I have a table with php values (table.php )retrieve from mysql database.
I want to insert this particular value into another database with the insertion code inside another php file (admin.php)
How should I go about doing it?
Code from table.php
<tr>
<td class="brack_under cell_1">
<?php
$row = mysql_fetch_row($data);
echo "<a>".$row[2]."</a>";
?>
</td>
<td class="cell_2"> </td>
<td class="cell_3"> </td>
<td class="cell_4"> </td>
<td class="cell_5"> </td>
<td class="cell_6"> </td>
</tr>
Code from admin.php
<?php
it is something like : $a = $_POST[ $row[2] ]; ???
$sql="INSERT INTO matchTable (schInitial, schName,position)VALUES
('$_POST[ $row[1] ]','$_POST[$row[2] ]','top8')";
mysql_close($con)
?>
According to the comment discussion and your comments, I'm gonna try to help you a bit here (hopefully I got the point)
You need to POST a <form ...> to your script. Unless you do that, there is no $_POST available. E.g.:
<form method="post" action="myscript.php">
<input type="hidden" name="some_var" value="player1" />
<input type="submit" />
</form>
This gives the following in myscript.php where you can do your filtering and insertion and stuff.
print_r($_POST);
// output: array( 'some_var' => 'player1' );
Which means, according to your tries (and to keep it understandable)
$a = $_POST['some_var']
// $a is now 'player1'
So, the only thing you need to do: create a form beneath your table, put some hidden fields in it with data you need to do your math things, and put a submit button in it.
Related
I have a dynamic table which is set inside a foreach, so for each item of the array fetched create a new row. I have in the last column a button for each row. When clicking that submit button I am suppose to receive the id of that in PHP. Submission is being done correctly, but I am receiving the wrong id in PHP. Its basically taking the last id of the array when submitting. Any idea why?
Here is the table:
<form method="post" id="frm-example" action="<?php echo $_SERVER["PHP_SELF"] . '?' . e(http_build_query($_GET)); ?>">
<table id="example" class="display compact">
<thead>
<th>Device</th>
<th>Sales date</th>
<th>Client comments</th>
<th>Breakage count</th>
</thead>
<tbody>
<?php foreach ($arr_cases_devices as $cases) { ?>
<tr>
<td>
<?php echo $cases['name']; ?>
</td>
<td>
<?php echo $cases["sales_date"]; ?>
</td>
<td>
<?php echo $cases["dev_comment"]; ?>
</td>
<td>
<input type="hidden" name="device_id_breakage" value="<?php echo $cases["Dev_Id"]; ?>" />
<button type="submit" name="see_rma">See RMA</button>
</td>
</tr>
<?php } ?>
</tbody>
</table>
</form>
When clicking on see_rma this is what I receive in PHP:
if (isset($_POST['see_rma'])) {
$selected_dev = e($_POST['device_id_breakage']);
print_r($selected_dev); // prints the "Dev_Id" of the last row, not of the row clicked
}
If I try printing $cases["Dev_Id"]; inside loop in the table, it prints perfectly fine, so it prints the Dev_Id of each row correctly. So, that means there is nothing wrong with the array or data. I don't why is this happening but it's for sure the first time I am having this issue.
I do this in many other tables but for some reasons in this one its not working properly.
You have multiple <input> elements with the same name within your form, and all of them are going to be submitted when you submit the form, but PHP can only get one of them. That's why you end up with only the last one in $_POST.
It looks like you should be able to fix this by just moving some attributes from the hidden input into the button (replacing the hidden input).
<button type="submit" name="device_id_breakage" value="<?php echo $cases["Dev_Id"]; ?>">
See RMA
</button>
Only the button that was clicked will be submitted. Note that after changing the name of the button, you won't have see_rma in $_POST any more, so if you have any code that depends on that you'll need to change it to look for the other name instead.
I have created a simple HTML form containing just one field. When I press submit some PHP code that I have written gets called and outputs text that would include submitted data if everything was working. But no submitted text gets printed by the PHP. The form has been created on a Godaddy HTML page and the form is as follows:
<FORM BORDER="1" action="http://www.bestpro.com.au/wordpress/PHB_action.php"
method="post" enctype="application/x-www-form-urlencoded"
eenctype="multipart/form-data" name="PHBForm" accept-charset="ISO-8859-1"
ienctype="text/plain">
<TABLE>
<TR>
<TD>First name:</TD><TD><INPUT type="text" name="firstname" id="firstname"></TD>
<TD></TD><TD></TD>
<TD> </TD><TD> </TD>
</TR>
<TR>
<TD> </TD><TD> </TD>
<TD> </TD><TD></TD>
<TD> </TD><TD><input type="submit" value="Submit"></TD>
</TABLE>
</FORM>
The PHP code output starts as follows:
This is where we end up.
