Error saving datetime to database after clicking buy on DoExpressCheckout - php

My problem is the following:
When DoExpressCheckout() is executed i have to save some data to Database, including the current time + X time
The type of the field of the database is set to "datetime"
I'm using the strtotime function in this way
date_default_timezone_set('Europe/Rome');
$currentTime = date("Y-m-d");
$expected = date('Y-m-d',strtotime($currentTime.'+ 7 days'));
echo $expected;
$sql = "INSERT INTO acquisti (durata,prezzi,expectedtime) VALUES (".$str.",".$resArray['AMT'].",".$expected.")";
echo $sql;
mysql_query($sql) or die("Errore di inserimento");
Here i have two problems:
1) The query always returns me error when putting the $expected variable into the expectedtime field
2) If i put it manually (just to try if i was stupid) it writes me 0000-00-00 (i've enabled the ALLOW_INVALID_DATES)
Any suggestions?
Thanks a lot

Your field type is 'datetime', but you are only sending date using the INSERT query.
You need to use date('Y-m-d H:i:s') instead of date('Y-m-d'), or if you need only the date change the type of the field to date.

Put values in enclosure:
$sql = "
INSERT INTO acquisti (
durata, prezzi, expectedtime
) VALUES (
'$str', '{$resArray['AMT']}', '$expected'
)
";
But you should really need to start using prepared statements.
If you wish to pass datetime, then you should format accordinaly, like Y-m-d H:i:s.
PHP example:
$expected = date_create('now')->modify('+7 day')->format('Y-m-d H:i:s');
MySQL example:
$sql = "
INSERT INTO acquisti (
durata, prezzi, expectedtime
) VALUES (
'$str', '{$resArray['AMT']}', DATE_ADD(NOW(), INTERVAL 7 DAY)
)
";

Related

Store a 'best before' date in SQL Database [duplicate]

