I'm trying to truncate the table named 'comments' Yet every time I run the script nothing happens. What is wrong with my syntax?
<?php
$con = mysql_connect("localhost","user","pass");
if (!$con)
mysql_select_db("dbname", $con);
mysql_query("TRUNCATE TABLE 'comments'");
mysql_close($con);
?>
The quotes, try changing it to:
$result = mysql_query("TRUNCATE TABLE `comments`");
if ( !$result ) print(mysql_error());
This will also tell you what goes wrong.
you seem to select the database "dbname" only if the connection to the mysql server failed ( $con == FALSE ).
you probably need to change your if condition to:
if ( $con )
mysql_select_db("dbname", $con);
Related
I'm having problems with this php code which needs to create a table in the database specified by the user. But whenever I try to execute the SQL it tells me no database selected. My code is as follow
<?php
$con = mysql_connect("127.0.0.1","peter")
or die('Error connecting to mysql'); // Check connection
// Create table
mysql_select_db("USE Ebooks");//Select Database
$foldername = mysql_real_escape_string($_POST['foldername']);//Obtain Folder Name
$sql = sprintf("CREATE TABLE %s (ID CHAR(3) ,Books CHAR(30))", $foldername);
mysql_query($sql) or die(mysql_error());
mysql_close($con);
?>
Use
mysql_select_db( "Ebooks" ) or die( 'Error'. mysql_error() );
Use this code:
mysql_select_db("Ebooks");//Select Database
I need to retrieve the auto increment field from my database table. I tried the following but $id is always just empty.
The insert works too.
My table is as follows:
idint(9) NOT NULL auto_increment,
and id is set as primary
What am I doing wrong?
$conn = mysql_connect($host,$username,$password);
mysql_select_db($database, $conn) or die( "Unable to select database");
include "update_activity.php";
updateActivity("logged in", "On Break");
$date = date("m/d/y"); $starttime = time();
$sesh = $_SESSION['fname']." ".$_SESSION['lname'];
$q = "INSERT INTO `breaks` (date, starttime, user) VALUES ('".$date."', '".$starttime."', '".$sesh."')";
$query = mysql_query($q, $conn);
$id = mysql_insert_id($conn);
echo var_dump($id); exit;
edited to show my more recent attempts
Have read all comments given and your replies to each.
Only one of these is possible:
Either the query works properly OR
You are not getting the generated primary key.
Both of these can never be true.
Define, how you know query is working? Do you know the max PK before and after the running query? Is the insert happening from some other place or thread or even other user? the query is working properly from code or from your mysql client?
To diagnose the problem, we have to go though the normal way.
Dump your generated query before calling mysql_query.
Wrap a error checking system around your query call so php can tell you if the query worked or not. I am sure just by these two steps you will realize the root cause of the problem.
error_reporting(E_ALL);
ini_set('display_errors','on');
echo "before calling: $q\n";
$query = mysql_query($q, $conn);
if(!$query)
{
echo "Error:" . mysql_error($conn);
return;
}
echo " generated id:" . mysql_insert_id($conn);
#adelphia as far as i get the idea there is a problem in the query that is executed.
plz check the query properly
Borrow a lead from this code extracted from here:
http://php.net/manual/en/function.mysql-insert-id.php
<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('mydb');
mysql_query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n", mysql_insert_id());
?>
The problem with your insert query
$q = "INSERT INTO `breaks` (date, starttime, user)
VALUES ('".$date."',
'".$starttime."',
'".$_SESSION['fname'] $_SESSION['lname']."')";
try with this
and main thing you are using most of the deprecated "mysql" things like "mysql_insert_id()"
store the values that u want to pass into an array or variable and pass it in the insert query.
its should work fine then...
Thanks for taking a look:
Here is the php I'm using to insert the data into the table
<?php
session_start();
//sets a variable from a session value
if (isset($_SESSION['sv_01'])) {$sv_01=$_SESSION['sv_01'];} else {$sv_01="";}
//to test that the variable has been set and is not empty
echo $sv_01;
//define database log in stuff
$username="username123";
$password="password123";
$database="database01";
$table="my_table";
$dbaddress="123.123.123.123";
//connect to dbserver
$con=mysql_connect($dbaddress,$username,$password);
if (!$con)
{
die('Could not connect:' .mysql_error());
}
//select the db
mysql_select_db($database) or die( "Unable to select database");
//insert data from variables
mysql_query("INSERT INTO $table
(
$sv_01
)
VALUES
(
'$sv_01'
)");
mysql_close($con);
?>
I run this, and then go to check out the contents of the DB. Using MySQL workbench I open the connection and the database and table in question, select all rows and there is no data contained in the table.
MySQL info:
Collation: latin1 - default
collation Engine: MyISAM
datatype: sv_01 VARCHAR (255)
default: NULL
Any ideas what I am doing incorrectly?
I believe that the name of the field is sv_01 not $sv_01
I would try:
$query = "INSERT INTO $table (sv_01) VALUES ('$sv_01')";
Update (dedicated to tadman):
A small piece of advice: DO NOT use mysql_query
Use localhost insted af your IP (if possible), and make your connection easy to read:
$con=mysql_connect($dbaddress,$username,$password) OR DIE mysql_error();
AND you also have to give you mysql_query a variable:
$mysql = mysql_query("INSERT INTO $table ($sv_01) VALUES ('".$sv_01."');");
:)
<?php
$link = mysql_connect('localhost', 'sc2broad_testing', '1BananA2');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_query("INSERT INTO Persons (re) VALUES ('Peter')");
mysql_close($link);
?>
This code isnt taking the value 'peter' and inserting it into persons row 're'?? should i attempt to tell it which database somewhere? thanks . it is saying it connects successfully even if i am not telling it which database to connect to? only the server and user? i am confused.
I think you may need to specify the database that you are querying to?
mysql_select_db('db_name', $link)
If not try changing the mysql_query to:
print("INSERT INTO Persons (re) VALUES ('Peter')");
You can then check the query is correct and test it works outside of the php.
I have this query:
$res=mysql_query("SELECT * FROM `t_modules` WHERE nPageM='61'") or die(mysql_error());
In phpmyadmin it returns (as expected) 2 rows but on page it returns 0.
If i use
$res=mysql_query("SELECT * FROM `t_modules` WHERE nPageM<>'61'") or die(mysql_error());
or
$res=mysql_query("SELECT * FROM `t_modules`") or die(mysql_error());
it runs on the page correctly it's just the WHERE and = combination that doesn't work
I also checked that the type for nPageM is int(11)
UPDATE
I can run comparisons on other columns in the table but not on nPageM
$res=mysql_query("SELECT * FROM `t_modules` WHERE id_md='5'") or die(mysql_error());
Is working. But i still don't have a clue about why it's not working on the nPageM column
have you ensured that you have included a connection to the databse in your php script before running this code?
<?php
$con = mysql_connect('sqluser', 'sqlpassword', 'sqlserver');
$db = mysql_select_db('dbame', $con);
//now, make sure it's connecting
if (!$con) {
die('mysql connection error' . mysql_error());
}
if (!$db) {
die('mysql Database error' . mysql_error());
}
?>
Instead try putting brackets around it:
$res=mysql_query("SELECT * FROM `t_modules` WHERE (nPageM<>'61') ") or die(mysql_error());