i have two table. Records and Villas
Records table:
ID, VID (Villa ID), NAME, PRICE
Villas table:
ID, NAME (Villa NAME), PHOTOS etc.
I using this SQL:
SELECT records.id, villa_name AS (SELECT name FROM villas WHERE id = records.vid), records.name
FROM records WHERE records.id = 5
What is wrong ?
Try
SELECT records.id, records.name AS record_name, villas.name AS villa_name FROM records INNER JOIN villas ON records.vid = villas.id WHERE records.id = 5
Edit: Incorporated suggestion from Mark Bannister, below.
You should use JOIN here.
SELECT r.id, r.name, v.name
FROM records r
INNER JOIN villas v ON v.id = r.vid
WHERE records.id = 5;
Related
In first table album has id and second table album_details has sub_id which relates from album table id
I need to display count for separate id value.
SELECT DISTINCT B.SUB_ID, A . * , B.CONTENT_VALUE AS detail,
(SELECT COUNT( ID )
FROM album_details WHERE A.ID = B.SUB_ID ) AS count
FROM album AS A, album_details AS B
WHERE A.WEBSITE_ID = '571710720'
AND A.ID = B.SUB_ID
GROUP BY B.SUB_ID
LIMIT 0 , 30
Now count column shows 40 for all rows but need to display 'count' 6 for 'id=4', 'count' 3 for 'id=2'
SELECT count(SUB_ID),SUB_ID from album_details group by SUB_ID
GROUP BY is your weapon of choice.
SELECT
a.ID,
a.CONTENT_VALUE,
COUNT(ad.ID)
FROM albums AS a
LEFT JOIN album_details AS ad ON a.ID = ad.SUB_ID
GROUP BY a.ID
Feel free to add your WHERE before the GROUP BY.
Lets say first table is A and second table is B then query will be like this
select a.ID, count(b.SUB_ID) AS total
FROM A LEFT JOIN B ON A.ID = B.SUB_ID
Group by B.SUB_ID.
It might help you. If not then ask please.
select count(sub_id) as count1 from album_details where sub_id in(select id from album) WHERE album.WEBSITE_ID = '571710720'
AND album.ID = album_details.SUB_ID
Let's say i have 3 tables:
table: SONGS
cell: ID primary key
cell: TITLE
cell: ADD_TIME
table: CATEGORIES
cell: ID primary key
cell: title
table: SONGS_CATEGORIES
cell: ID primary key
cell: SONG_ID
cell: CATEGORY_ID
Then let's assume that I have 3 songs(with id's 0, 1, 2), and I have 5 categories(rock, pop, rap and so on) and respectively, their id's(0, 1, 2...). How my sql query should look like, if I want to be able to select more than one category, then I need to look into table SONGS_CATEGORIES and get all songs_id with category id I selected, and then i get songs from table SONGS with those id's?
Hope i explained what i need pretty well, English is not my native language.
If you already know the ID numbers of the categories that you're wanting songs from then the following should do the trick:
SELECT *
FROM SONGS s
JOIN SONGS_CATEGORIES sc
ON s.ID = sc.SONG_ID
WHERE sc.CATEGORY_ID IN (#id1, #id2, #id3...#idN);
If you only know the names of the categories you want the songs for then you can use this:
SELECT *
FROM SONGS s
JOIN SONGS_CATEGORIES sc
ON s.ID = sc.SONG_ID
JOIN CATEGORIES c
ON sc.CATEGORY_ID = c.ID
WHERE c.title IN (#catTitle1, #catTitle2, #catTitle3...#catTitleN);
In both of these examples you would replace the # with the data you are providing and adjust the SELECT part to show only the columns you need.
If you want to select songs from categories 1 & 2 :
SELECT s.id song_id, s.title song_title, s.add_time song_add_time, c.id cat_id, c.title cat_title
FROM CATEGORIES c
INNER JOIN SONGS_CATEGORIES sg
ON c.id = sg.category_id
INNER JOIN SONGS s
ON sg.song_id = s.id
WHERE c.id = 1 OR c.id = 2
I guess this is what you need
SELECT * -- select what ever columns you need to display
FROM SONGS s
JOIN SONGS_CATEGORIES sc
ON s.ID = sc.SONG_ID
JOIN CATEGORIES c
ON c.ID = sc.CATEGORY_ID
where c.title in ('title1','title2')
I am stuck with a complex MySQL query. I have following tables:
[employee]
id
name
[department]
id
name
[employee_department_relation]
id
employee_id
department_id
[attendance]
id
employee_id
date
Note: attendance will be recorded only if the employee is present at that date. No specific flag is set for abseentism.
I need to find out that, how many employees from which department were absent on a particular date.
