I have two text boxes and one button. I want when i will type any value in 1st textbox and click on a button the value which i'll type in 1st text box should be the value of 2nd text box. And i was using this code. Can some one help me on this?
<?php
if(isset($_POST['sum']))
{
$v1=$_POST['abc'];
if($v1=="vivek")
{
echo "welcome Mr.".$v1;
}
else
{
echo "Unauthorised User Mr. ".$v1;
}
}
?>
<html>
<body>
<form method="post" action="">
<p>Name:     
<input type="text" name="abc" value=""/>  
</br></br>
Passed Value: <input type="text" name="xyz" value="<?php echo $v1;?>"/>
</p>
<p>
<input type="submit" name="sum" value=" Submit "/>
</p>
</form>
</body>
</html>
try this one.
<form method="post" action="">
<p>Name:     
<input type="text" name="abc" value=""/>  
</br></br>
Passed Value: <input type="text" name="xyz" value="<?php if(isset($_POST['abc'])) { echo $_POST['abc']; } ?>"/>
</p>
<p>
<input type="submit" name="sum" value=" Submit "/>
</p>
</form>
Passed Value:
<input type="text" name="xyz" value="<?php
if(isset($_POST['abc']))
echo htmlentities($_POST['abc'],ENT_QUOTES);
?>"/>
This should do it :)
Try this code.
<script type="text/javascript">
function sub() {
document.getElementById('xyz').value = document.getElementById('abc').value;
}
</script>
<form>
<label>Amonut</label>
<input type="text" name="abc" onkeyup="sub();" id="abc" />
<br /><br />
<label>Discount</label>
<input type="text" name="xyz" id="xyz" />
<input type="submit" name="sum" value=" Submit "/>
</form>
<script type="text/javascript">
function sub() {
document.getElementById('xyz').value = document.getElementById('abc').value;
}
</script>
<form onsubmit="sub();">
<label>Amonut</label>
<input type="text" name="abc" id="abc" />
<br /><br />
<label>Discount</label>
<input type="text" name="xyz" id="xyz" />
<input type="submit" name="sum" value=" Submit "/>
</form>
I think you want this.
Try this code
$v1='';
if(isset($_POST['sum']))
{
if($v1=="vivek")
{
echo "welcome Mr.".$v1;
$v1=$_POST['abc'];
}
else
{
echo "Unauthorised User Mr. ".$v1;
}
}
Related
I have a site where I make a payment, a bill is created through it, but the problem is that I can not use $ _POST twice in one, and this example:
<? if (isset($_POST['submit'])) { ?>
<form action="" method="POST" >
<input name="invoice" value="" type="text" />
<input name="pay" value="Pay Now" type="submit" />
</form>
<? } if (isset($_POST['pay'])) {
// MY QUERY HERE
// HEADERS HERE
} else { ?>
<form action="" method="POST" >
<input name="info" value="" type="text" />
<input name="submit" value="Submit" type="submit" />
</form>
<? } ?>
Try this.
Kindly check the code for comment.
<?
if (isset($_POST['submit'])) {
$info = $_POST['info'];
// use echo to display second form
echo '
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST" >
<!-- // Note the action value, it's for post back. This allow you to post back to the current page -->
<!-- This is to keep the record passed from the first form -->
<input name="info" value="'. $info .'" type="hidden" />
<input name="invoice" value="" type="text" />
<input name="pay" value="Pay Now" type="submit" />
</form>';
} else if (isset($_POST['pay'])) {
// MY QUERY HERE
} else {
// Note the action value, it's for post back. This allow you to post back to the current page
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST" >
<input name="info" value="" type="text" />
<input name="submit" value="Submit" type="submit" />
</form>
}
?>
Not the prettiest way to do this but to achieve your result try this...
<?php if (isset($_POST['submit'])) { ?>
<form action="" method="POST" >
<input name="invoice" value="" type="text" />
<input name="pay" value="Pay Now" type="submit" />
</form>
<?php } elseif (isset($_POST['pay'])) {
// Perform query here
} else { ?>
<form action="" method="POST" >
<input name="info" value="" type="text" />
<input name="submit" value="Submit" type="submit" />
</form>
<?php } ?>
can we use $_POST 2 times with different page ?
this example ..
action.php
<form action="next.php" method="post">
<input name="test" value="test" />
<button type="submit" name="test">submit</button>
</form>
next.php
<?php
$test=$_POST['test'];
?>
<form action="next1.php" method="post">
<input name="test1" value="<?php echo $test; ?>" />
<button type="submit" name="test1">submit</button>
</form>
next1.php
<?php
echo $test2=$_POST['test1']; >> in here i didnt get test1 value . why ?
