In my website, user have to upload a file, and should have two buttons that redirects to either "action1.php" or "action2.php" based on the submit button user clicked.
<form action="action1.php" method="post" enctype="multipart/form-data" />
<b>Upload a file:<br/>
<input type="hidden" name="MAX_FILE_SIZE" value="31457"/>
<input type="file" name="userfile" id="userfile" size="30" />
<input type="submit" value="GET SEQUENCE" />
</form>
<form action="action2.php" method="post" enctype="multipart/form-data" />
<input type="hidden" name="MAX_FILE_SIZE" value="3145728"/>
<input type="file" name="userfile" id="userfile" size="30" />
<input type="submit" value="GET HELIX INFO" />
Here I have two browse buttons and two actions but the uploaded file is same in both cases. So I want only one browse button and based on what user clicks, it should give either "action1.php" result or "action2.php" result.
<script>
function setAction(form,val,action)
{
form.MAX_FILE_SIZE.value=val;
form.setAttribute('action',action)
form.submit();
}
</script>
<form action="action1.php" method="post" enctype="multipart/form-data" />
<b>Upload a file:<br/>
<input type="hidden" name="MAX_FILE_SIZE" value="31457"/>
<input type="file" name="userfile" id="userfile" size="30" />
<input type="button" value="GET SEQUENCE" onclick="setAction(this.form,31457,'action1.php')"/>
<input type="button" value="GET HELIX INFO" onclick="setAction(this.form,3145728,'action2.php')"/>
</form>
Make a radiobutton named radio and an actions.php file.
Now do this in the actions.php:
<?php
if(isset($_GET["radio"])){
switch($_GET["radio"]){
case "a":
include("action1.php");
break;
case "b":
include("action2.php");
break;
default:
echo "Not valid radio button value";
}
}
else echo "Not valid radio button value";
?>
Related
I have two submit buttons in one form and when I used the first submit, all the text input fields become blank. I try to solve this by using a session to store the textfield inputs.However, I don't know how I can put back the value to the input field that I stored in the session after the first submit is used.
The HTML code:
<form method="post" enctype="multipart/form-data">
<input type="text" name="headline" id="headline" required />
<input type="file" name="files[]" multiple>
<input type="submit" value="Upload Images" name="submit_image">
<input type="submit" name="submit_post" value="Submit Your Post"/>
</form>
The php code:
<?php
session_start();
if (isset($_POST["submit_image"])) {
if (!empty($_POST['headline'])) {
$_SESSION["headline_session"] = $_POST ["headline"];
}
}
$headline_session = $_SESSION["headline_session"];
?>
Why you want to use a session!
you can echo the value of $post parameter in a property called (value) like this
<form method="post" enctype="multipart/form-data">
<input type="text" name="headline" id="headline" value="<?php echo $_POST ['headline']; ?>" required />
<input type="file" name="files[]" multiple>
<input type="submit" value="Upload Images" name="submit_image">
<input type="submit" name="submit_post" value="Submit Your Post"/>
</form>
You can still save things to session if you need them later but I recommend just echoing out the previous value.
<form method="post" enctype="multipart/form-data">
<input type="text" name="headline" id="headline" value="<?php echo $_POST['headline']; ?>" required />
<input type="file" name="files[]" multiple>
<input type="submit" value="Upload Images" name="submit_image">
<input type="submit" name="submit_post" value="Submit Your Post"/>
</form>
Should you need to compare the previous submissions with what was already submitted then this is one way to do it.
Good work thinking forward :) happy coding
I have a php and html based tool that has a form that, when submitted, outputs the data reformatted using echo commands.
I'd like to add a 2nd form to the same page that will also output using echo.
My issue is, when I submit the 2nd form the first forms output disappears. I'd like to make it so the echo output from the first form does not go away when the 2nd form is submitted so they will both be on the screen at the same time.
Is there a way I can do this?
Only one <form> block in a page can be submitted at a single time. <input> fields defined in one form will not be submitted when the other form is submitted.
e.g.
