I need to display multiple data row and display json data. Here is my code:
<?php
$dinner_food_category=$_GET['DinnerFoodCategory'];
$conn = mysqli_connect("localhost","taig9_gen_user","GenAdmin1/Pass");
if($conn) {
$select_database = mysqli_select_db($conn,"taig9_genumy");
$select_query = "SELECT food_id,food_name,serving_type,serving_type_amount,singal_unit_weight FROM food_details WHERE category_id IN ('VEG00','VGB00','SUP00','CAK00')";
$result = mysqli_query($conn, $select_query);
if (mysqli_num_rows($result) > 0) {
while($row = mysqli_fetch_assoc($result)) {
$foods_id=$row['food_id'];
$foods_name=$row['food_name'];
$foods_type=$row['serving_type'];
$foods_type_amount=$row['serving_type_amount'];
$singal_unit_weights=$row['singal_unit_weight'];
}
$data = array("FoodId" => $foods_id,"FoodNames" => $foods_name,"FoodType" => $foods_type,"FoodAmount" => $foods_type_amount,"SingalUnitWeight"=> $singal_unit_weights);
}
echo stripslashes(json_encode($data));
}
?>
On each iteration of while you food_ variables are overwritten, and after while loop is over - you have value for the last row only. To avoid this you should add variables to $data inside a while loop with [] notation:
while ($row = mysqli_fetch_assoc($result)) {
$data[] = array(
"FoodId" => $row['food_id'];
"FoodNames" => $row['food_name'];
"FoodType" => $row['serving_type'];
"FoodAmount" => $row['serving_type_amount'];
"SingalUnitWeight" => $row['singal_unit_weight'];
);
}
// using `stripslashes` is useless
echo json_encode($data);
if (mysqli_num_rows($result) > 0) {
$data = [];
foreach ($result as $row) {
$foods_id=$row['food_id'];
$foods_name=$row['food_name'];
$foods_type=$row['serving_type'];
$foods_type_amount=$row['serving_type_amount'];
$singal_unit_weights=$row['singal_unit_weight'];
$data[] = ["FoodId" => $foods_id,"FoodNames" => $foods_name,"FoodType" => $foods_type,"FoodAmount" => $foods_type_amount,"SingalUnitWeight"=> $singal_unit_weights];
}
echo stripslashes(json_encode($data));
}
Related
I want to select the database more values (I already did) and be converted to JSON
I tried all
php
$a = $_GET['name'];
header('Content-Type: application/json');
echo '{"results":[';
$selectSearch = "SELECT * from `users` WHERE `name` LIKE '".$a["term"]."%'";
$rezultatul = $db->query($selectSearch);
if ($rezultatul->num_rows > 0) {
while($row = $rezultatul->fetch_assoc()) {
$name = $row["name"];
$arr = array('id' => $row["id"], 'text' => $row["name"], 'level' => $row["Level"]);
echo json_encode($arr);
}
}
echo ']}';
And he looks like this:
{"results":[{"id":"1","text":"Pompiliu","level":"7"}
{"id":"11","text":"Pompiliu1","level":"100"}]}
But between the two must be like that
{"id":"1","text":"Pompiliu","level":"7"},
{"id":"11","text":"Pompiliu1","level":"100"}
And when there will be 3 results
{"id":"1","text":"Pompiliu","level":"7"},
{"id":"11","text":"Pompiliu1","level":"100"},
{"id":"12","text":"Pompiliu2","level":"100"}
Add to the array with [] and then json_encode.
Don't try and build json strings on your own.
if ($rezultatul->num_rows > 0) {
while($row = $rezultatul->fetch_assoc()) {
$name = $row["name"];
$arr[] = array('id' => $row["id"], 'text' => $row["name"], 'level' => $row["Level"]);
}
}
echo json_encode(["results" => $arr]);
For two objects:
{"publications":[{"nom":"toto","id":"2029","userid":"22","publication":"bla bla bla","time":"2017-02-20 00:00:00","avatar":{}},{"nom":"xxxx","id":"2027","userid":"31","publication":"kjdsfkuds","time":"2017-02-20 00:00:00","avatar":{}}]}
For One object:
{"publications":{"nom":"xxxx","id":"2027","userid":"31","publication":"kjdsfkuds","time":"2017-02-20 00:00:00","avatar":{}}}
i want to have always a json array as a return no matter how the number of objects.
PHP Code:
$result = $conn->query($sql);
$json = new SimpleXMLElement('<xml/>');
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$mydata = $json->addChild('publications');
$mydata->addChild('nom',$row['nom']);
$mydata->addChild('id',$row['id']);
$mydata->addChild('userid',$row['userid']);
/*echo(utf8_encode($row['publication']));*/
$mydata->addChild('publication',utf8_encode($row['publication']));
$mydata->addChild('time',$row['time']);
$mydata->addChild('avatar',$row['avatar']);
}
echo( json_encode ($json));
} else {
echo "0";
}
Well you are not using XML for anything else but convert it to JSON, so there is no need for XML. Use array
$result = $conn->query($sql);
$json = ['publications' => []];
if($result->num_rows > 0)
{
while($row = $result->fetch_assoc())
{
$json['publications'][] = [
'nom' => $row['nom'],
'id' => $row['id'],
'userid' => $row['userid'],
'publication' => $row['publication'],
'time' => $row['time'],
'avatar' => $row['avatar']
];
}
echo json_encode($json);
}
else
{
echo "0";
}
It's a particluar behaviour of SimpleXML.
