Sorry I'm a bit of a noob when it comes to PHP but I just wondered if someone had an idea on how I could solve this PHP/SQL problem.
I have a PDO statement that gets all users from a database.
With the array of users from the database I create a foreach loop to display all of the users in a table which I want to use to select a specific user, enter a number in the row of the user I select, then click submit and store the users name and also the number. I will use this information to populate another database later.
My question is, I cant seem to reference the user or the number in the table to extract the user and number I enter. When I try and request the numbered entered in the index.php, it will only ever display a number if I enter a number for a the final user in the table. When I try and view the FullName it never works and I get 'Undefined index: FullName' error.
I also specified to 'POST in the form but it doesnt seem to be doing that.
Does anyone have any ideas?
Thanks
//function.php
function getName($tableName, $conn)
{
try {
$result = $conn->query("SELECT * FROM $tableName");
return ( $result->rowCount() > 0)
? $result
: false;
} catch(Exception $e) {
return false;
}
}
//form.php
<form action "index.php" method "POST" name='form1'>
<table border="1" style="width:600px">
<tr>
<th>Name</th>
<th>Number Entered</th>
<tr/>
<tr>
<?php foreach($users as $user) : ?>
<td width="30%" name="FullName">
<?php echo $user['FullName']; ?>
</td>
<td width="30%">
<input type="int" name="NumberedEntered">
</td>
</tr>
<?php endforeach; ?>
</table>
<input type="submit" value="submit"></td>
</form>
//index.php
$users = getName('users', $conn);
if ( $_REQUEST['NumberedEntered']) {
echo $_REQUEST['NumberedEntered'];
echo $_REQUEST['FullName'];
}
The variable FullName isn't transmitted by your form to index.php. Only values of form elemnts are sent. You can add a hidden form field, that contains FullName like this:
<input type="hidden" name="FullName" value="<?php echo $user['FullName']">
But your second problem is, that your foreach loop will create several input fields with the exact same name. You won't be able to recieve any of the entered numbers, except the last one. have a look at this question for possible solutions.
Update
Putting each row in individual form tags should solve your problem:
<?php foreach($users as $user) : ?>
<form action="index.php" method="POST">
<tr>
<td align="center" width="40%" >
<?php echo $user['FullName']; ?>
<input type="hidden" name="FullName" value="<?php echo $user['FullName']; ?>" />
</td>
<td width="30%">
<input name="NumberedEntered"/>
</td>
<td>
<input type="submit" value="submit"/>
</td>
</tr>
</form>
<?php endforeach; ?>
Related
I am actually starting my newest codes with HTML/PHP .
I am searching for retrieving data (list of persons) from mysql Data Base, displaying it into html table, then when I will clik on button "edit" it will show me in another page the details of the selected person like this :
It works fine for all the rows expects the firt row of the table.
Any help please !!!
there is my code :
<table border = 1>
<caption> Liste des personnes </caption>
<tr>
<th>id </th>
<th>nom</th>
<th>prenom</th>
<th>date Naissance</th>
<th>sexe</th>
<th>ville</th>
<th>comptence</th>
<th>photo</th>
</tr>
<?php while ($obj = mysqli_fetch_object($result)){ ?>
<tr>
<td> <?= $obj->id ?> </td>
<td><?= $obj->nom?></td>
<td><?= $obj->prenom?></td>
<td><?= $obj->dateNaissance?></td>
<td><?= $obj->sexe?></td>
<td><?= $obj->ville?></td>
<td><?= $obj->competence?></td>
<?php if (isset($obj->photo)) {?>
<td><img src="uploads/<?= $obj->photo?>" width =20 height = 20 >
<?php } ?>
<td>
<form name="editPerson" action="edit.php" method="POST">
<input type="hidden" name="id" value="<?= $obj->id ?>">
<input type="submit" name="editer" value="Edit">
</form>
</td>
</tr>
<?php } ?>
</table>
Explainations
You can't have an action='edit.php' as you will edit a specific user, not all of them. You need to specify in your action what user you want to edit. And it is mostly done with the ID of the user. So you action will look like this action='edit.php?id=1. And so, your method would be GET.
In your edit.php, you will have a $_GET['id'] variable that will contain the ID of the user to be edited. So you will have to first create a new query to search for this specific user.
You can then proceed on preparing the query.
$query = $connexion->prepare('SELECT * FROM users WHERE id = :id');
And then, executing the query with the id from the URI.
$query->execute(['id' => $_GET['id']]);
And cast the result to a variable to get the user.
