I need to retrieve the auto increment field from my database table. I tried the following but $id is always just empty.
The insert works too.
My table is as follows:
idint(9) NOT NULL auto_increment,
and id is set as primary
What am I doing wrong?
$conn = mysql_connect($host,$username,$password);
mysql_select_db($database, $conn) or die( "Unable to select database");
include "update_activity.php";
updateActivity("logged in", "On Break");
$date = date("m/d/y"); $starttime = time();
$sesh = $_SESSION['fname']." ".$_SESSION['lname'];
$q = "INSERT INTO `breaks` (date, starttime, user) VALUES ('".$date."', '".$starttime."', '".$sesh."')";
$query = mysql_query($q, $conn);
$id = mysql_insert_id($conn);
echo var_dump($id); exit;
edited to show my more recent attempts
Have read all comments given and your replies to each.
Only one of these is possible:
Either the query works properly OR
You are not getting the generated primary key.
Both of these can never be true.
Define, how you know query is working? Do you know the max PK before and after the running query? Is the insert happening from some other place or thread or even other user? the query is working properly from code or from your mysql client?
To diagnose the problem, we have to go though the normal way.
Dump your generated query before calling mysql_query.
Wrap a error checking system around your query call so php can tell you if the query worked or not. I am sure just by these two steps you will realize the root cause of the problem.
error_reporting(E_ALL);
ini_set('display_errors','on');
echo "before calling: $q\n";
$query = mysql_query($q, $conn);
if(!$query)
{
echo "Error:" . mysql_error($conn);
return;
}
echo " generated id:" . mysql_insert_id($conn);
#adelphia as far as i get the idea there is a problem in the query that is executed.
plz check the query properly
Borrow a lead from this code extracted from here:
http://php.net/manual/en/function.mysql-insert-id.php
<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('mydb');
mysql_query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n", mysql_insert_id());
?>
The problem with your insert query
$q = "INSERT INTO `breaks` (date, starttime, user)
VALUES ('".$date."',
'".$starttime."',
'".$_SESSION['fname'] $_SESSION['lname']."')";
try with this
and main thing you are using most of the deprecated "mysql" things like "mysql_insert_id()"
store the values that u want to pass into an array or variable and pass it in the insert query.
its should work fine then...
Related
I've been spending a couple of hours trying to write mysqli queries to insert a new row in a database (with a primary key ID) and then select the ID of the new row. My code as it currently is:
<?php
include('connectionData.php');
$conn = mysqli_connect($server, $user, $pass, $dbname, $port)
or die('Connection error');
if(isset($_POST['submit'])) {
$pnum = $_POST['pnum'];
$phone_insert_text = "INSERT INTO `voterdatabase`.`phone` (`pnum`) VALUES (?)";
$phone_insert_query = $conn->prepare($phone_insert_text);
$phone_insert_query->bind_param('s', $pnum);
$phone_insert_query->execute();
$phone_select_text = "SELECT phone_id FROM voterdatabase.phone WHERE pnum=?";
$phone_select_query = $conn->prepare($phone_select_text);
$phone_select_query->bind_param('s', $pnum);
$phone_select_query->execute();
$phone_select_query->bind_result($phone_id);
echo $phone_id;
?>
$phone_insert_query executes without issue. But $phone_select_query doesn't appear to run at all, as echo $phone_id; has no effect. What might be going on here? I'm able to run the query directly in MySQLWorkbench.
Note that I previously tried doing this in one query using SELECT LAST_INSERT_ID();, but mysqli fails to execute any query containing that.
Please try this
$lastInsertID= mysqli_insert_id($conn);
Use insert_id property:
<?php
include('connectionData.php');
$conn = mysqli_connect($server, $user, $pass, $dbname, $port)
or die('Connection error');
if(isset($_POST['submit'])) {
$pnum = $_POST['pnum'];
$phone_insert_text = "INSERT INTO `voterdatabase`.`phone` (`pnum`) VALUES (?)";
$phone_insert_query = $conn->prepare($phone_insert_text);
$phone_insert_query->bind_param('s', $pnum);
$phone_insert_query->execute();
$phone_id = $conn->insert_id;
echo $phone_id;
?>
If you wish to be able to use the available functions to get the last inserted id, like mysqli_insert_id(), your table must have an AUTO_INCREMENT column. If not you will not get the id.
Also, even if you have the required columns, this will require two calls. To get around this, what you could do is something like create a stored procedure to do your insert for you and return the inserted id from the procedure.
No matter what I try - I cant seem to pull the last created id of the query I inserted to mySql.
I read here about syntaxes that are deprecated and all sort of code that wont work.
I tried both functions (I use bigint) so I understand that this is how to go:
if (($result = $conn->query("SELECT LAST_INSERT_ID()")) === FALSE) {
die(mysql_error());
}
if ($result->fetch_assoc()) {
$id = $row[0];
echo $id;
}
but nothing!!
Can someone please just give me a full simple php code sample of how to do it?