?>
Within next.php and action.php you need to change your input type like as
<input type="text" name="test" value="test" />
<input type="text" name="test1" value="<?php echo $test; ?>" />
Within next.php and action.php you were missing the type attr of input tag
and you have same name attributes for submit and input within next.php need to remove or change the value from respective
<input type="submit" value="submit"/>
Below code i have tried my local server and it executed successfully.
action.php:-
<form action="next.php" method="POST">
<input type="text" name="test"/>
<input type="submit" value="submit"/>
</form>
next.php:-
<?php
$test = $_POST['test'];
echo $test;
?>
<form action="next1.php" method="POST">
<input name="test1" value="<?php echo $test; ?>" />
<input type="submit" value="submit"/>
</form>
next1.php:-
<?php
$test2=$_POST['test1'];
echo "------".$test2;
?>
Hope this will help.I think this is achieved your requirement.
If you want to do it within one file e.g. index.php then here is the code
<?php
if(isset($_POST['test'])){
if(isset($_POST['test_text'])){
echo 'Output from NEXT: '.$_POST['test_text'];
}
}
elseif(isset($_POST['test1'])){
if(isset($_POST['test_text1'])){
echo 'Output from NEXT1: '.$_POST['test_text1'];
}
}
?>
<table style="width:100%;">
<tr >
<td style="width:50%;">
<form action="" method="post" name="next">
<input type="text" name="test_text" value="<?php echo isset($_POST['test_text']) ? $_POST['test_text']:''; ?>" />
<button type="submit" name="test">submit test1</button>
</form>
</td>
<td style="width:50%;">
<form action="" method="post" name="next1">
<input type="text1" name="test_text1" value="<?php echo isset($_POST['test_text1']) ? $_POST['test_text1']:''; ?>" />
<button type="submit" name="test1">submit test1</button>
</form>
</td>
</tr>
</table>
I hope this will help.
You need to send the POST value with the second form again, e.g. in a hidden field, otherwise the value won't be sent.
Furthermore your submit button shouldn't have the same name as the input field you want the content from. So change the name of your submit button, e.g.:
action.php
<form action="next.php" method="post"> <input name="test" value="test" /> <button type="submit" name="submit">submit</button> </form>
next.php
<form action="next1.php" method="post">
<input name="test1" value="<?php echo $test; ?>" />
<button type="submit" name="submit">submit</button>
</form>
I have n number of text box (n may be any number) with same name. And
I want to access the value of all the text box of that name.
Ex-:
<form method="post" id="create">
<input type="text" name="user[]" />
<input type="text" name="user[]" />
<input type="text" name="user[]" />
<input type="button" id="newFieldBtn"/>
<input type="submit" name="save" value="save"/>
</form>
jQuery
<script>
jQuery(document).ready(function($) {
$('#newFieldBtn').click(function(){
var code='<input type="text" name="user[]" />';
jQuery('#create').append(code);
</script>
or is there any other way to access the value of the text box. Either
by class or any other property..
<script>
jQuery(document).ready(function($) {
$('#newFieldBtn').click(function(){
var count = document.getElementById('count').value;
count++;
var code = '<input type="text" name="user'+count+'" />';
jQuery('#create').append(code);
document.getElementById('count').value = count;
</script>
and your html like...
<form method="post" id="create">
<input type="hidden" id="count" value="0" name="count">
<input type="button" id="newFieldBtn"/>
<input type="submit" name="save" value="save"/>
</form>
and in your php code...
<?php
if(isset($_POST))
{
$count = $_POST['count'];
for($i=1;$i<=$count;$i++)
{
$user.$i = $_POST['user'.$i];
}
}
?>
Try this one, it will show you the values :
<form action="#" method="post">
<input type="text" name="user[]" />
<input type="text" name="user[]" />
<input type="text" name="user[]" />
<input type="submit" value="submit" >
</form>
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
foreach($_POST['user'] as $key => $value)
{
echo $key." has the value = ". $value."<br>";
}
}
?>
See this in action: http://wistudat.be/try/array.php
I am using below code for a html form.(it has two forms) I am able to keep the textarea field after the first and second form submission. but issue I am facing here is the dropdown menu selection.
