I have the following code:
$items = array();
foreach($following as $storeOwner)
{
array_push($items, $productRepository->mostRecentItem($storeOwner->getId(), 5));
}
I am trying to append the results of
$productRepository->mostRecentItem($storeOwner->getId(), 5)
to $items. How do I do so? Why doesn't the above code work?
Try this:
$items = array();
foreach($following as $storeOwner)
{
$items[] = $productRepository->mostRecentItem($storeOwner->getId(), 5);
}
Also, take a look to the result of the mostRecentItem Method... .
var_dump you different objects and return values to make sure that contain what you think they should contain. The code looks "correct" so it's probably the objects and values that are not.
Related
I'm trying to apostrophe to items in an array. and return that into another array
I know I can use foreach to display it but I need the items to be back inside an array.
from: array('blue','red','yellow');
to: array("'blue'","'red'","'yellow'");
please help
Yes.
Use this PHP function :
$array=array('blue','red','yellow');
foreach ($array as $key=>$item)
{
$new_array[$key]="'".$item."'";
}
print_r ($new_array);
With array_map :
function myfunc($n)
{
return("'".$n."'");
}
$a = array('blue','red','yellow');
$b = array_map("myfunc", $a);
print_r($b);
A slightly cleaner way:
function addQuotes($a)
{
return "'".$a."'";
}
$array = array('blue','red','yellow');
$array = array_map('addQuotes', $array);
A simple search would have landed you this very basic information though. Please give effort next time.
If i knew the correct terms to search these would be easy to google this but im not sure on the terminology.
I have an API that returns a big object. There is one particular one i access via:
$bug->fields->customfield_10205[0]->name;
//result is johndoe#gmail.com
There is numerous values and i can access them by changing it from 0 to 1 and so on
But i want to loop through the array (maybe thats not the correct term) and get all the emails in there and add it to a string like this:
implode(',', $array);
//This is private code so not worried too much about escaping
Would have thought i just do something like:
echo implode(',', $bug->fields->customfield_10205->name);
Also tried
echo implode(',', $bug->fields->customfield_10205);
And
echo implode(',', $bug->fields->customfield_10205[]->name);
The output im looking for is:
'johndoe#gmail.com,marydoe#gmail.com,patdoe#gmail.com'
Where am i going wrong and i apologize in advance for the silly question, this is probably so newbie
You need an iteration, such as
# an array to store all the name attribute
$names = array();
foreach ($bug->fields->customfield_10205 as $idx=>$obj)
{
$names[] = $obj->name;
}
# then format it to whatever format your like
$str_names = implode(',', $names);
PS: You should look for attribute email instead of name, however, I just follow your code
use this code ,and loop through the array.
$arr = array();
for($i = 0; $i < count($bug->fields->customfield_10205); $i++)
{
$arr[] = $bug->fields->customfield_10205[$i]->name;
}
$arr = implode(','$arr);
This is not possible in PHP without using an additional loop and a temporary list:
$names = array();
foreach($bug->fields->customfield_10205 as $v)
{
$names[] = $v->name;
}
implode(',', $names);
You can use array_map function like this
function map($item)
{
return $item->fields->customfield_10205[0]->name;
}
implode(',', array_map("map", $bugs)); // the $bugs is the original array
pretty straight forward question this - I am trying to create an array to store the Model and Cost values taken from my database table. I figured I could begin the array, then create a while loop, and then end the array, and smiles all around. I may be mistaken, or I may have blindly missed something in my code, but could you have a look?
$array = array(
while ($overall_cost = mysql_fetch_assoc($query_ocost)) {
$overall_cost["model"] => $overall_cost["cost"],
}
);
var_dump($array);
I think this is what you're looking for:
$array = array();
while ($overall_cost = mysql_fetch_assoc($query_ocost)) {
$array[$overall_cost["model"]] = $overall_cost["cost"];
}
var_dump($array);
You can't do it like this. You need to add to the array inside the while loop:
$array = array();
while ($overall_cost = mysql_fetch_assoc($query_ocost)) {
$array[$overall_cost["model"]] = $overall_cost["cost"];
}
var_dump($array);
would be one way of doing it.
