my post doesn't insert in my database - php

Question

I am creating a facebook like posting system..
My problem today is it doesn't seem to insert the value i get from the text area into my data base..
here is my java script:
$("#share").click(function()
{
//var typeNew = document.getElementById("content").value;
var update = $( "textarea#content" ).val();
//document.write(update);
if(update.length == 0)
{
alert("empty, please type something.");
//$(this).html('<meta http-equiv=\"Refresh\" content=\"1; URL=insert.php\">');
}
else
{
//$("#flash").show();
$("#flash").html('<img src="loader.gif" />Loading Comment...').fadeIn("slow");
$.ajax({
type: "POST",
url: "post_update.php",
data: 'update=' + update,
success: function(msg)
{
$("#flash").ajaxComplete(function(event, request, settings){
//alert("Successfully Inserted")
$("#flash").hide();
//$(this).html('<meta http-equiv=\"Refresh\" content=\"1; URL=insert.php\">');
});
}
});
}
return false;
});
then here is my php code:
<?php
$post=$_REQUEST['update'];
$post=$_POST['update'];
//echo '$post';
# $db = new mysqli('localhost', 'root', '', 'wall');
if(mysqli_connect_errno())
{
echo "Error! Could not connect to database. Reset fields.";
exit;
}
$sql = "INSERT INTO posts(update,date_posted) VALUES('$post',NOW())";
$result = $db->query($sql);
if($result){
echo 'OK';
}
else{
echo 'FAIL';
}
$db->close();
?>
can someone tell me what's wrong?
it worked well when the delete function was in error but now that it's functional my share function does not work..

Answer 1

In your PHP code you have the following lines:
$post=$_REQUEST['update'];
$post=$_POST['update'];
You shouldn't have these both. In Your case, You actually need only the second one but for testing, try commenting it out leaving only the $_REQUEST line. Now you can pass parameters by GET too.
To see, if the query is correct, print it out too like this:
echo $sql = "INSERT INTO posts(update,date_posted) VALUES('$post',NOW())";
Now direct your browser to that location your.domain/post_update.php?update=testmessage and see the output.
If everything seems to be working, replace the POST/REQUEST lines with this:
$post=$db->real_escape_string($_POST["update"]);

Answer 2

I ran into this the other day. Use autocommit or start and commit transactions. Also, try a semicolon at the end of your statement (probably not the issue).
http://dev.mysql.com/doc/refman/5.0/en/commit.html

Answer 3

If your $post is coming out to be fine then try:
$post = $db->real_escape_string($_POST["update"]);
if (!db->query("INSERT INTO posts(update,date_posted) VALUES('$post' ,NOW())")) {
echo $db->sqlstate; //show error
}
else {
echo "inserted";
}

Answer 4

Assuming the column type of update is varchar / charand date_posted is datetime:
$sql = sprintf("INSERT INTO posts(update,date_posted) VALUES('%s',NOW())",
mysql_real_escape_string($post));
$result = $db->query($sql);

Answer 5

Please change the column name "update" to anyother. it may works. And Avoid some predefined varibales for column names.
Hope it helps.