Using `$_POST["firstname"]` which outputs nothing.
Using `htmlspecialchars($_POST["firstname"])` which also outputs nothing.
Question:
The PHP output doesn't include the value that I entered into the field.
Can anyone see what I am doing incorrectly?
I see nothing wrong here, so I can only assume it is something wrong with how you output it on your PHB_action.php page.
You say that you're placing $_POST['firstname'] on your page, but have you actually made sure to echo or print it to the page?
You can do this like so:
echo $firstname = $_POST['firstname']; // notice the echo placed before
or
$firstname = $_POST['firstname'];
print("$firstname");
EDIT:
I've notice you have put your post data inside of single quotation marks when echoing out to your page.
You must concatenate on your data rather than putting them inside of single quotes when echoing, like so:
echo 'Using' . $_POST['firstname']; // notice the dot in between the string and the post data.
Either that, or you have not installed PHP correctly (or at all) onto your server.
Hope this helps
So, this is pretty straight forward and I have written it up and will explain each bit as i go.
The PHP you need for this is:
<?php
if (isset($_POST['send']))
{
$fname = $_POST['firstName'];
if (!empty($fname))
{
echo "hello $fname";
} else {
echo "Please supply your first name.";
}
}
?>
$_POST['send'] is the name of your submit button, this will be the trigger for your PHP to initiate and run through the rest of the code.
$fname = $_POST['firstName']
This is just where I prefer to store the $_POST as a variable in the event you are going to re use it again it saves time writing the entire thing.
if(!empty)
if the username isn't empty (!empty meaning not empty) then perform the echo of $fname. however if it comes back as empty it will echo the else echo "please supply...;
Now for the form.
<form action="" method="post">
<table>
<tr>
<td>First Name:</td>
<td><input type="text" name="firstName"></td>
</tr>
<tr>
<td><input type="submit" name="send"></td>
</tr>
</table>
</form>
Just a straight forward form with a blank action on mine (I prefer to keep the PHP within the same file however I normally relay it back to a Class within a different file.
Each form input (First Name / Submit) must have a name="" value otherwise the PHP cannot read it and run with it.
I hope this makes sense and isn't too puzzling :)
Your input field should be inside tag and method should be post. Like:
<html>
<body>
<Form method=post>
<input id=mytextfield name=mytextfield type=text />
<input type=submit value=Submit />
</Form>
</body>
</html>
Sorry I'm a bit of a noob when it comes to PHP but I just wondered if someone had an idea on how I could solve this PHP/SQL problem.
I have a PDO statement that gets all users from a database.
With the array of users from the database I create a foreach loop to display all of the users in a table which I want to use to select a specific user, enter a number in the row of the user I select, then click submit and store the users name and also the number. I will use this information to populate another database later.
My question is, I cant seem to reference the user or the number in the table to extract the user and number I enter. When I try and request the numbered entered in the index.php, it will only ever display a number if I enter a number for a the final user in the table. When I try and view the FullName it never works and I get 'Undefined index: FullName' error.
I also specified to 'POST in the form but it doesnt seem to be doing that.
Does anyone have any ideas?
Thanks
//function.php
function getName($tableName, $conn)
{
try {
$result = $conn->query("SELECT * FROM $tableName");
return ( $result->rowCount() > 0)
? $result
: false;
} catch(Exception $e) {
return false;
}
}
//form.php
<form action "index.php" method "POST" name='form1'>
<table border="1" style="width:600px">
<tr>
<th>Name</th>
<th>Number Entered</th>
<tr/>
<tr>
<?php foreach($users as $user) : ?>
<td width="30%" name="FullName">
<?php echo $user['FullName']; ?>
</td>
<td width="30%">
<input type="int" name="NumberedEntered">
</td>
</tr>
<?php endforeach; ?>
</table>
<input type="submit" value="submit"></td>
</form>
//index.php
$users = getName('users', $conn);
if ( $_REQUEST['NumberedEntered']) {
echo $_REQUEST['NumberedEntered'];
echo $_REQUEST['FullName'];
}
The variable FullName isn't transmitted by your form to index.php. Only values of form elemnts are sent. You can add a hidden form field, that contains FullName like this:
<input type="hidden" name="FullName" value="<?php echo $user['FullName']">
But your second problem is, that your foreach loop will create several input fields with the exact same name. You won't be able to recieve any of the entered numbers, except the last one. have a look at this question for possible solutions.
