I know this question has been asked before, but I tried eveything and can't find how it works.
I have a prepared query, and I need to use it twice with two while() loops like this:
$query = $pdo->prepare('SELECT ...');
$query->execute();
while( $results = $query->fetch() ){
// instructions
}
// rewind
while( $results = $query->fetch() ){
// instructions
}
Thanks
To expand on above answer, you could use:
$results = $query->fetchAll();
$results now being an array containing the result set, so:
foreach ($results as $row) ...
Alternatively with MySQL, you can use buffered queries:
$stmt = $db->prepare('SELECT ...', array(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => true));
The fetchAll() method will be database vendor independent, but will have higher memory requirements.
Could be as simple as getting all the results on the 1st iteration and loop on the 2nd:
$res = array();
while( $results = $query->fetch() ){
$res[] = $results;
// instructions
}
foreach($res as $results){
// instructions
}
Related
Here is the code
$exec = "EXEC RPT_TEST_2resultSet";
$resultSet = \DB::select($exec);
SP is returning 3 result sets. But in php it prints first set of result set only. How to fetch the other 2 set of result sets? Tried the solution suggested by others. Was getting some other errors.
Make a foreach
check example:
foreach ($resultSet as $result) {
echo $result['someDataFromResult'];
}
This will repeat for the amount of data is in the $resultSet array
Found the simple solution for this problem.
$pdo = \DB::connection()->getPdo();
$sql = 'EXEC Test_SP_MultiResultSet';
$stmt = $pdo->query($sql);
do {
$rows = $stmt->fetchAll(\PDO::FETCH_NUM); // Keys will be start from zero , one, two
$rows = $stmt->fetchAll(\PDO::FETCH_ASSOC); // Column names will be assigned for each value
if ($rows) {
$sheetData[] = $rows;
}
} while ($stmt->nextRowset());
Source Link
I believe I am using the PDO fetch functions completely wrong. Here is what I am trying to do:
Query a row, get the results, use a helper function to process the results into an array.
Query
function userName($db){
$q = $db->prepare("SELECT id, name FROM users WHERE id = :user");
$q->bindParam(":user", $user);
$q->execute();
$qr = $q->fetchAll(PDO::FETCH_ASSOC);
if ($qr->rowCount() > 0){
foreach($qr as $row){
$names[$row['id']] = buildArray($row);
}
return $names;
}
}
My custom array building function
function buildArray($row){
$usernames = array();
if(isset($row['id'])) $usernames['id'] = $row['id'];
if(isset($row['name'])) $usernames['name'] = $row['name'];
}
I'm actually getting exactly what I want from this, but when I echo inbetween I see that things are looping 3 times instead of once. I think I am misusing fetchAll.
Any help appreciated
If you're going to build a new array, there's not much point in having fetchAll() build an array. Write your own fetch() loop:
function userName($db){
$q = $db->prepare("SELECT id, name FROM users WHERE id = :user");
$q->bindParam(":user", $user);
$q->execute();
$names = array();
while ($row = $q->fetch(PDO::FETCH_ASSOC)) {
$names[$row['id']] = $row;
}
return $names;
}
There's also no need for buildArray(), since $row is already the associative array you want.
I am querying like this, in snippet below 1st loop takes column names and second loops push values in another array(i know this may not be an optimal way but this is what came in my mind and is solving my task). The problem is
$results = '';
$dataArray = array();
$columns_array = array();
$dataArray = array();
$results = mysqli_query($mysqli, ("SELECT
DISTINCT states_drg.`Provider State`,
SUM(states_drg.`Total Discharges`) AS discharges
FROM states_drg
GROUP BY states_drg.`Provider State`")
);
$columns_names = mysqli_fetch_assoc($results);
foreach ($columns_names as $key => $value) {
array_push($columns_array, $key);
}
array_push($dataArray, $columns_array);
foreach ($results as $result) {
array_push($dataArray, mysqli_fetch_row($results));
}
print_r($dataArray);
echo json_encode($dataArray, JSON_NUMERIC_CHECK);
exit;
);
Query runs absolutely fine in query browser, but when I take dump of print_r($dataArray); I get only 26 records where as I have around 51 records in total if I run the Query in Query Browser.
