JQuery AJAX update a textbox on another textbox textchanged - php

Question

I would like to update my input text type (id="textbox2") when i typed something at another input text type (id="textbox1").
Here's my initial code:
$("#textbox1").keyup(function(){
$.ajax({
type: "POST",
url: "idgetter.php",
data: 'id='+$("#textbox1").val(),
success: function(n) {
$('#textbox2').val(n);
},
error: function(n) {
$('#textbox2').val(n);
}
});
});
And my idgetter.php :
include("inc/conn.php");
$q = mysql_query("SELECT name FROM jurnalis WHERE userid = '".$_POST['id']."'")or trigger_error("SQL", E_USER_ERROR);
if(mysql_num_rows($q)<=0) return "none";
else{
$r = mysql_fetch_array($q);
return $r["name"];
Long story short, this did not work, any idea why?

Answer 1

In idgetter.php, Instead of returning using return give
echo "none";
and
echo $r["name"];

Answer 2

You should try echo instead of return:
your code would be like this:
include("inc/conn.php");
$q = mysql_query("SELECT name FROM jurnalis WHERE userid = '".$_POST['id']."'")or trigger_error("SQL", E_USER_ERROR);
if(mysql_num_rows($q)<=0) echo "none";
else{
$r = mysql_fetch_array($q);
echo $r["name"];

Answer 3

Think there are a few amends needed in your php:
change return to echo (like stated in the other answers)
change your if statement to
if(mysql_num_rows($q)==0){
echo 'none';
}else{
$r = mysql_fetch_assoc($q);
echo $r['name'];
}
That should do it hopefully. Also as an FYI its worth trying to avoid adding $_POST[''] items to SQL statements directly, as its prone to SQL injection breaches.