PDO SUM MYSQL table - php

I am learning as i go and been picking up snippets of code as i go and been working on this for the past few days and now i have thrown the towel in to seek help.
I am trying to calculate the sum of 2 columns in my database using PDO.
here is my code
<?php
$host = "localhost";
$db_name = "dbname";
$username = "root";
$password = "root";
try {
$con = new PDO("mysql:host={$host};dbname={$db_name}", $username, $password);
}
// show error
catch(PDOException $exception){
echo "Connection error: " . $exception->getMessage();
}
$query = "SELECT SUM (fill_up) AS TotalFill,
SUM (mileage_covered) AS Totalmiles
FROM fuel_cost";
$row = $query->fetch(PDO::FETCH_ASSOC);
$total_fill = $row['TotalFill'];
$total_miles = $row['Totalmiles'];
$myanswer = $total_fill/$total_miles;
//display the answer
echo $myanswer
?>
I have also checked my database table and both columns are varchar(32)
the error I am getting is Call to a member function fetch() on a non-object
I have searched into this but not sure what's the issue with the above code
Thank You in advance

Try this code :-
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT SUM (fill_up) AS TotalFill,
SUM (mileage_covered) AS Totalmiles
FROM fuel_cost";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
$total_fill = $row['TotalFill'];
$total_miles = $row['Totalmiles'];
$myanswer = $total_fill / $total_miles;
//display the answer
echo $myanswer;
die;
}
} else {
echo "0 results";
}
$conn->close();
?>

Related

When I add a column, I can't retrieve it from mysql

After I add a column to my database, I want to retrieve it but not expected.
In PHP, I try reopening apache and mysql still not work.
Does anyone know how to resolve it? Thanks!
your question is not fully explanatory but with what I could try to understand you want to retrieve data or records from your database
you could try the code below and tweak it to work your way
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM databaseName";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data
while($row = $result->fetch_assoc()) {
print $row"<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>

Need help to display data from mysql database

I would need some help with showing data that I have on my database but I can't seen to be able to.`
$servername = "servername";
$username = "username";
$password = "password";
$dbname = "dbname";
$connect = mysqli_connect($servername, $username, $password, $dbname) or die ("connection failed");
//Query
$query = "SELECT * FROM 'Students'";
mysqli_master_query($dbname, $query) or die ("Error while Query");
$result = mysqli_master_query($dbname, $query);
$row = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result)) {
echo "<p>".$row['Name']."</p>";
};
mysql_close($connect);
?>`
I am pretty new to this so I could have missed something simple. Any help appreciated.
Below is a sample code of the normal procedure to connect to a database and to select data from it. Please follow this type of coding since MySQL is now deprecated and MySQLi is used.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
For further reference check out http://php.net/manual/en/book.mysqli.php and also https://www.w3schools.com/php/php_mysql_insert.asp

