZone('Europe/London');
$date = new DateTime($today, $tz);
$date->modify('+10 hours');
// use $date->format() to outputs the result.
see DateTime Class
(PHP 5 >= 5.2.0)
You can simply make use of the DateTime class , OOP Style.
<?php
$date = new DateTime('1:00:00');
$date->add(new DateInterval('PT10H'));
echo $date->format('H:i:s a'); //"prints" 11:00:00 a.m
$date = date('h:i:s A', strtotime($today . ' + 10 hours'));
(untested)
$date = date('h:i:s A', strtotime($today . " +10 hours"));
Full code that shows now and 10 minutes added.....
$nowtime = date("Y-m-d H:i:s");
echo $nowtime;
$date = date('Y-m-d H:i:s', strtotime($nowtime . ' + 10 minute'));
echo "<br>".$date;
In order to increase or decrease time using strtotime you could use a Relative format in the first argument.
In your case to increase the current time by 10 hours:
$date = date('h:i:s A', strtotime('+10 hours'));
In case you need to apply the change to another timestamp, the second argument can be specified.
Note:
Using this function for mathematical operations is not advisable. It is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and later, or DateTime::modify() in PHP 5.2.
So, the recommended way since PHP 5.3:
$dt = new DateTime(); // assuming we need to add to the current time
$dt->add(new DateInterval('PT10H'));
$date = $dt->format('h:i:s A');
or using aliases:
$dt = date_create(); // assuming we need to add to the current time
date_add($dt, date_interval_create_from_date_string('10 hours'));
$date = date_format($dt, 'h:i:s A');
In all cases the default time zone will be used unless a time zone is specified.