I'm using jQuery datepicker
the format of the datepicker is this 08/25/2012
I have errors when inserting to my database it inserts only 0000-00-00 00 00 00
My code is:
<?php
$id = $_POST['id'];
$name = $_POST['name'];
$date = $_POST['date'];
$sql = mysql_query( "INSERT INTO user_date VALUE( '', '$name', '$date')" ) or die ( mysql_error() );
echo 'insert successful';
?>
I'm sure my insert is correct.
As stated in Date and Time Literals:
MySQL recognizes DATE values in these formats:
As a string in either 'YYYY-MM-DD' or 'YY-MM-DD' format. A “relaxed” syntax is permitted: Any punctuation character may be used as the delimiter between date parts. For example, '2012-12-31', '2012/12/31', '2012^12^31', and '2012#12#31' are equivalent.
As a string with no delimiters in either 'YYYYMMDD' or 'YYMMDD' format, provided that the string makes sense as a date. For example, '20070523' and '070523' are interpreted as '2007-05-23', but '071332' is illegal (it has nonsensical month and day parts) and becomes '0000-00-00'.
As a number in either YYYYMMDD or YYMMDD format, provided that the number makes sense as a date. For example, 19830905 and 830905 are interpreted as '1983-09-05'.
Therefore, the string '08/25/2012' is not a valid MySQL date literal. You have four options (in some vague order of preference, without any further information of your requirements):
Configure Datepicker to provide dates in a supported format using an altField together with its altFormat option:
<input type="hidden" id="actualDate" name="actualDate"/>
$( "selector" ).datepicker({
altField : "#actualDate"
altFormat: "yyyy-mm-dd"
});
Or, if you're happy for users to see the date in YYYY-MM-DD format, simply set the dateFormat option instead:
$( "selector" ).datepicker({
dateFormat: "yyyy-mm-dd"
});
Use MySQL's STR_TO_DATE() function to convert the string:
INSERT INTO user_date VALUES ('', '$name', STR_TO_DATE('$date', '%m/%d/%Y'))
Convert the string received from jQuery into something that PHP understands as a date, such as a DateTime object:
$dt = \DateTime::createFromFormat('m/d/Y', $_POST['date']);
and then either:
obtain a suitable formatted string:
$date = $dt->format('Y-m-d');
obtain the UNIX timestamp:
$timestamp = $dt->getTimestamp();
which is then passed directly to MySQL's FROM_UNIXTIME() function:
INSERT INTO user_date VALUES ('', '$name', FROM_UNIXTIME($timestamp))
Manually manipulate the string into a valid literal:
$parts = explode('/', $_POST['date']);
$date = "$parts[2]-$parts[0]-$parts[1]";
Warning
Your code is vulnerable to SQL injection. You really should be using prepared statements, into which you pass your variables as parameters that do not get evaluated for SQL. If you don't know what I'm talking about, or how to fix it, read the story of Bobby Tables.
Also, as stated in the introduction to the PHP manual chapter on the mysql_* functions:
This extension is deprecated as of PHP 5.5.0, and is not recommended for writing new code as it will be removed in the future. Instead, either the mysqli or PDO_MySQL extension should be used. See also the MySQL API Overview for further help while choosing a MySQL API.
You appear to be using either a DATETIME or TIMESTAMP column for holding a date value; I recommend you consider using MySQL's DATE type instead. As explained in The DATE, DATETIME, and TIMESTAMP Types:
The DATE type is used for values with a date part but no time part. MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The supported range is '1000-01-01' to '9999-12-31'.
The DATETIME type is used for values that contain both date and time parts. MySQL retrieves and displays DATETIME values in 'YYYY-MM-DD HH:MM:SS' format. The supported range is '1000-01-01 00:00:00' to '9999-12-31 23:59:59'.
The TIMESTAMP data type is used for values that contain both date and time parts. TIMESTAMP has a range of '1970-01-01 00:00:01' UTC to '2038-01-19 03:14:07' UTC.
You should consider creating a timestamp from that date witk mktime()
eg:
$date = explode('/', $_POST['date']);
$time = mktime(0,0,0,$date[0],$date[1],$date[2]);
$mysqldate = date( 'Y-m-d H:i:s', $time );
$date_field = date('Y-m-d',strtotime($_POST['date_field']));
