str_repeat(A, B) repeat string A, B times:
$string = "This is a " . str_repeat("test", 2) .
"! " . str_repeat("hello", 3) . " and Bye!";
// Return "This is a testtest! hellohellohello and Bye!"
I need reverse operation:
str_shrink($string, array("hello", "test"));
// Return "This is a test(x2)! hello(x3) and Bye!" or
// "This is a [test]x2! [hello]x3 and Bye!"
Best and efficient way for create str_shrink function?
Here are two versions that I could come up with.
The first uses a regular expression and replaces duplicate matches of the $needle string with a single $needle string. This is the most vigorously tested version and handles all possibilities of inputs successfully (as far as I know).
function str_shrink( $str, $needle)
{
if( is_array( $needle))
{
foreach( $needle as $n)
{
$str = str_shrink( $str, $n);
}
return $str;
}
$regex = '/(' . $needle . ')(?:' . $needle . ')+/i';
return preg_replace_callback( $regex, function( $matches) { return $matches[1] . '(x' . substr_count( $matches[0], $matches[1]) . ')'; }, $str);
}
The second uses string manipulation to continually replace occurrences of the $needle concatenated with itself. Note that this one will fail if $needle.$needle occurs more than once in the input string (The first one does not have this problem).
function str_shrink2( $str, $needle)
{
if( is_array( $needle))
{
foreach( $needle as $n)
{
$str = str_shrink2( $str, $n);
}
return $str;
}
$count = 1; $previous = -1;
while( ($i = strpos( $str, $needle.$needle)) > 0)
{
$str = str_replace( $needle.$needle, $needle, $str);
$count++;
$previous = $i;
}
if( $count > 1)
{
$str = substr( $str, 0, $previous) . $needle .'(x' . $count . ')' . substr( $str, $previous + strlen( $needle));
}
return $str;
}
See them both in action
Edit: I didn't realize that the desired output wanted to include the number of repetitions. I've modified my examples accordingly.
You can play around with tis one, not tested a lot though
function shrink($s, $parts, $mask = "%s(x%d)"){
foreach($parts as $part){
$removed = 0;
$regex = "/($part)+/";
preg_match_all($regex, $s, $matches, PREG_OFFSET_CAPTURE);
if(!$matches)
continue;
foreach($matches[0] as $m){
$offset = $m[1] - $removed;
$nb = substr_count($m[0], $part);
$counter = sprintf($mask, $part, $nb);
$s = substr($s, 0, $offset) . $counter . substr($s, $offset + strlen($m[0]));
$removed += strlen($m[0]) - strlen($part);
}
}
return $s;
}
I think you can try with:
<?php
$string = "This is a testtest! hellohellohello and Bye!";
function str_shrink($string, $array){
$tr = array();
foreach($array as $el){
$n = substr_count($string, $el);
$tr[$el] = $el.'(x'.$n.')';
$pattern[] = '/('.$el.'\(x'.$n.'\))+/i';
}
return preg_replace($pattern, '${1}', strtr($string,$tr));
}
echo $string;
echo '<br/>';
echo str_shrink($string,array('test','hello')); //This is a test(x2)! hello(x3) and Bye!
?>
I have a second version in order to works with strings:
<?php
$string = "This is a testtest! hellohellohello and Bye!";
function str_shrink($string, $array){
$tr = array();
$array = is_array($array) ? $array : array($array);
foreach($array as $el){
$sN = 'x'.substr_count($string, $el);
$tr[$el] = $el.'('.$sN.')';
$pattern[] = '/('.$el.'\('.$sN.'\))+/i';
}
return preg_replace($pattern, '${1}', strtr($string,$tr));
}
echo $string;
echo '<br/>';
echo str_shrink($string,array('test','hello')); //This is a test(x2)! hello(x3) and Bye!
echo '<br/>';
echo str_shrink($string,'test'); //This is a test(x2)! hellohellohello and Bye!
?>
I kept it short:
function str_shrink($haystack, $needles, $match_case = true) {
if (!is_array($needles)) $needles = array($needles);
foreach ($needles as $k => $v) $needles[$k] = preg_quote($v, '/');
$regexp = '/(' . implode('|', $needles) . ')+/' . ($match_case ? '' : 'i');
return preg_replace_callback($regexp, function($matches) {
return $matches[1] . '(x' . (strlen($matches[0]) / strlen($matches[1])) . ')';
}, $haystack);
}
The behavior of cases like str_shrink("aaa", array("a", "a(x3)")) is it returns "a(x3)", which I thought was more likely intended if you're specifying an array. For the other behavior, giving a result of "a(x3)(x1)", call the function with each needle individually.