Then, all you have to do in your page is a little bit of refactoring from your previous page. Meaning that there will be now a big <form> tag surrounding your <table> tag and the <td> tag will now contain <input value='<?php $user->id; ?>'> tag for example for the ID. And your edit buttons will now be a save button.
The method of the <form> in your edit?id=1 would be a POST method ot itself. So in the same page, you will be able to update the user. You can also cast the form to another page, like saveUser.php. Just be consistent from one solution to another in all your project.
<form method='POST' action='<?php echo $_SERVER['PHP_SELF']; ?>'>
Use this Code
<input type="submit" name="editer" value="Edit">
Instead of
<form name="editPerson" action="edit.php" method="POST">
<input type="hidden" name="id" value="<?= $obj->id ?>">
<input type="submit" name="editer" value="Edit">
</form>
And get the id value on edit.php file by using $_GET['id'].
Example for edit.php file:
$id = $_GET['id']
I'm having some difficulty with php forms.
I have created a page called 'post_details.php' (this simply displays a photo of a product & description). Each product has a unique id
Within posts_details.php, I have used to include command to include a form. This form allows users to send me feedback regarding the product.
For some reason the form is not workin. Everytime the submit button is clicked, the alert box warns me that I need to complete the form (even if the form is complete)
The last part of line one doesn't seem to work. It's not picking up the post_id
Can anyone please help ??
post a comment
<form method="post" action="post_details.php?post= <?php echo $post_id; ?>">
<table width "600">
<tr>
<td>Your email:</td>
<td><input type="text" name="comment_email"/></td>
</tr>
<tr>
<td>Your Comment:</td>
<td><textarea name="comment" cols="35" rows="16"/></textarea></td>
</tr>
<tr>
<td><input type="submit" name="submit" value="postcom"/></td>
</tr>
</table>
</form>
<?php
if(isset($_POST['comment'] )) {
$comment_email = $POST['comment_email'];
$comment = $POST['comment'];
if( $comment_email=='' OR $comment=='') {
echo "<script>alert('Please complete form')</script>";
echo "<script>window.open('post_details.php?post=post_id')</script>";
exit();
}
else {
echo "complete";
}
}
?>
You have error here
if(isset($_POST['comment'] )) {
$comment_email = $POST['comment_email'];
^
$comment = $POST['comment'];
^
....
Instead of $POST it must be $_POST['comment_email'] and $_POST['comment']
Dunno if the title makes sense, but I have a variable which would to put it in basic terms would be called like this:
$_POST['something'+$variable2]
I have a form which is for editing selected records, this form contains entries for all previously selected records:
<form name="input" action="editcar.php" method="POST">
<input type="submit" value="Yes">
while($row = mysqli_fetch_assoc($result))
{
echo'
</div>
<table style="color:white">
<tr>
<td style="text-align:right">Manufacture:</td><td><input type="text" name="manufacture'.$row['carIndex'].'" value="'.$row['make'].'"></td>
<td style="text-align:right">Model: </td><td><input type="text" name="model'.$row['carIndex'].'" value="'.$row['model'].'"></td>
</tr>
<tr>
<td style="text-align:right">Colour: </td><td><input type="text" name="colour'.$row['carIndex'].'" value="'.$row['colour'].'"></td>
<td style="text-align:right">Reg: </td><td><input type="text" name="reg'.$row['carIndex'].'" value="'.$row['Reg'].'"></td>
</tr>
<tr>
<td style="text-align:right">Price: </td><td><input type="text" name="price'.$row['carIndex'].'" value="'.$row['price'].'"></td>
<td style="text-align:right">Mileage: </td><td><input type="text" name="mileage'.$row['carIndex'].'" value="'.$row['miles'].'"></td>
</tr>
<tr>
<td style="text-align:right">Max MPH: </td><td><input type="text" name="mph'.$row['carIndex'].'" value="'.$row['mph'].'"></td>
<td style="text-align:right">MPG: </td><td><input type="text" name="mpg'.$row['carIndex'].'" value="'.$row['mpg'].'"></td>
</tr>
</table>
</form>
</div> ';
}
?>
</form>
The form is looped for each record previously chosen, to enable mass editing. The isue arouses when I realised I'd have multiple inputs with the same name, so I did:
<input type="text" name="model'.$row['carIndex'].'" value="'.$row['model'].'">
Placing the primary key of the record it was currently tired to on the end of it's name. Which seemed like a logical way to go about things.
However now I need to call these variables to place in the mysql query and I dunno how to do that, or even if I can.
