Getting every 7th element from array while echoing a table - php

Question

I'm getting the data I need from fgetcsv and store them into $data. It contains a table with a header row and lot's of info. Every 7th column is the path to where the file is stored.
I've already searched for what my problem is but I can't seem the find the solution.
My Code yet:
echo '<table border="0" cellspacing="0" cellpadding="5" class="csvTable" width="auto">';
$handle = fopen("index.csv", "r");
$start = 0;
while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
echo '<tr>' . "\n";
for ( $x = 0; $x < count($data); $x++) {
if ($start == 0 && $hasTitle == true)
echo '<th>'.$data[$x].'</th>' . "\n";
else
echo '<td>'.$data[$x].'</td>' . "\n";
}
$start++;
echo '</tr>' . "\n";
}
fclose($handle);
echo '</table>';
I want to add a hyperlink via <a href=?> on every 7th column but I don't know how. How can I do it and is that the right way?

Answer 1

You check every column is a 7th column or divisible by 7 you can just check if the variable is divided by 7 like this.
echo '<table border="0" cellspacing="0" cellpadding="5" class="csvTable" width="auto">';
$handle = fopen("index.csv", "r");
$start = 0;
while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) {
echo '<tr>' . "\n";
for ( $x = 0; $x < count($data); $x++) {
if ($start == 0 && $hasTitle == true)
echo '<th>'.$data[$x].'</th>' . "\n";
else
echo '<td>'.$data[$x].'</td>' . "\n";
if( $x && !($x % 7) ){
echo '<a href=?>'
}
}
$start++;
echo '</tr>' . "\n";
}
fclose($handle);
echo '</table>';

Answer 2

Check if the remainder by 7 of your counter is 0. If it is, then it is a multiple of seven and you can echo your desired string.
if($start % 7 === 0){
echo '<a href=?>'
}