If you don't want multiples of one to get "(x1)" change:
return $matches[1] . '(x' . (strlen($matches[0]) / strlen($matches[1])) . ')';
to:
$multiple = strlen($matches[0]) / strlen($matches[1]);
return $matches[1] . (($multiple > 1) ? '(x' . $multiple . ')' : '');
Here's a very direct, single-regex technique and you don't need to collect the words in the string in advance.
There will be some fringe cases to mitigate which are not represented in the sample input, but as for the general purpose of this task, I reckon this is the way that I'd script this in my project.
Match (and capture) any full word that is repeated one or more times.
Match the contiguous repetitions of the word.
Replace the fullstring match (substring of multiple words) with the captured first instance of the word.
Before returning the replacement string for re-insertion, add the desired formatting and calculate the number of repetitions by dividing the fullstring length by the captured string's length.
Code: (Demo)
$string = "This is a " . str_repeat("test", 2) .
"!\n" . str_repeat("hello", 3) . " and Bye!\n" .
"When I sleep, the thought bubble says " . str_repeat("zz", 3) . ".";
echo preg_replace_callback(
'~\b(\w+?)\1+\b~',
function($m) {
return "[{$m[1]}](" . (strlen($m[0]) / strlen($m[1])) . ")";
},
$string
);
Output:
This is a [test](2)!
[hello](3) and Bye!
When I sleep, the thought bubble says [z](6).
For a whitelist of needles, this adaptation to my above code does virtually the same job.
Code: (Demo)
function str_shrink($string, $needles) {
// this escaping is unnecessary if only working with alphanumeric characters
$needles = array_map(function($needle) {
return preg_quote($needle, '~');
}, $needles);
return preg_replace_callback(
'~\b(' . implode('|', $needles) . ')\1+\b~',
function($m) {
return "[{$m[1]}](" . (strlen($m[0]) / strlen($m[1])) . ")";
},
$string
);
}
echo str_shrink($string, ['test', 'hello']);
Output:
This is a [test](2)!
[hello](3) and Bye!
When I sleep, the thought bubble says zzzzzz.
Related
I am using multidimensional arrays and am accessing them after using explode on a string. The resulting array should be nested with the number of occurrences of '.' in the given string. For instance, foo.bar.ok is ['foo']['bar']['ok'].
Currently, I am doing:
switch (count($_match)):
case 1:
$retVal = str_replace('{' . $match . '}', $$varName[$_match[0]], $retVal);
break;
case 2:
$retVal = str_replace('{' . $match . '}', $$varName[$_match[0]][$_match[1]], $retVal);
break;
case 3:
$retVal = str_replace('{' . $match . '}', $$varName[$_match[0]][$_match[1]][$_match[2]], $retVal);
break;
endswitch;
Quintessentially I would like to have unlimited number of $_match[x] using a loop.
Edit
The resulting array should be in the format: $array[foo][bar][ok]
Here are some examples I tried:
$string = 'foo.bar.ok';
$exploded = explode('.', $string);
$bracketed = array_map(function($x) { return [$x]; }, $exploded);
echo "<pre>";var_dump($bracketed);
$bracketed = array_map(function($x) { return "['$x']"; }, $_match);
$result = implode('', $bracketed);
var_dump(eval('return $t' . $result . ';'));
The first doesn't append arrays in nested structure, it lists them as 0, 1, 2, etc and the second works but it uses eval.
Finally, using loops as suggested worked.
for ($replace = $$varName[$_match[0]], $i = 1; $i < count($_match); $i++) {
if (isset($replace[$_match[$i]]))
$replace = $replace[$_match[$i]];
}
if (is_string($replace) || is_numeric($replace))
$retVal = str_replace('{' . $match . '}', $replace, $retVal);
I would like to see a working array_walk example though? - thank you!
Use array_map() and implode().
