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So Im scraping a website for data, and one piece of data that im scraping is the date of certain items.
The date of the items comes in the format "Wed 11th March, 2015".
I have been trying to then insert this into my mysql database. The structure of the database contains a column with "datapublished" as a Timestamp,
`feeddatapublished` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP)
When updating the rest of the columns with the data it updates fine with the following code
$stmt = $dbh->prepare("INSERT INTO `feedsdata` (`id`, `feedid`, `feedurl`, `feedsummary`, `feedtitle`, `feeddatapublished`) VALUES (NULL, :feed_id, :feed_url, :feed_summary, :title, :datapublished)");
$stmt->bindParam(':feed_id', $feed_id);
$stmt->bindParam(':feed_url', $feed_url);
$stmt->bindParam(':feed_summary', $feed_summary);
$stmt->bindParam(':title', $feed_title);
$stmt->bindParam(':datapublished',$datepublished);
$stmt->execute();
I converted the string from the feed before passing it to be inserted with
$datepublished = strtotime(scrape_between($separate_result, "<span class=\"date\">", "</span>"));
scrape_between is a function I use for the scraping.
When echoing out the $datepublished I get the timestamp 1458155700, which isnt the correct timestamp from what i can see.
All other columns are updating as required, the only one which isnt is the datepublished one.
My two questions are
Is the reason its not updating because im passing a malformed timestamp to the mysql database
How can I generate a better timestamp from the format above, Ive checked the date function but I cant seem to get it to work.
The MySQL timestamp format is 2016-02-13 15:48:29 or Y-m-d H:i:s convert your unix timestamp to that format first, and then MySQL will accept it.
Either with
<?php
$datapublished = date("Y-m-d H:i:s", strtotime(scrape_between($separate_result, "<span class=\"date\">", "</span>")));
OR
your query to
$stmt = $dbh->prepare("INSERT INTO `feedsdata` (`id`, `feedid`, `feedurl`, `feedsummary`, `feedtitle`, `feeddatapublished`)
VALUES (NULL, :feed_id, :feed_url, :feed_summary, :title, from_unixtime(:datapublished))");
the problem is that strtotime is not smart enough to recognise the string so its best guess is 1458155700.
you can add an additional step to clean the date:
$scrape = scrape_between(...);
$cleanDate = preg_replace(
'/[a-z]+ ([0-9]{1,2})[a-z]+ ([a-z]+), ([0-9]{4})/i',
'$1 $2 $3',
$scrape
);
$datepublished = strtotime($cleanDate);
the preg_replace function uses a regular expression to remove the unnecessary parts.
If you know the date format used on the webpage you're scraping and it stays constant, you can use DateTime::createFromFormat() for safer and more controlled date parsing.
<?php
$datestring = "Wed 11th March, 2015";
$date = DateTime::createFromFormat("D dS F, Y", $datestring);
// Reset hours, minutes and seconds - otherwise the current time is used
$date->setTime(0, 0, 0);
// Format for MySQL database insertion
$datepublished = $date->format("Y-m-d H:i:s");
I would like to show the date 2 weeks before the date stored in a DB
The date isnt stored in Timestamp, it is stored like 01/01/2015
I have tried the below but this isnt working, can anyone help?
echo date('$valid_to', strtotime("-2 week"));
I would use DateTime class instead.
// timezone is optional
$date = new DateTime($valid_to, new DateTimeZone('Europe/Vilnius'));
echo $date->modify('-2 weeks');
// there you have your wanted date
$valid_date = $date->format('Y-m-d');
Then would recommend STR_TO_DATE mysql function to convert to correct timestamp.
For example:
$query = "SELECT * FROM table WHERE time_col <= STR_TO_DATE('" . $valid_date . "', '%Y-%m-%d')";
My problem is the following:
When DoExpressCheckout() is executed i have to save some data to Database, including the current time + X time
The type of the field of the database is set to "datetime"
I'm using the strtotime function in this way
date_default_timezone_set('Europe/Rome');
$currentTime = date("Y-m-d");
$expected = date('Y-m-d',strtotime($currentTime.'+ 7 days'));
echo $expected;
$sql = "INSERT INTO acquisti (durata,prezzi,expectedtime) VALUES (".$str.",".$resArray['AMT'].",".$expected.")";
echo $sql;
mysql_query($sql) or die("Errore di inserimento");
Here i have two problems:
1) The query always returns me error when putting the $expected variable into the expectedtime field
2) If i put it manually (just to try if i was stupid) it writes me 0000-00-00 (i've enabled the ALLOW_INVALID_DATES)
Any suggestions?