You can use $result = $conn->insert_id; to know last inserted row
Try this to get the last insert Id,
echo mysql_insert_id();
Dont use mysql its depricated, instead use mysqli or PDO. To get last inserted record use mysqli_inserted_id(). The following shows the snipped how to use-
<?php
$link = mysqli_connect("localhost", "username", "password", "dbname") or die('Facing some problem connecting with database');
$query = "INSERT INTO `table_name` VALUES (v1, v2, v3...vn)";
mysqli_query($link, $query);
printf ("New Record with id %d inserted", mysqli_insert_id($link));
I use PHP for server side scripting and mysql server for database.
If I use mysql_insert_id() then it gives "0" and use of LAST_INSERT_ID() causes error "object returned empty description".This error I see when I debug on client-side in objective-C.
My table's id column is auto generated. I dont' pass id explicitly.
Below is the PHP code :
// Connect to our database
$db = Frapi_Database::getInstance();
$sql = "INSERT INTO userTrip
(userId, fromLat, fromLon, fromLoc, fromPOI,
toLat, toLon, toLoc, toPOI,
tripFinished, isMatched, departureTime, createdAt)
values
(".$userId.",".$fromLat.",".$fromLon.", GeomFromText('POINT($fromLat $fromLon)')".",'".$fromPOI."',".$toLat.","
.$toLon.", GeomFromText('POINT($toLat $toLon)')".",'".$toPOI."',0,0,'".
$departureTime."','".date('Y-m-d H:i:s')."')";
$stmt = $db->prepare($sql);
if (!$stmt->execute())
throw new Frapi_Error('ERROR_INSERTING_RECORD');
$lastId = LAST_INSERT_ID();
$this->data['tripId'] = $lastId;
$db = null;
Frapi Database extends from PDO, so you would use this:
$lastId = $db->lastInsertId();
See also: PDO::lastInsertId()
Try this (if you use mysqli):
$db->insert_id;
Or (if you use PDO):
$db->lastInsertId();
are you looking for this ?
to get the last inserted id
mysql_insert_id();
mysql_insert_id
Try with
$id = mysql_insert_id();
it will work for you,try this link mysql_insert_id
and this
If your table have AUTO INCREMENT column like UserID,Emp_ID,.. then you can use this query to get last inserted record
SELECT * FROM table_name where UserID=(select MAX(UserID)from table_name)
In PHP code:
$con = mysqli_connect('localhost', 'userid', 'password', 'database_name');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
$sql = "SELECT * FROM table_name where UserID=(select MAX(UserID)from table_name)";
$result = mysqli_query($con, $sql);
Then you can use fetched data as your requirement
This a bit looks complicated, i want to get the id column value of the processed query.
example:
$qu = mysql_query("INSERT INTO msgs (msg,stamp) VALUES('$v1','$v2')");
i want to get the ID of this query after storing the infos in database.
if it's impossible, is getting the last ID record and adding 1 will be safe and guaranteed?
Note: i use PHP and mySQL
Thanks
Here are the MySQL docs on this.
http://dev.mysql.com/doc/refman/5.1/en/getting-unique-id.html
If it's an auto_increment column, use the PHP function mysql_insert_id.
If you are using standard mysql in PHP, all you have to do, is to use mysql_insert_id() which takes resource $link as parameter (your mysql connection)
http://php.net/manual/en/function.mysql-insert-id.php
Basic usage:
<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('mydb');
mysql_query("INSERT INTO mytable (product) values ('some product')");
echo 'Last inserted record has id of ' . mysql_insert_id();
?>
No, it is not safe to grab the highest id and just add 1 and use that as the new id. This is what's known as a race condition. If two queries attempt to do this operation at the same time, it could be that they both select the SAME highest id, both attempt to add 1, and then BOTH attempt to use the same id (which would be bad).
It's much better to use AUTO_INCREMENT fields as you're doing, and you can retrieve the inserted id in PHP as follows (from http://php.net/manual/en/function.mysql-insert-id.php):
<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('mydb');
mysql_query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n", mysql_insert_id());
?>
Here's the code:
$qu = mysql_query("INSERT INTO msgs (msg,stamp) VALUES('$v1','$v2')");
$recent_id = mysql_insert_id();
The variable recent_id is what you are looking for.
Getting the last ID record and adding 1 MAY NOT be safe and IS NOT guaranteed. You are better off using the solution that I have indicated if you really want to play it safe.
Hope it helps.
Hope this helps:
int mysql_insert_id ([ resource $link_identifier ] )
http://us3.php.net/mysql_insert_id
check here if it`s not problem for you to use mysqli for php
The 'id' field of my table auto increases when I insert a row. I want to insert a row and then get that ID.
I would do it just as I said it, but is there a way I can do it without worrying about the time between inserting the row and getting the id?
I know I can query the database for the row that matches the information that was entered, but there is a high change there will be duplicates, with the only difference being the id.
$link = mysqli_connect('127.0.0.1', 'my_user', 'my_pass', 'my_db');
mysqli_query($link, "INSERT INTO mytable (1, 2, 3, 'blah')");
$id = mysqli_insert_id($link);
See mysqli_insert_id().