You're using mysqli totally wrong.
foreach($results as $result)
is NOT how you fetch data from a query result. You should have
while($row = mysqli_fetch_assoc($result)) {
$dataArray[] = $row;
}
And not to mention the multiple syntax errors in your pasted code...
Can anybody tell me why not all the results for MySQL aren't ending up in the array?
$result = mysql_query("select * from groups order by id desc");
if ($row = $result->fetch()) {
$groups[] = $row;
}
Use while not if
while ($row = $result->fetch()) {
$groups[] = $row;
}
The code you have there does not iterate over the result set.
Try this instead.
while ($row = $result->fetch()) {
$groups[] = $row;
}
Because fetch only fetches a row as explained in the php manual:
Fetches the next row from a result set
I'd like to suggest changing your mysql_ code for PDO
$db = new PDO("..."); // Creates the PDO object. Put the right arguments for your connection.
$statement = $db->prepare("SELECT * FROM groups ORDER BY id DESC");
$statement->execute();
while ($groups = $statement->fetch())
{
// Do whatever you want to do
}
I have this sample query:
$STH = $DBH->query("SELECT id FROM table");
I want to get the first row and then loop and display all rows. So I use the following to get the first row:
$STH->setFetchMode(PDO::FETCH_ASSOC);
$first_row = $STH->fetch();
$first_row = $first_row['id'];
I use while loop to display all rows again:
while ($list = $STH->fetch()) {
$id = $list['id'];
echo $id;
}
Now the while skips the first row and I want it to be displayed. Is there an equivalent to mysql_data_seek to reset the pointer again to the first row? I know fetchall can be used but it's bad on memory and wasteful. I could also run the query and limit to 1 but this is not recommended as I have a query that joins multiple tables and would be very slow. Is there any other solution?
Thanks
I take that back looks like you can use the cursor orientation contants to select the result... sample code coming... I havent tried this so you may need to play a bit. This is also based on the assumption that a PDO::FETCH_ORI_FIRST acts like a data_seek and leaves the cursor on the first position as opposed to returning it to whatever it was before.
$stmt = $pdo->prepare('SELECT id FROM table', array(PDO::ATTR_CURSOR => PDO::CURSOR_SCROLL));
$stmt->execute();
$first = $pdo->fetch(PDO::FETCH_ASSOC, PDO::FETCH_ORI_FIRST);
$first_row = $first['id'];
// other stuff
// first iteration we rewind to the first record;
$cursor = PDO::FETCH_ORI_FIRST;
while (false !== ($row = $stmt->fetch(PDO::FETCH_ASSOC, $cursor))) {
$id = $row['id'];
// successive iterations we hit the "next" record
$cursor = PDO::FETCH_ORI_NEXT;
echo $id;
}
I dont think you can rewind a statement... Assuming these blocks arent seprated by a bunch of intermediary logic id just do it in the loop.
$STH->setFetchMode(PDO::FETCH_COLUMN); // no need to pull an array
$count = 0;
while ($id = $STH->fetch()) {
if($count === 0) {
$first_row = $id;
}
echo $id;
$count++;
}
Could you just use a do...while loop instead?
$STH->setFetchMode(PDO::FETCH_ASSOC);
$list = $STH->fetch();
$first_id = $list['id'];
do {
$id = $list['id'];
echo $id;
} while ($list = $STH->fetch());
You can fetch all the result, and then just act on it as an array. So, for instance, you could shift the first result off the front, and then loop over any additional rows:
<?php
$sql = "YOUR QUERY";
$stmt = $pdo->prepare($sql);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
// get first row
$firstRow = array_shift($rows);
// loop over remaining rows
foreach ($rows as $row) {
// do something
}