Thanks a lot
Your field type is 'datetime', but you are only sending date using the INSERT query.
You need to use date('Y-m-d H:i:s') instead of date('Y-m-d'), or if you need only the date change the type of the field to date.
Put values in enclosure:
$sql = "
INSERT INTO acquisti (
durata, prezzi, expectedtime
) VALUES (
'$str', '{$resArray['AMT']}', '$expected'
)
";
But you should really need to start using prepared statements.
If you wish to pass datetime, then you should format accordinaly, like Y-m-d H:i:s.
PHP example:
$expected = date_create('now')->modify('+7 day')->format('Y-m-d H:i:s');
MySQL example:
$sql = "
INSERT INTO acquisti (
durata, prezzi, expectedtime
) VALUES (
'$str', '{$resArray['AMT']}', DATE_ADD(NOW(), INTERVAL 7 DAY)
)
";
I have an availability calendar in which I am currently adding in dates one by one, and using a mysql query to determine if there exists a row with a certain date and changing the class of the day to "booked" (Red).
I would like to enter in a range into my form, and process it through php (or mysql) into multiple, individual dates. My date format is M/D/YYYY, or MM/DD/YYYY, both are accepted. Unfortunately, when I built my calendar, I did not use the date format in sql for entries, but used varchar.
Is there a way to enter into my form for example 1/1/2014-1/3/2014 and have php convert that to 1/1/2014, 1/2/2014, 1/3/2014, and then have a mysql INSERT query to insert multiple values at once?
if (empty($_POST) === false && empty($errors) === true) {
$adcp_data = array(
'date' => $_POST['date'],
'customer' => $_POST['customer'],
'notes' => $_POST['notes'],
);
insert_adcp($adcp_data);
header('Location: adcp.php?success');
exit();
the insert_adcp function looks like this:
function insert_adcp ($adcp_data) {
array_walk($adcp_data, 'array_sanitize');
$fields = '`' . implode('`, `', array_keys($adcp_data)) . '`';
$data = '\'' . implode('\', \'', $adcp_data) . '\'';
mysql_query("INSERT INTO `adcp` ($fields) VALUES ($data)");
}
My workaround and last resort will be to add multiple text inputs and just add multiple dates manually so I only have to submit once. But a range is so much faster!
As a last note, if I could have those multiple entries keep the "customer" and "notes" values for each date in the range that would be amazing. I am prepared to lose those fields though to make this work. Thanks
Something like:
$day = new DateTime($_POST['range_start']);
$end = new DateTime($_POST['range_end']);
$all_dates = array();
while ($day <= $end){
$all_dates[] = $day;
$day->add(new DateInterval('P1D'));
}
That will give you an array of DateTime objects each of which represents a day in your range. You can get each object back into a string by calling DateTime::format() and passing 'm/d/Y' as the format string.
As for getting multiple entries into MySQL, the INSERT syntax allows INSERT INTO table (column) VALUES (row1), (row2), ... (rowN)
(this is clearly not not tested or the final code you would use -- just written into this web form from memory ... you'll have to write it out properly with input sanitation and range checking and whatnot.)
Check if the value from the input match your range format, capture the parts and generate the from and to dates.
if (preg_match('%\A(?<fromMonth>\d{1,2})/(?<fromDay>\d{1,2})/(?<fromYear>\d{4})-(?<toMonth>\d{1,2})/(?<toDay>\d{1,2})/(?<toYear>\d{4})\Z%', $str, $res)) {
$dates['from'] = mktime(0, 0, 0, $res['fromMonth'], $res['fromDay'], $res['fromYear']);
$dates['to'] = mktime(0, 0, 0, $res['toMonth'], $res['toDay'], $res['toYear']);
}
Generate the range between from and to dates.
for ($date = $dates['from']; $date <= $dates['to']; $date = strtotime('+1 day', $date) ){
$dates['range'][] = date('m-d-Y', $date);
}
I think, strtotime is more usable for your case. You can found definition at php.net site:
http://php.net/manual/en/function.strtotime.php
I'm using jQuery datepicker
the format of the datepicker is this 08/25/2012
I have errors when inserting to my database it inserts only 0000-00-00 00 00 00
My code is:
<?php
$id = $_POST['id'];
$name = $_POST['name'];
$date = $_POST['date'];
$sql = mysql_query( "INSERT INTO user_date VALUE( '', '$name', '$date')" ) or die ( mysql_error() );
echo 'insert successful';
?>
I'm sure my insert is correct.
