Ignore first loop result - php

Question

I have a a FOR loop that lists all files within a certain directory. One of the results is also INDEX.PHP, a result which I don't need. It's the first result/entry of the loop...
Is there any way to skip this first result and start looping from the second one?
Please help.
<?php
$myDirectory = opendir('.');
while($entryName = readdir($myDirectory))
{
$dirArray[] = $entryName;
}
closedir($myDirectory);
$indexCount = count($dirArray);
echo '<h5>There are ' . $indexCount . ' files in the Media Center</h5>';
sort($dirArray);
echo '<table width="100%">';
echo '<tr>';
echo '<th width="33%" align="center" class="admin_th" style="border-radius: 10px 0 0 0">Download</th>';
echo '<th width="33%" align="center" class="admin_th">Filetype</th>';
echo '<th width="33%" align="center" class="admin_th" style="border-radius: 0 10px 0 0">Filesize (in bytes)</th>';
echo '</tr>';
for($index = 0; $index < $indexCount; $index++)
{
if (substr("$dirArray[$index]", 0, 1) != ".")
{
echo '<tr><td width="33%" align="center" class="admin_td-even">' . $dirArray[$index] . '</td>';
echo '<td width="33%" align="center" class="admin_td-odd">';
echo strtoupper(substr($dirArray[$index], -3));
echo '</td>';
echo '<td width="33%" align="center" class="admin_td-even">';
echo filesize($dirArray[$index]);
echo '</td>';
echo '</tr>';
}
}
echo '</table>';
?>

Answer 1

As soon as you see it what you don't want, place a continue statement which backs the loop to for condition.

Answer 2

I see two ways of doing it:
You can start one index later:
Instead of for($index = 0; $index < $indexCount; $index++) { ...},
do
for($index = 1; $index < $indexCount; $index++) { ...}
You can also add a condition:
for example:
for ($index = 0; $index < $indexCount; $index++) {
if ($dirArray[$index] == 'INDEX.PHP') continue;
// rest of the loop
}
But they are a few ways you can improve your code. Instead of using opendir() and readdir(), you can just use scandir like this:
foreach (scandir('.') as $file) {
}
But it looks like you want to grab some media file and display them. So an even better solution would be to use the glob() function, like this:
foreach (glob("*{.mp3,.mp4,.jpg,.png}", GLOB_BRACE) as $filename) {
echo "$filename size " . filesize($filename) . "\n";
}

Answer 3

Does the loop return the files as objects? then you could just add an if statement to the filename parameter

Answer 4

for($index = 0; $index < $indexCount; $index++)
{
//skip first entry
if($index == 0) continue;
if (substr("$dirArray[$index]", 0, 1) != ".")
{
echo '<tr><td width="33%" align="center" class="admin_td-even">' . $dirArray[$index] . '</td>';
echo '<td width="33%" align="center" class="admin_td-odd">';
echo strtoupper(substr($dirArray[$index], -3));
echo '</td>';
echo '<td width="33%" align="center" class="admin_td-even">';
echo filesize($dirArray[$index]);
echo '</td>';
echo '</tr>';
}
}

Answer 5

Just ignore the desired file by comparing name of the current file with desired. For example, you can do it in list retrieving:
$myDirectory = opendir('.');
while( false!==($entryName = readdir($myDirectory)) )
{
if( strtolower($entryName)=='index.php' )continue;
$dirArray[] = $entryName;
}
closedir($myDirectory);
Do not rely on the index (number of file), because your index.php may be not first in list.

Answer 6

for($index = 0; $index < $indexCount; $index++) {
if(index == 0) continue;
// other stuff
}