In first table album has id and second table album_details has sub_id which relates from album table id
I need to display count for separate id value.
SELECT DISTINCT B.SUB_ID, A . * , B.CONTENT_VALUE AS detail,
(SELECT COUNT( ID )
FROM album_details WHERE A.ID = B.SUB_ID ) AS count
FROM album AS A, album_details AS B
WHERE A.WEBSITE_ID = '571710720'
AND A.ID = B.SUB_ID
GROUP BY B.SUB_ID
LIMIT 0 , 30
Now count column shows 40 for all rows but need to display 'count' 6 for 'id=4', 'count' 3 for 'id=2'
SELECT count(SUB_ID),SUB_ID from album_details group by SUB_ID
GROUP BY is your weapon of choice.
SELECT
a.ID,
a.CONTENT_VALUE,
COUNT(ad.ID)
FROM albums AS a
LEFT JOIN album_details AS ad ON a.ID = ad.SUB_ID
GROUP BY a.ID
Feel free to add your WHERE before the GROUP BY.
Lets say first table is A and second table is B then query will be like this
select a.ID, count(b.SUB_ID) AS total
FROM A LEFT JOIN B ON A.ID = B.SUB_ID
Group by B.SUB_ID.
It might help you. If not then ask please.
select count(sub_id) as count1 from album_details where sub_id in(select id from album) WHERE album.WEBSITE_ID = '571710720'
AND album.ID = album_details.SUB_ID
Related
I'm trying to create a leaderboard but i'm not sure how to do the mysql query.
I would like to count all the levels from a player in the skills table and get the total Level and count all the experience from a player in the experience table and get the Total Exp along with displaying the persons name from the users column.
There is 3 tables factions_mcmmo_users, factions_mcmmo_experience, factions_mcmmo_skills.
This is what i have so far but it doesn't work:
$sql = ("SELECT a.id,
(SELECT COUNT(*) FROM factions_mcmmo_experience WHERE user_id = a.id) as TotalXP,
(SELECT COUNT(*) FROM factions_mcmmo_skills WHERE user_id = a.id) as TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a LIMIT 10;");
Any help would be very appreciated
EDIT: I have it working now but i'm unsure if its the most efficient way to do things so if anyone could help me out if theres a better way, it would mean a lot.
I would also like to know if it's possible to display the total exp and level with commas if the number is in the thousands for example: total level 5,882 and total xp 582,882
EDIT 2:
I have figured out how to format the numbers but still don't know if my code is efficient
$sql = ("SELECT id, user,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_skills b WHERE b.user_id = a.id) as TotalLevel,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_experience c WHERE c.user_id = a.id) as TotalXP
FROM (SELECT id, user FROM factions_mcmmo_users) a group by id ORDER BY TotalLevel DESC, TotalXP DESC LIMIT 10;");
EDIT 3
Updated code from scaisEdge but was displaying everyones level as 1 and XP as 1, so i changed count(*) changed to sum, added an order By TotalLevel in Descending order and that seems to have worked but i can't get it to display the persons name (user column) in the user table? not sure if i was supposed to change to sum because it didn't work the other way.
$sql = ("SELECT a.id, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC
LIMIT 10;");
EDIT 4
Everything working but when i try to format the totals using "FORMAT(Sum(Columns), 0) on the inner joins, the EXP Total appears to work but the main Total Level is not displaying results that are over 1,000 and it breaks the leaderboard positioning, it should be sorting them on total level but it appears to be random, when u remove the format,0 it goes back to working
I would like it to display commas if the number number is the thousands for example: Total Level: 5,532 and Total EXP 5882,882
See live demo: http://mcbuffalo.com/playground/leaderboards/server/factions-mcmmo.php
Updated Code trying to use Format:
$sql = ("SELECT a.id, a.user, b.TotalXP, c.TotalLevel
FROM (SELECT id, user FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC;");
EDIT 5
Changed number with PHP, everything works
Original Images
you could use an couple of inner join
$sql = ("SELECT a.id, a.name, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id, name FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, COUNT(*) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, COUNT(*) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
LIMIT 10
I want to get all id with the max id2 value.
I tried just to get the max id2 but then it will looks for the overall maximum value of id2 inside the table , but i want to get all maxiums of id.
So I got 2 tables - table news and table topics.
Everytime I create a news there will automaticly create a topic. Now I want to show all news - and the current number of replies. So first step - topicid = id.
and every topic got id and id2.
id is the topic id
and id2 is the reply id
so if i got topic (a) with 4 comments it would look like
(id(1),id2(1))
(id(1),id2(2))
(id(1),id2(3))
(id(1),id2(4))
now a new topic (b) with 6 comments
(id(2),id2(1))
(id(2),id2(2))
(id(2),id2(3))
(id(2),id2(4))
(id(2),id2(5))
(id(2),id2(6))
so i want to get ((id(1),id2(4)) and (id(2),id2(6)))
<?php
$news = "SELECT n.titel,n.datum,n.typ_news,n.news,n.verfasser,n.time,n.topicid,
t.id, t.id2 FROM news n LEFT JOIN topics t ON t.id = n.topicid
ORDER BY n.id DESC LIMIT 10 ";
$neuenews = mysql_query($news);
while ($dnews = mysql_fetch_array($neuenews))
{
echo " <div style='text-align:center;color:#FFFFFF;font-size: 24px;'> "
.$dnews['titel'].
