I have a very simple GET form with one text field:
<form action="blah" method="get" name="blah" onsubmit="blah">
<input type="text" name="page" value="blah" />
</form>
What I want is to get the current submitted value from the url:
$page_value = $_REQUEST["page"];
but this will only get the previous submitted value, not the current one.
<form action="blah" name="blah" onsubmit="blah">
<input type="text" name="page" value="<?=htmlspecialchars($_GET['page'])?>" />
</form>
Related
i am submitting form using get method to a url which already contain parameter like
localhost/myfile.php?section=console
my form code is
<form method="GET" action="<?=basename($_SERVER['PHP_SELF'])?>/section=console">
<input type="text" name="cmd" />
<input type="submit" value="execute" />
</form>
when i submit this data through post type it submit data then it submit like myfile.php?cmd=blahblah
but i want to submit it to myfile.php?section=console&cmd=blahblah.
i can do this by using hidden field but i am insearch of other better way
Simply add a hidden field into your form
<input type="hidden" name="section" value="console">
If you are not interested in using hidden fields then rewrite your form like this
<form method="GET" action="<?php basename($_SERVER['PHP_SELF']) ?>/?section=console">
You should use a hidden input within your form
<form method="GET" action="<?php echo basename($_SERVER['PHP_SELF']); ?>">
<input type="hidden" name="section" value="console">
<input type="text" name="cmd">
<input type="submit" value="execute">
</form>
I've two forms in a single page. One form fetches data from database table. In the other form I need those fetched values to be added in another table, with additional values.
<form method="post" action="same.php" name="form1">
<input type="text" name="search" />
<input type="submit" name="result" value="search_for" />
</form>
<form method="post" action="same.php" name="form2">
<input type="date" name="add_date" />
<input type="submit" name="result" value="search_for" />
</form>
After searching I will get values in a variable $search.
Now I need to post the variable $search in another table, but when I click submit the search values get null.
i don't think you can do this
you have only one way to do this is to include all input's in to one form
i think you can do this by 2 way
putting all input in one form
or you can do this by making two step as
page 1 contains form one and page2 contain form2
as follows
page 1
<form method="post" action="same.php" name="form1">
<input type="text" name="search"/>
<input type="submit" name="result" value="search_for">
</form>
page 2
<form method="post" action="same.php" name="form2">
//data from page1 {form1}
<input type="hidden" name="search" value=<?php echo $_POST['search']; ?> />
//you will not need this
<input type="submit" name="result" value="search_for">
<input type="date" name="add_date"/>
<input type="submit" name="result" value="search_for">
</form>
I have a php and html based tool that has a form that, when submitted, outputs the data reformatted using echo commands.
I'd like to add a 2nd form to the same page that will also output using echo.
My issue is, when I submit the 2nd form the first forms output disappears. I'd like to make it so the echo output from the first form does not go away when the 2nd form is submitted so they will both be on the screen at the same time.
Is there a way I can do this?
Only one <form> block in a page can be submitted at a single time. <input> fields defined in one form will not be submitted when the other form is submitted.
e.g.
<form>
<input type="text" name="foo" />
<input type="submit" />
</form>
<form>
<input type="text" name="bar" />
<input type="submit" />
</form>
Clicking on submit will submit either a foo field, OR a bar field. Not both. If you want both fields to be submitted, then you have to either build them into a SINGLE form:
<form>
<input type="text" name="foo" />
<input type="text" name="bar" />
<input type="submit" />
</form>
or use Javascript to copy the data from one form to another.
<form method="post"> <div>Module1</div> <input type="text"
value="module1" name="module_id"> <input type="text" value="title 1"
name="title"> <input type="text" value="some text 1" name="text">
<input type="submit" name="form_1" value="submit"> </form>
<form method="post"> <div >Module2</div> <input type="text"
value="module2" name="module_id"> <input type="text" value="title 2"
name="title"> <input type="text" value="some text 2" name="text">
<input type="submit" name="form_2" value="submit"> </form>
<?php
if(isset($_POST['form_1'])){
echo '<pre>';
print_r($_POST); }
if(isset($_POST['form_2'])){
echo '<pre>';
print_r($_POST); } ?>
Yes,you can do it.
