I am trying to find out the years, months, days and minutes between 2 timestamps.
I have used the following code, but it is not working:
$diff = time()-$res['asked_on'];
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
I am getting the output as:
0
0
0
$res['asked_on'] = 1331980897 ( It is also a time stamp getting from time() function )
If the $res['asked_on'] is a string of date format, you should turn it to timestamp by using strtotime.
And if your php >= 5.3, you could take a look at the method php provide to you: DateTime::diff
Related
I'm facing some problem while calculating the difference between two dates because of Date Format, please help me to fix this issue.
Date 1 - (Format: d/m/Y)
date_default_timezone_set("Asia/Kolkata");
$date1 = date('d/m/Y');
//Output - 20/05/2020
Date 2 - (Format: d/m/Y)
$date2 - 01/27/2020
My Code -
$diff = abs($date2 - $date1);
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
// Print the result
printf("%d years, %d months, %d days", $years, $months, $days);
You don't have to calculate days, month etc manually. There is already DateTime Class available in PHP which you can leverage.
$date1 = DateTime::createFromFormat('d/m/Y', '20/05/2020'); // Use $date1 = new DateTime('NOW'); For Current Time
$date2 = DateTime::createFromFormat('d/m/Y', '25/05/2020');
$interval = $date1->diff($date2);
printf("%d years, %d months, %d days", $interval->y, $interval->m, $interval->d);
Official PHP Documentation: PHP DateTime Class
First you shoud use date format(Format: Y/m/d) and second use strtotime to convert date to seconds because abs function working with numeric values. try following code :
date_default_timezone_set("Asia/Kolkata");
$date1 = strtotime(date('Y/m/d'));
$date2 = strtotime('2020/05/27');
$diff = abs($date2 - $date1);
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
// Print the result
printf("%d years, %d months, %d days", $years, $months, $days);
Output :
0 years, 0 months, 7 days
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 6 years ago.
I need to find the different between 2 timestamp values ,how to calculate it
$time1 ='2016-08-31T07:00:00';
$time2 ='2016-08-31T08:45:00';
I need output time value as 1h 45m
How to get desired output
<?php
$time1 ='2016-08-31T07:00:00';
$time2 ='2016-08-31T08:45:00';
$d = strtotime($time2) - strtotime($time1);
echo gmdate("g", $d),'h ',gmdate('i',$d),'m ';
$date_a = new DateTime('2016-08-31T07:00:00');
$date_b = new DateTime('2016-08-31T08:45:00');
$interval = date_diff($date_a,$date_b);
echo $interval->format('%h Hours:%i Min:%s sec');
You Can test the code Here
Use strtotime() to convert datetime in timestamps and get the difference between 2 times.
Now, Divide the difference into desire format. Use below code.
$time1 ='2016-08-31T07:00:00';
$time2 ='2016-08-31T08:45:00';
$diff = abs(strtotime($time1) - strtotime($time2));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));
$minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
echo $hours . "h " .$minuts."m";
Output
1h 45m
Live Demo : Click Here
Use this code,
$datetime1 = strtotime("09:00");
$datetime2 = strtotime($items['duration']);
$interval = abs($datetime2 - $datetime1);
$min = round($interval / 60);
$d = floor ($min / 1440);
$h = floor (($min - $d * 1440) / 60);
$m = $min - ($d * 1440) - ($h * 60);
if (!$m) {
$m = '00';
}
echo $h."h:".$m."m";
$date2 = $row['returnbefore'];
$date1 = date('Y/m/d');
$diff = abs(strtotime($date1) - strtotime($date2));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$final = ($days * 10) ;
echo $final;
i want to do a library system when user return book will check the return date between current date and calculate a fine to user which multiply day by 10 .
what step i left ? and i wan set the current time is my computer time so i can test it
This is a fairly simple problem to accomplish using DateTime and DateInterval.
$now = new DateTime();
$dueDate = new DateTime($row['returnbefore']);
$lateInterval = $now - $dueDate;
$daysLate = $lateInterval->format('d');
$fine = $daysLate > 0 ? intval(floor($daysLate)) * 10 : 0; // This means that you are not charged for a late day until the end of the day
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 7 years ago.
I am trying to show the difference in days and months between 2 dates
$date1 = $start;
$date2 = $end;
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
However this shows as 0 years, 0 months, 0 days
The dates in $start and $end are in the format DD/MM/YYYY
As you have stated within your comment that The dates in $start and $end are in the format DD/MM/YYYY. So you need to first replace that into d-m-Y using str_replace or DateTime::createFromFormat so try using like as
$date1 = str_replace('/','-',$start);
$date2 = str_replace('/','-',$end);
PHP date conversion to strtotime
I want to subtract one date to another using php and display result in the days - hours - min - sec format. How i do this using php . I tried this using time stamp but it does not give proper values. please give suggestion
For ex : from date 2012-04-27 19:30:56 to date 2012-04-27 19:37:56
i used this code
if(strtotime($history['datetimestamp']) > strtotime($lasttime)) {
$totalelapsed1 = (strtotime($history['datetimestamp'])-strtotime($lasttime));
if($totalelapsed1 > 60 ) {
$sec = $totalelapsed1%60;
$min = round($totalelapsed1/60 , 0);
$minute = $min + $minute;
$second = $sec + $second;
// echo $min. " min " .$sec." sec";
} else {
//echo "0 min " . $totalelapsed1." sec";
$minute = 0 + $minute;
$second = $totalelapsed1 + $second;
}
} else {
$minute = 0 + $minute;
$second = 0 + $second;
// echo "0 min 0 sec";
}
From how to subtract two dates and times to get difference by VolkerK:
You have to use like this:-
<?php
//$now = new DateTime(); // current date/time
$now = new DateTime("2010-07-28 01:11:50");
$ref = new DateTime("2010-07-30 05:56:40");
$diff = $now->diff($ref);
printf('%d days, %d hours, %d minutes', $diff->d, $diff->h, $diff->i);
prints 2 days, 4 hours, 44 minutes
see http://docs.php.net/datetime.diff
edit: But you could also shift the problem more to the database side, e.g. by storing the expiration date/time in the table and then do a query like
... WHERE key='7gedufgweufg' AND expires<Now()
Many rdbms have reasonable/good support for date/time arithmetic.
Link Url:- how to subtract two dates and times to get difference
http://www.webpronews.com/calculating-the-difference-between-two-dates-using-php-2005-11
I suggest to use DateTime and DateInterval objects.
$date1 = new DateTime("2007-03-24");
$date2 = new DateTime("2009-06-26");
$interval = $date1->diff($date2);
echo "days difference ".$interval->d." days ";
read more php DateTime::diff manual
Try using DateTime:diff().
Examples are provided on that page.
This script resolve my issue
$date1 = date("d-m-Y H:i:s",strtotime($date1));
$date2 = date("d-m-Y H:i:s",strtotime($lasttime));
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24)); $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24)); $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60)); $minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60); $seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);