I am using the following code to transform a universal time code into something a little more user friendly.
$meeting_time = date('g:i a', strtotime($time_date_data));
But now I need to subtract 6 hours from meeting_time. Should I do it after the code above or can I work it into the same date function?
Something like:
$meeting_time = date('g:i a' - 6, strtotime($time_date_data));
$meeting_time = date('g:i a', strtotime($time_date_data) - 60 * 60 * 6);
String-to-time (strtotime) returns a Unix Time Stamp which is in seconds (since Epoch), so you can simply subtract the 21600 seconds, before converting it back to the specified date format.
Another approach:
$meeting_time = date('g:i a', strtotime('-6 hours', strtotime($time_date_data)));
Try this:
// 6 hours, 3600 seconds in an hour
$meeting_time = date('g:i a', strtotime($time_date_data) - 6 * 3600);
The way of OO PHP:
$date = new DateTime(); // current time
echo 'Current: '. $date->format('Y-m-d H:i:s') . "\n";
$date->sub(new DateInterval('PT3H55M10S'));
echo $date->format('Y-m-d H:i:s') . "\n";
For subtract 6 hrs:
$date = new DateTime('2017-01-20'); // pass $time_date_data to here
$date->sub(new DateInterval('PT6H'));
You should be able to do this:
$meeting_time = date('g:i a', strtotime($time_date_data));
date_add($meeting_time, - date_interval_create_from_date_string('6 hours'));
Related
I currently have php returning the current date/time like so:
$now = date("Y-m-d H:m:s");
What I'd like to do is have a new variable $new_time equal $now + $hours, where $hours is a number of hours ranging from 24 to 800.
Any suggestions?
You may use something like the strtotime() function to add something to the current timestamp. $new_time = date("Y-m-d H:i:s", strtotime('+5 hours')).
If you need variables in the function, you must use double quotes then like strtotime("+{$hours} hours"), however better you use strtotime(sprintf("+%d hours", $hours)) then.
An other solution (object-oriented) is to use DateTime::add
Example:
<?php
$now = new DateTime(); //now
echo $now->format('Y-m-d H:i:s'); // 2021-09-11 01:01:55
$hours = 36; // hours amount (integer) you want to add
$modified = (clone $now)->add(new DateInterval("PT{$hours}H")); // use clone to avoid modification of $now object
echo "\n". $modified->format('Y-m-d H:i:s'); // 2021-09-12 13:01:55
Run script
DateTime::add PHP doc
DateInterval::construct PHP doc
You can use strtotime() to achieve this:
$new_time = date("Y-m-d H:i:s", strtotime('+3 hours', $now)); // $now + 3 hours
Correct
You can use strtotime() to achieve this:
$new_time = date("Y-m-d H:i:s", strtotime('+3 hours', strtotime($now))); // $now + 3 hours
You can also use the unix style time to calculate:
$newtime = time() + ($hours * 60 * 60); // hours; 60 mins; 60secs
echo 'Now: '. date('Y-m-d') ."\n";
echo 'Next Week: '. date('Y-m-d', $newtime) ."\n";
Um... your minutes should be corrected... 'i' is for minutes. Not months. :) (I had the same problem for something too.
$now = date("Y-m-d H:i:s");
$new_time = date("Y-m-d H:i:s", strtotime('+3 hours', $now)); // $now + 3 hours
I use this , its working cool.
//set timezone
date_default_timezone_set('GMT');
//set an date and time to work with
$start = '2014-06-01 14:00:00';
//display the converted time
echo date('Y-m-d H:i',strtotime('+1 hour +20 minutes',strtotime($start)));
for add 2 hours to "now"
$date = new DateTime('now +2 hours');
or
$date = date("Y-m-d H:i:s", strtotime('+2 hours', $now)); // as above in example
or
$now = new DateTime();
$now->add(new DateInterval('PT2H')); // as above in example
You can try lib Ouzo goodies, and do this in fluent way:
echo Clock::now()->plusHours($hours)->format("Y-m-d H:m:s");
API's allow multiple operations.