$sql = mysql_query("INSERT INTO user_date (column_name,column_name,column_name) VALUES('',$name,$date_field)") or die (mysql_error());
You must make sure that the date format is YYYY-MM-DD on your jQuery output. I can see jQuery returns MM-DD-YYYY, which is not the valid MySQL date format and this is why it returns an error.
To convert it to the right one you could do this:
$dateFormated = split('/', $date);
$date = $dateFormated[2].'-'.$dateFormated[0].'-'.$dateFormated[1];
Then you will get formatted date that will be valid MySQL format, which is YYYY-MM-DD, i.e. 2012-08-25
I would also recommend using mysql_real_escape_string as you insert data into database to prevent SQL injections as a quick solution or better use PDO or MySQLi.
Your insert query using mysql_real_escape_string should rather look like this:
$sql = mysql_query( "INSERT INTO user_date VALUE( '', '" .mysql_real_escape_string($name). "', '" .mysql_real_escape_string($date). "'" ) or die ( mysql_error() );
Get a date object from the jquery date picker using
var myDate = $('element').datepicker('getDate')
For mysql the date needs to be in the proper format. One option which handles any timezone issues is to use moment.js
moment(myDate).format('YYYY-MM-DD HH:mm:ss')
The simplest method is
$dateArray = explode('/', $_POST['date']);
$date = $dateArray[2].'-'.$dateArray[0].'-'.$dateArray[1];
$sql = mysql_query("INSERT INTO user_date (column,column,column) VALUES('',$name,$date)") or die (mysql_error());
HTML:
<div class="form-group">
<label for="pt_date" class="col-2 col-form-label">Date</label>
<input class="form-control" type="date" value=<?php echo date("Y-m-d") ;?> id="pt_date" name="pt_date">
</div>
SQL
$pt_date = $_POST['pt_date'];
$sql = "INSERT INTO `table` ( `pt_date`) VALUES ( '$pt_date')";
Suppose you receive a Christmas date:
December 25, 2021 (25 de Diciembre del año 2021) in string format: "d-m-Y" for example "12-25-2021". First create a valid DateTime object from the received format:
var_dump(DateTime::createFromFormat("d-m-Y","25-12-2021", new DateTimeZone("America/Argentina/Buenos_Aires")));
This generates as output:
object(DateTime)#2 (3) {
["date"]=>
string(26) "2021-12-25 10:21:11.000000"
["timezone_type"]=>
int(3)
["timezone"]=>
string(30) "America/Argentina/Buenos_Aires"
}
Now to get the date field from the DateTime object ready to go using format("Y-m-d H:i:s")):
var_dump(DateTime::createFromFormat("d-m-Y","25-12-2021",new DateTimeZone("America/Argentina/Buenos_Aires"))->format("Y-m-d H:i:s"));
This generates as output a ready to insert value:
string(19) "2021-12-25 10:56:30"
In summary now you can insert a formated date ('DD-MM-YYYY') in MySQL like this:
<?php
//string input post like "25-12-2021"
$date_input = $_POST['date_input'];
//create DateTime object
$date_time_obj=DateTime::createFromFormat("d-m-Y","25-12-2021",new DateTimeZone("America/Argentina/Buenos_Aires"));
//format date ready to insert as string at MySQL
$str_date=$date_time_obj->format("Y-m-d H:i:s");
?>
Now run directly from PHP to MySQL as a query:
<?php
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'world');
//verify connection
if (mysqli_connect_errno()) {
printf("Error de conexión: %s\n", mysqli_connect_error());
exit();
}
//prepare the query to execute
$stmt = $mysqli->prepare("INSERT INTO table_example (DATE_FIELD) VALUES (?)");
//prevent sql injection
$stmt->bind_param('s', $str_date);
//execute prepared statements
$stmt->execute ();
?>
These days, I am not good with dates. Thanks to the following work, I can print the dates in the format I want.
$year = $_POST['year'];
$month = $_POST['month'];
$day = $_POST['day'];
$scr = strtotime($year . '-' . $month . '-' . $day);
$gelis_tarihi = date('Y-m-d', $scr);
$yil = $_POST['yil'];
$ay = $_POST['ay'];
$gun = $_POST['gun'];
$birlestir = strtotime($yil . '-' . $ay . '-' . $gun);
$gelis_tarihi = date('Y-m-d', $birlestir);
Try Something like this..
echo "The time is " . date("2:50:20");
$d=strtotime("3.00pm july 28 2014");
echo "Created date is " . date("d-m-y h:i:sa",$d);
First of all store $date=$_POST['your date field name'];
insert into **Your_Table Name** values('$date',**other fields**);
You must contain date in single cote (' ')
I hope it is helps.

