This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 7 years ago.
I am trying to show the difference in days and months between 2 dates
$date1 = $start;
$date2 = $end;
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
However this shows as 0 years, 0 months, 0 days
The dates in $start and $end are in the format DD/MM/YYYY
As you have stated within your comment that The dates in $start and $end are in the format DD/MM/YYYY. So you need to first replace that into d-m-Y using str_replace or DateTime::createFromFormat so try using like as
$date1 = str_replace('/','-',$start);
$date2 = str_replace('/','-',$end);
PHP date conversion to strtotime
Related
I'm facing some problem while calculating the difference between two dates because of Date Format, please help me to fix this issue.
Date 1 - (Format: d/m/Y)
date_default_timezone_set("Asia/Kolkata");
$date1 = date('d/m/Y');
//Output - 20/05/2020
Date 2 - (Format: d/m/Y)
$date2 - 01/27/2020
My Code -
$diff = abs($date2 - $date1);
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
// Print the result
printf("%d years, %d months, %d days", $years, $months, $days);
You don't have to calculate days, month etc manually. There is already DateTime Class available in PHP which you can leverage.
$date1 = DateTime::createFromFormat('d/m/Y', '20/05/2020'); // Use $date1 = new DateTime('NOW'); For Current Time
$date2 = DateTime::createFromFormat('d/m/Y', '25/05/2020');
$interval = $date1->diff($date2);
printf("%d years, %d months, %d days", $interval->y, $interval->m, $interval->d);
Official PHP Documentation: PHP DateTime Class
First you shoud use date format(Format: Y/m/d) and second use strtotime to convert date to seconds because abs function working with numeric values. try following code :
date_default_timezone_set("Asia/Kolkata");
$date1 = strtotime(date('Y/m/d'));
$date2 = strtotime('2020/05/27');
$diff = abs($date2 - $date1);
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
// Print the result
printf("%d years, %d months, %d days", $years, $months, $days);
Output :
0 years, 0 months, 7 days
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 4 years ago.
I used the following code to find out the time past between two dates:
$date1 = "1900-00-00";
$date2 = "2000-00-00";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d daysn", $years, $months, $days);
But this prints 100 years, 0 months, 24 daysn, instead of 100 years, 0 months, 0 daysn
What is going on?
You can use the DateTime::diff method of the DateTime class to get the difference between two dates. You don't need to calculate the difference yourself:
<?php
$date1 = "1900-00-00";
$date2 = "2000-00-00";
$dt1 = new DateTime($date1);
$dt2 = new DateTime($date2);
$diff = $dt1->diff($dt2);
printf("%d years, %d months, %d days", $diff->y, $diff->m, $diff->d);
//output: 100 years, 0 months, 0 days
You can also use the procedural style to get and output the difference in two lines:
$diff = date_diff(new DateTime("1900-00-00"), new DateTime("2000-00-00"));
printf("%d years, %d months, %d days", $diff->y, $diff->m, $diff->d);
//output: 100 years, 0 months, 0 days
demo: https://ideone.com/rosaJJ
Here is the easiest solution :-
$date1 = "1900-00-00";
$date2 = "2000-00-00";
$expDate = date_create($date2);
$todayDate = date_create($date1);
$diff = date_diff($todayDate, $expDate);
printf("%d years, %d months, %d days", $diff->y, $diff->m, $diff->d);
You will get your expected result .
Im trying to return the difference between 2 dates, i'm working according to the example found on stackoverflow
My Problem? Im getting completely the wrong results returned, the following code returns 30 years, 0 months, 9 days, when it should obviously be only 7 days or 1 week.
Code follows below:
date_default_timezone_set('America/Los_Angeles');
$pickupDate = '2016-10-13';
$returnDate = 2016-10-20;
$diff = abs(strtotime($pickupDate) - strtotime($returnDate));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
Any input appreciated
just put single quote in return date like $returnDate = '2016-10-20'; and you can use date_diff() function of php like,
$daysdiffernce = date_diff(date_create('2016-10-13'),date_create('2016-10-20'));
echo $daysdiffernce->format("%R%a days");
and this will give exactly +7days answer
First, the code doesn't take into account leap years, varying length of months and things like that.
There is actually a function in php for this, please check the link for details: http://php.net/manual/en/datetime.diff.php , and an example taken:
$datetime1 = new DateTime('2016-10-13');
$datetime2 = new DateTime('2016-10-20');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%y years, %m months, %d days');
Try this, it will give you differ in date, and , time, minutes, hour ,second ,and etc.
date_default_timezone_set('America/Los_Angeles');
$now = '2016-10-13';
$returnDate = '2016-10-20';
$start = date_create($returnDate);
$end = date_create($now);
$diff=date_diff($end,$start);
print_r($diff);
DEMO
From the manual
$pickupDate = new DateTime('2016-10-13');
$returnDate = new DateTime('2016-10-20');
$interval = $pickupDate->diff($returnDate);
echo $interval->format('%R%a days');
http://php.net/manual/en/datetime.diff.php
date_default_timezone_set('America/Los_Angeles');
$pickupDate = '2016-10-13';
$returnDate = '2016-10-20'; //use signle quote same as pickupDate
$diff = abs(strtotime($returnDate) - strtotime($pickupDate)); // change the order
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
Thanks
I want to find difference between 2 dates in php.But I am not getting exact difference.
please help me.
The output I must get as "2 years 0 months 0 days".
But I am getting as "1 years 12 months and 4 days".
where I am wrong?
$createddate="2015-12-24";
//find difference between the dates present-createddate of user
$now = time(); // present time
$your_date = strtotime($createddate);
$difference = abs($now - $your_date);
echo $difference;
// Years, months and days version
$years = floor($difference / (365*60*60*24));
//echo $years;
$months = floor(($difference - $years * 365*60*60*24) / (30*60*60*24));
//echo $months;
$days = floor(($difference - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
//echo $days;
$membersince .= $years.' years '.$months.' months and '.$days.' days';
<?php
$datetime1 = new DateTime();
$datetime2 = new DateTime('2015-12-24');
$interval = $datetime1->diff($datetime2);
$elapsed = $interval->format('%y years, %m months, %d days');
echo $elapsed;
See it in action
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 9 years ago.
In php, if you have a string in the date/time format example "2013-09-08 00:25:31", how can you compare that with the current time, and get the difference in number of days?
Thanks.
you should check DateTime::diff
you may do it like
$now = new DateTime();
$prev = new DateTime('2013-09-08');
$interval = $now->diff($prev);
echo $interval->format('%R%a days');
You can use strtotime() to convert two dates to unix time and then calculate the number of seconds between them. From this it's rather easy to calculate different time periods.
$date1 = "2007-03-24";
$date2 = "2009-06-26";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
printf("%d years, %d months, %d days\n", $years, $months, $days);
You check this link for more answers.