"a";
}
Ehm this was the solution :
$dn1 = mysql_query('select c.id, c.name, c.description, c.position,c.bild,
(select count(t.id) from topics as t where t.parent=c.id and t.id2=1) as topics,
(select count(t2.id) from topics as t2 where t2.parent=c.id and t2.id2!=1) as replies
from categories as c group by c.id order by c.position asc');
Try this:
SELECT n.titel,n.datum,n.typ_news,n.news,n.verfasser,n.time,n.topicid, t.id, MAX(t.id2) AS id2
FROM news n
LEFT JOIN
topics t
ON t.id = n.topicid
GROUP BY n.topicid
ORDER BY n.id DESC LIMIT 10
It looks like the specified/desired result from the topics table is accomplished by a query like this:
SELECT t.id
, MAX(t.id2) AS max_id2
FROM topics t
GROUP BY t.id
OPTION 1
To get that result joined to rows in news, you could use that query as an inline view in your query in place of the topics table. For example:
SELECT n.titel
, n.datum
, n.typ_news
, n.news
, n.verfasser
, n.time
, n.topicid
, t.id
, t.max_id2
FROM news n
LEFT
JOIN ( SELECT m.id
, MAX(m.id2) AS max_id2
FROM topics m
GROUP BY m.id
) t
ON t.id = n.topicid
ORDER BY n.id DESC LIMIT 10
OPTION 2
If id is UNIQUE (or PRIMARY KEY) in news table, then you may be able to eliminate the inline view, do a join to topics, and do a GROUP BY n.id, something like this:
SELECT n.titel
, n.datum
, n.typ_news
, n.news
, n.verfasser
, n.time
, n.topicid
, t.id
, MAX(t.id2) AS max_id2
FROM news n
LEFT
JOIN topics t
ON t.id = n.topicid
GROUP BY n.id
ORDER BY n.id DESC LIMIT 10
Not clear enough. what are the columns id= 1 id2=1 etc.? Two tables each with 2 columns? No clue.
I'm thinking something on the order but No clue what you actually want.
SELECT `MAX(`id2`) as MAX,`id` FROM `News` WHERE `id2` = `MAX`
I have 2 tables.
First:
TABLE Articles
ID
Second:
TABLE Viewcount
DATE DATE PK
ARTICLE_ID INT PK (MATCHES ID IN TABLE Articles)
NUMVIEWS INT
How do I select all IDs from table Articles and then order by NUMVIEWS (DESC) of Viewcount according to dates?
I then need to append the IDs from Articles that were not found in viewcount to the End of the results in no particular order.
I know it has to be some sort of Join but I can't figure it out..
try this
SELECT id from Articles a
LEFT JOIN Viewcount v
ON a.id = v.article_id
AND v.date = 'some date here'
ORDER BY v.numviews ,v.date desc
A simple join will suffice, yes:
SELECT a.id FROm Articles a LEFT JOIN Viewcount v
ON v.article_id = a.id
ORDER BY v.numviews desc, v.date
This should work:
SELECT * FROM `Articles` `a`, `Viewcount` `v`
WHERE `v`.`ARTICLE_ID`=`a`.`ID`
ORDER BY `v`.`NUMVIEWS` DESC
Replace SELECT * by SELECT `a`.`ID` to get only the Article IDs.
SELECT ID from (Articles JOIN Viewcount on Articles.ID = Viewcount.ID) ORDER BY Viewcount.NUMVIEWS, Viewcount.date
I currently have this left join as part of a query:
LEFT JOIN movies t3 ON t1.movie_id = t3.movie_id AND t3.popularity = 0
The trouble is that if there are several movies with the same name and same popularity (don't ask, it just is that way :-) ) then duplicate results are returned.
All that to say, I would like to limit the result of the left join to one.
I tried this:
LEFT JOIN
(SELECT t3.movie_name FROM movies t3 WHERE t3.popularity = 0 LIMIT 1)
ON t1.movie_id = t3.movie_id AND t3.popularity = 0
The second query dies with the error:
Every derived table must have its own alias
I know what I'm asking is slightly vague since I'm not providing the full query, but is what I'm asking generally possible?
The error is clear -- you just need to create an alias for the subquery following its closing ) and use it in your ON clause since every table, derived or real, must have its own identifier. Then, you'll need to include movie_id in the subquery's select list to be able to join on it. Since the subquery already includes WHERE popularity = 0, you don't need to include it in the join's ON clause.