how to insert date time object in the type of DateTime column in database using php

I want to insert a DateTime object in database where the column type is DateTime. How can I achieve this?
I am using this code:
$cdate = new DateTime('now')
$cd = $cdate->format('d/m/Y h:i:sa')
$udate = new DateTime('72 hours');
$ud = $udate->format('d/m/Y h:i:sa')
$insert = "insert into `winpc_user(mac_address,reg_date,updated_date,status,processor_name,ram_size,os_Name, os_Bits) values('$mac','$cdate','$udate','$stat','$proName','$rSize','$osName','$osBits')"
Same as the comment above, DATETIME's format is:
YYYY-MM-DD HH:MM:SS
Quite straightforward to follow using date()'s format function, it'll share the same with the ->format():
->format('Y-m-d H:i:s');
Sidenote: Of course, this needs to be quoted as well on insertion.
As an alternative, you could also use MySQL functions to achieve the same goal:
NOW()
DATE_ADD(NOW(), INTERVAL 72 HOUR)

PHP mysql insert date format

I'm using jQuery datepicker
the format of the datepicker is this 08/25/2012
I have errors when inserting to my database it inserts only 0000-00-00 00 00 00
My code is:
<?php
$id = $_POST['id'];
$name = $_POST['name'];
$date = $_POST['date'];
$sql = mysql_query( "INSERT INTO user_date VALUE( '', '$name', '$date')" ) or die ( mysql_error() );
echo 'insert successful';
?>
I'm sure my insert is correct.
As stated in Date and Time Literals:
MySQL recognizes DATE values in these formats:
As a string in either 'YYYY-MM-DD' or 'YY-MM-DD' format. A “relaxed” syntax is permitted: Any punctuation character may be used as the delimiter between date parts. For example, '2012-12-31', '2012/12/31', '2012^12^31', and '2012#12#31' are equivalent.
As a string with no delimiters in either 'YYYYMMDD' or 'YYMMDD' format, provided that the string makes sense as a date. For example, '20070523' and '070523' are interpreted as '2007-05-23', but '071332' is illegal (it has nonsensical month and day parts) and becomes '0000-00-00'.
As a number in either YYYYMMDD or YYMMDD format, provided that the number makes sense as a date. For example, 19830905 and 830905 are interpreted as '1983-09-05'.
Therefore, the string '08/25/2012' is not a valid MySQL date literal. You have four options (in some vague order of preference, without any further information of your requirements):
Configure Datepicker to provide dates in a supported format using an altField together with its altFormat option:
<input type="hidden" id="actualDate" name="actualDate"/>
$( "selector" ).datepicker({
altField : "#actualDate"
altFormat: "yyyy-mm-dd"
});
Or, if you're happy for users to see the date in YYYY-MM-DD format, simply set the dateFormat option instead:
$( "selector" ).datepicker({
dateFormat: "yyyy-mm-dd"
});
Use MySQL's STR_TO_DATE() function to convert the string:
INSERT INTO user_date VALUES ('', '$name', STR_TO_DATE('$date', '%m/%d/%Y'))
Convert the string received from jQuery into something that PHP understands as a date, such as a DateTime object:
$dt = \DateTime::createFromFormat('m/d/Y', $_POST['date']);
and then either:
obtain a suitable formatted string:
$date = $dt->format('Y-m-d');
obtain the UNIX timestamp:
$timestamp = $dt->getTimestamp();
which is then passed directly to MySQL's FROM_UNIXTIME() function:
INSERT INTO user_date VALUES ('', '$name', FROM_UNIXTIME($timestamp))
Manually manipulate the string into a valid literal:
$parts = explode('/', $_POST['date']);
$date = "$parts[2]-$parts[0]-$parts[1]";
Warning
Your code is vulnerable to SQL injection. You really should be using prepared statements, into which you pass your variables as parameters that do not get evaluated for SQL. If you don't know what I'm talking about, or how to fix it, read the story of Bobby Tables.
Also, as stated in the introduction to the PHP manual chapter on the mysql_* functions:
This extension is deprecated as of PHP 5.5.0, and is not recommended for writing new code as it will be removed in the future. Instead, either the mysqli or PDO_MySQL extension should be used. See also the MySQL API Overview for further help while choosing a MySQL API.
You appear to be using either a DATETIME or TIMESTAMP column for holding a date value; I recommend you consider using MySQL's DATE type instead. As explained in The DATE, DATETIME, and TIMESTAMP Types:
The DATE type is used for values with a date part but no time part. MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The supported range is '1000-01-01' to '9999-12-31'.
The DATETIME type is used for values that contain both date and time parts. MySQL retrieves and displays DATETIME values in 'YYYY-MM-DD HH:MM:SS' format. The supported range is '1000-01-01 00:00:00' to '9999-12-31 23:59:59'.
