Radio button checked issue - php

Question

My question was about the browser matter as far as I see.
I asked is there any solution to tell browser to move checked="checked" between radio buttons. I thought there will be a quick solution for this but this case is just confusing. I changed my code now. I use select list element now.
I have a form, and I get the actual settings with php, but the matter is this:
When the radio button 1 comes checked="checked" if that is actual, after it when I change to other option in post I get checked="checked"'s value, I was wondering is there a solution for this or Javascript is needed something like onclick"this.checked otherone uncheck" ?
if($type==1) { $like = 'checked="checked"'; } else { $ref='checked="checked"'; }
<form method="post" action="process.php" id="fbform" name="fbform">
<div class="radio">
<p>Like button: </p>
<input type="radio" name="tipi" <?=$like?> value="1" />
</div>
<div class="radio1">
<p>Link:</p>
<input type="radio" name="tipi" <?=$ref?> value="2" />
</div>
</form>
Process.php file code
<?php
$mysql->update('settings'," tipi='".$_POST['tipi]."' ");
?>

Answer 1

checked is a marker tag - it does not care , as long if the word 'checked' is there.

Answer 2

Here is what I would do:
<div class="radio">
<p>Like button: </p>
<input type="radio" name="tipi" id="tipi1" value="1"<?php if ($type == 1) echo ' checked="checked"'; ?> />
</div>
<div class="radio1">
<p>Link:</p>
<input type="radio" name="tipi" id="tipi2" value="2"<?php if ($type != 1) echo ' checked="checked"'; ?> />
</div>
I have changed the id's because you had two elements with the same id, which will never work, even if those elements are part of the same group.

Answer 3

You can do better with this. Also, IDs are used only for CSS or JS, and moreover must be UNIQUE.
<div class="radio">
<p>Like button: </p>
<input type="radio" name="tipi" id="tipi" <?php echo ($type == '1')?'checked="checked"' : '';?> value="1" />
</div>
<div class="radio1">
<p>Link:</p>
<input type="radio" name="tipi" id="tipi2" <?php echo ($type=='2')?'checked="checked"' : '';?> value="2" />
</div>
Then you access them in php
$tipi = $_POST['tipi']; //either 1 or 2

Answer 4

you need very simple changes in your code..See below code:
first of all you need to define variables at very top of the page/Code:
$like = "";
$ref = "";
Now your code will working good as per my knowledge..
Thanks.

Answer 5

Ghostology: Not sure about your query ... But all I can do is explain you the working of the radio button.
suppose there are two radio buttons inside a form:
<input type="radio" name="radioTest" value="1" checked />
<input type="radio" name="radioTest" value="0" />
Here checked specifies the button which will be checked(or turned on) during page load.
Now suppose we check the second button and submit this form, now we get the value 0 against the parameter 'radioTest' as radio button with value 0 is checked.
Now when page loads again with some value of radio buttons. You would want the proper radio button to be checked.
For this case I guess u can use if/else condition like:
<% if(radioTest.value == 1){ %>
<% }else{ %>
<% } %>