I cannot get the $_POST['value'] after form submission.
I have used javascript to assign a value to an input field.
code:
function updateValue(pid, value){
// this gets called from the popup window and updates the field with a new value
document.getElementById(pid).value = value;
}
The above function is called by a popup widow to assign a value to my input field: pid
Here is the form script:
<form action="test.php" method="post">
<input type="text" name="project_name" id="pid" disabled="disabled" />
<input type="submit" id="search" name="search" value="Search" />
</form>
In my test.php, I have done:
include 'functions.php'; //Has the connection script
if (isset($_POST['search'])){
echo $project_id = $_POST['project_name'];
$sql = mysql_query("SELECT * from item
where category like '$project_id %'
");
echo $num = mysql_num_rows($sql);
}
But I am getting the error: Undefined index: project_name
Disabled inputs doesnt post. Use hidden input like this:
<form action="test.php" method="post">
<input type="text" name="project" disabled="disabled" />
<input type="hidden" name="project_name" id="pid" />
<input type="submit" id="search" name="search" value="Search" />
</form>
Try filling the hidden field when you set the value into disabled field
<form action="test.php" method="post">
<input type="text" name="project" id="pid" onchange="document.getElementById("pid-new").value=document.getElementById("pid").value" disabled="disabled" />
<input type="hidden" id="pid-new" name="project_name" />
<input type="submit" id="search" name="search" value="Search" />
</form>
your project_name input field is disabled.
remove this attribute then it will work.
It's because disabled attributes aren't passed along the form requests.
If you're setting the value through javascript, and that part works, replace your text input with this:
<input type="hidden" name="project_name" id="pid" />
this will work
Related
Let's say I have a form that I send via GET:
<form method="get" action="/search.php?foo=bar&test=1&something=else">
<input type="text" name="day" placeholder="day"/>
<input type="text" name="link" placeholder="link"/>
</form>
And after submitting my form and processing the data (which consists of only saving it to a file), the url is changed to:
search.php?day=test&link=google.com
What should I do so the url becomes:
/search.php?foo=bar&test=1&something=else&day=test&link=google.com
(preserving the old parameters that were included in action attribute.)
The form action will change every time and it's difficult to keep the old GET parameters in the form action.
However, you can go with hidden fields.
Try this:
<form method="get" action="/search.php">
<input type="hidden" name="foo" value="bar"/> <!-- Add this -->
<input type="hidden" name="test" value="1"/> <!-- Add this -->
<input type="text" name="day" placeholder="day"/>
<input type="text" name="link" placeholder="link"/>
</form>
You could try changing the action before submitting, depending how you're going to submit the form. This can be done if you apply IDs to your texts and either a name or an ID to the form.
HTML:
<form id="frm" method="get" action="/search.php?foo=bar&test=1&something=else">
<input type="text" name="day" id="day" placeholder="day"/>
<input type="text" name="link" id="link" placeholder="link"/>
</form>
Then with JavaScript you can run a function and change the form's action:
var _form = document.getElementById('frm');
var day = document.getElementById('day').value;
var link = document.getElementById('link').value;
_form.action += '&day=' + day + '&link=' + link;
_form.submit();
You could try to use a hidden input field.
<input type="hidden" name="name" value="value">
if you are getting your variables first from get and then want to add into 2nd form you could get this and create input fields hidden with these get values
Now when you submit form in get url you will get all you desire data
<?php
if($_GET){
if(isset($_GET['submit1'])){
$foo = $_GET['foo'];
$test = $_GET['test'];
$something = $_GET['something'];
?>
<form method="get" action="/search.php">
<input type="hidden" name="foo" placeholder="foo" value="<?php echo $foo; ?>"/>
<input type="hidden" name="test" placeholder="test" value="<?php echo $test; ?>"/>
<input type="hidden" name="something" placeholder="something" value="<?php echo $something; ?>"/>
<input type="text" name="day" placeholder="day"/>
<input type="text" name="link" placeholder="link"/>
</form>
<?php
}
}
?>
i have a problem keeping a post element in variables before calling one more time post in a second form .
briefly:
variable below contain elements from previous post
$img=isset($_POST['image'])?$_POST['image']:false;
$table=isset($_POST['tabl'])?$_POST['tabl']:false;
Then i have as next to the lines above the form below :
<form method="post" action="" style="padding-top:200px;padding-bottom:200px;padding-left:500px">
<div><span>Email</span></div> <input type="text" value="" name="user"/><br><br>
<div><span>Password</span></div> <input type="password" value="" name="pass"/><br><br>
<input type="submit" value="send" name="submit"/>
</form>
and right after pressing submit $img and $table are both empty .
how can i keep the values in $imgand $table even after calling post again ?
any clue ?