As stated in Date and Time Literals:
MySQL recognizes DATE values in these formats:
As a string in either 'YYYY-MM-DD' or 'YY-MM-DD' format. A “relaxed” syntax is permitted: Any punctuation character may be used as the delimiter between date parts. For example, '2012-12-31', '2012/12/31', '2012^12^31', and '2012#12#31' are equivalent.
As a string with no delimiters in either 'YYYYMMDD' or 'YYMMDD' format, provided that the string makes sense as a date. For example, '20070523' and '070523' are interpreted as '2007-05-23', but '071332' is illegal (it has nonsensical month and day parts) and becomes '0000-00-00'.
As a number in either YYYYMMDD or YYMMDD format, provided that the number makes sense as a date. For example, 19830905 and 830905 are interpreted as '1983-09-05'.
Therefore, the string '08/25/2012' is not a valid MySQL date literal. You have four options (in some vague order of preference, without any further information of your requirements):
Configure Datepicker to provide dates in a supported format using an altField together with its altFormat option:
<input type="hidden" id="actualDate" name="actualDate"/>
$( "selector" ).datepicker({
altField : "#actualDate"
altFormat: "yyyy-mm-dd"
});
Or, if you're happy for users to see the date in YYYY-MM-DD format, simply set the dateFormat option instead:
$( "selector" ).datepicker({
dateFormat: "yyyy-mm-dd"
});
Use MySQL's STR_TO_DATE() function to convert the string:
INSERT INTO user_date VALUES ('', '$name', STR_TO_DATE('$date', '%m/%d/%Y'))
Convert the string received from jQuery into something that PHP understands as a date, such as a DateTime object:
$dt = \DateTime::createFromFormat('m/d/Y', $_POST['date']);
and then either:
obtain a suitable formatted string:
$date = $dt->format('Y-m-d');
obtain the UNIX timestamp:
$timestamp = $dt->getTimestamp();
which is then passed directly to MySQL's FROM_UNIXTIME() function:
INSERT INTO user_date VALUES ('', '$name', FROM_UNIXTIME($timestamp))
Manually manipulate the string into a valid literal:
$parts = explode('/', $_POST['date']);
$date = "$parts[2]-$parts[0]-$parts[1]";
Warning
Your code is vulnerable to SQL injection. You really should be using prepared statements, into which you pass your variables as parameters that do not get evaluated for SQL. If you don't know what I'm talking about, or how to fix it, read the story of Bobby Tables.
Also, as stated in the introduction to the PHP manual chapter on the mysql_* functions:
This extension is deprecated as of PHP 5.5.0, and is not recommended for writing new code as it will be removed in the future. Instead, either the mysqli or PDO_MySQL extension should be used. See also the MySQL API Overview for further help while choosing a MySQL API.
You appear to be using either a DATETIME or TIMESTAMP column for holding a date value; I recommend you consider using MySQL's DATE type instead. As explained in The DATE, DATETIME, and TIMESTAMP Types:
The DATE type is used for values with a date part but no time part. MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The supported range is '1000-01-01' to '9999-12-31'.
The DATETIME type is used for values that contain both date and time parts. MySQL retrieves and displays DATETIME values in 'YYYY-MM-DD HH:MM:SS' format. The supported range is '1000-01-01 00:00:00' to '9999-12-31 23:59:59'.
The TIMESTAMP data type is used for values that contain both date and time parts. TIMESTAMP has a range of '1970-01-01 00:00:01' UTC to '2038-01-19 03:14:07' UTC.
You should consider creating a timestamp from that date witk mktime()
eg:
$date = explode('/', $_POST['date']);
$time = mktime(0,0,0,$date[0],$date[1],$date[2]);
$mysqldate = date( 'Y-m-d H:i:s', $time );
$date_field = date('Y-m-d',strtotime($_POST['date_field']));
$sql = mysql_query("INSERT INTO user_date (column_name,column_name,column_name) VALUES('',$name,$date_field)") or die (mysql_error());
You must make sure that the date format is YYYY-MM-DD on your jQuery output. I can see jQuery returns MM-DD-YYYY, which is not the valid MySQL date format and this is why it returns an error.