<form>
<input type="text" name="foo" />
<input type="submit" />
</form>
<form>
<input type="text" name="bar" />
<input type="submit" />
</form>
Clicking on submit will submit either a foo field, OR a bar field. Not both. If you want both fields to be submitted, then you have to either build them into a SINGLE form:
<form>
<input type="text" name="foo" />
<input type="text" name="bar" />
<input type="submit" />
</form>
or use Javascript to copy the data from one form to another.
<form method="post"> <div>Module1</div> <input type="text"
value="module1" name="module_id"> <input type="text" value="title 1"
name="title"> <input type="text" value="some text 1" name="text">
<input type="submit" name="form_1" value="submit"> </form>
<form method="post"> <div >Module2</div> <input type="text"
value="module2" name="module_id"> <input type="text" value="title 2"
name="title"> <input type="text" value="some text 2" name="text">
<input type="submit" name="form_2" value="submit"> </form>
<?php
if(isset($_POST['form_1'])){
echo '<pre>';
print_r($_POST); }
if(isset($_POST['form_2'])){
echo '<pre>';
print_r($_POST); } ?>
Yes,you can do it.
Eg :
// form1 on page a.php
<form method="post" action="a.php" name="form_one" >
<input type="text" name="form_1" value="if(isset($_POST['form_1'])) echo $_POST['form_1']; ?>" >
<input type="submit" name="submit_1" >
</form>
<?php
if(isset($_POST['submit']))
{
?>
<form method="post" action="a.php" name="form_two" >
<input type="text" name="form_2" value="if(isset($_POST['form_2'])) echo $_POST['form_2']; ?>" >
<input type="submit" name="submit_2" >
</form>
<?php
}
?>
Now when you will submit form_one you will see form_two appear and the value in form one will stay intact in form_one and one the submitting form two the value will remain.
Hope it helped :)
I have multiple forms and I have one php script that I want to use to process these forms but when I click on submit for any of the forms...the script is processed by the number of forms with the submit button named 'submitForm' in this case, the alert will show 3 times instead of once! What am I not doing right?
NB. I hope this makes much sense?
html code
<form action="" name="form1" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
php script
<?php
if (isset($_POST['submitForm'])) {
echo('<script>alert("Form Submitted")</script>');
}
?>
when I click on submit for any particular form, it submits all the forms.
this is not true.
Once your forms have proper formatting, your browser will submit only current one.
(and PHP has nothing to do here)
however, whole page will be reloaded, if you mean that. That is okay - when you submit a form, a page is intended to reload. If you need another behavior, you have to explain your wishes.
Also note that none of your text fields being sent to the server as they have no names.
I guess the question I should be asking is, how do I pass a particular form to php instead of writing multiple php scripts to handle each form!!!
well, it seems you want to ask how to distinguish these forms.
add a hidden field into each
<input type="hidden" name="step" value="1" />
and then in PHP
if ($_POST['step'] == 1) {
//first form
}
if ($_POST['step'] == 2) {
//second
}
This submits one form of many to php. Copy, paste, test, and study.
<?php
if (isset($_POST['submitForm'])) {
print_r($_POST);
}
?>
<form action="" name="form1" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
Using a,b,c,d for the first form, e,f,g,h for the second form and i,j,k,l for the third form and submitting the second form yields the following output:
Array
(
[A] => e
[B] => f
[C] => g
[D] => h
[submitForm] => Submit Form
)
#Jay
Actually its not hard.
Once you supply form names, your work is done. the DOM does the rest.
write one php block to do your functions (create/update/retrieve/delete)
Whichever button is clicked, by default it submits only the elements enclosed together with it.
if(!empty($_POST)){
if(isset($_POST['submit'])){
print "<pre>";
var_dump($_POST); // write your code here as you would
print "<pre>";
}
}
try this with your form above.
I know this is an old post but here's how I solve this very problem.
All you need to do is make sure the submit buttons in each form have different names. Eg:
<form action="" name="form1" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm1" />
</form>
<form action="" name="form2" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm2" />
</form>
<form action="" name="form3" method="post">
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="text" value="" />
<input type="Submit" value="Submit Form" name="submitForm3" />
</form>
Then, you simply check which form's submit button was pressed.
