I have the following code:
print $node->field_carousel_1[0]['filepath'];
What i would like to do is change the 1 and use a variable instead.
Do you have any idea how i would be able to do this?
What i am aiming for: Using a variable instead of the one to create a looping function to print field_carousel_1, field_carousel_2, field_carousel_3 etc
You can try something like this:
for ($i=1; $i<4; $i++) {
$field = "field_carousel_$i";
$arr = $node->$field;
print $arr[0]['filepath'];
}
I would store these in an array.
field_carousel=array('value1', 'value2', 'value3', 'etc.')
To print them, you would do...
foreach(field_carousel as $item) {
echo $item
}
Related
I will be getting some certain amount of data. I will get the number for which the for loop to be run.
For example
I get the number 3 and I will get three parameters like par1,par2 and par3 then how should I pass this par1 in the $_post
like
$i=$_POST["number"];
for($i=1;$i<=$n;$i++)
{
$par.$i = $_POST["par".$i];
}
Here I cant get the value from $_POST["par".$i];
As it is not able to get the variable inside the paramater of $_POST
Any help will be thankful
I suggest that you create a new array $par and there you will put by index all the par you will have like this:
$i=$_POST["number"];
$par = [];
for($i=1;$i<=$n;$i++)
{
$par[$i] = $_POST["par".$i];
}
After that if you want to go throw all pars you can simply use foreach like this:
foreach($par as $key => $value) {
// $key will be 1,2,3
// $value will be the value from $_POST["par" . $i]
}
The . is to concatenate two strings in PHP, and you can't create a new variable like you tried. If you want to have in $par1, $par2 and $par3 you can do like this:
${"par" . $i} = $_POST["par".$i];
But I don't recommend this way because it's more hard to handle.
One Way
According to your question.
<?php
$n = $_POST["number"];
$par = "par";
for($i=1; $i<=$n; $i++){
$par.$i = $_POST["par".$i];
}?>
Alternative Way
In this scenario,
For example I get the number 3 and I will get three parameters like
par1,par2 and par3 then how should I pass this par1 in the $_post.
Better, make 'par' input name as an array type as 'par[]' (<input type='text' name='par[]'>) in your file instead using par1, par2 .. par(n).
And, no need to worry in submit page.
<?php
$n = $_POST["number"];
for($i=1;$i<= $n;$i++){
$newPar = $_POST["par"][$i];
// Write here your logic to use how you want.
}
?>
I have the following code:
$items = array();
foreach($following as $storeOwner)
{
array_push($items, $productRepository->mostRecentItem($storeOwner->getId(), 5));
}
I am trying to append the results of
$productRepository->mostRecentItem($storeOwner->getId(), 5)
to $items. How do I do so? Why doesn't the above code work?
Try this:
$items = array();
foreach($following as $storeOwner)
{
$items[] = $productRepository->mostRecentItem($storeOwner->getId(), 5);
}
Also, take a look to the result of the mostRecentItem Method... .
var_dump you different objects and return values to make sure that contain what you think they should contain. The code looks "correct" so it's probably the objects and values that are not.
If i knew the correct terms to search these would be easy to google this but im not sure on the terminology.
I have an API that returns a big object. There is one particular one i access via:
$bug->fields->customfield_10205[0]->name;
//result is johndoe#gmail.com
There is numerous values and i can access them by changing it from 0 to 1 and so on
But i want to loop through the array (maybe thats not the correct term) and get all the emails in there and add it to a string like this:
implode(',', $array);
//This is private code so not worried too much about escaping
Would have thought i just do something like:
echo implode(',', $bug->fields->customfield_10205->name);
Also tried
echo implode(',', $bug->fields->customfield_10205);
And
echo implode(',', $bug->fields->customfield_10205[]->name);
The output im looking for is:
'johndoe#gmail.com,marydoe#gmail.com,patdoe#gmail.com'
Where am i going wrong and i apologize in advance for the silly question, this is probably so newbie
You need an iteration, such as
# an array to store all the name attribute
$names = array();
foreach ($bug->fields->customfield_10205 as $idx=>$obj)
{
$names[] = $obj->name;
}
# then format it to whatever format your like
$str_names = implode(',', $names);
PS: You should look for attribute email instead of name, however, I just follow your code
use this code ,and loop through the array.