For a given DateTime, you can add days, hours, minutes, etc. Here's some examples:
$now = new \DateTime();
$now->add(new DateInterval('PT24H')); // adds 24 hours
$now->add(new DateInterval('P2D')); // adds 2 days
PHP: DateTime::add - Manual https://www.php.net/manual/fr/datetime.add.php
$to = date('Y-m-d H:i:s'); //"2022-01-09 12:55:46"
$from = date("Y-m-d H:i:s", strtotime("$to -3 hours")); // 2022-01-09 09:55:46
$date_to_be-added="2018-04-11 10:04:46";
$added_date=date("Y-m-d H:i:s",strtotime('+24 hours', strtotime($date_to_be)));
A combination of date() and strtotime() functions will do the trick.
$now = date("Y-m-d H:i:s");
date("Y-m-d H:i:s", strtotime("+1 hours $now"));
Here I have set the my Centos time Zone.> sudo hwclock – show
Tue 04 Feb 2014 10:23:10 AM AFT -0.596389 seconds
asia/kabul
Now on PHP I want to echo from 10:23:10 AM to 11:23:10 AM
Here I have set my code for the echoing.
<? echo (date('G', time())+5) ;
echo(':00 To ');
echo (date('G', time())+6);
echo(':00'); ?>
Now as result of my above echoing PHP code I get the result of
15:00 To 16:00
But instead I want to get the echo of below or as what ever my HTTP server time is from NOW to 1 hour next.
10:23:10 AM to 11:23:10 AM
You should try strtotime(). Something like this:
echo date('h:i:s A'), ' to ', date('h:i:s A', strtotime('+1 hour'));
echo date('Y-m-d H:i:s', strtotime('now')), ' to ', date('Y-m-d H:i:s', strtotime('+1 hour'));
For date format, please read: http://www.php.net/manual/en/function.date.php
For your format:
echo date('h:i:s A', strtotime('now')), ' to ', date('h:i:s A', strtotime('+1 hour'));
Add to the time and then print the date.
echo date('G',time()+3600);
time() returns number of seconds since the unix epoch, then you add 3600 seconds for 1 hour and you use that in your date.
You can use explode function.
<?PHP
$time = date('G:i:s');
$eTime = explode(':', $time);
$timePlusOneHour = $eTime+1 . ":{$eTime[1]}:{$eTime[2]}";
echo $time . " To " . $timePlusOneHour;
I want to add 5 minutes to this date: 2011-04-8 08:29:49
$date = '2011-04-8 08:29:49';
When I use strtotime I am always getting 1970-01-01 08:33:31
How do I add correctly 5 minutes to 2011-04-8 08:29:49?
$date = '2011-04-8 08:29:49';
$currentDate = strtotime($date);
$futureDate = $currentDate+(60*5);
$formatDate = date("Y-m-d H:i:s", $futureDate);
Now, the result is 2011-04-08 08:34:49 and is stored inside $formatDate
Enjoy! :)
Try this:
echo date('Y-m-d H:i:s', strtotime('+5 minutes', strtotime('2011-04-8 08:29:49')));
$expire_stamp = date('Y-m-d H:i:s', strtotime("+5 min"));
$now_stamp = date("Y-m-d H:i:s");
echo "Right now: " . $now_stamp;
echo "5 minutes from right now: " . $expire_stamp;
Results in:
2012-09-30 09:00:03
2012-09-30 09:05:03
$date = '2011-04-8 08:29:49';
$newDate = date("Y-m-d H:i:s",strtotime($date." +5 minutes"))
For adding
$date = new DateTime('2014-02-20 14:20:00');
$date->add(new DateInterval('P0DT0H5M0S'));
echo $date->format('Y-m-d H:i:s');
It add 5minutes
For subtracting
$date = new DateTime('2014-02-20 14:20:00');
$date->sub(new DateInterval('P0DT0H5M0S'));
echo $date->format('Y-m-d H:i:s');
It subtract 5 minutes
If i'm right in thinking.