<?php
if (isset($_POST['submitForm1'])) {
echo('<script>alert("Form 1 Submitted")</script>');
} elseif (isset($_POST['submitForm2'])) {
echo('<script>alert("Form 2 Submitted")</script>');
} elseif (isset($_POST['submitForm3'])) {
echo('<script>alert("Form 3 Submitted")</script>');
}
?>
If you need dynamic forms, you may try below code. While statement can be changed to fetch data from DB and use foreach instead. Hope you know this.
Here, I used while($n<10) for 10 dynamic forms.
You can also use tag as below if you need separate form names.
<form action="" name="form<?=$n?>" method="post">
This will create separate form names such as form1, form2, etc but not necessary here.
<?php
if (isset($_POST['submitForm'])) {
echo '<pre>';
print_r($_POST);
echo '</pre>';
}
$n=0;
while($n<10) {
$n++;
?>
<form action="" name="form1" method="post">
<input type="text" value="" name="A" />
<input type="text" value="" name="B" />
<input type="text" value="" name="C" />
<input type="text" value="" name="D" />
<input type="Submit" value="Submit Form" name="submitForm" />
</form>
<?php
}
?>
Sample page with output when I click row 5..
I have several html textareas on my site. Each has a submit button. When a user types in one of the textareas i need to know which textarea this is. These textareas are each assigned a number taken from a mysql database. I can get the numbers out of the database, but how can I make it so that when a user types in a textarea and clicks submit the submit form knows which textarea this is. Please ask to clarify if needed. I tried my best to explain the problem. thanks.
p.s. the submit button just performs a mysql set values query. I'm using php on my site.
for example: a textarea is assigned '3.' When i submit this form i need 3 to be sent into my mysql set values query.
Use a hidden input to store a reference for each form
<input type="hidden" name="database_reference" value="<?php echo $dbId; ?>" />
Then when you submit the form $_POST['database_reference'] gives you the database id.
<input type="hidden" value="5" name="which_one" />
so for example
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="1" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="2" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="3" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="4" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="5" name="which_one" />
<input type="button" />
</form>
UPDATE:
<?php
if ($_POST){
include("db_connection.php");
mysql_query("UPDATE table SET column = '".mysql_real_escape_string($_POST['text'])."' WHERE value = ".intval($_POST['value']));
echo "done";
}
?>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="1" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="2" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="3" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="4" name="which_one" />
<input type="button" />
</form>
<form method="post" action="">
<textearea name="text"></textarea>
<input type="hidden" value="5" name="which_one" />
<input type="button" />
</form>
Assuming you have multiple <form></form> tags set up, one for each <textarea>, I would just add a hidden input field in each form. For example:
<form>
<textarea />
<input type="hidden" value="1" />
<input type="submit" />
</form>
<form>
<textarea />
<input type="hidden" value="2" />
<input type="submit" />
</form>
You can flesh it out from there, but you get the idea.
<body>
<form method="post" action="xx.php" >
Enter Title of the Post<INPUT type="text" name="title">
<br/>
Enter Description
<textarea rows="10" cols="50" wrap="physical" name="post">
</textarea><br/>
<input type="Submit" value="Post">
<br/><br/>
<form enctype="multipart/form-data" action="xx.php" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
Choose a file to upload: <input name="uploaded_file" type="file" />
<input type="submit" value="Upload" />
</form>
How Do I get the user to write the text and browse the image, only after which pressing a single button would both upload the text and the file?
You can't submit two forms with the same button. You'll need to combine the two fields into a single form.
You can move the file input to the first <form> (which btw, you haven't closed) and use javascript to check if text has been entered and file has been selected.
Don't nest your form tags (It's invalid HTML). You can place all the inputs in one form so they are posted together.
e.g.
<form enctype="multipart/form-data" action="xx.php" method="post">
Enter Title of the Post<INPUT type="text" name="title">
<br/>
Enter Description
<textarea rows="10" cols="50" wrap="physical" name="post">
</textarea>
<br/>
<br/>
<input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
Choose a file to upload: <input name="uploaded_file" type="file" />
<input type="submit" value="Upload" />
</form>
Oh, as a sidenote, you may not want to use a name like "post" in your input control.