I have a database which has a table called 'propImages' and there are two columns.- 'pid' and 'location'.
And i have data in the database where multiple images can contained by single pid.
image contains database data
now i want to retrieve images from database according to given pid. there can be more than one image.
All i know it there should be an iteration to retrieve images.
I want to display images in HTML .
can you please show me the way to do it in php?
Thanks in advance guys
This may help you
<?php
include 'inc/database.php';
$conn = new mysqli($servername, $username, $password, $database);
$propid = $_GET['propid'];
$sql = "SELECT * FROM propImages WHERE propid='" . $propid . "';";
$result = $conn->query($sql);
if($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "<img src=" . $row['image'] . ">";
}
}
else {
echo "No results";
}
?>
in the inc/database.php :
<?php
$servername = "localhost";
$username = "root";
$password = "";
$database = "database";
?>
To see how it works try visiting : file.php?propid=22
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "databasename";
// Create connection
$con = mysqli_connect($servername, $username, $password, $dbname);
//create sql
$sql = "SELECT * FROM `propImages` where pid='$YOUR_PID'";
$result = mysqli_query($con, $sql);
$row = mysqli_num_rows($result);
//retrive data print here
if($row > 0){
while($col = mysqli_fetch_assoc($result))
{
echo $col['location'];
}
} else {
echo 'no result found.';
}
?>
wish it helps
Related
I'm trying to echo the query made to my database. So far the code runs but nothing happens. I'm very new at coding so help or an explanation about what I'm doing wrong would be awesome! Thanks a lot!!!
<?php
$servername = "servername";
// REPLACE with your Database name
$dbname = "dbsname";
// REPLACE with Database user
$username = "username";
// REPLACE with Database user password
$password = "password";
$ID = 1;
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
echo "Error de conexion.";
}
$sql = "SELECT * FROM registro WHERE ID = '1' ";
$result = $conn->query($sql);
while ($data = $result->fetch_assoc()){
$sensor_data[] = $data;
}
echo $data;
$conn->close();
Thanks everyone who replied, #AbraCadaver was right, I can't echo an array so I used print_r() instead and printed the variable $data. Now the php file prints the array with the query results. Thank you all!
$sql = "SELECT * FROM registro WHERE ID = $ID";
while ($data = $result->fetch_assoc()){
$sensor_data[] = $data;
print_r($data);
}
I have been trying to echo out database data through a while loop now for awhile but it doesn't work, I can't find where the issue is. I have tried echoing out data manually and that works just fine.
<?php $results = mysqli_query($con,"SELECT * FROM guestbook ORDER BY id DESC"); ?>
<?php while ($row = mysqli_fetch_assoc($results)) : ?>
<li>
<?php echo $row['message']; ?>
</li>
<?php endwhile ?>
First of all make sure you are connected to the database. I don't know if you omitted that on purpose or not. Also, check if the connection is established.
<?php
//Insert your server info here
$servername = "servername";
$username = "root";
$password = "root";
$dbname = "test_database";
// Create and check your connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM guestbook ORDER BY id DESC";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
echo '<li>' . row["message"] . '</li>';
}
} else {
// Your query produced 0 results
echo "Empty result!";
}
// Remember to close the connection
mysqli_close($conn);
?>
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = 'blood_db';
$connection = new mysqli($dbhost,$dbuser,$dbpass,$db);
if($connection->connect_error){
die("Server Error ".$connection->connect_error);
}
else{
$query = ("SELECT first_name FROM accounts WHERE email_address = '".$_SESSION['username']."'");
$obj = $connection->query($query);
echo "Welcome ".$obj->first_name;
here it shows a notice, which is "
Notice: Undefined property: mysqli_result::$first_name "
It is returning the object, So how would i extract the first name from it?