The TIMESTAMP data type is used for values that contain both date and time parts. TIMESTAMP has a range of '1970-01-01 00:00:01' UTC to '2038-01-19 03:14:07' UTC.
You should consider creating a timestamp from that date witk mktime()
eg:
$date = explode('/', $_POST['date']);
$time = mktime(0,0,0,$date[0],$date[1],$date[2]);
$mysqldate = date( 'Y-m-d H:i:s', $time );
$date_field = date('Y-m-d',strtotime($_POST['date_field']));
$sql = mysql_query("INSERT INTO user_date (column_name,column_name,column_name) VALUES('',$name,$date_field)") or die (mysql_error());
You must make sure that the date format is YYYY-MM-DD on your jQuery output. I can see jQuery returns MM-DD-YYYY, which is not the valid MySQL date format and this is why it returns an error.
To convert it to the right one you could do this:
$dateFormated = split('/', $date);
$date = $dateFormated[2].'-'.$dateFormated[0].'-'.$dateFormated[1];
Then you will get formatted date that will be valid MySQL format, which is YYYY-MM-DD, i.e. 2012-08-25
I would also recommend using mysql_real_escape_string as you insert data into database to prevent SQL injections as a quick solution or better use PDO or MySQLi.
Your insert query using mysql_real_escape_string should rather look like this:
$sql = mysql_query( "INSERT INTO user_date VALUE( '', '" .mysql_real_escape_string($name). "', '" .mysql_real_escape_string($date). "'" ) or die ( mysql_error() );
Get a date object from the jquery date picker using
var myDate = $('element').datepicker('getDate')
For mysql the date needs to be in the proper format. One option which handles any timezone issues is to use moment.js
moment(myDate).format('YYYY-MM-DD HH:mm:ss')
The simplest method is
$dateArray = explode('/', $_POST['date']);
$date = $dateArray[2].'-'.$dateArray[0].'-'.$dateArray[1];
$sql = mysql_query("INSERT INTO user_date (column,column,column) VALUES('',$name,$date)") or die (mysql_error());
HTML:
<div class="form-group">
<label for="pt_date" class="col-2 col-form-label">Date</label>
<input class="form-control" type="date" value=<?php echo date("Y-m-d") ;?> id="pt_date" name="pt_date">
</div>
SQL
$pt_date = $_POST['pt_date'];
$sql = "INSERT INTO `table` ( `pt_date`) VALUES ( '$pt_date')";
Suppose you receive a Christmas date:
December 25, 2021 (25 de Diciembre del año 2021) in string format: "d-m-Y" for example "12-25-2021". First create a valid DateTime object from the received format:
var_dump(DateTime::createFromFormat("d-m-Y","25-12-2021", new DateTimeZone("America/Argentina/Buenos_Aires")));
This generates as output:
object(DateTime)#2 (3) {
["date"]=>
string(26) "2021-12-25 10:21:11.000000"
["timezone_type"]=>
int(3)
["timezone"]=>
string(30) "America/Argentina/Buenos_Aires"
}
Now to get the date field from the DateTime object ready to go using format("Y-m-d H:i:s")):
var_dump(DateTime::createFromFormat("d-m-Y","25-12-2021",new DateTimeZone("America/Argentina/Buenos_Aires"))->format("Y-m-d H:i:s"));
This generates as output a ready to insert value:
string(19) "2021-12-25 10:56:30"
In summary now you can insert a formated date ('DD-MM-YYYY') in MySQL like this:
<?php
//string input post like "25-12-2021"
$date_input = $_POST['date_input'];
//create DateTime object
$date_time_obj=DateTime::createFromFormat("d-m-Y","25-12-2021",new DateTimeZone("America/Argentina/Buenos_Aires"));
//format date ready to insert as string at MySQL
$str_date=$date_time_obj->format("Y-m-d H:i:s");
?>
Now run directly from PHP to MySQL as a query:
<?php
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'world');
//verify connection
if (mysqli_connect_errno()) {
printf("Error de conexión: %s\n", mysqli_connect_error());
exit();
}
//prepare the query to execute
$stmt = $mysqli->prepare("INSERT INTO table_example (DATE_FIELD) VALUES (?)");
//prevent sql injection
$stmt->bind_param('s', $str_date);
//execute prepared statements
$stmt->execute ();
?>
These days, I am not good with dates. Thanks to the following work, I can print the dates in the format I want.
$year = $_POST['year'];
$month = $_POST['month'];
$day = $_POST['day'];
$scr = strtotime($year . '-' . $month . '-' . $day);
$gelis_tarihi = date('Y-m-d', $scr);
$yil = $_POST['yil'];
$ay = $_POST['ay'];
$gun = $_POST['gun'];
$birlestir = strtotime($yil . '-' . $ay . '-' . $gun);
$gelis_tarihi = date('Y-m-d', $birlestir);
Try Something like this..
echo "The time is " . date("2:50:20");
$d=strtotime("3.00pm july 28 2014");
echo "Created date is " . date("d-m-y h:i:sa",$d);
First of all store $date=$_POST['your date field name'];
insert into **Your_Table Name** values('$date',**other fields**);
You must contain date in single cote (' ')
I hope it is helps.