Code:
<html>
<body>
<div class="emcsaninfo-symcli-main">
<form id="form1" name="form1" action=" " method="post" >
<div class="input">Your Name</div>
<div class="response"><span><input class="textbox" id="myname" name="myname" type="text" value="<?php if(isset($_POST['myname'])) { echo htmlentities ($_POST['myname']); }?>" /></span> </div>
<div class="input">Your Place</div>
<div class="response"><span><input class="textbox" id="myplace" name="myplace" type="text" value="<?php if(isset($_POST['myplace'])) { echo htmlentities ($_POST['myplace']); }?>" /></span> </div>
<div class="input-quest">Graduation Status</div>
<div class="input-resp"><select id="graduation" name="graduation" OnChange="CMT();"><option class="dropdown-options">Graduate</option><option class="dropdown-options">Non Graduate</option></select></div>
<div class="submit">
<input id="first_submit" type="submit" name="first_submit" value="first_submit" />
</div>
</form>
<?php
if(!empty($_POST['myname']) && !empty($_POST['myplace']) || !empty($_POST['output_textarea'] ) )
{
$myname = $_POST['myname'];
$myplace = $_POST['myplace'];
$graduation = $_POST['graduation'];
?>
<form id="form2" name="form2" action=" " method="post" >
<textarea onclick="this.select()" name="output_textarea" id="output_textarea" cols="100" rows="25" readonly value="<?php if(isset($_POST['output_textarea'])) { echo htmlentities ($_POST['output_textarea']); }?>">
<?php
echo "My name is $myname and I am from $myplace, and I am $graduation";
?>
</textarea>
<input id="submit1" type="submit" name="name_field" value="submit1" />
<input id="submit2" type="submit" name="place_field" value="submit2" />
<input id="myname_hidden" name="myname" type="hidden" value="<?php if(isset($_POST['myname'])) { echo htmlentities ($_POST['myname']); }?>"/>
<input id="myplace_hidden" name="myplace" type="hidden" value="<?php if(isset($_POST['myplace'])) { echo htmlentities ($_POST['myplace']); }?>" />
<input id="graduation_hidden" name="graduation" type="hidden" value="<?php if(isset($_POST['graduation'])) { $graduation = $_POST['graduation']; }?>" />
</form>
<?php
function name()
{
echo $_POST["output_textarea"];
}
if(isset($_POST['name_field']))
{
name();
}
function place()
{
echo $_POST["output_textarea"];
}
if(isset($_POST['place_field']))
{
place();
}
}
?>
</div>
</html>
</body>
For example if I put name = John, place : UK and selecting graduation status as graduate, it will will give me first form output as in my output textarea
My name is John and I am from UK, and I am Graduate
I have two seperate submit button for second form, using that I am doing some other function with help of the output textarea
If I press any of the second button,I m able to keep entries my name and place area, but it not keeping the dropdown selection. so it will only display like after submitting submit1 or submit2
My name is John and I am from UK, and I am
Here,
How can I keep the the dropdown selection also with the output text area
Will I able to show only the output_textarea content after second form submission without keeping the first form data ?
PHP FIDDLE
You have an error in logic in the hidden input for the "graduate" element.
This is what you have at lines 53-55. Line 55 doesn't have an echo instead it has an $graduation = $_POST['graduation']; which won't help you:
<input id="myname_hidden" name="myname" type="hidden" value="<?php if(isset($_POST['myname'])) { echo htmlentities ($_POST['myname']); }?>"/>
<input id="myplace_hidden" name="myplace" type="hidden" value="<?php if(isset($_POST['myplace'])) { echo htmlentities ($_POST['myplace']); }?>" />
<input id="graduation_hidden" name="graduation" type="hidden" value="<?php if(isset($_POST['graduation'])) { $graduation = $_POST['graduation']; }?>" />
instead of that, this code should work:
<input id="myname_hidden" name="myname" type="hidden" value="<?php if(isset($_POST['myname'])) { echo htmlentities ($_POST['myname']); }?>"/>
<input id="myplace_hidden" name="myplace" type="hidden" value="<?php if(isset($_POST['myplace'])) { echo htmlentities ($_POST['myplace']); }?>" />
<input id="graduation_hidden" name="graduation" type="hidden" value="<?php if(isset($_POST['graduation'])) { echo htmlentities($_POST['graduation']); }?>" />
When I input numeric value in Number 1 and Number 2, and press "Add". It does not display the total added value. Please see my coding below. and advice me, what to is the problem, and what can be done.