// printf("Welcome %s",$result->);
echo '<br>Logout';
use below code
$result = $connection->query($query);
if($result){
$row = $result->fetch_assoc();
echo "Welcome ".$row['first_name'];
}else{
// check error
}
you can try this which select data and add condition if you want to check that data empty or not
$obj = $connection->query($query);
if ($obj->num_rows > 0) {
$row = $obj->fetch_assoc();
echo "Welcome ".$row['first_name'];
}
if you do not want to check data have then use this
$row = $obj->fetch_assoc();
echo "Welcome ".$row['first_name'];
for more information
https://www.w3schools.com/php/php_mysql_select.asp
A very basic example would be like this:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test";
$firstname = "";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM tbl_test WHERE email_address = '". $_SESSION['username']. "'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// Retrieve Firstname
while($row = $result->fetch_assoc()) {
$firstname = $row["first_name"];
}
} else {
echo "No results found!";
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Test</title>
</head>
<body>
<header>
<h3>Welcome <?php echo $firstname; ?></h3>
</header>
</body>
</html>
<?php
$conn->close();
?>
I have a script that I want to put on a dashboard. The SQL works and groups the items in the while and it is displayed in the dashboard correctly. However I also want the QTY's to show.
So if the SQL is grouping how can I count the rows it returns so I can echo the QTY out in to my table for each row. This is my code.
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
$custid = $row['CustomerID'];
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql1 = "SELECT * FROM stock
JOIN hardware ON stock.HardwareID = hardware.HardwareID
WHERE stock.CustomerID = $custid GROUP BY stock.HardwareID";
$result1 = $conn->query($sql1);
if ($result1->num_rows > 0) {
// output data of each row
while($row1 = $result1->fetch_assoc()) {
echo "<tr>";
echo "<td>".$row1['Hardware']."</td>";
echo "<td></td>";
echo "</tr>";
}
}
?>
So the aim is to have the row
echo "<td></td>";
Have a variable in it that shows the qty for each row that is grouped.
you can use this query, group by query has to select and provide aggregation, here i have provided count, if you require some of appropriate column you can change it accordingly...
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
$custid = $row['CustomerID'];
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql1 = "SELECT stock.Hardwareid, count(*) as CountHardware FROM stock
JOIN hardware ON stock.HardwareID = hardware.HardwareID
WHERE stock.CustomerID = $custid GROUP BY stock.HardwareID";
$result1 = $conn->query($sql1);
if ($result1->num_rows > 0) {
// output data of each row
while($row1 = $result1->fetch_assoc()) {
echo "<tr>";
echo "<td>".$row1['Hardware']."</td>";
echo "<td></td>";
echo "</tr>";
}
}
?>
I am learning as i go and been picking up snippets of code as i go and been working on this for the past few days and now i have thrown the towel in to seek help.
I am trying to calculate the sum of 2 columns in my database using PDO.
here is my code
<?php
$host = "localhost";
$db_name = "dbname";
$username = "root";
$password = "root";
try {
$con = new PDO("mysql:host={$host};dbname={$db_name}", $username, $password);
}
// show error
catch(PDOException $exception){
echo "Connection error: " . $exception->getMessage();
}
$query = "SELECT SUM (fill_up) AS TotalFill,
SUM (mileage_covered) AS Totalmiles
FROM fuel_cost";
$row = $query->fetch(PDO::FETCH_ASSOC);
$total_fill = $row['TotalFill'];
$total_miles = $row['Totalmiles'];
$myanswer = $total_fill/$total_miles;
//display the answer
echo $myanswer
?>
I have also checked my database table and both columns are varchar(32)
the error I am getting is Call to a member function fetch() on a non-object
I have searched into this but not sure what's the issue with the above code
Thank You in advance
Try this code :-
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT SUM (fill_up) AS TotalFill,
SUM (mileage_covered) AS Totalmiles
FROM fuel_cost";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
$total_fill = $row['TotalFill'];
$total_miles = $row['Totalmiles'];
$myanswer = $total_fill / $total_miles;
//display the answer
echo $myanswer;
die;
}
} else {
echo "0 results";
}
$conn->close();
?>