MySQL/PHP foreach still only displaying first in database - php

Question

I am querying results from a database, where more than one result should be queried. However, when I tried displaying the result of the query, only one result showed, so I tried to use a foreach function, but it's still not working. I'm beat, no idea what I'm doing wrong. Anyone have a good idea of what's going wrong?
Here's the MySQL query code:
<?php
//Database Information
$dbhost = "";
$dbname = "";
$dbuser = "";
$dbpass = "";
//Connect to database
mysql_connect ( $dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error());
mysql_select_db($dbname) or die(mysql_error());
$filename = $_GET['filename'];
$new_captions = mysql_query("SELECT * from captions where image = 'http://math.stanford.edu/inc/img/PalmDrive.png' ORDER BY idnum DESC LIMIT 5");
while($rows = mysql_fetch_array($new_captions)){
$caption = $rows;
}
?>
And here's the foreach:
<?php foreach($caption as $rows) {?>
<div id="set_caption" style="width:<?php echo $caption['width'];?>px; height:<?php echo $caption['height'];?>px; left:<?php echo $caption['posleft'];?>px; top:<?php echo $caption['postop'];?>px;"><?php echo $caption['text'];?></div>
<?php } ?>

Answer 1

I think $caption is an array, so your code should be like this
while($rows = mysql_fetch_array($new_captions)){
$caption[] = $rows;
}
EDIT:
Your foreach loop is also wrong.
Your variable is $rows not $caption.
<div id="set_caption" style="width:<?php echo $rows['width'];?>px; height:<?php echo $rows['height'];?>px; left:<?php echo $rows['posleft'];?>px; top:<?php echo $rows['postop'];?>px;"><?php echo $rows['text'];?></div>
<?php } ?>

Answer 2

You have following mistakes.
$caption is not declare before.
use array_push or $caption[] = $rows; to make caption array.
Use $row variable in the foreach.
//Database Information
$dbhost = "";
$dbname = "";
$dbuser = "";
$dbpass = "";
//Connect to database
mysql_connect ( $dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error());
mysql_select_db($dbname) or die(mysql_error());
$filename = $_GET['filename'];
$new_captions = mysql_query("SELECT * from captions where image = 'http://math.stanford.edu/inc/img/PalmDrive.png' ORDER BY idnum DESC LIMIT 5");
$caption = array();
while($rows = mysql_fetch_array($new_captions)){
$caption[] = $rows;
}
foreach($caption as $row) {
<div id="set_caption"
style="width:<?php echo $row['width'];?>px;
height:<?php echo $row['height'];?>px;
left:<?php echo $row['posleft'];?>px;
top:<?php echo $row['postop'];?>px;">
<?php echo $row['text'];?>
</div>
}