<html>
<head>
<title>Simple Calculator</title>
<?php
if(isset($_POST['submitted'])){
if(is_numeric($_POST['number1']) && is_numeric($_POST['number2'])){
$add = ($_POST['number1'] + $_POST['number2']);
echo "Add: ".$_POST['number1']."+".$_POST['number2']."=";
}
}
?>
<script type="text/javascript">
</script>
</head>
<body>
<h1>Simple Calculator</h1>
<form action="simple_calculator.php" method="post">
<p>Number 1: <input type="text" name="number1" size="20" value="<?php if(isset($_POST['number1'])) echo $_POST['number1'];?>"/></p>
<p>Number 2: <input type="text" name="number2" size="20" value="<?php if(isset($_POST['number2'])) echo $_POST['number2'];?>"/></p>
<input type="button" name="add" value="Add" />
<input type="button" name="minus" value="Minus" />
<input type="button" name="multiply" value="Multiply" />
<input type="button" name="divide" value="Divide" />
<input type="reset" name="rest" value="Reset" />
<input type="hidden" name="submitted" value="TRUE" />
</form>
</body>
</html>
You are echoing the result data into the <head>, so it will not be displayed.
You forgot to echo $add.
Your <input>s are of type button and not submit, so the form will not be submitted to the server.
Because you are echoing the previously entered values into the form, <input type="reset"> will probably not do what you want/expect it to do. I think it would be better to implement this as another submit.
Because this form affects only what the next page displays and does not make a permanent change to the server, you should use the GET method and not POST.
Try this:
<html>
<head>
<title>Simple Calculator</title>
<script type="text/javascript"></script>
</head>
<body>
<h1>Simple Calculator</h1>
<form action="simple_calculator.php" method="get">
<p>Number 1: <input type="text" name="number1" size="20" value="<?php if (isset($_GET['number1']) && !isset($_GET['reset'])) echo $_GET['number1'];?>"/></p>
<p>Number 2: <input type="text" name="number2" size="20" value="<?php if (isset($_GET['number2']) && !isset($_GET['reset'])) echo $_GET['number2'];?>"/></p>
<input type="submit" name="add" value="Add" />
<input type="submit" name="minus" value="Minus" />
<input type="submit" name="multiply" value="Multiply" />
<input type="submit" name="divide" value="Divide" />
<input type="submit" name="reset" value="Reset" />
<input type="hidden" name="submitted" value="1" />
</form>
<?php
if (isset($_GET['submitted']) && !isset($_GET['reset'])) {
echo "<div>";
if (is_numeric($_GET['number1']) && is_numeric($_GET['number2'])) {
if (isset($_GET['add'])) {
$result = $_GET['number1'] + $_GET['number2'];
echo "Add: ".$_GET['number1']." + ".$_GET['number2']." = ".$result;
} else if (isset($_GET['minus'])) {
$result = $_GET['number1'] - $_GET['number2'];
echo "Minus: ".$_GET['number1']." - ".$_GET['number2']." = ".$result;
} else if (isset($_GET['multiply'])) {
$result = $_GET['number1'] * $_GET['number2'];
echo "Multiply: ".$_GET['number1']." * ".$_GET['number2']." = ".$result;
} else if (isset($_GET['divide'])) {
$result = $_GET['number1'] / $_GET['number2'];
echo "Divide: ".$_GET['number1']." / ".$_GET['number2']." = ".$result;
}
} else {
echo "Invalid input";
}
echo "</div>";
}
?>
</body>
</html>
The solution of DaveRandom works fine if you change this
action="simple_calculator.php"
by
action="<?php echo $_SERVER['PHP_SELF'] ?>"