$arr = array();
for($i = 0; $i < count($bug->fields->customfield_10205); $i++)
{
$arr[] = $bug->fields->customfield_10205[$i]->name;
}
$arr = implode(','$arr);
This is not possible in PHP without using an additional loop and a temporary list:
$names = array();
foreach($bug->fields->customfield_10205 as $v)
{
$names[] = $v->name;
}
implode(',', $names);
You can use array_map function like this
function map($item)
{
return $item->fields->customfield_10205[0]->name;
}
implode(',', array_map("map", $bugs)); // the $bugs is the original array
I am theming a drupal content type, and I have a set of similarly named variables. e.g. field_anp_1, field_anp_2,..., field_anp_10. I want to dynamically print them out from within a for loop. Normally, one would print the values out individually by doing something like:
print $field_anp_1[0]['value'];
in my case, I can't do this because the last number changes. So, within a for loop, how would one print out these fields? I tried variable variables, but I don't seem to understand exactly what is going on there - and I don't think it likes the fact that this in an array. Any help would be greatly appreciated!
Definitely not an array. But you can use a variable as the name of a variable with {..}
ghoti#pc:~ $ cat invar.php
#!/usr/local/bin/php
<?php
$field_anp_3="three";
$field_anp_2="two";
for ($i=1; $i<5; $i++) {
$thisvar="field_anp_" . $i;
if (isset(${$thisvar})) {
printf("%s: %s\n", $i, ${$thisvar});
} else {
printf("%s: not set\n", $i);
}
}
ghoti#pc:~ $ ./invar.php
1: not set
2: two
3: three
4: not set
Alternately, if you are sure that the variables that do exist will be sequential. you can stop on failure (per comments below):
#!/usr/local/bin/php
<?php
$field_anp_1="one";
$field_anp_2="two";
$field_anp_3="three";
for ($i=1; $i<5; $i++) {
$thisvar="field_anp_" . $i;
if (!isset(${$thisvar})) {
break;
}
printf("%s: %s\n", $i, ${$thisvar});
}
I can see no reason for having an untold number of variables generated like that. But this is how you could collect them:
$vars = array();
foreach(get_defined_vars() as $name => $value) {
if(strpos($name, 'field_anp_') === 0) {
$vars[$name] = $value;
}
}
Now you would have your values as an associative array in $vars. Instead of adding the values to $vars, you could print them directly.
Update In response to your comment
$array = array('foo' => 'bar');
$x = 'foo';
$field_anp_bar = 'baz';
echo ${'field_anp_' . $array[$x]};
Ok, I figured it out. I simply needed to be more specific with PHP. To call a variable such as: $field_anp_0[0]['value'] from within a for loop, where 0 is increasing, one simply needs to do the following:
<?php
$numbers = array(123,235,12332,2342);
for($i; $i<count($numbers); $i++){
$var = "field_anp_".$numbers[$i];
printf("%s\n", ${$var}[0]['value']);
}
?>
This will allow me to list the fields that I will need to have printed out in the order I need to have them printed out. Then, I can use a for loop to print out a themed table for instance.
Thank you for the help!
I want to create a array with values:
3,2,1.... and I want to use array_push and a forloop.
I have written the following code is not working..
============
<?PHP
$temp0=3;
$temp1=2;
$temp2=1;
$temp3=1;
$temp4=1;
$temp5=1;
$arraytemp=array();
for($i=0;$i<4;$i++)
{
$r="temp";
$dd=$r.$i;
array_push($arraytemp,$dd);
}
echo $arraytemp[3];
?>
can you please let me know what I am missing
This is how should you assign $dd
for($i=0;$i<4;$i++)
{
$dd=${"temp".$i};
array_push($arraytemp,$dd);
}
your $dd has the name of your var as a string. you want to use this for this technique:
array_push($arraytemp,$$dd);
Pay attention to the double $$ :)
What happens here is the following: the $dd gets replaced by the string it contains. so your call
array_push($arraytemp,$dd);
will do this:
array_push($arraytemp,'temp0');
But you want this:
array_push($arraytemp,$temp0);
so you need to show you want an acutal $var with that name, so you add the $. It's just the way the syntax works, neccessairy to distinguish between a normal string and a string that's supposed to be a variable
confusing what do you want to achieve here, do you want to:
create array with value: temp0, temp1, temp2 ...
for($i=0;$i<4;$i++){
array_push($array,"temp{$i}");
}
echo $array[3];
create array with value: 0, 1, 2, 3 ..
for($i=0;$i<4;$i++){
array_push($array,$i);
}
echo $array[3];
create array with value based on your defined variable above ($temp0, $temp1 ...)
$temp0=3;
$temp1=2;
$temp2=1;
$temp3=1;
$array = array();
for($i=0;$i<4;$i++){
$val = "temp{$i}";
array_push($array,$$val);
}
echo $array[3];
Easiest way, going by what you're requesting, although you didn't specify how many numbers you wanted to add. so for loop won't work that way. you're best off with a while loop.
$foo = array();
$i = 1;
while (some end condition) {
array_push($foo, $i);
$i++;
}
print_r($foo);