LEFT JOIN (
SELECT
movie_id,
movie_name
FROM movies
WHERE popularity = 0
ORDER BY movie_name
LIMIT 1
) the_alias ON t1.movie_id = the_alias.movie_id
If you are using one of these columns in the outer SELECT, reference it via the_alias.movie_name for example.
Update after understanding the requirement better:
To get one per group to join against, you can use an aggregate MAX() or MIN() on the movie_id and group it in the subquery. No subquery LIMIT is then necessary -- you'll receive the first movie_id per name withMIN() or the last with MAX().
LEFT JOIN (
SELECT
movie_name,
MIN(movie_id) AS movie_id
FROM movies
WHERE popularity = 0
GROUP BY movie_name
) the_alias ON t1.movie_id = the_alias.movie_id
LEFT JOIN movies as m ON m.id = (
SELECT id FROM movies mm WHERE mm.movie_id = t1.movie_id
ORDER BY mm.id DESC
LIMIT 1
)
you could try to add GROUP BY t3.movie_id to the first query
Try this:
LEFT JOIN
(
SELECT t3.movie_name, t3.popularity
FROM movies t3 WHERE t3.popularity = 0 LIMIT 1
) XX
ON t1.movie_id = XX.movie_id AND XX.popularity = 0
On MySQL 5.7+ use ANY_VALUE & GROUP_BY:
SELECT t1.id,t1.movie_name, ANY_VALUE(t3.popularity) popularity
FROM t1
LEFT JOIN t3 ON (t3.movie_id=t1.movie_id AND t3.popularity=0)
GROUP BY t1.id
more info
LEFT JOIN only first row
https://dev.mysql.com/doc/refman/5.7/en/group-by-handling.html
Easy solution to left join the 1 most/least recent row is using select over ON phrase
SELECT A.ID, A.Name, B.Content
FROM A
LEFT JOIN B
ON A.id = (SELECT MAX(id) FROM B WHERE id = A.id)
Where A.id is the auto-incremental primary key.
LEFT JOIN (
SELECT id,movie_name FROM movies GROUP BY id
) as m ON (
m.id = x.id
)
// Mysql
SELECT SUM(db.item_sales_nsv) as total FROM app_product_hqsales_otc as db
LEFT JOIN app_item_target_otc as it ON
db.id = (SELECT MAX(id) FROM app_item_target_otc as ot WHERE id = db.id)
and db.head_quarter = it.hqcode
AND db.aaina_item_code = it.aaina_item_code AND db.month = it.month
AND db.year = it.year
WHERE db.head_quarter = 'WIN001' AND db.month = '5' AND db.year = '2022' AND db.status = '1'
I have table 'posters', table 'reviews' and table 'trailers'. Every table is connected with an movieID column, but each table can be empty for certain movieIDs:
++ posters_table +++ ++ reviews_table ++ ++ trailers_table ++
--itemID--+--filename- --itemID--+--review-- --itemID--+--trailer
---------------------- --------------------- ---------------------
----001---+--0012343-- ----004---+--blalba-- ----002---+--002345--
----001---+--0013331-- ----004---+--xlalxa-- ----005---+--005434--
----002---+--0020052-- ----005---+--zlalza-- ----001---+--005335--
I want to COUNT() the number of posters, reviews and trailers for the specified movieID and get 0 if no available.
So if I want to count movieID = 001 I get: ['posters'] = 2 / ['reviews'] = 0 and ['trailers'] = 1 (for example)
Can someone post the SQL query to do this?
select
(select count(*) from posters_table where itemId = ?) as posters,
(select count(*) from reviews_table where itemId = ?) as reviews,
(select count(*) from trailers_table where itemId = ?) as trailers;
I think if you JOIN the movie table to a result set that gives the count, you can then pick out whether or not the count is > 0 and give the appropriate value:
SELECT movieID, IF(posters.posters_count > 0, posters.posters_count,0) AS posters_total, IF(reviews.reviews_count > 0, reviews.reviews_count,0) AS reviews_total, IF(trailers.trailers_count > 0, trailers.trailers_count,0) AS trailers_total
FROM movies m
LEFT JOIN (SELECT itemID,COUNT(*) AS posters_count FROM posters_table WHERE itemID = '001' GROUP BY itemID) posters ON posters.itemID = movies.movieID
LEFT JOIN (SELECT itemID,COUNT(*) AS reviews_count FROM reviews_table WHERE itemID = '001' GROUP BY itemID) reviews ON reviews.itemID = movies.movieID
LEFT JOIN (SELECT itemID,COUNT(*) AS trailers_count FROM trailers_table WHERE itemID = '001' GROUP BY itemID) trailers ON trailers.itemID = movies.movieID
WHERE m.movieID = '001'
EDIT: I prefers ar's solution. Much simpler!
select
(select count(P.movieid) from posters P where P.movieid=1),
(select count(R.movieid) from reviews R where R.movieid=1),
(select count(T.movieid) from trailers T where T.movieid=1)
The tables are not "really" joined so you need three selects.