If you convert your date to a unix timestamp via strtotime(), then just add 300 (5min * 60 seconds) to that number.
$timestamp = strtotime($date) + (5*60)
Hope this helps
more illustrative for simple and clear solution
$date = '2011-04-8 08:29:49';
$newtimestamp = strtotime($date. ' + 5 minute');//gets timestamp
//convert into whichever format you need
$newdate = date('Y-m-d H:i:s', $newtimestamp);//it prints 2011-04-08 08:34:49
I have a date returned as part of a MySQL query in the form 2010-09-17.
I would like to set the variables $Date2 to $Date5 as follows:
$Date2 = $Date + 1
$Date3 = $Date + 2
etc., so that it returns 2010-09-18, 2010-09-19, etc.
I have tried
date('Y-m-d', strtotime($Date. ' + 1 day'))
but this gives me the date before $Date.
What is the correct way to get my Dates in the format form 'Y-m-d' so that they may be used in another query?
All you have to do is use days instead of day like this:
<?php
$Date = "2010-09-17";
echo date('Y-m-d', strtotime($Date. ' + 1 days'));
echo date('Y-m-d', strtotime($Date. ' + 2 days'));
?>
And it outputs correctly:
2010-09-18
2010-09-19
If you're using PHP 5.3, you can use a DateTime object and its add method:
$Date1 = '2010-09-17';
$date = new DateTime($Date1);
$date->add(new DateInterval('P1D')); // P1D means a period of 1 day
$Date2 = $date->format('Y-m-d');
Take a look at the DateInterval constructor manual page to see how to construct other periods to add to your date (2 days would be 'P2D', 3 would be 'P3D', and so on).
Without PHP 5.3, you should be able to use strtotime the way you did it (I've tested it and it works in both 5.1.6 and 5.2.10):
$Date1 = '2010-09-17';
$Date2 = date('Y-m-d', strtotime($Date1 . " + 1 day"));
// var_dump($Date2) returns "2010-09-18"
From PHP 5.2 on you can use modify with a DateTime object:
http://php.net/manual/en/datetime.modify.php
$Date1 = '2010-09-17';
$date = new DateTime($Date1);
$date->modify('+1 day');
$Date2 = $date->format('Y-m-d');
Be careful when adding months... (and to a lesser extent, years)
Here is a small snippet to demonstrate the date modifications:
$date = date("Y-m-d");
//increment 2 days
$mod_date = strtotime($date."+ 2 days");
echo date("Y-m-d",$mod_date) . "\n";
//decrement 2 days
$mod_date = strtotime($date."- 2 days");
echo date("Y-m-d",$mod_date) . "\n";
//increment 1 month
$mod_date = strtotime($date."+ 1 months");
echo date("Y-m-d",$mod_date) . "\n";
//increment 1 year
$mod_date = strtotime($date."+ 1 years");
echo date("Y-m-d",$mod_date) . "\n";
You can also use the following format
strtotime("-3 days", time());
strtotime("+1 day", strtotime($date));
You can stack changes this way:
strtotime("+1 day", strtotime("+1 year", strtotime($date)));
Note the difference between this approach and the one in other answers: instead of concatenating the values +1 day and <timestamp>, you can just pass in the timestamp as the second parameter of strtotime.
Here has an easy way to solve this.