$string = 'foo.bar.ok';
$exploded = explode('.', $string);
$bracketed = array_map(function($x) { return "[$x]"; }, $exploded);
$result = implode('', $bracketed);
So you want to perform $$varName[$_match[0]][$_match[1]][$_match[2]...[$_match[count($_match)-1]?
for ($var_name = $varName[$_match[0]], $i=1; $i<count($_match); $i++) {
$var_name = $var_name[$_match[$i]];
}
$retVal = str_replace('{' . $match . '}', $$var_name, $retVal);
This could probably be improved by replacing the for() with array_walk().
I want to do a str_replace() but only at the Nth occurrence.
Inputs:
$originalString = "Hello world, what do you think of today's weather";
$findString = ' ';
$nthOccurrence = 8;
$newWord = ' beautiful ';
Desired Output:
Hello world, what do you think of today's beautiful weather
Here is a tight little regex with \K that allows you to replace the nth occurrence of a string without repeating the needle in the pattern. If your search string is dynamic and might contain characters with special meaning, then preg_quote() is essential to the integrity of the pattern.
If you wanted to statically write the search string and nth occurrence into your pattern, it could be:
(?:.*?\K ){8}
or more efficiently for this particular case: (?:[^ ]*\K ){8}
\K tells the regex pattern to "forget" any previously matched characters in the fullstring match. In other words, "restart the fullstring match" or "Keep from here". In this case, the pattern only keeps the 8th space character.
Code: (Demo)
function replaceNth(string $input, string $find, string $replacement, int $nth = 1): string {
$pattern = '/(?:.*?\K' . preg_quote($find, '/') . '){' . $nth . '}/';
return preg_replace($pattern, $replacement, $input, 1);
}
echo replaceNth($originalString, $findString, $newWord, $nthOccurrence);
// Hello world, what do you think of today's beautiful weather
Another perspective on how to grapple the asked question is: "How to insert a new string after the nth instance of a search string?" Here is a non-regex approach that limits the explosions, prepends the new string to the last element then re-joins the elements. (Demo)
$originalString = "Hello world, what do you think of today's weather";
$findString = ' ';
$nthOccurrence = 8;
$newWord = 'beautiful '; // notice that leading space was removed
function insertAfterNth($input, $find, $newString, $nth = 1) {
$parts = explode($find, $input, $nth + 1);
$parts[$nth] = $newString . $parts[$nth];
return implode($find, $parts);
}
echo insertAfterNth($originalString, $findString, $newWord, $nthOccurrence);
// Hello world, what do you think of today's beautiful weather
I found an answer here - https://gist.github.com/VijayaSankarN/0d180a09130424f3af97b17d276b72bd
$subject = "Hello world, what do you think of today's weather";
$search = ' ';
$occurrence = 8;
$replace = ' nasty ';
/**
* String replace nth occurrence
*
* #param type $search Search string
* #param type $replace Replace string
* #param type $subject Source string
* #param type $occurrence Nth occurrence
* #return type Replaced string
*/
function str_replace_n($search, $replace, $subject, $occurrence)
{
$search = preg_quote($search);
echo preg_replace("/^((?:(?:.*?$search){".--$occurrence."}.*?))$search/", "$1$replace", $subject);
}
str_replace_n($search, $replace, $subject, $occurrence);
$originalString = "Hello world, what do you think of today's weather";
$findString = ' ';
$nthOccurrence = 8;
$newWord = ' beautiful ';
$array = str_split($originalString);
$count = 0;
$num = 0;
foreach ($array as $char) {
if($findString == $char){
$count++;
}
$num++;
if($count == $nthOccurrence){
array_splice( $array, $num, 0, $newWord );
break;
}
}
$newString = '';
foreach ($array as $char) {
$newString .= $char;
}
echo $newString;
I would consider something like:
function replaceNth($string, $substring, $replacement, $nth = 1){
$a = explode($substring, $string); $n = $nth-1;
for($i=0,$l=count($a)-1; $i<$l; $i++){
$a[$i] .= $i === $n ? $replacement : $substring;
}
return join('', $a);
}
$originalString = 'Hello world, what do you think of today\'s weather';
$test = replaceNth($originalString, ' ', ' beautiful ' , 8);
$test2 = replaceNth($originalString, 'today\'s', 'good');
First explode a string by parts, then concatenate the parts together and with search string, but at specific number concatenate with replace string (numbers here start from 0 for convenience):
function str_replace_nth($search, $replace, $subject, $number = 0) {
$parts = explode($search, $subject);
$lastPartKey = array_key_last($parts);
$result = '';
foreach($parts as $key => $part) {
$result .= $part;
if($key != $lastPartKey) {
if($key == $number) {
$result .= $replace;
} else {
$result .= $search;
}
}
}
return $result;
}
Usage:
$originalString = "Hello world, what do you think of today's weather";
$findString = ' ';
$nthOccurrence = 7;
$newWord = ' beautiful ';
$result = str_replace_nth($findString, $newWord, $originalString, $nthOccurrence);
How can I process text with some codes.