How to correctly use the DateTime feature below

I have a timepicker where the textbox (durationChosen) formats the time like this '00 Hrs 00 Mins 00 Secs'.. Now the problem is that I want this time to be inserted into the database but obviously the format is incorrect. I want the textbox format to remain the same but how can I insert the time correctly in the database with the correct format?
At the moment the code below is causing the page not to load and because of this it is not inserting anything in the database. Have I coded the DateTime feature below incorrectly:
Below is the code for the INSERT VALUES:
$time = DateTime::createFromFormat( 'h * i * s *', $_POST['durationChosen'] );
$sql="
INSERT INTO Session (SessionDuration)
VALUES ('" . $time->format( 'H:i:s' ) . "')";
mysql_query($sql);
Maybe you could use this:
$time = date("H:i:s", strtotime($_POST["durationChosen"]));
Lets the datepicker return a valid ISO duration string like
$duration = "PT3H12M36S";
Now you can use DateInteval
$time = new DateTime;
$time->add(new DateInterval($duration);
As a side note: MySQL accepts an ISO formatted string for every of its DATE*-typed columns
VALUES (' . $time->format('c') . ')
http://php.net/datetime

PHP/MySQL: Convert from YYYY-MM-DD to DD Month, YYYY?

I have in a MySQL table a DATE column that represents the date in this format: YYYY-MM-DD.
I wanto to retrieve the date from the database using PHP but display it like this: DD Month, YYYY.
From '2009-04-13' to '13 April, 2009' for example.
Witch is the best way to do it?? ( I know how to get the date from the DB. I only need to know how to convert it)
I also need to display the month names in Spanish. There is a way to do it without translating each month using strplc or something like that??
I'm new to programming, please be detailed.
Thanks!!!
Refer to DATE_FORMAT() function in MySQL. I guess that's the best way for you to do it.
Also, you can make this:
Fetch your date from DB
Use strtotime in PHP, to convert to unix time
Then format the time using date.
By using date() you'll be able to get months names in Spanish when you set your locale in PHP with setlocale.
You could also skip the strtotime() part by using UNIX_TIMESTAMP(date) in your MySql select. But remember that this is a MySQL specific function and may not be be portable in the future.
Execute following MySQL queries:
SET lc_time_names = 'es_ES';
SELECT DATE_FORMAT(t.date,'%e de %M, %Y') FROM your_table t ...
With MySQLi it'll be:
$mysqli->query("SET lc_time_names = 'es_ES'");
$stmt = $mysqli->prepare("SELECT DATE_FORMAT(t.date,'%e de %M, %Y') FROM your_table t ...where id = ?");
...
Another option not yet mentioned:
SQL:
SELECT UNIX_TIMESTAMP(date) FROM table
PHP:
print date('your format', $timestamp_from_the_db);
Personally, I like to use integer data types in MySQL for date storage in the UNIX timestamp format. I leave all the processing of that integer up to PHP. Keeping tables and queries as simple as possible has always served me well. Predominantly, in the code I write, dates have some sort of calculation done to them. This is all done on the PHP side and always in the UNIX timestamp format. Storing or retrieving the dates in anything other than the UNIX timestamp format just means another step for errors to creep in and makes the query less modular. How a date is formatted is best left up until the last minute before it's displayed. It's just my opinion, but unless there are extreme circumstances where you can't process the DB value after extraction, a date shouldn't be formatted SQL-side.
A simplified example:
<?php
$date = now();
$dueDate = $date + 60*60*24*7; // One week from now
$sqlInsert = "INSERT INTO reports SET `dueDate` = $date";
$resInsert = mysql_query( $sqlInsert );
$sqlSelect = "SELECT `dueDate` FROM reports";
$resSelect = mysql_query( $sqlSelect );
$rowSelect = mysql_fetch_array( $resSelect );
$DB_dueDate = $rowSelect['dueDate'];
$daysUntilDue = ( $DB_dueDate - now() ) / 60*60*24;
$formattedDueDate = date( "j F, Y", $DB_dueDate );
?>
The report is due on <?=$formattedDueDate?>. That is <?=$daysUntilDue?> from now.
Simplest way is to use the strtotime() function to normalize the input to UNIX timestamp.
Then use the date() function to output the date in any format you wish. Note that you need to pass the UNIX timestamp as the second argument to date().
This will help you to convert as you want:
$dob ='2009-04-13';
echo date('d M Y', strtotime($dob));
$origDate = "2018-04-20";
$newDate = date("d-m-Y", strtotime($origDate));
echo $newDate;

Categories