Update
Putting each row in individual form tags should solve your problem:
<?php foreach($users as $user) : ?>
<form action="index.php" method="POST">
<tr>
<td align="center" width="40%" >
<?php echo $user['FullName']; ?>
<input type="hidden" name="FullName" value="<?php echo $user['FullName']; ?>" />
</td>
<td width="30%">
<input name="NumberedEntered"/>
</td>
<td>
<input type="submit" value="submit"/>
</td>
</tr>
</form>
<?php endforeach; ?>
Dunno if the title makes sense, but I have a variable which would to put it in basic terms would be called like this:
$_POST['something'+$variable2]
I have a form which is for editing selected records, this form contains entries for all previously selected records:
<form name="input" action="editcar.php" method="POST">
<input type="submit" value="Yes">
while($row = mysqli_fetch_assoc($result))
{
echo'
</div>
<table style="color:white">
<tr>
<td style="text-align:right">Manufacture:</td><td><input type="text" name="manufacture'.$row['carIndex'].'" value="'.$row['make'].'"></td>
<td style="text-align:right">Model: </td><td><input type="text" name="model'.$row['carIndex'].'" value="'.$row['model'].'"></td>
</tr>
<tr>
<td style="text-align:right">Colour: </td><td><input type="text" name="colour'.$row['carIndex'].'" value="'.$row['colour'].'"></td>
<td style="text-align:right">Reg: </td><td><input type="text" name="reg'.$row['carIndex'].'" value="'.$row['Reg'].'"></td>
</tr>
<tr>
<td style="text-align:right">Price: </td><td><input type="text" name="price'.$row['carIndex'].'" value="'.$row['price'].'"></td>
<td style="text-align:right">Mileage: </td><td><input type="text" name="mileage'.$row['carIndex'].'" value="'.$row['miles'].'"></td>
</tr>
<tr>
<td style="text-align:right">Max MPH: </td><td><input type="text" name="mph'.$row['carIndex'].'" value="'.$row['mph'].'"></td>
<td style="text-align:right">MPG: </td><td><input type="text" name="mpg'.$row['carIndex'].'" value="'.$row['mpg'].'"></td>
</tr>
</table>
</form>
</div> ';
}
?>
</form>
The form is looped for each record previously chosen, to enable mass editing. The isue arouses when I realised I'd have multiple inputs with the same name, so I did:
<input type="text" name="model'.$row['carIndex'].'" value="'.$row['model'].'">
Placing the primary key of the record it was currently tired to on the end of it's name. Which seemed like a logical way to go about things.
However now I need to call these variables to place in the mysql query and I dunno how to do that, or even if I can.
I have the selected records saved in an array so I have:
foreach ($postid as $carID)
{
$query = "stuff";
mysqli_query($db, $query);
}
Each loop has $carID containing the variables that was put on the end of the form input names.
So something like:
$_POST['something'+$variable2]
is all I can think of but doesn't work.
Any method that works for my overall code is welcome not just a solution to the issue I've made.
Actually your way should work. Just replace the + with . in $_POST['something'+$variable2].
My tip is: use an array as name in your html instead:
<input type="text" name="model[]" value="'.$row['model'].'">
On php-Side you can loop through all $_POST['model'] since its an array now.
You can add the index for every entry in your html, too:
<input type="text" name="model['.$row['carIndex'].']" value="'.$row['model'].'">
PHP uses a dot for concatenation, not + like Java and Javascript:
$_POST['something' . $variable2]
Try something like this:
<form ...>
<?php
while($row = mysqli_fetch_assoc(...):
$index = $row['carIndex'];
?>
<input type="text" name="carmodel[<?php echo $index?>][model]" value="<?php echo $row['model'] ?>">
<?php endforeach; ?>
</form>
This way you will have the data stored in $_POST['carmodel'] as an array indexed by carIndex value as the structure of data in $_POST is defined by names of inputs, here you will have names likee carmodel[1][model] for example so then in post it will be in $_POST['carmodel'][1][model]
you can read here as well
How would I create this array structure in an HTML form?