I have the selected records saved in an array so I have:
foreach ($postid as $carID)
{
$query = "stuff";
mysqli_query($db, $query);
}
Each loop has $carID containing the variables that was put on the end of the form input names.
So something like:
$_POST['something'+$variable2]
is all I can think of but doesn't work.
Any method that works for my overall code is welcome not just a solution to the issue I've made.
Actually your way should work. Just replace the + with . in $_POST['something'+$variable2].
My tip is: use an array as name in your html instead:
<input type="text" name="model[]" value="'.$row['model'].'">
On php-Side you can loop through all $_POST['model'] since its an array now.
You can add the index for every entry in your html, too:
<input type="text" name="model['.$row['carIndex'].']" value="'.$row['model'].'">
PHP uses a dot for concatenation, not + like Java and Javascript:
$_POST['something' . $variable2]
Try something like this:
<form ...>
<?php
while($row = mysqli_fetch_assoc(...):
$index = $row['carIndex'];
?>
<input type="text" name="carmodel[<?php echo $index?>][model]" value="<?php echo $row['model'] ?>">
<?php endforeach; ?>
</form>
This way you will have the data stored in $_POST['carmodel'] as an array indexed by carIndex value as the structure of data in $_POST is defined by names of inputs, here you will have names likee carmodel[1][model] for example so then in post it will be in $_POST['carmodel'][1][model]
you can read here as well
How would I create this array structure in an HTML form?
I've been trying to develop a real estate page where people can add listings. I am new to the world of php mysql. I have been over this problem for over a day and can't figure out where the problem is.
I have a form where people can add data. That's good and working. Now I am starting to have a place where people can add / delete / update their info. I am trying to build this step by step.
This is where a user could pull the information. My problem is with the piece of the code:
edit_form.php?idBAR=$row[id].
Full code below.
<table>
<tr>
<td align="center">EDIT DATA</td>
</tr>
<tr>
<td>
<table border="1">
<?php
include"configS_OH.php";//database connection
$order = "SELECT * FROM braaasil_brokerstour.property";
$result = mysql_query($order);
while ($row=mysql_fetch_array($result)){
echo ("<tr><td>$row[id]</td>");
echo ("<td>$row[address]</td>");
echo ("<td>$row[day]</td>");
echo ("<td>$row[hours]</td>");
echo ("<td>Edit</td></tr>");
}
?>
</table>
</td>
</tr>
</table>
Then this tutorial try to pass id through the address bar (I don't know much about php to actually say much)
It tries to upload the data into a new form where a person could edit info.
But I can't load the data into the new form. If I use where id=7, I get the info into the form. But this method of passing the info in the address bar like ?idBAR=8... and then try to catch it in the other code (where id=$idBAR), is not working.
Here is the code:
<table border=1>
<tr>
<td align=center>Form Edit Employees Data</td>
</tr>
<tr>
<td>
<table>
<?php
include "configS_OH.php";//database connection
print $database;
$order = "SELECT * FROM braaasil_brokerstour.property
WHERE id='$idBAR'";
print $idBAR;
$result = mysql_query($order) or die( mysql_error() );
$row = mysql_fetch_array($result);
?>
<form method="post" action="edit_data.php">
<input type="hidden" name="idBAR" value="<?php echo "$row[id]"?>">
<tr>
<td>Address</td>
<td>
<input type="text" name="address"
size="20" value="<?php echo "$row[address]"?>">
</td>
</tr>
<tr>
<td>Date</td>
<td>
<input type="text" name="day" size="40"
value="<?php echo "$row[day]"?>">
</td>
</tr>
<tr>
<td>Time</td>
<td>
<input type="text" name="time" size="40"
value="<?php echo "$row[hours]"?>">
</td>
</tr>
<tr>
<td align="right">
<input type="submit"
name="submit value" value="Edit">
</td>
</tr>
</form>
</table>
</td>
</tr>
</table>
I tried an tried and tried..
Thank you for your time in advance.
WHERE id='$idBAR'
You haven't assigned $idBAR any value. You need to read it from the $_GET array first:
$idBAR = $_GET['idBAR'];
You should, of course, check that this value exists first, and is acceptable.
I don't see anywhere you have actually used the GET data, just the reference name which is used in GET.