php echo result from mysql and datetime selection

MySQL database Start = "2017-03-29 01:30:00"
The problem is:
I print the $SQL and search the record in MySQL database, it can search the record. However, I need to debug and test if there is no result, it will be expected to echo "No". But, it always to echo "Yes" no matter I can get the record in MySQL or not.
How can I fixed it.
Main purpose: Get the record if there are and Echo "No" if there don't have record
<?php
$serverName = "localhost";
$username = "root";
$password = "";
$dbName = "fyp";
$tbName = "events";
$String_start = '2017-03-29 01:28:00';
$String_end = '2017-03-29 01:32:00';
$conn = new mysqli($serverName, $username, $password, $dbName);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//$staffID = $_SESSION['userID'];
$staff_ID = '15207800';
$sql = "SELECT *
FROM `$tbName`
WHERE `start` BETWEEN ('$String_start') AND ('$String_end')";
echo $sql;
$result=mysqli_query($conn,$sql);
if($result)
{
echo "Yes";
}
else{
echo "no";
}
?>
Mysql query only return fails if there is an issue, for successful execution it returns TRUE even if there is no record. You can achieve with follwing way
<?php
$serverName = "localhost";
$username = "root";
$password = "";
$dbName = "fyp";
$tbName = "events";
$String_start = '2017-03-29 01:28:00';
$String_end = '2017-03-29 01:32:00';
$conn = new mysqli($serverName, $username, $password, $dbName);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//$staffID = $_SESSION['userID'];
$staff_ID = '15207800';
$sql = "SELECT *
FROM `$tbName`
WHERE `start` BETWEEN ('$String_start') AND ('$String_end')";
echo $sql;
$result=mysqli_query($conn,$sql);
$num_rows = mysqli_num_rows($result);
if($num_rows > 0)
{
echo "Yes";
}
else{
echo "no";
}
?>
Use mysqli_num_rows that will return total results returned by the query. If total > 0 then results found else no results.
To fetch rows from MySQL result set, use mysqli_fetch_assoc
$result = mysqli_query($conn,$sql);
// $result contains result set and will return `TRUE` if query was successfully executed
// and will return `FALSE` only in case of error
$total = mysqli_num_rows($result);
if($total > 0)
{
echo "Yes";
// Fetch rows from mysql result set
while($row=mysqli_fetch_assoc($result))
{
print_r($row);
}
}
else
{
echo "no";
}

SQL database connection in PHP successful, but I can't query it [duplicate]

This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 6 years ago.
<?php
$servername = "localhost";
$username = "user";
$password = "pass";
$dbname = "test";
$tablename = "mapcoords";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error)
{
echo "Failure";
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
$sql = "SELECT (lat, lng) FROM mapcoords";
$result = $conn->query($sql);
while($row = $result->fetch_assoc())
{
echo "ok";
}
$conn->close();
?>
Here is the code. So like I said, it can connect successfully, but the code won't successfully query. What's weird is that if I copy and paste the same code, which seems to be EXACTLY the same, it works. It makes no sense. I can't find a single difference between their code and my code besides the way they space things and the way I space things. Here is their code:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT (lat, lng) FROM mapcoords";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["lat"]. " " . $row["lng"] . "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
The problem is that this query:
SELECT (lat, lng) FROM mapcoords
returns the folloowing error:
[21000][1241] Operand should contain 1 column(s)
You have to change the query to
SELECT lat, lng FROM mapcoords

Mysqli to variable in PHP

I've been a few days working on my project, but just stay stuck a specific part.
My problem is that i like to get a value from the database (mysqli)
But i always receive a 0. So, no value.
This is my code:
$servername = "localhost";
$username = "user";
$password = "pass";
$dbname = "dbname";
$serialkey = $_GET['hardwareSerial'];
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$user_idSQL = "SELECT user_id FROM ss_devices WHERE serialkey = '$serialkey'";
$user_idResult = $conn->query($user_idSQL);
$user_id = $user_idResult;
The script should see what the userid, it is in equality with the specified serial number.
But when i take a serial number like: FJRI433. I always get a 0. But in the database has this serial number user_id: 3.
I hope someone can help me out whith this problem.
Thanks.
You are executing the query but not fetching any results.
The manual has plenty of examples of using mysqli :
if ($result = $conn->query($query)) {
while ($row = $result->fetch_assoc()) {
//Do stuff with the next row.
}
}
Try this perhaps...
$servername = "localhost";
$username = "user";
$password = "pass";
$dbname = "dbname";
$serialkey = $_GET['hardwareSerial'];
$conn=mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if ( mysqli_connect_errno() ) {
die("Connection failed: " . mysqli_connect_error() );
}
$user_idSQL = "SELECT `user_id` FROM `ss_devices` WHERE `serialkey` = '$serialkey'";
if( $user_idResult = mysqli_query( $conn, $user_idSQL ) ) {
while ($row = mysqli_fetch_assoc($user_idResult)) {
echo $row['user_id'].'<br />';
}
}
mysqli_close( $conn );

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