jQuery clone - data post to php function - php

Question

Here is my form element
<form method="post" id="add_facility_form" class="blocks" action="<?php echo base_url(); ?>index.php/facility_management/add">
<div id="contact_wrapper">
<p>Name: </p>
<input type="text" class="inp-form" name="contact_name[]" />
<p>Department: </p>
<input type="text" class="inp-form" name="department_name[]" />
<p>Email: </p>
<input type="text" class="inp-form" name="contact_email[]" />
<p>Phone number: </p>
<input type="text" class="inp-form" name="contact_phone_number[]" />
<p>Fax number: </p>
<input type="text" class="inp-form" name="contact_fax_number[]" />
</div>
<img width="21" height="21" alt="" src="<?php echo base_url() ?>images/forms/icon_plus.gif" class="add_new_contact add_new" />
</form>
when I click on the image it clones the whole div.I want to post the data but the problem is that it posts only first div's information.How can I post the cloned element's data?
here is jquery function and php
$(".add_new_contact").click(function () {
$("#contact_wrapper").clone().attr('id','contact_wrapper'+new Date().getTime()).appendTo($(this).parent());
return false;
});
PHP
$contact_name = $this->input->post('contact_name');
$department = $this->input->post('department_name');
$contact_phone = $this->input->post('contact_phone_number');
$contact_fax = $this->input->post('contact_fax_number');
$contact_email = $this->input->post('contact_email');
$contact_count = count($contact_name);

Answer 1

<?php
$array=$_POST['contact_name'];
foreach($array as $name)
{
echo "Name is ".$name."<br>";
}
$array=$_POST['contact_email'];
foreach($array as $email)
{
echo "email is ".$email."<br>";
}
?>