To convert it to the right one you could do this:
$dateFormated = split('/', $date);
$date = $dateFormated[2].'-'.$dateFormated[0].'-'.$dateFormated[1];
Then you will get formatted date that will be valid MySQL format, which is YYYY-MM-DD, i.e. 2012-08-25
I would also recommend using mysql_real_escape_string as you insert data into database to prevent SQL injections as a quick solution or better use PDO or MySQLi.
Your insert query using mysql_real_escape_string should rather look like this:
$sql = mysql_query( "INSERT INTO user_date VALUE( '', '" .mysql_real_escape_string($name). "', '" .mysql_real_escape_string($date). "'" ) or die ( mysql_error() );
Get a date object from the jquery date picker using
var myDate = $('element').datepicker('getDate')
For mysql the date needs to be in the proper format. One option which handles any timezone issues is to use moment.js
moment(myDate).format('YYYY-MM-DD HH:mm:ss')
The simplest method is
$dateArray = explode('/', $_POST['date']);
$date = $dateArray[2].'-'.$dateArray[0].'-'.$dateArray[1];
$sql = mysql_query("INSERT INTO user_date (column,column,column) VALUES('',$name,$date)") or die (mysql_error());
HTML:
<div class="form-group">
<label for="pt_date" class="col-2 col-form-label">Date</label>
<input class="form-control" type="date" value=<?php echo date("Y-m-d") ;?> id="pt_date" name="pt_date">
</div>
SQL
$pt_date = $_POST['pt_date'];
$sql = "INSERT INTO `table` ( `pt_date`) VALUES ( '$pt_date')";
Suppose you receive a Christmas date:
December 25, 2021 (25 de Diciembre del año 2021) in string format: "d-m-Y" for example "12-25-2021". First create a valid DateTime object from the received format:
var_dump(DateTime::createFromFormat("d-m-Y","25-12-2021", new DateTimeZone("America/Argentina/Buenos_Aires")));
This generates as output:
object(DateTime)#2 (3) {
["date"]=>
string(26) "2021-12-25 10:21:11.000000"
["timezone_type"]=>
int(3)
["timezone"]=>
string(30) "America/Argentina/Buenos_Aires"
}
Now to get the date field from the DateTime object ready to go using format("Y-m-d H:i:s")):
var_dump(DateTime::createFromFormat("d-m-Y","25-12-2021",new DateTimeZone("America/Argentina/Buenos_Aires"))->format("Y-m-d H:i:s"));
This generates as output a ready to insert value:
string(19) "2021-12-25 10:56:30"
In summary now you can insert a formated date ('DD-MM-YYYY') in MySQL like this:
<?php
//string input post like "25-12-2021"
$date_input = $_POST['date_input'];
//create DateTime object
$date_time_obj=DateTime::createFromFormat("d-m-Y","25-12-2021",new DateTimeZone("America/Argentina/Buenos_Aires"));
//format date ready to insert as string at MySQL
$str_date=$date_time_obj->format("Y-m-d H:i:s");
?>
Now run directly from PHP to MySQL as a query:
<?php
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'world');
//verify connection
if (mysqli_connect_errno()) {
printf("Error de conexión: %s\n", mysqli_connect_error());
exit();
}
//prepare the query to execute
$stmt = $mysqli->prepare("INSERT INTO table_example (DATE_FIELD) VALUES (?)");
//prevent sql injection
$stmt->bind_param('s', $str_date);
//execute prepared statements
$stmt->execute ();
?>
These days, I am not good with dates. Thanks to the following work, I can print the dates in the format I want.
$year = $_POST['year'];
$month = $_POST['month'];
$day = $_POST['day'];
$scr = strtotime($year . '-' . $month . '-' . $day);
$gelis_tarihi = date('Y-m-d', $scr);
$yil = $_POST['yil'];
$ay = $_POST['ay'];
$gun = $_POST['gun'];
$birlestir = strtotime($yil . '-' . $ay . '-' . $gun);
$gelis_tarihi = date('Y-m-d', $birlestir);
Try Something like this..
echo "The time is " . date("2:50:20");
$d=strtotime("3.00pm july 28 2014");
echo "Created date is " . date("d-m-y h:i:sa",$d);
First of all store $date=$_POST['your date field name'];
insert into **Your_Table Name** values('$date',**other fields**);
You must contain date in single cote (' ')
I hope it is helps.