How to fetch 2 times in MYSQL PDO without FETCHALL - php

I have this sample query:
$STH = $DBH->query("SELECT id FROM table");
I want to get the first row and then loop and display all rows. So I use the following to get the first row:
$STH->setFetchMode(PDO::FETCH_ASSOC);
$first_row = $STH->fetch();
$first_row = $first_row['id'];
I use while loop to display all rows again:
while ($list = $STH->fetch()) {
$id = $list['id'];
echo $id;
}
Now the while skips the first row and I want it to be displayed. Is there an equivalent to mysql_data_seek to reset the pointer again to the first row? I know fetchall can be used but it's bad on memory and wasteful. I could also run the query and limit to 1 but this is not recommended as I have a query that joins multiple tables and would be very slow. Is there any other solution?
Thanks

I take that back looks like you can use the cursor orientation contants to select the result... sample code coming... I havent tried this so you may need to play a bit. This is also based on the assumption that a PDO::FETCH_ORI_FIRST acts like a data_seek and leaves the cursor on the first position as opposed to returning it to whatever it was before.
$stmt = $pdo->prepare('SELECT id FROM table', array(PDO::ATTR_CURSOR => PDO::CURSOR_SCROLL));
$stmt->execute();
$first = $pdo->fetch(PDO::FETCH_ASSOC, PDO::FETCH_ORI_FIRST);
$first_row = $first['id'];
// other stuff
// first iteration we rewind to the first record;
$cursor = PDO::FETCH_ORI_FIRST;
while (false !== ($row = $stmt->fetch(PDO::FETCH_ASSOC, $cursor))) {
$id = $row['id'];
// successive iterations we hit the "next" record
$cursor = PDO::FETCH_ORI_NEXT;
echo $id;
}
I dont think you can rewind a statement... Assuming these blocks arent seprated by a bunch of intermediary logic id just do it in the loop.
$STH->setFetchMode(PDO::FETCH_COLUMN); // no need to pull an array
$count = 0;
while ($id = $STH->fetch()) {
if($count === 0) {
$first_row = $id;
}
echo $id;
$count++;
}

Could you just use a do...while loop instead?
$STH->setFetchMode(PDO::FETCH_ASSOC);
$list = $STH->fetch();
$first_id = $list['id'];
do {
$id = $list['id'];
echo $id;
} while ($list = $STH->fetch());

You can fetch all the result, and then just act on it as an array. So, for instance, you could shift the first result off the front, and then loop over any additional rows:
<?php
$sql = "YOUR QUERY";
$stmt = $pdo->prepare($sql);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
// get first row
$firstRow = array_shift($rows);
// loop over remaining rows
foreach ($rows as $row) {
// do something
}

Related

After fetching data from MySQL database fetching column data from nth row and assigning to variable

So I have fetched data from a MySQL database and I want to assign it to a variable based on an nth row. Only the bottom three rows are filtered and I want to assign values from the firs and last row to two variables.
$sql3 = "SELECT * FROM login_attempts WHERE login_attempt_user_id=? AND login_attempt_result=? ORDER BY login_attempt_id DESC LIMIT 3;";
$stmt3 = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($stmt3, $sql3)) {
echo 6;
exit();
} else {
mysqli_stmt_bind_param($stmt3, "ss", $login_attempt_user_id, $login_attempt_success);
mysqli_stmt_execute($stmt3);
$result2 = mysqli_stmt_get_result($stmt3);
if (mysqli_num_rows($result2) > 0) {
while ($row2 = mysqli_fetch_assoc($result2)) {
$test1 = $row2['login_attempt_time'][0];
$test2 = $row2['login_attempt_time'][2];
echo $test1.$test2;
exit();
}
} else {
//echo 4;
exit();
}
}
The section of code is within the while loop and I realize that what I am attempting is for arrays. I want to do something similar to achieve my goal.
My code is not assigning the database entry to the variable: $test = $row2['login_attempt_time'] assigns the last value of the fetched row, however $test = $row2['login_attempt_time'][0] only returns the value 1.
Would anyone please be able to help with this?
Fetch all (three) rows into an array (2-dimensional) with mysqli::fetch_all(). Then get the first and the last elements (rows) with reset() and end().
Change
while ($row2 = mysqli_fetch_assoc($result2)) {
$test1 = $row2['login_attempt_time'][0];
$test2 = $row2['login_attempt_time'][2];
echo $test1.$test2;
exit();
}
to
$data = $result2->fetch_all(MYSQLI_ASSOC);
$variable1 = reset($data); // first row
$variable2 = end($data); // last row
Remember, this mysqli_fetch_assoc($result2)) will fetch one row from the database. So the first time, $row2 will be the contents of the first row, the second time $row2 is the second row, etc. Perhaps add a counter to the loop to know when to populate $test1 and $test2, as with an if condition.

