I have a question about JSON PHP Multi Values - php

Question

I want to select the database more values (I already did) and be converted to JSON
I tried all
php
$a = $_GET['name'];
header('Content-Type: application/json');
echo '{"results":[';
$selectSearch = "SELECT * from `users` WHERE `name` LIKE '".$a["term"]."%'";
$rezultatul = $db->query($selectSearch);
if ($rezultatul->num_rows > 0) {
while($row = $rezultatul->fetch_assoc()) {
$name = $row["name"];
$arr = array('id' => $row["id"], 'text' => $row["name"], 'level' => $row["Level"]);
echo json_encode($arr);
}
}
echo ']}';
And he looks like this:
{"results":[{"id":"1","text":"Pompiliu","level":"7"}
{"id":"11","text":"Pompiliu1","level":"100"}]}
But between the two must be like that
{"id":"1","text":"Pompiliu","level":"7"},
{"id":"11","text":"Pompiliu1","level":"100"}
And when there will be 3 results
{"id":"1","text":"Pompiliu","level":"7"},
{"id":"11","text":"Pompiliu1","level":"100"},
{"id":"12","text":"Pompiliu2","level":"100"}

Answer 1

Add to the array with [] and then json_encode.
Don't try and build json strings on your own.
if ($rezultatul->num_rows > 0) {
while($row = $rezultatul->fetch_assoc()) {
$name = $row["name"];
$arr[] = array('id' => $row["id"], 'text' => $row["name"], 'level' => $row["Level"]);
}
}
echo json_encode(["results" => $arr]);