Whatever you do, don't insert and then do a "SELECT MAX(id) FROM mytable". Like you say, it's a race condition and there's no need. mysqli_insert_id() already has this functionality.
Another way would be to run both queries in one go, and using MySQL's LAST_INSERT_ID() method, where both tables get modified at once (and PHP does not need any ID), like:
mysqli_query($link, "INSERT INTO my_user_table ...;
INSERT INTO my_other_table (`user_id`) VALUES (LAST_INSERT_ID())");
Note that Each connection keeps track of ID separately (so, conflicts are prevented already).
The MySQL function LAST_INSERT_ID() does just what you need: it retrieves the id that was inserted during this session. So it is safe to use, even if there are other processes (other people calling the exact same script, for example) inserting values into the same table.
The PHP function mysql_insert_id() does the same as calling SELECT LAST_INSERT_ID() with mysql_query().
As to PHP's website, mysql_insert_id is now deprecated and we must use either PDO or MySQLi (See #Luke's answer for MySQLi). To do this with PDO, proceed as following:
$db = new PDO('mysql:dbname=database;host=localhost', 'user', 'pass');
$statement = $db->prepare('INSERT INTO people(name, city) VALUES(:name, :city)');
$statement->execute([':name' => 'Bob', ':city' => 'Montreal']);
echo $db->lastInsertId();
As #NaturalBornCamper said, mysql_insert_id is now deprecated and should not be used. The options are now to use either PDO or mysqli. NaturalBornCamper explained PDO in his answer, so I'll show how to do it with MySQLi (MySQL Improved) using mysqli_insert_id.
// First, connect to your database with the usual info...
$db = new mysqli($hostname, $username, $password, $databaseName);
// Let's assume we have a table called 'people' which has a column
// called 'people_id' which is the PK and is auto-incremented...
$db->query("INSERT INTO people (people_name) VALUES ('Mr. X')");
// We've now entered in a new row, which has automatically been
// given a new people_id. We can get it simply with:
$lastInsertedPeopleId = $db->insert_id;
// OR
$lastInsertedPeopleId = mysqli_insert_id($db);
Check out the PHP documentation for more examples: http://php.net/manual/en/mysqli.insert-id.php
I just want to add a small detail concerning lastInsertId();
When entering more than one row at the time, it does not return the last Id, but the first Id of the collection of last inserts.
Consider the following example
$sql = 'INSERT INTO my_table (varNumb,userid) VALUES
(1, :userid),
(2, :userid)';
$sql->addNewNames = $db->prepare($sql);
addNewNames->execute(array(':userid' => $userid));
echo $db->lastInsertId();
What happens here is that I push in my_table two new rows. The id of the table is auto-increment. Here, for the same user, I add two rows with a different varNumb.
The echoed value at the end will be equal to the id of the row where varNumb=1, which means not the id of the last row, but the id of the first row that was added in the last request.
An example.
$query_new = "INSERT INTO students(courseid, coursename) VALUES ('', ?)";
$query_new = $databaseConnection->prepare($query_new);
$query_new->bind_param('s', $_POST['coursename']);
$query_new->execute();
$course_id = $query_new->insert_id;
$query_new->close();
The code line $course_id = $query_new->insert_id; will display the ID of the last inserted row.
Hope this helps.
Try like this you can get the answer:
<?php
$con=mysqli_connect("localhost","root","","new");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
mysqli_query($con,"INSERT INTO new values('nameuser','2015-09-12')");
// Print auto-generated id
echo "New record has id: " . mysqli_insert_id($con);
mysqli_close($con);
?>
Have a look at following links:
http://www.w3schools.com/php/func_mysqli_insert_id.asp
http://php.net/manual/en/function.mysql-insert-id.php
Also please have a note that this extension was deprecated in PHP 5.5 and removed in PHP 7.0
I found an answer in the above link http://php.net/manual/en/function.mysql-insert-id.php
The answer is:
mysql_query("INSERT INTO tablename (columnname) values ('$value')");
echo $Id=mysql_insert_id();
Try this... it worked for me!
$sql = "INSERT INTO tablename (row_name) VALUES('$row_value')";
if (mysqli_query($conn, $sql)) {
$last_id = mysqli_insert_id($conn);
$msg1 = "New record created successfully. Last inserted ID is: " . $last_id;
} else {
$msg_error = "Error: " . $sql . "<br>" . mysqli_error($conn);
}
Another possible answer will be:
When you define the table, with the columns and data it'll have. The column id can have the property AUTO_INCREMENT.
By this method, you don't have to worry about the id, it'll be made automatically.
For example (taken from w3schools )
CREATE TABLE Persons
(
ID int NOT NULL AUTO_INCREMENT,
LastName varchar(255) NOT NULL,
FirstName varchar(255),
Address varchar(255),
City varchar(255),
PRIMARY KEY (ID)
)
Hope this will be helpful for someone.
Edit: This is only the part where you define how to generate an automatic ID, to obtain it after created, the previous answers before are right.