So suppose I have text as below
Hello {::first_name::} {::last_name::},
How are you?
Your organisation is {::organisation::}
For any text between {:: and ::} should be evaluated to get its value.
I tried exploding text to array using space as delimiter and then parsing array items to look for "{::" and if found get string between "{::" and "::}" and calling database to get this field value.
So basically these will be db fields.
Below is the code I have tried
$msg = "Hello {::first_name::} {::last_name::},
How are you?
Your organisation is {::organisation::}";
$msg_array = explode(" ", $msg);
foreach ($msg_array as $str) {
if (strpos($str, "{::") !== false) {
$field_str = get_string_between($str, "{::", "::}");
$field_value = $bean->$field_str; //Logic that gets the value of the field
$msgStr .= $field_value . " ";
} else {
$msgStr .= $str . " ";
}
}
function get_string_between($string, $start, $end)
{
$string = ' ' . $string;
$ini = strpos($string, $start);
if ($ini == 0) return '';
$ini += strlen($start);
$len = strpos($string, $end, $ini) - $ini;
return substr($string, $ini, $len);
}
Your script seems fine. Your script in fiddle
If you are looking for alternative way, you can try using preg_match_all() with str_replace(array, array, source)
<?php
$bean = new stdClass();
$bean->first_name = 'John';
$bean->last_name = 'Doe';
$bean->organisation = 'PHP Company';
$string = "Hello {::first_name::} {::last_name::}, How are you? Your organisation is {::organisation::}";
// find all placeholders
preg_match_all('/{::(.+?)::}/i', $string, $matches);
$placeholders = $matches[0];
//strings inside placeholders
$parts = $matches[1];
// return values from $bean by matching object property with strings inside placeholders
$replacements = array_map(function($value) use ($bean) {
// use trim() to remove unexpected space
return $bean->{trim($value)};
}, $parts);
echo $newstring = str_replace($placeholders, $replacements, $string);
Short format:
$string = "Hello {::first_name::} {::last_name::}, How are you? Your organisation is {::organisation::}";
preg_match_all('/{::(.+?)::}/i', $string, $matches);
$replacements = array_map(function($value) use ($bean) {
return $bean->{trim($value)};
}, $matches[1]);
echo str_replace($matches[0], $replacements, $string);
And if you prefer to use a function:
function holder_replace($string, $source = null) {
if (is_object($source)) {
preg_match_all('/{::(.+?)::}/i', $string, $matches);
$replacements = array_map(function($value) use ($source) {
return (property_exists(trim($value), 'source')) ? $source->{trim($value)} : $value;
}, $matches[1]);
return str_replace($matches[0], $replacements, $string);
}
return $string;
};
echo holder_replace($string, $bean);
OUTPUT:
Hello John Doe, How are you? Your organisation is PHP Company
fiddle
Or you can simply use str_replace function:
$data = "{:: string ::}";
echo str_replace("::}", "",str_replace("{::", "", $data));
I want string format with incremental numbers. I've strings starting with alphabets and containing numbers with few leading 0's.
$string = M001; //input
$alf= trim(str_replace(range(0,9),'',$string)); //removes number from string
$number = preg_replace('/[A-Za-z]+/', '', $string);// removes alphabets from the string
$number+=1;
$custom_inv_id = $alf.$number;
Expected result:
input M002 output M003
input A00003 output A00004
Using above code if input is M002, I'm getting output as M3. How I can get M003? Number of 0's is not fixed.