EDITED to produce simple array.
I don't think that will work. Try something like:
$array = array();
while ($overall_cost = mysql_fetch_assoc($query_ocost)) {
$array[$overall_cost["model"]] = $overall_cost["cost"];
}
var_dump($array);
Is it possible to have an AND in a foreach loop?
For Example,
foreach ($bookmarks_latest as $bookmark AND $tags_latest as $tags)
You can always use a loop counter to access the same index in the second array as you are accessing in the foreach loop (i hope that makes sense).
For example:-
$i = 0;
foreach($bookmarks_latest as $bookmark){
$result['bookmark'] = $bookmark;
$result['tag'] = $tags_latest[$i];
$i++;
}
That should achieve what you are trying to do, otherwise use the approach sugested by dark_charlie.
In PHP 5 >= 5.3 you can use MultipleIterator.
Short answer: no. You can always put the bookmarks and tags into one array and iterate over it.
Or you could also do this:
reset($bookmarks_latest);
reset($tags_latest);
while ((list(, $bookmark) = each($bookmarks_latest)) && (list(,$tag) = each($tags_latest)) {
// Your code here that uses $bookmark and $tag
}
EDIT:
The requested example for the one-array solution:
class BookmarkWithTag {
public var $bookmark;
public var $tag;
}
// Use the class, fill instances to the array $tagsAndBookmarks
foreach ($tagsAndBookmarks as $bookmarkWithTag) {
$tag = $bookmarkWithTag->tag;
$bookmark = $bookmarkWithTag->bookmark;
}
you can't do that.
but you can
<?php
foreach($keyval as $key => $val) {
// something with $key and $val
}
the above example works really well if you have a hash type array but if you have nested values in the array I recommend you:
or option 2
<?php
foreach ($keyval as $kv) {
list($val1, $val2, $valn) = $kv;
}
No, but there are many ways to do this, e.g:
reset($tags_latest);
foreach ($bookmarks_latest as $bookmark){
$tags = current($tags_latest); next($tags_latest);
// here you can use $bookmark and $tags
}
No. No, it is not.
You'll have to manually write out a loop that uses indexes or internal pointers to traverse both arrays at the same time.
Yes, for completeness:
foreach (array_combine($bookmarks_latest, $tags_latest) as $bookm=>$tag)
That would be the native way to get what you want. But it only works if both input arrays have the exact same length, obviously.
(Using a separate iteration key is the more common approach however.)
How can you do this? My code seen here doesn't work
for($i=0;i<count($cond);$i++){
$cond[$i] = $cond[$i][0];
}
It can be as simple as this:
$array = array_map('reset', $array);
There could be problems if the source array isn't numerically index. Try this instead:
$destinationArray = array();
for ($sourceArray as $key=>$value) {
$destinationArray[] = $value[0]; //you may want to use a different index than '0'
}
// Make sure you have your first array initialised here!
$array2 = array();
foreach ($array AS $item)
{
$array2[] = $item[0];
}
Assuming you want to have the same variable name afterwards, you can re-assign the new array back to the old one.
$array = $array2;
unset($array2); // Not needed, but helps with keeping memory down
Also, you might be able to, dependant on what is in the array, do something like.
$array = array_merge(array_values($array));
As previously stated, your code will not work properly in various situation.
Try to initialize your array with this values:
$cond = array(5=>array('4','3'),9=>array('3','4'));
A solution, to me better readable also is the following code:
//explain what to do to every single line of the 2d array
function reduceRowToFirstItem($x) { return $x[0]; }
// apply the trasnformation to the array
$a=array_map('reduceRowTofirstItem',$cond);
You can read the reference for array map for a thorough explanation.
You can opt also for a slight variation using array_walk (it operate on the array "in place"). Note that the function doesn't return a value and that his parameter is passed by reference.
function reduceToFirstItem(&$x) { $x=$x[0]; }
array_walk($cond, 'reduceToFirstItem');
That should work. Why does it not work? what error message do you get?
This is the code I would use:
$inArr;//This is the 2D array
$outArr = array();
for($i=0;$i<count($inArr);$i++){
$outArr[$i] = $inArr[$i][0];
}