PHP echo array value after while loop - php

Question

How can I echo out value after the while loop. If I do the echo in below code its says Undefined index.
$sql_cast = "SELECT *
FROM
title_cast
INNER JOIN title ON (title_cast.id_title = title.id)
INNER JOIN `cast` ON (title_cast.id_cast = `cast`.id)
WHERE
title_cast.id_title = '1'";
$result_cast = mysql_query($sql_cast) or die('log error with' .mysql_error());
$cast = array();
while ($row = mysql_fetch_assoc($result_cast)) {
$id = $row['id'];
$name = $row['name'];
$img = $row['photo_localurl'];
$poster = str_replace("./", "lib/", $img);
$cast[] = array('id' => $id, 'name' => $name, 'img' => $poster);
//$cast[] = $row;
}
//var_dump($cast);
echo $cast['id'] . " " . $cast['name'] . " " . $cast['poster']."<br />";

Answer 1

Within the while loop, you set the cast array content using $cast[] syntax. This will create a numerical index, starting at 0, then 1 and so on, so you're creating an array that looks like this:
$cast = array(
0 => array('id' => $id, 'name' => $name, 'img' => $poster),
1 => array('id' => $id, 'name' => $name, 'img' => $poster)
);
You need to include the numerical key of the array that you want to echo. For example, if you want to echo the first row:
echo $cast[0]['id']; // Echo the id of the first result
If you want to echo ALL of the rows, use foreach:
foreach($cast as $row) {
echo $row['id'];
}

Answer 2

Maybe you should do:
$cast = array('id' => $id, 'name' => $name, 'img' => $poster);
//$cast[] = $row;
}
//var_dump($cast);
echo $cast['id'] . " " . $cast['name'] . " " . $cast['poster']."<br />";
because if you use $cast[], it will append the new array to your array..

Answer 3

That's because you are pushing a new array in $cast at each index..
So you should echo like this..
$i = 0;
while ($row = mysql_fetch_assoc($result_cast)) {
$id = $row['id'];
$name = $row['name'];
$img = $row['photo_localurl'];
$poster = str_replace("./", "lib/", $img);
$cast[] = array('id' => $id, 'name' => $name, 'img' => $poster);
//$cast[] = $row;
//var_dump($cast);
echo $cast[$i]['id'] . " " . $cast[$i]['name'] . " " . $cast[$i]['poster']."<br />";
$i++;
}

Answer 4

Try this:
<?php
while ($row = mysql_fetch_assoc($result_cast)) {
$id = $row['id'];
$name = $row['name'];
$img = $row['photo_localurl'];
$poster = str_replace("./", "lib/", $img);
$cast[] = array('id' => $id, 'name' => $name, 'img' => $poster);
}
foreach($cast as $rows) {
echo $rows['id']." ".$rows['name']." ".$rows['img']."<br />";
}
?>

Answer 5

print_r($cast[0]); or you can use $cast[0]['id'] ;

Answer 6

There are two problems with your code, First is that $cast[] is a two-dimensional array so it contains arrays at each of its index, so you must use
$cast[$i]['id']
Where i will be the counter variable that will iterate through all the indexes. Secondly change
$cast['poster']
to
$cast['img']
Hope this helps.