Thanks
You aren't sending the variables you want in the POST data in your second form.
You could use a hidden field to send it,
A bit like this.
<form method="post" action="" style="padding-top:200px;padding-bottom:200px;padding-left:500px">
<input type="hidden" name="img" value="<?php echo $img;?>" />
<input type="hidden" name="table" value="<?php echo $table;?>" />
<div><span>Email</span></div> <input type="text" value="" name="user"/><br><br>
<div><span>Password</span></div> <input type="password" value="" name="pass"/><br><br>
<input type="submit" value="send" name="submit"/>
</form>
By default, when you visit this page $_GET['page'] is set to 1. I have a search box that allows users to search the same page using $_GET['search'] as the search parameter; however it clears the $_GET['page'] parameter.
Is there a way I can make both parameters stay in the URL when using the search box?
Here's my code:
Search Form:
<form action="page.php?page=1" method="get">
<input type="text" placeholder="Search" name="search" />
</form>
page.php:
<?php
if (isset($_GET['search']) && isset($_GET['page'])) {
// My query goes here
}
?>
Pass the page parameter in as a hidden HTML field.
<form action="page.php" method="get">
<input type="text" placeholder="Search" name="search" />
<input type="hidden" name="page" value="1" />
</form>
In your search form you need a button and you can add an input type hidden and print in his value your $_GET['page'], like this :
<form action="page.php" method="get">
<input type="text" placeholder="Search" name="search" />
<input type="hidden" name="page" value="<?php echo $_GET['page']; ?>" />
<input name="btn" type="submit" value="Send" />
</form>
I have a php and html based tool that has a form that, when submitted, outputs the data reformatted using echo commands.
I'd like to add a 2nd form to the same page that will also output using echo.
My issue is, when I submit the 2nd form the first forms output disappears. I'd like to make it so the echo output from the first form does not go away when the 2nd form is submitted so they will both be on the screen at the same time.
Is there a way I can do this?
Only one <form> block in a page can be submitted at a single time. <input> fields defined in one form will not be submitted when the other form is submitted.
e.g.
<form>
<input type="text" name="foo" />
<input type="submit" />
</form>
<form>
<input type="text" name="bar" />
<input type="submit" />
</form>
Clicking on submit will submit either a foo field, OR a bar field. Not both. If you want both fields to be submitted, then you have to either build them into a SINGLE form:
<form>
<input type="text" name="foo" />
<input type="text" name="bar" />
<input type="submit" />
</form>
or use Javascript to copy the data from one form to another.
<form method="post"> <div>Module1</div> <input type="text"
value="module1" name="module_id"> <input type="text" value="title 1"
name="title"> <input type="text" value="some text 1" name="text">
<input type="submit" name="form_1" value="submit"> </form>
<form method="post"> <div >Module2</div> <input type="text"
value="module2" name="module_id"> <input type="text" value="title 2"
name="title"> <input type="text" value="some text 2" name="text">
<input type="submit" name="form_2" value="submit"> </form>
<?php
if(isset($_POST['form_1'])){
echo '<pre>';
print_r($_POST); }
if(isset($_POST['form_2'])){
echo '<pre>';
print_r($_POST); } ?>
Yes,you can do it.
Eg :
// form1 on page a.php
<form method="post" action="a.php" name="form_one" >
<input type="text" name="form_1" value="if(isset($_POST['form_1'])) echo $_POST['form_1']; ?>" >
<input type="submit" name="submit_1" >
</form>
<?php
if(isset($_POST['submit']))
{
?>
<form method="post" action="a.php" name="form_two" >
<input type="text" name="form_2" value="if(isset($_POST['form_2'])) echo $_POST['form_2']; ?>" >
<input type="submit" name="submit_2" >
</form>
<?php
}
?>
Now when you will submit form_one you will see form_two appear and the value in form one will stay intact in form_one and one the submitting form two the value will remain.
Hope it helped :)
I have a very simple GET form with one text field:
<form action="blah" method="get" name="blah" onsubmit="blah">
<input type="text" name="page" value="blah" />
</form>
What I want is to get the current submitted value from the url:
$page_value = $_REQUEST["page"];
but this will only get the previous submitted value, not the current one.
<form action="blah" name="blah" onsubmit="blah">
<input type="text" name="page" value="<?=htmlspecialchars($_GET['page'])?>" />
</form>