<?php
$date = "2015-11-17";
echo date('Y-m-d', strtotime($date. ' + 5 days'));
?>
Output will be:
2015-11-22
Solution has found from here - How to Add Days to Date in PHP
Using a variable for Number of days
$myDate = "2014-01-16";
$nDays = 16;
$newDate = strtotime($myDate . '+ '.$nDays.' days');
echo new Date('d/m/Y', $newDate); //format new date
Here is the simplest solution to your query
$date=date_create("2013-03-15"); // or your date string
date_add($date,date_interval_create_from_date_string("40 days"));// add number of days
echo date_format($date,"Y-m-d"); //set date format of the result
This works. You can use it for days, months, seconds and reformat the date as you require
public function reformatDate($date, $difference_str, $return_format)
{
return date($return_format, strtotime($date. ' ' . $difference_str));
}
Examples
echo $this->reformatDate('2021-10-8', '+ 15 minutes', 'Y-m-d H:i:s');
echo $this->reformatDate('2021-10-8', '+ 1 hour', 'Y-m-d H:i:s');
echo $this->reformatDate('2021-10-8', '+ 1 day', 'Y-m-d H:i:s');
To add a certain number of days to a date, use the following function.
function add_days_to_date($date1,$number_of_days){
/*
//$date1 is a string representing a date such as '2021-04-17 14:34:05'
//$date1 =date('Y-m-d H:i:s');
// function date without a secrod argument returns the current datetime as a string in the specified format
*/
$str =' + '. $number_of_days. ' days';
$date2= date('Y-m-d H:i:s', strtotime($date1. $str));
return $date2; //$date2 is a string
}//[end function]
All have to use bellow code:
$nday = time() + ( 24 * 60 * 60);
echo 'Now: '. date('Y-m-d') ."\n";
echo 'Next Day: '. date('Y-m-d', $nday) ."\n";
Another option is to convert your date string into a timestamp and then add the appropriate number of seconds to it.
$datetime_string = '2022-05-12 12:56:45';
$days_to_add = 1;
$new_timestamp = strtotime($datetime_string) + ($days_to_add * 60 * 60 * 24);
After which, you can use one of PHP's various date functions to turn the timestamp into a date object or format it into a human-readable string.
$new_datetime_string = date('Y-m-d H:i:s', $new_timestamp);
I get the time:
$today = time();
$date = date('h:i:s A', strtotime($today));
if the current time is "1:00:00 am", how do i add 10 more hours to become 11:00:00 am??
strtotime() gives you a number back that represents a time in seconds. To increment it, add the corresponding number of seconds you want to add. 10 hours = 60*60*10 = 36000, so...
$date = date('h:i:s A', strtotime($today)+36000); // $today is today date
Edit: I had assumed you had a string time in $today - if you're just using the current time, even simpler:
$date = date('h:i:s A', time()+36000); // time() returns a time in seconds already
$tz = new DateTimeZone('Europe/London');
$date = new DateTime($today, $tz);
$date->modify('+10 hours');
// use $date->format() to outputs the result.
see DateTime Class
(PHP 5 >= 5.2.0)
You can simply make use of the DateTime class , OOP Style.
<?php
$date = new DateTime('1:00:00');
$date->add(new DateInterval('PT10H'));
echo $date->format('H:i:s a'); //"prints" 11:00:00 a.m
$date = date('h:i:s A', strtotime($today . ' + 10 hours'));
(untested)
$date = date('h:i:s A', strtotime($today . " +10 hours"));
Full code that shows now and 10 minutes added.....
$nowtime = date("Y-m-d H:i:s");
echo $nowtime;
$date = date('Y-m-d H:i:s', strtotime($nowtime . ' + 10 minute'));
echo "<br>".$date;
In order to increase or decrease time using strtotime you could use a Relative format in the first argument.
In your case to increase the current time by 10 hours:
$date = date('h:i:s A', strtotime('+10 hours'));
In case you need to apply the change to another timestamp, the second argument can be specified.
Note:
Using this function for mathematical operations is not advisable. It is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and later, or DateTime::modify() in PHP 5.2.
So, the recommended way since PHP 5.3:
$dt = new DateTime(); // assuming we need to add to the current time
$dt->add(new DateInterval('PT10H'));
$date = $dt->format('h:i:s A');
or using aliases:
$dt = date_create(); // assuming we need to add to the current time
date_add($dt, date_interval_create_from_date_string('10 hours'));
$date = date_format($dt, 'h:i:s A');
In all cases the default time zone will be used unless a time zone is specified.