How can I get this php to return the entire column of an sql db

I am trying to query a db for an entire column of data, but can't seem to get back more than the first row.
What I have so far is:
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_fetch_array($medicationItemObj, MYSQLI_NUM)){
echo count($row);
}
It's not my intention to just get the number of rows, I just have that there to see how many it was returning and it kept spitting out 1.
When I run the sql at cmd line I get back the full result. 6 items from 6 individual rows. Is mysqli_fetch_array() not designed to do this?
Well, I had a hard time understanding your question but i guess you are looking for this.
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_num_rows($medicationItemObj))
{
echo $row;
}
Or
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
$i = 0;
while ($row = mysqli_fetch_array($medicationItemObj))
{
$medicationItem[] = $row[0];
$i++;
}
echo "Number of Rows: " . $i;
If you just want the number of rows i would suggest using the first method.
http://php.net/manual/en/mysqli-result.num-rows.php
You can wrote your code like below
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
while ($row = mysqli_fetch_assoc($medicationItemObj))
{
echo $row['medication'];
}
I think this you want
You could give this a try:
$results = mysqli_fetch_all($medicationItemObj, MYSQLI_NUM);
First, I would use the object oriented version of this and always use prepared statements!
//prepare SELECT statement
$medicationItemSQL=$connection->prepare("SELECT medication FROM medication");
// execute statement
$medicationItemSQL->execute();
//bind results to a variable
$medicationItemSQL->bind_result($medication);
//fetch data
$medicationItemSQL->fetch();
//close statement
$medicationItemSQL->close();
You can use mysqli_fetch_assoc() as below.
while ($row = mysqli_fetch_assoc($medicationItemObj)) {
echo $row['medication'];
}

fetch data from mysql in php does not work

I'm doing sth like this:
$q3 = $conn3->prepare("SELECT...");
$q3->bindParam(':param1', $param1);
$q3->execute();
$check3 = $q3->fetchAll(PDO::FETCH_ASSOC);
if (!empty($check3)){
$arr = array();
while($row = $q3->fetch(PDO::FETCH_ASSOC)) {
$arr[] = $row;
}
}
but I don't see the data in arr[] later on. What exactly am I doing wrong here? Is there a better way to fetch the data from mysql to an array in php?
fetch() returns the next row in the set. fetchAll() will fetch all the (remaining) rows and move the pointer to the last row, therefore fetch() after fetchAll() will not return anything because there will not be a next row in the set.
You need one or the other. To take advantage of fetchAll you could do:
$check3 = $q3->fetchAll(PDO::FETCH_ASSOC);
foreach ($check3 as $row) {
}
or just use fetch without fetchAll:
while ($row = $q3->fetch(PDO::FETCH_ASSOC)) {
}
Your code, as is, makes the fetch() useless. You could just do:
$arr = $q3->fetchAll(PDO::FETCH_ASSOC);
Which is equivalent to:
$arr = array();
while($row = $q3->fetch(PDO::FETCH_ASSOC)) {
$arr[] = $row;
}
}

MySQL results issue in php array

Can anybody tell me why not all the results for MySQL aren't ending up in the array?
$result = mysql_query("select * from groups order by id desc");
if ($row = $result->fetch()) {
$groups[] = $row;
}
Use while not if
while ($row = $result->fetch()) {
$groups[] = $row;
}
The code you have there does not iterate over the result set.
Try this instead.
while ($row = $result->fetch()) { 
$groups[] = $row;
}
Because fetch only fetches a row as explained in the php manual:
Fetches the next row from a result set
I'd like to suggest changing your mysql_ code for PDO
$db = new PDO("..."); // Creates the PDO object. Put the right arguments for your connection.
$statement = $db->prepare("SELECT * FROM groups ORDER BY id DESC");
$statement->execute();
while ($groups = $statement->fetch())
{
// Do whatever you want to do
}

php mysqli stmt

i'm new to the php mysql usage. i'm selecting the results from database .. and i'm cycling/printing them out to the screen using while($stmt->fetch()): .. what i'd like to do is to cycle through the results again after the first cycle without calling the database (frombuffered results set).
i'm using php5, mysqli, stms on xampp server.
while($row = $stmt->fetch()){
$storedRows[] = $row;
//do stuff
}
foreach($storedRows as $row){
//do more stuff
}
You can use arrays.
When you cycle through the result for the first time you can put the values in the array and later in the 2nd cycle you can access the elements from the array.
Something like:
$query = "SELECT name FROM EMP";
$arr = array();
if ($stmt = $mysqli->prepare($query)) {
$stmt->execute();
$stmt->bind_result($name);
// 1st cycle.
while ($stmt->fetch()) {
$arr[] = $name; // save in array.
}
$stmt->close();
// 2nd cycle.
foreach($arr as $name) {
// use $name again.
}
}

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