PHP - OOP class extend - php

Question

Been searching all around but still cannot find a solution for this problem.
My problem is that i got these snips of code(Examples):
Core file
class Core {
public $DB = null;
public $Handler = null;
function run() {
$this->DB = "somedatabase";
include_once('handler.php');
$this->Handler = new Handler;
$this->Handler->run();
}
}
This is the helper.php example
class Handler extends Core {
function run() {
echo "<pre>"; print_r($this); echo "</pre>"; die();
}
}
Even tho i defined the DB variable before i include the helper then it is still empty inside the helper class. It's defined yes but it's empty. Which means it properly doesn't share the same memory as the Core class.
Keep in mind that the Core class it self is instanced too.
-
Thanks for all suggestions
Edit
PhpMyCoder got it right. Thank you for the detailed and well written reply.
For over 2 years i been seeing PHP scopes as being the same or sorta the same as JavaScript's scope. Now i realize that if i extend my "Core" class i get all the methods and properties within it. But the values is private to my class and my class alone.
This is great. Finally i got it.

Answer 1

From what I gather here you are talking about public instance variables. They are performing as OOP would require. Each time you instantiate a class with
$core = new Core(); // or
$handler = new Handler();
Each of them gets a fresh space in memory to store their instance variables. Instance variables are unique to each instance of a class, as the name would suggest. So, two separate instances of Core and Handler do not share instance variables. However since Handler extends Core, two instances of Core are created. One instance is the one that I created on the first line. The other is created so that Handler can extend it on the second line. These two instances of Core are not the same object. To have the same values for Core across all core objects you will need to use static (class) variables.
class Core {
public static $hello = 'World';
}
var_dump(Core::$hello); //string('Word')
In my example, $hello will always be available to everyone by accessing it with the scope resolution operator, ::. So Handler could access it with either Core::$hello or parent::$hello. If you wanted to only expose this static variable to Core and its subclasses, then you would need to make it protected and access it from within Core with self::$hello and from its subclasses with parent::$hello.
class Core {
protected static $hello = 'World';
public function sayHello() {
echo 'Hello '.self::$hello; //from within Core, access with `self`
}
}
class Handler extends Core {
public function myParentSays() {
echo 'My parent says: Hello '.parent::$hello;
}
}
$core = new Core();
$core->sayHello(); // 'Hello World'
$handler = new Handler();
$handler->myParentSays(); // 'My parent says: Hello World'
Check the PHP docs for more on the static keyword and the scope resolution operator.
EDIT
I believe your confusion lies in a misunderstanding of how inheritance works in OOP so let me give you a little real-world-ish example. Let's say you create a class for employees called Employee. This class has a public instance variable (that is, one that can be accessed with ->) for the name of the person. In PHP this would be:
class Employee {
public $name;
public __construct($name) {
$this->name = $name;
}
}
Now let's create a new employee:
$tim = new Employee('Tim');
Let's say that we need a new class, Intern, that should subclass Employee. That should be easy enough:
class Intern extends Employee {
public function makeCoffee(Employee $receiver) {}
}
If we create a new intern now, should his name be Time just because we have already created another employee named Tim? No. That doesn't make sense.
$intern = new Intern();
var_dump($intern->name); //string(0) ""
Now say that setting the name was some complicated and arduous process and we'd rather not have to code it again. With a little modification to our Intern class we can leave the name setting to its superclass, Employee.
class Intern {
public function __construct($name) {
parent::__construct($name);
}
public function makeCoffee(Employee $receiver) {}
}
Now we can create a new intern and set his or her name. Notice how the other Employee keeps his name.
$intern = new Intern('Something Forgettable');
var_dump($intern->name); // string(21) "Something Forgettable"
var_dump($employee->name); // string(3) "Tim"
Now why is this? In OOP, a subclass/superclass is an "is a" relationship. The Intern "is an" Employee. The Intern has all the same properties and methods as an Employee but because each Intern and Employee are distinct they have their own values for these properties.
With this in mind, I suggest you rethink your strategy for your classes. Does it really make sense that Handler is a Core? Does it make sense that MainController is a Handler?

Answer 2

Classes don't share memory unless you pass a reference to them. When you make an instance of a class (an object), it is unique. You could have:
$a = new Core();
$b = new Core();
$a->var1 = 'foo';
$b->var1 = 'bar';
echo $a->var1; // 'foo'
echo $b->var1; // 'bar'
The same holds for extending a class. It doesn't explicitly share the values of the fields, it just shares their existence/visibility.
To share the value, you would do something more like this:
$a = new Core();
$b = new Core();
$c = 'foo';
$a->var1 = &$c;
$b->var1 = &$c;
echo $a->var1; // 'foo'
$b->var1 = 'bar';
echo $a->var1; // 'bar'
$c = 'baz';
echo $a->var1; // 'baz'

Answer 3

Variables are only set on objects (class instances). Don't confuse classes with objects.
If you want to have variables bound to classes, use the static keyword:
class Core {
public static $static = 'abc';
public $instance = 'xyz';
}
Core::$static = 'x';
$core = new Core();
$core->instance = 'a';

Answer 4

In PHP, classes are extended, not objects. This is class:
class SomeClass{
// ...
}
And this is object:
$object = new SomeClass();
So, when your are extending some class, all its protected/public properties are become available to child class.