Incremental strings in PHP - php

Question

I want string format with incremental numbers. I've strings starting with alphabets and containing numbers with few leading 0's.
$string = M001; //input
$alf= trim(str_replace(range(0,9),'',$string)); //removes number from string
$number = preg_replace('/[A-Za-z]+/', '', $string);// removes alphabets from the string
$number+=1;
$custom_inv_id = $alf.$number;
Expected result:
input M002 output M003
input A00003 output A00004
Using above code if input is M002, I'm getting output as M3. How I can get M003? Number of 0's is not fixed.

Answer 1

Use PHP preg_match or str_replace and try this code :-
$str='M001';
preg_match('!\d+!', $str, $matches);
$num=(int)$matches[0];
$num++;
echo str_replace((int)$matches[0],'',$str);
echo $num;
Demo

Answer 2

<?php
$tests = ['M0', 'M1', 'M001', 'M9', 'M09', 'M010',
'M2M0', 'M2M1', 'M2M001', 'M2M9', 'M2M09', 'M2M010',
'M2M', 'MM', '9M'];
foreach ($tests as $string) {
if (preg_match('/([\w\W]+)([0-9]+)$/', $string, $matches)) {
$output_string = $matches[1] . ($matches[2] + 1);
echo '<p>' . $string . ' => ' . $output_string . '</p>';
} else {
echo '<p>' . $string . ' (nothing to increment)</p>';
}
}

Answer 3

$a = 'm002';
$pattern = '#(?P<word>[A-Za-z0]+)(?P<digtt>[1-9]+)#';
preg_match($pattern, $a, $matches);
$final = $matches['word'].(string)($matches['digtt']+1);
echo $final;

Answer 4

You can use the sprintf and preg_match functions to get your expected result.
First: Split your string with preg_match to seperated values to work with
Second: Format a new string with sprintf
http://php.net/manual/en/function.sprintf.php
http://php.net/manual/en/function.preg-match.php
function increase($string, $amount = 1) {
$valid = preg_match("#^(.)(0+)?(\d+)$#s", $string, $matches);
if($valid) {
list($match, $char, $zero, $integer) = $matches;
$integer += $amount;
return sprintf("%s%'.0" . (strlen($zero)+1) . "d", $char, $integer);
}
return null;
}
echo increase("M00001"); // M00002
echo increase("A001", 5); // A006

Answer 5

i hope this can help you . i have made some thing dynamic make M% also dynamic
<?php
$vl = "A00004";
$number = substr($vl ,1);
$num= substr_count($vl,0);
$num++;
$number++;
$string = "M%'. 0".$num."d";
echo sprintf($string, $number);
?>
i got this result
M00005

Answer 6

As leading 0 is copied, I would do it like this. It works if the leading chars is also lowercase. It's also a non-regex and non-array way.
$str = "M0099";
$num = ltrim($str, "a..zA..Z0");
$new = str_replace($num, $num + 1, $str);
Output:
echo $new; // string(6) "M00100"