If you first query is working and is getting the $row['id'] value ok - you can verify this when you go to edit_form.php, in your browser URL bar at the top, does it say this:
edit_form.php?idBAR=7
(or whatever number should be there)
If so, then you just need to use the PHP GET. Your data is stored in $_GET[], and in this case, the reference name is idBAR. So your id from your previous page query is sent through the link into your URL, and on your edit_form.php page, you'd use that data as:
$_GET['idBAR']
You can use that, but personally I assign the data to a variable, such as:
$strGetId = $_GET['idBAR'];
Then you can use $strGetId throughout your code.
Also, check things like isset(), empty() etc, just so you know you are working with A) something is actually there, and B) it's not empty etc
if you are putting a variable directly in a string without concatenating, it can't be an array variable; you must concatenate those you also need to surr. so this
echo ("<td>Edit</td></tr>");
should be this
echo ("<td>Edit</td></tr>");
also, it looks like your form is sending data with POST. When you pass form data in the url string after the question mark, that is passing with get.
so...in your form where you want to use that variable, you set it up like this
$idBAR=$_GET['idBAR']; //to get the variable if it was part of the URL
$idBAR=$_POST['idBAR']; //if it was sent with post, as is the case with your form
also, request contains both get and post, so
$idBAR=$_REQUEST['idBAR'];
will work in either case.
The problem is the $row[id] is seen as text just like everything else. You want the value of $row[id]. Instead of
echo ("<td>Edit</td></tr>");
try
echo ("<td>Edit</td></tr>");
I wonder whether someone may be able to help me please.
Firstly, this is something I've never tackled before, so please bear with me if this is something which is straight forward to the more seasoned developer.
The code below is a portion of a script which correctly shows a 'Locations List' for each user.
$i=0;
while ($i < $num) {
$lid=mysql_result($result,$i,"locationid");
$lname=mysql_result($result,$i,"locationname");
$laddress=mysql_result($result,$i,"returnedaddress");
include("admin/link.php");
include("admin/opendb.php");
$fquery = "SELECT COUNT(*) num FROM finds WHERE locationid = '$lid'";
$fcount = mysql_query($fquery) or die('error');
$row = mysql_fetch_assoc($fcount);
$findscount = $row['num'];
mysql_close($connect);
?>
<table width="603" border="0">
<tr>
<th width="156">Location</th>
<th width="302">Address</th>
<th width="131">No. Of Finds Made</th>
</tr>
<tr>
<td><?php echo $lname;?></td>
<td><?php echo $laddress;?></td>
<td><?php echo $findscount;?></td>
</tr>
</table>
<?php
echo'<form name="locations" method="post">';
$i++;
}
if ($num == 0) {
echo"<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td> </td>
<td colspan='3'><div align='center'><strong>No locations have been added yet. <a href='saveaddress.php'>Click here</a> to add one.</strong></div></td>
<td> </td>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>";
}
echo '<input type="submit" name="submitlocation" id="submitlocation" value="View/Amend Location Details">';
echo '<input type="submit" name="submitfinds" id="submitaddfinds" value="Add Finds">';
echo '</div>'."\n";
if(isset($_POST["submitlocation"])) {
header("updatelocation.php");
}
else if(isset($_POST["submitaddfinds"])) {
header("addfinds.php");
}
?>
What I'm trying to do is add two submit buttons for each Location record, one which takes the user to a page called updatelocation.php and the second which takes the user to a page called addfinds.php. But both must be linked to the Location via the field 'locationid'. So in other words if the user wants to Add Finds for Location 1 upon clicking on the relevant button, they are taken to the Add Finds page for Location 1.
I've read a number of tutorials, but I've obviously misunderstood somewhere along the lines because although I've managed to add the buttons to the record, when I click either button the 'Locations List is refreshed, rather than the user being taken to the respective page.
I just wondered whether someone could possibly have a look at this please and let me know where I'm going wrong?
Many thanks and kind regards
You'd be better off making a seperate page (i.e., forrmaction.php) which processes the logic and sends the user to the correct page. If you do not want to do that, you can also make a seperate form for each button and simply set the action attribute of form to point to either updatelocation.php or addfinds.php
Example of formaction.php:
if (isset($_POST['type']) {
if ($_POST['type'] == 'update')
$url = 'updatelocation.php';
else
$url = 'addthis.php';
header("Location: " . $url);
}
Example of form with two buttons that works with formaction.php:
<form name="locations" method="POST" action="formaction.php">
<input type="submit" name="type" value="update">
<input type="submit" name="type" value="add">
</form>
However, for your question, the problem is that you are not using the correct header. To use a redirect, you must use "Location:" in the header. For example,
header("Location: updatelocation.php");
Be careful, because this will not work if headers have already been sent. You may want to look into output control in that case.