Use PHP preg_match or str_replace and try this code :-
$str='M001';
preg_match('!\d+!', $str, $matches);
$num=(int)$matches[0];
$num++;
echo str_replace((int)$matches[0],'',$str);
echo $num;
Demo
<?php
$tests = ['M0', 'M1', 'M001', 'M9', 'M09', 'M010',
'M2M0', 'M2M1', 'M2M001', 'M2M9', 'M2M09', 'M2M010',
'M2M', 'MM', '9M'];
foreach ($tests as $string) {
if (preg_match('/([\w\W]+)([0-9]+)$/', $string, $matches)) {
$output_string = $matches[1] . ($matches[2] + 1);
echo '<p>' . $string . ' => ' . $output_string . '</p>';
} else {
echo '<p>' . $string . ' (nothing to increment)</p>';
}
}
$a = 'm002';
$pattern = '#(?P<word>[A-Za-z0]+)(?P<digtt>[1-9]+)#';
preg_match($pattern, $a, $matches);
$final = $matches['word'].(string)($matches['digtt']+1);
echo $final;
You can use the sprintf and preg_match functions to get your expected result.
First: Split your string with preg_match to seperated values to work with
Second: Format a new string with sprintf
http://php.net/manual/en/function.sprintf.php
http://php.net/manual/en/function.preg-match.php
function increase($string, $amount = 1) {
$valid = preg_match("#^(.)(0+)?(\d+)$#s", $string, $matches);
if($valid) {
list($match, $char, $zero, $integer) = $matches;
$integer += $amount;
return sprintf("%s%'.0" . (strlen($zero)+1) . "d", $char, $integer);
}
return null;
}
echo increase("M00001"); // M00002
echo increase("A001", 5); // A006
i hope this can help you . i have made some thing dynamic make M% also dynamic
<?php
$vl = "A00004";
$number = substr($vl ,1);
$num= substr_count($vl,0);
$num++;
$number++;
$string = "M%'. 0".$num."d";
echo sprintf($string, $number);
?>
i got this result
M00005
As leading 0 is copied, I would do it like this. It works if the leading chars is also lowercase. It's also a non-regex and non-array way.
$str = "M0099";
$num = ltrim($str, "a..zA..Z0");
$new = str_replace($num, $num + 1, $str);
Output:
echo $new; // string(6) "M00100"
I need to edit all odd words to upper case.
Here is sample of imput string:
very long string with many words
Expected output:
VERY long STRING with MANY words
I have this code, but it seams to me, that I can do it in better way.
<?php
$lines = file($_FILES["fname"]["tmp_name"]);
$pattern = "/(\S[\w]*)/";
foreach($lines as $value)
{
$words = NULL;
$fin_str = NULL;
preg_match_all($pattern, $value, $matches);
for($i = 0; $i < count($matches[0]); $i = $i + 2){
$matches[0][$i] = strtoupper($matches[0][$i]);
$fin_str = implode(" ", $matches[0]);
}
echo $fin_str ."<br>";
P.S. I need to use only preg_match function.
Here's a preg_replace_callback example:
<?php
$str = 'very long string with many words';
$newStr = preg_replace_callback('/([^ ]+) +([^ ]+)/',
function($matches) {
return strtoupper($matches[1]) . ' ' . $matches[2];
}, $str);
print $newStr;
// VERY long STRING with MANY words
?>
You only need to match the repeating pattern: /([^ ]+) +([^ ]+)/, a pair of words, then preg_replace_callback recurses over the string until all possible matches are matched and replaced. preg_replace_callback is necessary to call the strtoupper function and pass the captured backreference to it.
Demo
If you have to use regular expressions, this should get you started:
$input = 'very long string with many words';
if (preg_match_all('/\s*(\S+)\s*(\S+)/', $input, $matches)) {
$words = array();
foreach ($matches[1] as $key => $odd) {
$even = isset($matches[2][$key]) ? $matches[2][$key] : null;
$words[] = strtoupper($odd);
if ($even) {
$words[] = $even;
}
}
echo implode(' ', $words);
}
This will output:
VERY long STRING with MANY words
You may don't need regex simply use explode and concatenate the string again:
<?php
function upperizeEvenWords($str){
$out = "";
$arr = explode(' ', $str);
for ($i = 0; $i < count($arr); $i++){
if (!($i%2)){
$out .= strtoupper($arr[$i])." ";
}
else{
$out .= $arr[$i]." ";
}
}
return trim($out);
}
$str = "very long string with many words";
echo upperizeEvenWords($str);
Checkout this DEMO