I've been trying to develop a real estate page where people can add listings. I am new to the world of php mysql. I have been over this problem for over a day and can't figure out where the problem is.
I have a form where people can add data. That's good and working. Now I am starting to have a place where people can add / delete / update their info. I am trying to build this step by step.
This is where a user could pull the information. My problem is with the piece of the code:
edit_form.php?idBAR=$row[id].
Full code below.
<table>
<tr>
<td align="center">EDIT DATA</td>
</tr>
<tr>
<td>
<table border="1">
<?php
include"configS_OH.php";//database connection
$order = "SELECT * FROM braaasil_brokerstour.property";
$result = mysql_query($order);
while ($row=mysql_fetch_array($result)){
echo ("<tr><td>$row[id]</td>");
echo ("<td>$row[address]</td>");
echo ("<td>$row[day]</td>");
echo ("<td>$row[hours]</td>");
echo ("<td>Edit</td></tr>");
}
?>
</table>
</td>
</tr>
</table>
Then this tutorial try to pass id through the address bar (I don't know much about php to actually say much)
It tries to upload the data into a new form where a person could edit info.
But I can't load the data into the new form. If I use where id=7, I get the info into the form. But this method of passing the info in the address bar like ?idBAR=8... and then try to catch it in the other code (where id=$idBAR), is not working.
Here is the code:
<table border=1>
<tr>
<td align=center>Form Edit Employees Data</td>
</tr>
<tr>
<td>
<table>
<?php
include "configS_OH.php";//database connection
print $database;
$order = "SELECT * FROM braaasil_brokerstour.property
WHERE id='$idBAR'";
print $idBAR;
$result = mysql_query($order) or die( mysql_error() );
$row = mysql_fetch_array($result);
?>
<form method="post" action="edit_data.php">
<input type="hidden" name="idBAR" value="<?php echo "$row[id]"?>">
<tr>
<td>Address</td>
<td>
<input type="text" name="address"
size="20" value="<?php echo "$row[address]"?>">
</td>
</tr>
<tr>
<td>Date</td>
<td>
<input type="text" name="day" size="40"
value="<?php echo "$row[day]"?>">
</td>
</tr>
<tr>
<td>Time</td>
<td>
<input type="text" name="time" size="40"
value="<?php echo "$row[hours]"?>">
</td>
</tr>
<tr>
<td align="right">
<input type="submit"
name="submit value" value="Edit">
</td>
</tr>
</form>
</table>
</td>
</tr>
</table>
I tried an tried and tried..
Thank you for your time in advance.
WHERE id='$idBAR'
You haven't assigned $idBAR any value. You need to read it from the $_GET array first:
$idBAR = $_GET['idBAR'];
You should, of course, check that this value exists first, and is acceptable.
I don't see anywhere you have actually used the GET data, just the reference name which is used in GET.
If you first query is working and is getting the $row['id'] value ok - you can verify this when you go to edit_form.php, in your browser URL bar at the top, does it say this:
edit_form.php?idBAR=7
(or whatever number should be there)
If so, then you just need to use the PHP GET. Your data is stored in $_GET[], and in this case, the reference name is idBAR. So your id from your previous page query is sent through the link into your URL, and on your edit_form.php page, you'd use that data as:
$_GET['idBAR']
You can use that, but personally I assign the data to a variable, such as:
$strGetId = $_GET['idBAR'];
Then you can use $strGetId throughout your code.
Also, check things like isset(), empty() etc, just so you know you are working with A) something is actually there, and B) it's not empty etc
if you are putting a variable directly in a string without concatenating, it can't be an array variable; you must concatenate those you also need to surr. so this
echo ("<td>Edit</td></tr>");
should be this
echo ("<td>Edit</td></tr>");
also, it looks like your form is sending data with POST. When you pass form data in the url string after the question mark, that is passing with get.
so...in your form where you want to use that variable, you set it up like this
$idBAR=$_GET['idBAR']; //to get the variable if it was part of the URL
$idBAR=$_POST['idBAR']; //if it was sent with post, as is the case with your form
also, request contains both get and post, so
$idBAR=$_REQUEST['idBAR'];
will work in either case.
The problem is the $row[id] is seen as text just like everything else. You want the value of $row[id]. Instead of
echo ("<td>Edit</td></tr>");
try
echo ("<td>Edit</td></tr>");