I have done so far, following SQL, but, its not perfect:
SELECT A.date,
(SELECT name FROM employee WHERE id = emp_id) AS employee,
(SELECT D.name AS dept_name
FROM deptartment D
INNER JOIN employee_department_relation R ON R.dept_id = D.id
INNER JOIN employee E ON E.id = R.emp_id
WHERE R.emp_id = A.emp_id
) AS dept
FROM attendance A
WHERE A.date = '2014-07-03'
How can I proceed?
try this changing date as you like:
select employee.name, department.name from employee
left join employee_department_relation r on r.employee_id = employee.id
left join department on department.id = r.department_id
where employee.id not in (
select employee_id from attendance where date = '2014-07-28'
)
I have a problem with MySQL statement:
SELECT
oxarticles.OXTITLE AS TITLE,
oxmanufacturers.OXTITLE_1 AS OXMANTITLE,
oxarticles.OXDISTEAN AS OXDISTEAN,
oxarticles.OXMPN AS MPN,
oxarticles.OXPRICE AS OXPRICE,
oxarticles.OXSTOCK AS OXSTOCK,
oxarticles.OXARTNUM AS OXARTNUM,
oxseo.OXSEOURL AS OXSEOURL,
oxartextends.OXLONGDESC_1 AS OXLONGDESC
FROM `oxarticles`
INNER JOIN `oxartextends` ON oxarticles.OXID = oxartextends.OXID
INNER JOIN `oxmanufacturers` ON oxarticles.OXID = oxmanufacturers.OXID
INNER JOIN `oxseo` ON oxarticles.OXID = oxseo.OXOBJECTID;
My problem is that tables oxarticles and oxmanufacturers have two same column names OXID and OXTITLE_1 but the above code doesn't work. Please help.
You are trying to match article id to manufacturer id. That's wrong. You need to join your article table to the manufacturer table using the manufacturer id, not the article id.
In your case, that is oxarticles.OXMANUFACTURERID for the manufacturer id in the article table and oxmanufacturers.OXID in the manufacturer table.
SELECT
oxarticles.OXTITLE AS TITLE,
oxmanufacturers.OXTITLE_1 AS OXMANTITLE,
oxarticles.OXDISTEAN AS OXDISTEAN,
oxarticles.OXMPN AS MPN,
oxarticles.OXPRICE AS OXPRICE,
oxarticles.OXSTOCK AS OXSTOCK,
oxarticles.OXARTNUM AS OXARTNUM,
oxseo.OXSEOURL AS OXSEOURL,
oxartextends.OXLONGDESC_1 AS OXLONGDESC
FROM `oxarticles`
INNER JOIN `oxartextends`
ON oxarticles.OXID = oxartextends.OXID
INNER JOIN `oxmanufacturers`
ON oxarticles.OXMANUFACTURERID = oxmanufacturers.OXID
-- ^^^
-- Here's the manufacturer id
-- in the article table
INNER JOIN `oxseo`
ON oxarticles.OXID = oxseo.OXOBJECTID;
I have a table containing persons information (one row per person) and another table containing persons photos filenames (many rows per person). I want to select a group of persons (based on another table) but only one photo per person.
My old SQL was like this:
SELECT persons.personID, persons.name, persons.photo_filename, movie_cast.role
FROM persons, movie_cast
WHERE persons.personID = movie_cast.personID
AND movie_cast.imdbID = ?
ORDER BY movie_cast.castORDER
LIMIT 9';
But here, the 'persons' table contains also a 'photo_filename' column. In my new database design, this column is in another table. So if I try to get the photo_filename from the new table I get all the photos available for each person, but I need to get only one.
How to do it?
In the first example I have assumed there is always a photo, and am just grabbing the highest sorted photo filename alphabetically as a means to get a consistent photo for each user each time you run the query.
SELECT p.personID, p.name, ph.photo_filename, mc.role
FROM persons p
INNER JOIN movie_cast mc ON p.personID = mc.personID
INNER JOIN (
select personID, max(photo_filename) as MaxPhotoName
from photos
group by personID
) phm on p.personID = phm.personID
INNER JOIN photos ph on phm.personID = ph.personID
and phm.MaxPhotoName = ph.photo_filename
WHERE mc.imdbID = ?
ORDER BY mc.cast
LIMIT 9
If there is a photo_date column and you want to use the newest photo you can do it like this:
SELECT p.personID, p.name, ph.photo_filename, mc.role
FROM persons p
INNER JOIN movie_cast mc ON p.personID = mc.personID
INNER JOIN (
select personID, max(photo_date) as MaxPhotoDate
from photos
group by personID
) phm on p.personID = phm.personID
INNER JOIN photos ph on phm.personID = ph.personID
and phm.MaxPhotoDate = ph.photo_date
WHERE mc.imdbID = ?
ORDER BY mc.cast
LIMIT 9
If there is not always a photo, you can use a LEFT OUTER JOIN so that you will still get all your records back:
SELECT p.personID, p.name, ph.photo_filename, mc.role
FROM persons p
INNER JOIN movie_cast mc ON p.personID = mc.personID
LEFT OUTER JOIN (
select personID, max(photo_date) as MaxPhotoDate
from photos
group by personID
) phm on p.personID = phm.personID
LEFT OUTER JOIN photos ph on phm.personID = ph.personID
and phm.MaxPhotoDate = ph.photo_date
WHERE mc.imdbID = ?
ORDER BY mc.cast
LIMIT 9