Put DIV ID into a PHP Variable - php

Question

I am wanted to get the id's of all the divs on my page with the class archive and put them in a MySQL query to check and see if the ids are archived in the database.
So basically I am wondering how I can do this: $div = $(this).attr('id');
Then I would throw it into the loop to check:
$matches = mysql_query("SELECT * FROM content WHERE `div` = '$div'");
while ($post = mysql_fetch_assoc($matches))
{
if (mysql_num_rows($matches) > 0)
{
//DO THIS
}
}
UPDATE
I have this code for the AJAX now:
$('div.heriyah').each(function() {
var curID = $(this).attr('id');
$.post("admin/btnCheck.php", { div : curID }, function(data) {
if (data == "yes") {
$('#' + curID).html('<div class=\"add\"><div id=\"add_button_container\"><div id=\"add_button\" class=\"edit_links\"> + Add Element</div></div></div><div class=\"clear\"></div></div>');
} else {
$('#' + curID).html('<div class=\"add\"><div id=\"add_button_container\"><div id=\"add_button\" class=\"edit_links\"> + Set As Editable Region</div></div></div><div class=\"clear\"></div></div>');
}
});
});
And my PHP:
$matches = mysql_query("SELECT * FROM content WHERE `div` = '".$_POST['div']."'");
if (mysql_num_rows($matches) > 0)
{
echo "yes";
} else {
echo "no";
}
What am I doing wrong?

Answer 1

You cannot throw a javascript variable to PHP script like that. You have to send an ajax request to the page
$div = $(this).attr('id');
$.post("yourquerypage.php", { divid : $div }, function(data) {
// Something to do when the php runs successfully
});
Next, configure your query to get the variable from $_POST()
$matches = mysql_query("SELECT * FROM content WHERE `div` = '".$_POST['divid']."'");
And of course, you have to take measures for injection.

Answer 2

It's simple syntax error. Remove the condition after the else and you should be fine.
else (data == "yes") { // remove (data == "yes")
// snip
}