Put input value back to input filed - php

Question

I have two submit buttons in one form and when I used the first submit, all the text input fields become blank. I try to solve this by using a session to store the textfield inputs.However, I don't know how I can put back the value to the input field that I stored in the session after the first submit is used.
The HTML code:
<form method="post" enctype="multipart/form-data">
<input type="text" name="headline" id="headline" required />
<input type="file" name="files[]" multiple>
<input type="submit" value="Upload Images" name="submit_image">
<input type="submit" name="submit_post" value="Submit Your Post"/>
</form>
The php code:
<?php
session_start();
if (isset($_POST["submit_image"])) {
if (!empty($_POST['headline'])) {
$_SESSION["headline_session"] = $_POST ["headline"];
}
}
$headline_session = $_SESSION["headline_session"];
?>

Answer 1

Why you want to use a session!
you can echo the value of $post parameter in a property called (value) like this
<form method="post" enctype="multipart/form-data">
<input type="text" name="headline" id="headline" value="<?php echo $_POST ['headline']; ?>" required />
<input type="file" name="files[]" multiple>
<input type="submit" value="Upload Images" name="submit_image">
<input type="submit" name="submit_post" value="Submit Your Post"/>
</form>

Answer 2

You can still save things to session if you need them later but I recommend just echoing out the previous value.
<form method="post" enctype="multipart/form-data">
<input type="text" name="headline" id="headline" value="<?php echo $_POST['headline']; ?>" required />
<input type="file" name="files[]" multiple>
<input type="submit" value="Upload Images" name="submit_image">
<input type="submit" name="submit_post" value="Submit Your Post"/>
</form>
Should you need to compare the previous submissions with what was already submitted then this is one way to do it.
Good work thinking forward :) happy coding