Eg :
// form1 on page a.php
<form method="post" action="a.php" name="form_one" >
<input type="text" name="form_1" value="if(isset($_POST['form_1'])) echo $_POST['form_1']; ?>" >
<input type="submit" name="submit_1" >
</form>
<?php
if(isset($_POST['submit']))
{
?>
<form method="post" action="a.php" name="form_two" >
<input type="text" name="form_2" value="if(isset($_POST['form_2'])) echo $_POST['form_2']; ?>" >
<input type="submit" name="submit_2" >
</form>
<?php
}
?>
Now when you will submit form_one you will see form_two appear and the value in form one will stay intact in form_one and one the submitting form two the value will remain.
Hope it helped :)
I cannot get the $_POST['value'] after form submission.
I have used javascript to assign a value to an input field.
code:
function updateValue(pid, value){
// this gets called from the popup window and updates the field with a new value
document.getElementById(pid).value = value;
}
The above function is called by a popup widow to assign a value to my input field: pid
Here is the form script:
<form action="test.php" method="post">
<input type="text" name="project_name" id="pid" disabled="disabled" />
<input type="submit" id="search" name="search" value="Search" />
</form>
In my test.php, I have done:
include 'functions.php'; //Has the connection script
if (isset($_POST['search'])){
echo $project_id = $_POST['project_name'];
$sql = mysql_query("SELECT * from item
where category like '$project_id %'
");
echo $num = mysql_num_rows($sql);
}
But I am getting the error: Undefined index: project_name
Disabled inputs doesnt post. Use hidden input like this:
<form action="test.php" method="post">
<input type="text" name="project" disabled="disabled" />
<input type="hidden" name="project_name" id="pid" />
<input type="submit" id="search" name="search" value="Search" />
</form>
Try filling the hidden field when you set the value into disabled field
<form action="test.php" method="post">
<input type="text" name="project" id="pid" onchange="document.getElementById("pid-new").value=document.getElementById("pid").value" disabled="disabled" />
<input type="hidden" id="pid-new" name="project_name" />
<input type="submit" id="search" name="search" value="Search" />
</form>
your project_name input field is disabled.
remove this attribute then it will work.
It's because disabled attributes aren't passed along the form requests.
If you're setting the value through javascript, and that part works, replace your text input with this:
<input type="hidden" name="project_name" id="pid" />
this will work
I'm trying to build a form using php & jquery, but I'm a little confused as to what to do with the jquery portion of it...
Basically, when the user submits the first form, I want to direct them to the "next step" form, but I want to retain the values submitted from the first one in a hidden input field...
If someone can either show me how or point me to a good tutorial, I'd appreciate it...
I don't have any of the php or jquery yet, and this is just a simplified version of the html markup...
//first.php
<form name="form1" method="post" action="second.php">
<input type="text" name="name" value="" />Name
<input type="submit" name="step1" value="Next" />
</form>
//second.php
<form name="form2" method="post" action="process.php">
<input type="hidden" name="name" value="{$_POST['name']}" />
<input type="text" name="message" value="" />message
<input type="submit" name="step2" value="Finish" />
</form>
<input type="hidden" name="name" value="{$_POST['name']}" />
should be,
<input type="hidden" name="name" value="<?php echo $_POST['name']}; ?>" />
and also sanitize the input, if you want
I don't no if there is a better way to do that.
But, when I need to do such thing, I do in this way:
<script>
<?php
foreach($_POST as $key => $valule)
{
echo "$('$key').val('$value')";
}
?>
</script>
So, in your nextstep file, all you'll need to do is set up the hidden fields and then just loop through the post vars and set each one via jquery.