If you have one child in xml - you will have an object in json, if you have more than one child - you will get array of objects. So, I advise you to rewrite your code using simple arrays instead of xml-approach:
$result = $conn->query($sql);
$json = []; // just array
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
// add new item
$json[] = $row;
// or more specifically
$json[] = [
'nom' => $row['nom'],
'id' => $row['id'],
// more fields that you need
];
}
}
echo json_encode(['publications' => $json]);
I have this php code that i need to change the JSON format i get the data from a mysql db:
// Retrieve data from database
$sql="SELECT nombre FROM deudores ORDER BY fecha ASC LIMIT 10";
$result=mysqli_query($con, $sql);
$emparray = array();
// Start looping rows in mysql database.
while($rows=mysqli_fetch_assoc($result)){
$emparray[] = $rows;
// close while loop
}
//print_r($emparray);
//echo json_encode($emparray);
$output = array(
'c2array' => true,
'size' => array(
0 => count($emparray),
1 => 1,
2 => 1
),
'data' => array()
);
$x = 0;
foreach ($emparray as $value) {
$output['data'][$x] = array();
$output['data'][$x][0] = array();
$output['data'][$x][0][0] = $value;
$x++;
}
echo json_encode($output);
That code print this JSON:
{"c2array":true,"size":[7,1,1],"data":[[[{"nombre":"test"}]],[[{"nombre":"Oscar"}]],[[{"nombre":"Oscar"}]],[[{"nombre":"test"}]],[[{"nombre":"test"}]],[[{"nombre":"oscar"}]],[[{"nombre":"Oscar"}]]]}
but i need the JSON to look like this:
{"c2array":true,"size":[7,1,1],"data":[[[test]],[[Oscar]],[[Oscar]],[[test]],[[test]],[[oscar]],[[Oscar]]]}
How can i achive this?
Thanks in advance!
Use mysql_fetch_row() instead of mysql_fetch_assoc.
while($rows=mysqli_fetch_row($result)){
$emparray[] = $rows;
// close while loop
}
And just set $emparray as value for $output['data']. No need extra work!
$output['data'] = $emparray;
This should make the output like this :
{"c2array":true,"size":[7,1,1],"data":[["test"],["Oscar"],["Oscar"],["test"],["test"],["oscar"],["Oscar"]]}
I have a multidimensional array, and I can not update one of these:
public function get_list($query){
if(mysql_query($query,DB::connect())){
$result = mysql_query($query);
if (mysql_affected_rows() != 0) {
while ($row = mysql_fetch_array($result)) {
$list_annunci[] = array(
"id" => $row["id"],
"title" => $row["title"]
);
if(mysql_query($immagini,DB::connect())){
$result_img = mysql_query($immagini);
if (mysql_affected_rows() != 0) {
while ($row_img = mysql_fetch_array($result_img)) {
$list_annunci[] = array(
"img" => $row_img["path_img"]
);
}
}
}
}
how do I insert the record in the array already declared?
tnx stefania
Use your ids as keys for the original array.
$list_annunci[$id] = array(
Make the database query returns those ids as well.
SELECT id, path_img
Then you can inject or update the right group.
$list_annunci[ $id ]["img"] = $row_img["path_img"];
^
|
from $row_img["id"]
How can i make an array like below through a loop? The text will generated from database!
$listofimages = array(
array( 'titre' => 'PHP',
'texte' => 'PHP (sigle de PHP: Hypertext Preprocessor), est un langage de scripts (...)',
'image' => './images/php.gif'
),
array( 'titre' => 'MySQL',
'texte' => 'MySQL est un système de gestion de base de données (SGDB). Selon le (...)',
'image' => './images/mysql.gif'
),
array( 'titre' => 'Apache',
'texte' => 'Apache HTTP Server, souvent appelé Apache, est un logiciel de serveur (...)',
'image' => './images/apache.gif'
)
);
do something like this,
$result = mysql_query("SELECT * FROM table;");
while($row = mysql_fetch_assoc($result) {
//$row will hold all the fields's value in an array
$mymainarray[] = $row; //hold your array into another array
}
//To display
echo "<pre>";
print_r($mymainarray);
echo "</pre>";
Something like :
$listofimages = array();
foreach ( $rowset as $row ) {
$listofimages[] = array(
'titre' => $row['titre'],
'texte' => $row['texte'],
'image' => $row['image']
);
}
?
If you only select the fields titre, texte and image in your query, then it is just (assuming MySQL):
$listofimages = array();
$result = mysql_query("SELECT titre, texte, image FROM table");
while((row = mysql_fetch_assoc($result))) {
$listofimages[] = $row;
}
mysql_fetch_assoc() will fetch the results in an associative array.
Let's say you have done a query and get a result identifier:
$result = mysql_query("SELECT * FROM table;");
Now you can get every row as an array by using mysql_fetch_assoc($result). Now just make a final array and add all these arrays to it:
$final_array = array();
while($row = mysql_fetch_assoc($result) !== false) {
$final_array[] = $row;
}
print_r($final_array);
$mult_array = array();
$result = mysql_query("SELECT col1,col2,... FROM table");
if(mysql_num_rows($result)>0){
while((row = mysql_fetch_assoc($result)) {
$mult_array[] = $row;
}
}
// if u want to pick some specific cols from data selected from database then-
if(mysql_num_rows($result)>0){
$temp_arr = array();
while((row = mysql_fetch_assoc($result)) {
$temp_arr['col1'] = $row['col1'];
$temp_arr['col2'] = $row['col2'];
//... so on
$mult_array[] = $temp_arr;
}
}
foreach ($listofimages as $image) {
echo '<img src="'.$image['image'].'" />';
}